Matambudziko Akagadziriswa muFizikisi Yekutanga

1. Muviri we 1 kg unodonha zvakasununguka kubva pakuzorora, kubva pakukwirira kwemamita makumi masere. Kuwedzera nekuda kwegiravhiti is 10 m / s²Chii chinonzi simba reinetic kana mutumbi warova pasi.

Zvinozivikanwa:

Misa (m) = 1 kg

urefu (h) = 80 m

Kuwedzera nekuda kwegiravhiti (g) = 10 m/s²

Kuda: simba remagetsi kana muviri warova pasi

Solution:

The kwokutanga michina simba (Ini_o) = simba regiravhiti (FOOT)

ME_o =PE = mgh = (1)(10)(80) = 800 maJoules

Simba rekupedzisira remakanika (ME_t) = simba reinetic (KE)

Musimboti we kuchengetedzwa kwesimba remakanika :

ME_o =ME_t

PE =KE

800=KE

Simba rekupedzisira rekinetic ndiro Majoules mazana masere.

2. Muviri we4 kg free-fall kubva pakuzorora, kubva pakukwirira kwemamita gumi. Kukurumidza kwesimba nekuda kwegiravhiti 10 ms^-2Chii chinonzi kinetic energy uye kumhanya kwemamita mashanu pamusoro penyika?

Zvinozivikanwa:

Kuchinja kwehurefu (h) = 10 – 5 = mamita mashanus

Huremu (m) = 4 kg

Kuwedzera nekuda kwegiravhiti (g) = 10 m/s²

Kuda: Kinetic energy iri pamamita mashanu kubva pasi uye kumhanya kwemamita mashanu pamusoro penyika

Solution:

(A) Kinetic energy iri pamamita mashanu kubva pasi

Simba rekutanga remakanika (ME_o) = simba regiravhiti (PE)

ME_o =PE = mgh = (4)(10)(5) = 200 maJoules

Simba rekupedzisira remakanika (EM)_t) = simba reinetic (EK)

ME_t =KE

Nheyo yekuchengetedza simba remakanika inoti simba rekutanga remakanika = simba rekupedzisira remakanika.

ME_o =ME_t

200=KE

Kinetic energy iri pamamita mashanu pamusoro pevhu iri Majoules mazana masere.

(B) kumhanya pa 5 mamitapamusoro pevhu

Simba rekutanga remakanika (ME_o) = simba rekupedzisira remakanika (ME_t)

PE =KE

200 = ½ mv²

2(200) / 4 = v²

100 = v²

v = √100

v = 10 m / s

Kumhanya kwemuviri pamamita mashanu kubva pasi i10 m/s.

3. Mango inodonha zvakasununguka kubva pakuzorora, kubva pakukwirira kwemamita maviri. Kukurumidza kwesimba regiravhiti kunoitika 10 ms^-2. Tarisa kumhanya kwemango kana yasvika pasi.

Zvinozivikanwa:

urefu (h) = mamita mashanus

Kuwedzera nekuda kwegiravhiti (g) = 10 m/s²

Zvaidiwa: kumhanya kwemango kana yarova pasi.

Solution:

Simba rekutanga remakanika (ME_o) = simba regiravhiti (PE)

ME =PE = mgh = m (10)(2) = 20 m

Simba rekupedzisira remakanika (ME_t) = simba rekinetic (KE)

ME_t =KE = ½ mv²

Nheyo yekuchengetedza simba remakanika inoti simba rekutanga remakanika = simba rekupedzisira remakanika.

ME_o =ME_t

20 m = ½ mv²

20 = ½ v²

2(20) = v²

40 = v²

v = √40 = √(4)(10) = 2√10 m/s

[wpdm_package id='1166′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro wakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Munhu anokanda dombo re 1-kg mudenga ne 2 m/s akamira pamucheto pedombo kuitira kuti dombo ridonhe pasi pedombo riri pasi pe 40 metres. Chii chinonzi simba reinetic yematombo ari pamusoro pevhu mamita gumi? Kuwedzera nekuda kwegiravhiti g = 10 m/s².

Zvinozivikanwa:

Misa (m) = 1 kg

Kumhanya kwekutanga (v)_o) = 2 m/s

Kuchinja kwehurefu = 40 - 10 = mamita makumi matatu

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Zvaidiwa: simba rekinetic rematombo pamamita gumi pamusoro pevhu

Solution:

Simba rekutanga remakanika

Simba rekutanga regiravhiti (EP) = mgh = (1)(10)(30) = 300 maJoules

Simba rekutanga rekinetic (KE) = ½ mv_o² = ½ (1)(2)² = ½ (4) = 2 maJoule

The kwokutanga michina simba = yekutanga simba regiravhiti + simba rekutanga rekinetic = 300 + 2 = 302 Joules.

Simba rekupedzisira remakanika

Simba rekupedzisira remakanika = simba rekupedzisira rekinetic = simba rekutanga regiravhiti + simba rekutanga rekinetic = 300 + 2 = 302 Joules.

2. Munhu anokanda chinhu chinorema 1-kg mudenga nekumhanya kwekutanga kwe10 m/s. Sarudza (a) simba regiravhiti pakukwirira kwepamusoro (b) kukwirira kwepamusoro.

Kukurumidza kwesimba nekuda kwegiravhiti ndeye 10 m/s²

Zvinozivikanwa:

Huremu (m) = 1 kg

Kumhanya kwekutanga (v)_o) = 10 m/s

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Wanted : simba regiravhiti pakukwirira kwepamusoro uye kukwirira kwepamusoro

Solution:

(a) simba regiravhiti rinokwevera zvinhu pasi pakakwirira

Simba rekutanga remakanika:

Simba rekutanga remakanika (ME) = simba rekutanga remakanika (KE) = ½ mv_o² = ½ (1)(10)² = ½ (100) = 50 maJoules.

Simba rekupedzisira remakanika:

Simba rekupedzisira remakanika (ME) = simba regiravhiti (PE)

Nheyo yekuchengetedza simba remakanika:

Simba rekutanga remakanika = simba rekupedzisira remakanika

KE = PE

50 = PE

Simba regiravhiti rinokwanisa kukweva zvinhu i50 Joules.

(b) Kureba kwakanyanya

PE = mgh

50 = (1)(10) h

50 = maawa makumi maviri

h = 50 / 10 = mamita mashanu

Kureba kwakanyanya kwemamita mashanu kubva pasi.

[wpdm_package id='1174′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro wakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Huremu hwe2-kg hunosungirirwa pachitubu. Kana kureba kwechitubu kuri 4 cm, tsvaga simba rinogona kuwanikwa rechitubu chinonamira. Kuwedzera nekuda kwegiravhiti iri 10 m/s².

Zvinozivikanwa:

Misa (m) = 2 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

uremu (w) = mg = (2)(10) = 20 N

Kureba (x) = 4 cm = 0.04 m

Zvaidiwa: Simba rinogona kuwanikwa muchitubu chinonamira

Solution:

Fomura ye Mutemo waHooke :

F = kx

F = simba, k = chitubu chisingachinji, x = kuchinja kwehurefu hwechitubu

Chirimo chinogara kwenguva refu:

k = w / x = 20 / 0.04 = 500 N/m

Simba rinogona kuwanikwa muchitubu chinopfava:

PE = ½ kx² = ½ (500)(0.04)² = (250)(0.0016) = 0.4 Joule

Imwe mhinduro:

PE = ½ kx² = ½ (w / x) x² = ½ wx = ½ mgx

w = huremu, m ​​= huremu, x = kuchinja kwehurefu hwechitubu

PE = ½ (2) (10) (0.04) = (10) (0.04) = 0.4 Joules.

2. Kureba kwechitubu kwakatambanudzwa nesimba F = 50 N i10 cm. Ndeipi simba rinogona kushandiswa nechitubu chinopfava kana kureba kwechitubu kuri 12 cm.

Zvinozivikanwa:

Kureba (x) = 10 cm = 0.1 m

Simba (F) = 50 N

Wanted : Simba rinogona kuwanikwa muchitubu chinonamira

Solution:

Chirimo chinogara kwenguva refu:

k = F / x = 50 / 0.1 = 500 N/m

Simba rinogona kuwanikwa muchitubu chinonamira kana kureba kwechitubu kuri 12 cm. :

PE = ½ kx² = ½ (500)(0.12)² = (250)(0.0144) = 3.6 Joules.

3. Girafu yeF vs x inoratidzwa mumufananidzo uri pazasi. Ndeipi simba rinogona kushandiswa nechitubu chinopfava, kana kureba kwechitubu kuri 10 cm.

Zvinozivikanwa:

Simba (F) = 5 N

Kureba kwechitubu (x) = 2 cm = 0.02 m

Kuda: Simba rinogona kuwanikwa muchitubu chinopfava kana kureba kwechitubu kuri 0.1 m.

Solution:

Chirimo chinogara kwenguva refu:

k = F / x = 5 / 0.02 = 250 N/m

Simba rinogona kuwanikwa muchitubu chinopfava kana kureba kwechitubu kuri 0.1 m:

PE = ½ kx² = ½ (250)(0.1)² = (125)(0.01) = 1.25 Joules.

4. Mutambi anosvetukira pachiridzwa chechirimo chine huremu hwe500 N, chitubu chinopfupika ne4 cm. Sarudza huwandu hwesimba rinogona kumanikidza mutambi.

A. 20 Joule

B. 10 Joule

C. 5 Joule

D. 2 Joule

Zvinozivikanwa:

Simba (F) = 500 N

Kuchinja kwehurefu hwechitubu (Δx) = 4 cm = 0.04 m

Kuda: Simba rinogona kuwanikwa muchirimo

Solution:

Verenga chisipiti che elastic constant uchishandisa equation yemutemo waHooke:

k = F / Δx = 500 N / 0.04 m = 12500 N/m

Simba rinoita kuti chitubu chive chakasimba:

PE = ½ k Δx² = ½ (12500)(0.04)² = (6250)(0.0016)

PE = 10 Joule

Mhinduro chaiyo ndeiyi B.

5. Chitubu apo yakasungirirwa nehuremu hwe 500 magiramu, kureba kwayo inowedzera ne5 cm. Sarudza kuti chii nguva dzose uye its simba rinogona kuwanikwa.

Zvinozivikanwa:

Huremu hwechinhu (m) = 500 magiramu = (500/1000) kg = 5/10 kg = 0.5 kg

Kukurumidza (g) = 10 m/s²

Kurema kwechinhu (w) = mg = (0.5 kg)(10 m/s²) = 5 kg m/s² = 5 Newton

Kuchinja kwehurefu hwechitubu (Δx) = 5 cm = 0.05 m

Zvaidiwa: simba risingaperi rechirimo (k) uye simba rinogona kuwanikwa (PE)

Solution:

Kutanga, verenga chiverengero chechirimo uchishandisa equation yemutemo waHooke:

k = w / Δx = 5 N / 0.05 m = 100 N/m

Kugona kunamira kwechirimo:

PE = ½ k Δx² = ½ (100)(0.05)² = (50)(0.0025)

PE = 0.125 Joule

[wpdm_package id='1179′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika pakufamba panzvimbo dzakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Muviri we1 kg free-fall kubva pakuzorora, kubva pakukwirira kwemamita gumi.

Sarudza:

(A) Basa rakaitwa nechisimba of giravhiti

(b) Kuchinja kuri simba regiravhiti

Kuwedzera nekuda kwegiravhiti (g) = 10 m/s²

Zvinozivikanwa:

Misa (m) = 1 kg

Kureba (h) = 10 m

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

uremu (w) = mg = (1 kg)(10 m/s²) = 10 N

Solution:

(A) Basa rinoitwa nesimba regiravhiti

W = wh = mgh

W = (1)(10)(10) = 100 Joule

(B) Kuchinja kwesimba regiravhiti

Kuchinja kwesimba regiravhiti kwakaenzana nebasa rinoitwa negiravhiti.

ΔEP = 100 Joule

2. Chinhu che10 N chinotsvedza pasi panzvimbo yakatsetseka yakatsetseka nemamita maviri. Tsvaga basa rinoitwa nesimba rehuremu!

Zvinozivikanwa:

huremu (w) = 10 N

w_x = chivi θ = (10)(chivi 30^o) = (10)(0.5) = 5 N

d = 2 m

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Zvaidiwa: basa rinoitwa nesimba rinorema

Solution:

W = F d = w_x d = (5)(2) = 10 Joule

Imwe mhinduro:

Pasina makumi matatu nemaviri^o = h / d

0.5 = awa / 2

h = (0.5)(2)

h = 1 m

Basa rinoitwa nesimba rinorema;

W = F d = wh = (10 N)(1 m) = 10 N m = 10 Joules

3. Chinhu che 1,500 gram pa 20 metres pamusoro pevhu, kudonha pasi pasina muripo. Chii chinonzi simba rekukwevera rechinhu chacho. Kukurumidza kunokonzerwa nekukwevera pasi i10 m/s².

Zvinozivikanwa:

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Huremu (m) = 1500 magiramu = 1500/1000 makirogiramu = 1.5 makirogiramu

Kureba (h) = mamita mashanu

Zvaidiwa: Simba regiravhiti

Solution:

PE = mgh = (1.5 kg)(10 m/s²)(20 m) = 300 kg m²/s² = 300 Joule

4. Zvichibva pamufananidzo uri pazasi, kana huremu hwechinhu 1 huri 2 kg uye huremu hwechinhu 2 huri 4 kg, kuenzanisa simba rinogona kuwanikwa rechinhu 1 nechinhu 2 ndiko…..

Zvinozivikanwa:

Huremu hwechinhu 1 (m₁) = 2 kg

Huremu hwechinhu 2 (m₂) = 4 kg

Kureba 1 (h)₁) = mamita makumi matanhatu

Kureba 2 (h)₂) = mamita makumi matanhatu

Kuda: Ckuenzanisa simba rinogona kuwanikwa rechinhu 1 nechinhu 2

Solution:

PE = mgh

m = huremu (chiyero chayo chepasi rose ikirogiramu, kg yakapfupikiswa)

g = kukurumidza kunokonzerwa negiravhiti (chikamu chayo chepasi rose chemamita pasekondi imwe chete, chakapfupikiswa m/s²)

h = kureba (chikamu chayo chepasi rose imita, chakapfupikiswa m)

PE = simba rekukwevera pasi (chikamu chayo chepasi rose i kg m²/s² kana Joule)

Simba rekukwevera rechinhu 1:

EP₁ = m₁ gh₁= (2)(g)(12) = 24 g

Simba rekukwevera rechinhu 2:

EP₂ = m₂ gh₂ = (4)(g)(9) = 36 g

Ckuenzanisa simba rinogona kuwanikwa rechinhu 1 nechinhu 2:

PE₁ : PE₂

24 g : 36 g

24: 36

12/24: 12/36

2: 3

[wpdm_package id='1175′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro wakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Bhokisi re2-kg rinodzika kubva pa10 m/s kusvika razorora. Chiyero che kukweshana kwekinetic is 0.2. Kuwedzera nekuda kwegiravhiti iri 10 m/s². Hukuru hwei? kudzingiswa?

Kuzivikanwa;

Misa (m) = 2 kg

Kumhanya kwekutanga (v)_o) = 10 m/s

Kumhanya kwekupedzisira (v)_t) = 0 m/s

Kukwana kwekukweshana kwekinetic (μ_k= = 0.2

uremu (w) = mg = (1 kg)(10 m/s²) = 10 kg m/s² = 10N

Zvaidiwa: Hukuru hwekutama (d)

Solution:

Musimboti wesimba rekushanda nemechanical :

W_nc = ΔEM

W_nc = ΔEK + ΔEP

W_nc = ½ m (v)_t² - v_o²) + mgh

W_nc = basa zvakaitwa na simba risingachengetedzi kuita chinhu chacho

ΔEK = shanduko mu simba reinetic

ΔEP = shanduko mu simba rinobvira

m = huremu

v = kumhanya

g = kukurumidza nekuda kwesimba rinokwevera pasi

h = kuchinja kwehurefu

Kuchinja kwehurefu h = 0 saka ΔEP = 0

W_nc = ΔEK

Basa rinoitwa nemauto asingachengetedze tsika:

W_nc = -F_c d = – μ_k N d = – μ_k wd = – μ_k mgd

W_nc = -(0.2)(2)(10)(s)

W_nc = – (4)(2)

Chiratidzo chekusiya chinoratidza kuti divi resimba rekukweshana kwekinetic rakapesana nedivi rekutama.

Kuchinja kwesimba rekinetic:

ΔEK = ½ m (v)_t² - v_o²) = ½ (2)(0 – 10²) = 0 – 100 = -100

Kukura kwekutama:

W_nc = ΔEK

– masekondi mana = – zana

s = -100/-4

s = 25 m

2. Chivharo chinotsvedza pasi padivi rakanamira. Chiyero chekukweshana kwekinetic i0.4. Kukurumidza kunokonzerwa negiravhiti ndiko g = 10 ms^-2Sarudza kumhanya kwekupedzisira apo bhokisi rinorova pasi.

Zvinozivikanwa:

Kureba kwekutanga (h)_o) = 6 m

Kureba kwekupedzisira (h)_t) = 0 m

Kumhanya kwekutanga (v)_o= = 0

Kukwana kwekukweshana kwekinetic (μ_k= = 0.4

Kukurumidza kunokonzerwa negiravhiti (g) = 10 ms^-2

cos θ = 8 / 10

Chikamu chakamira chehuremu = w_y = w cos θ = mg cos θ = m (10)(8/10) = m (10)(4/5) = m (40/5) = 8 m

Simba rakajairika = N = w_y = 8 XNUMX m

Simba rekukweshana kwekinetic = f_k = μ_k N= μ_k w_y = (0.4)(8 m) = 3.2 m

Zvaidiwa: Kumhanya kwekupedzisira (v)_t)

Solution:

Musimboti wesimba rekushanda nemagetsi:

W_nc = ΔEM

W_nc = ΔEK + ΔEP

Kuchinja kwesimba rekinetic:

ΔEK = 1/2 m (v)_t² - v_o²) = 1/2 m (v)_t² - 0) = 1/2 mv_t²

Kuchinja kwesimba rinogona kushandiswa:

ΔEP = mg (h)_t - h_o) = m (10)(0-6) = m (10)(-6) = – 60 m

Basa rinoitwa nesimba rekukweshana kwekinetic:

W_nc = – f_k s = – (3.2 m(10) = – 32 m

Chiratidzo chekusiya chinoratidza kuti divi resimba rekukweshana kwekinetic rakapesana nedivi rekutama.

Kumhanya kwekupedzisira (v)_t):

W_nc = ΔEK + ΔEP

- 32 m = 1/2 mv_t² - 60 m

- 32 m = m (1/2 v)_t² - 60)

- 32 = 1/2 v_t² - 60

– 32 + 60 = 1/2 v_t²

28 = 1/2 v_t²

2 (28) = v_t²

56 = v_t²

v_t = √4.14

v_t = 2√14 ms^-1

3. Chivharo chinotsvedza pasi padenderedzwa rakakombama. Kumhanya kwekutanga i0 m/s uye kumhanya kwekupedzisira i 10 ms^-1Kana simba rekukweshana kwekinetic riri 2 N uye kumhanyisa nekuda kwegiravhiti g = 10 ms^-2, chii chinonzi kureba (h) ?

Zvinozivikanwa:

Huremu (m) = 1 kg

Kumhanya kwekutanga (v)_o= = 0 (kuzorora kwebhuroko)

Kumhanya kwekupedzisira (v)_t) = 10 ms^-1

Kureba kwekutanga (h)_o) = h

Kureba kwekupedzisira (h)_t= = 0

Simba rekukweshana kwekinetic (f)_k) = 2 N

Kukurumidza kunokonzerwa negiravhiti (g) = 10 ms^-2

Zvaidiwa: Urefu (h)

Solution:

Basa rinoitwa nesimba rekukweshana kwekinetic:

W_nc = – f_k s = – (2))(15) = – 30

Chiratidzo chekusiya chinoratidza kuti divi resimba rekukweshana kwekinetic rakapesana nedivi rekutama.

Kuchinja kwesimba rekinetic:

ΔEK = 1/2 m (v)_t² - v_o²) = 1/2 (1)(10² - 0) = 1/2 (10²) = 1/2 (100= = 50

Kuchinja kwesimba rinogona kushandiswa:

ΔEP = mg (h)_t - h_o) = (1)(10)(0-h) = (10)(-h) = -10 maawa

Musimboti wesimba rekushanda nemagetsi:

W_nc = ΔEK + ΔEP

– 30 = 50 – 10 maawa

Maawa gumi = 50 + 30

10 maawa = 80

h = 80/10

h = 8 m

4Kana bhokisi richifamba pasi rakarerekera zvakanyanya, saka….
A. Basa rinoitwa nesimba regiravhiti pabhuroko rakakura kupfuura shanduko yesimba ringangoitika rebhuroko
B. Simba remakanika rinowedzera
C. Huwandu hwesimba rekinetic uye simba raro rinogoneka zvinoderedzwa
D. Basa rinoitwa nesimba rekukweshana rakaenzana nekuchinja kwesimba rekinetic reblock
mhinduro

A haina kururama

Basa rinoitwa nesimba regiravhiti pabhuroko rakaenzana nekuchinja kwesimba regiravhiti rebhuroko.

B haana kururama

Kana mukaticNzvimbo ine mutsetse yakatsetseka saka simba remuchina rebhokisi rinogara riripo. Kana riri pamusoro penzvimbo yakatsveyama uye risati rafamba, simba remuchina rebhokisi rakaenzana nesimba regiravhiti. Bhokisi racho richiri pakadzika saka simba raro regiravhiti harisi zero. Pakufamba pasi penzvimbo yakatsveyama, kukwirira kwebhokisi kunoderedzwa saka simba regiravhiti rinoderedzwawo. Simba regiravhiti rinoderera nekuti rinochinja kuenda kusimba regiravhiti. Kunyangwe simba regiravhiti richichinja kuita simba regiravhiti, simba remuchina rinogara riripo.

Kana denderedzwa rakakombama rakashata, simba remuchina weblock rinodzikira nekuda kwebasa rakaipa rinoitwa nechisimba chemuchina. Simba remuchina we ...

C yakarurama

Nzvimbo yakakombama yakakombama saka pane simba rekukweshana rinoedza mafambiro eblock. Simba rekukweshana isimba risingachengetedzi. Theorem work-mechanical energy inoti basa rinoitwa nesimba risingachengetedzi (semuenzaniso simba rekukweshana) rakaenzana nekuchinja kwesimba remakanika. Mukutsvaga uku, simba remakanika riri kudzikira.

Simba remuchina reblock = simba regiravhiti + simba rekinetic.

D haana kururama.

Basa rinoitwa nesimba rekukweshana pabhuroko rakaenzana nekuchinja kwesimba remuchina rebhuroko, kwete kuchinja kwesimba remuchina rebhuroko. Ichokwadi kuti simba rekukweshana rinopikisa kufamba kwebhuroko saka rinoderedza kumhanya kwebhuroko uye rinoderedza simba remuchina rebhuroko. Asi ziva kuti simba remuchina rebhuroko rinobva kusimba regiravhiti. Saka ichokwadi kuti basa rinoitwa nesimba rekukweshana rakaenzana nekuchinja kwesimba remuchina (simba remuchina rinoderera).

Mhinduro chaiyo ndeinoti C.

5Chinhu chiri paburiro rakashata chinorohwa saka chinofamba kwemasekonzi matatu chobva chamira. Kana huremu hunozivikanwa hwechinhu chacho huri magiramu gumi, simba rekukweshana pakati pechinhu chacho neburiro i2 kilodyne. Sarudza basa rinoitwa nesimba rekukweshana.

A. 0.18 J

B. -0.18 J

C. 0.36 J

D. -0.36 J

Zvinozivikanwa:

Nguva yepakati (t) = masekondi gumi nemashanu

Kumhanya kwekupedzisira (v)_t) = 0 m/s (chinhu chinozorora)

Huremu hwechinhu (m) = magiramu gumi = 10/1000 kg = 1/100 kg = 0.01 kg

Simba rekukweshana (F) = 2 kilodyne = 2 x 10³ nhanga

Zvaidiwa: Basa (W) rinoitwa nesimba rekukweshana

Solution:

Kushandurwa kwezvikamu zvesimba:

1 Newton = 1 x 10⁵ nhanga

1 dyne = 1/10⁵ Newton = 1 x 10^-5 Newton = 10^-5 Newton

Simba rekukweshana (F) = 2 x 10³ dyne = 2 x 10³ x 10^-5 Newton = 2 x 10^-2 Newton = 2/100 Newton = 0.02 Newton

Dzidziso yesimba rekushanda nemechanical inotaura kuti basa rinoitwa nesimba risingachinji pane chinhu chakaenzana nekuchinja kwesimba remuchina wechinhu chacho.

Kana chinhu chichifamba padenderedzwa rakanamira, simba remagetsi (ME) = simba regiravhiti (PE) + simba remagetsi (KE). Asi kana chinhu chichifamba padenderedzwa rakanamira chete saka hapana shanduko pakukwirira, simba remagetsi = simba remagetsi. Padenderedzwa rakanamira, simba regiravhiti harisi zero nekuti hapana shanduko pakukwirira.

Simba rekukweshana isimba risingachengetedzi. Simba rekukweshana rinowanzo kuderedza kumhanya kwechinhu uye simba rekukweshana rechinhu. Tinogona kugumisa kuti basa rinoitwa nesimba rekukweshana pachinhu rakaenzana nekuderera kwesimba remakanika.

Pamasvomhu:

Basa (W) = Kuchinja kwesimba remakanika (ΔEM)

F s = ΔEP + ΔEK

F s = mg Δh + ½ m (v_t² - v_o²)

F s = mg (0) + ½ m (0)² - v_o²)

Fs = 0 + ½ m (– (v_o²))

Fs = – ½ mv_o² ———— Equation 1

Tsananguro: F = simba rekukweshana, d = kutama, m = huremu, v_o = kumhanya kwekutanga

Kutamiswa (d) uye kumhanya kwekutanga (v)_o) hazvizivikanwe nekuti tanga waverenga v_o kana d. Basa rinoitwa nesimba rekukweshana rakaverengwa uchishandisa imwe ye equation mushure mekuzivikanwa kwa v_o kana d.

Equation yekutama (d) pakufamba kwemutsara kusingaenderane:

v_t² =v_o² + 2 (-a) s

Kumhanya kwekupedzisira (v)_t) = 0 uye kukurumidza (a) kunosainwa negative nekuti chinhu chacho chaderera (kumhanya kwechinhu kwadzikira).

0 = v_o² - 2 kushambadzira

v_o² = 2 kushambadza

d = v_o² / 2 a———— Equation 2

Chinja d muequation 2 na d muequation 1:

F d = – ½ mv_o²

F (v)_o²/2a) = – ½ mv_o²

(F/2a) v_o² = – ½ mv_o²

F/2a = – ½ m

F = (2)(a)(-1/2)(m)

F = – (a)(m)

a = – (F / m)

a = – 0.02 Newtons / 0.01 kg

a = – 2 Newton/kilogiramu

a = – 2 m/s²

Equation yekuverenga kumhanya kwekutanga (v)_o) mukufamba kwemutsara kusingaenzaniswi:

v_t =v_o + pa —–> Kumhanya kwekupedzisira (v)_t) = 0, Kukurumidza (a) = 2 m/s², nguva yechinguva (t) = masekondi matatu

0 = v_o + (-2)(3)

0 = v_o - 6

v_o = mamita maviri/sekondi

Basa (W) rinoitwa nechisimba chemagetsi:

W = – ½ mv_o² = -1/2 (0.01)(6²) = -1/2 (0.01)(36)

W = -1/2 (0.36)

W = – 0.18 Joule

Basa rinoitwa nechisimba rinosainwa nechiratidzo chekuti harina simba zvichireva kuti basa racho rinoderedza simba remuchina wechinhu chacho.

Kana zvikazivikanwa d basa rinogona kuverenga richishandisa equation ye W = F d.

Mhinduro chaiyo ndeiyi B.

[wpdm_package id='1178′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro wakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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Simba reKinetic reBasa :

1. Mota inorema 5000 kg yakakurumidza kubva pakuzorora kusvika 20 m/s. Sarudza mambure basa zvaitwa pamotokari.

Zvinozivikanwa:

Misa (m) = 5000 kg

Kumhanya kwekutanga (v_o) = 0 m/s (zororo remota)

Kumhanya kwekupedzisira (v_t) = 20 m/s

Wanted : net work

Solution:

Musimboti wesimba rekushanda-kinetic :

W_mambure = ΔEK

W_mambure = ½ m (v)_t² - v_o²)

W_mambure = net work

ΔEK = shanduko musimba rekinetic

m = huremu (kg),

v_t = kumhanya kwekupedzisira (m/s),

v_o = kumhanya kwekutanga (m/s).

Network:

W_mambure = ½ m (v)_t² - v_o²)

W_mambure = ½ (5000)(20² - 0²)

W_mambure = (2500)(400 – 0)

W_mambure = (2500)(400)

W_mambure = 1000,000 Joule

2. Chinhu chinorema 10 kg chakakurumidza kubva pa5 m/s kusvika pa10 m/s. Tsvaga basa remambure rakaitwa pachinhu chacho!

Zvinozivikanwa:

Misa (m) = 10 kg

Kumhanya kwekutanga (v_o) = 5 m/s

Kumhanya kwekupedzisira (v_t) = 10 m/s

Wanted : net work

Solution:

Network:

W_mambure = ΔEK

W_mambure = ½ m (v)_t² - v_o²)

W_mambure = ½ (10)(10² - 5²)

W_mambure = (5)(100 – 25)

W_mambure = (5)(75)

W_mambure = 375 Joule

3. Mota inorema 2000 kg inodzikira kubva pa10 m/s kusvika pa5 m/s. Basa rakaitwa pamota iyi nderei?

Zvinozivikanwa:

Mota mmbongoro (m) = 2000 kg

Kumhanya kwekutanga (v_o) = 10 m/s

Kumhanya kwekupedzisira (v_t) = 5 m/s

Kuda: net work

Solution:

Network:

W_mambure = ΔEK

W_mambure = ½ m (v)_t² - v_o²)

W_mambure = ½ (2000)(5² - 10²)

W_mambure = (1000)(25 – 100)

W_mambure = (1000)(-75)

W_mambure = -75,000 Joule

Chiratidzo chekusiya chinoratidza kuti nzira yekutama yakatarisana nenzira yesimba remagetsi.

4. Simba risingaperi re60-N rinoitwa pachinhu chinorema 10-kg kwemasekonzi gumi nemaviri. Kumhanya kwekutanga kwechinhu i6 m/s uye kutungamira kwechinhu kwakafanana nekutungamira kwesimba.

(1) Basa rakaitwa pachinhu ichi i30,240 Joules

(2) Simba rekupedzisira rekinetic i30,240 joules

(3) simba i2,520 Watts

(4) Kuwedzera kwesimba rekinetic rechinhu ichi i180 Joules

Mashoko echokwadi ndeekuti…

Zvinozivikanwa:

Simba (F) = 60 N

Nguva yepakati (t) = masekondi gumi nemashanu

Huremu hwechinhu (m) = 10 kg

Kumhanya kwekutanga (v)_o) = 6 m/s

Zvaidiwa: Mashoko akarurama

Solution:

Kukurumidzisa kwechinhu:

∑F = ma

60 = 10 a

a = 60 / 10 = 6 m/s²

Kumhanya kwekupedzisira:

v_t =v_o + pa

v_t = 6 + (6)(12)

v_t = 6 + 72

v_t = 78 m/s

The mufambo akafamba mumasekonzi gumi nemaviri:

s = v_o t + 1/2 pa²

s = (6)(12) + 1/2 (6)(12)²

s = 72 + (3)(144)

s = 72 + 432

s = mamita gumi

(1) Basa rinoitwa nechisimba

W = F s = (60)(504) = 30,240 Joules

(2) Simba rekupedzisira rekufamba kwemhepo

KE = 1/2 mv_t² = 1/2 (10)(78)² = (5)(6084) = 30,420 Joule

(3) Simba

P = W / t = 30,240 / 12 = 2,520 Joules/sekondi

(4) Kuwedzera kwesimba remagetsi

ΔKE = 1/2 mv_t² – 1/2 mv_o² = 1/2 m (v)_t² - v_o²) = 1/2 (10)(78² - 6²) = 5 (6084 –36) = 5 (6048)

ΔKE = 30,240 Joule

5. Basa guru rinoitwa nenhamba yechinhu…

Solution:

Basa reNet = shanduko yesimba reKinetic

W_mambure = ½ m (v)_t² - v_o²)

Basa guru:

W₁ = ½ (8)(4² - 2²) = (4)(16 – 4) = (4)(12) = 48 Joules

W₂ = ½ (8)(5² -3²) = (4)(25 – 9) = (4)(16) = 64 Joules

W₃ = ½ (10)(6² - 5²) = (5)(36 – 25) = (5)(11) = 55 Joules

W₄ = ½ (10)(4² - 0²) = (5)(16 – 0) = (5)(16) = 80 Joules

W₅ = ½ (20)(3² - 3²) = (10)(9 – 9) = (10)(0) = 0 Joules

6. Mota inorema 4000 kg inofamba nemutsetse wakatwasuka pa25 m/s. Mota inoderedzwa speed zvekuti kumhanya kwekupedzisira kwemota kuri 15 m/s. Basa rakaitwa pamota nderei?

Zvinozivikanwa:

Huremu (m) = 4000 kg

Kumhanya kwekutanga (v)_o) = 25 m/s

Kumhanya kwekupedzisira (v)_t) = 15 m/s

Wanted : Basa rakaitwa pamotokari

Solution:

W_mambure = ½ m (v)_t² - v_o²) = ½(4000)(15²-25²) = (2000)(225-625) = (2000)(-400) = -800,000 Majoules = -800 kJ

7. Chiyero che 0.1-kg chakakandwa chakatambarara pa 6 m/s kubva pakukwirira kwemamita mashanu. Kana kukurumidza kwegiravhiti iri 10 m/s², saka chii chinonzi kinetic energy yebhora pakukwirira kwemamita maviri.

Zvinozivikanwa:

Huremu (m) = 0.1 kg

Kuchinja kwehurefu (h) = 5 m – 2 m = 3 metres

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Zvaidiwa: Simba rekinetic riri pakakwirira mamita maviri.

Solution:

Kufamba kweprojectile kunogona kunzwisiswa nekuongorora zvikamu zvekufamba zvakatwasuka uye zvakatwasuka zvakasiyana. Kufamba kwakatwasuka kwakaongororwa se kufamba kwekukurumidza nguva dzose uye kufamba kwakatwasuka kwakaongororwa se kufamba kwemahara kwekudonha kana kufamba kwakamira.

The kwokutanga michina simba = iyo simba regiravhiti.

PE = mgh = (0.1)(10)(3) = 3 maJoules.

The yokupedzisira michina simba = simba rekufamba nemhepo.

KE = 3 maJoules.

8. Mota inorema 1000 kg inomhanya nekukurumidza kubva pakuzorora uye inofamba ne5 m/s. Ndeipi basa rinoitwa nemota?

Zvinozivikanwa:

Huremu (m) = 1000 kg

Kumhanya kwekutanga (v)_o= = 0

Kumhanya kwekupedzisira (v)_t) = 5 m/s

Zvaidiwa: Basa (W) rinoitwa nemotokari

Solution:

W_mambure = ½ m (v)_t² - v_o²)

Basa rinoitwa nemota:

W_mambure = ½ (1000)(5² - 0²) = (500)(25 – 0) = (500)(25) = 12,500 Joules

9. Bhora remagiramu mazana mashanu rinokandwa rakamira mudenga kubva pamusoro penyika nekumhanya kwekutanga kwe10 m/s²Kukurumidza kwesimba regiravhiti (gravity) i10 ms^-2Chii chinoitwa nesimba rinorema kana bhora rasvika pakukwirira kwakanyanya?

Inozivikanwa :

Huremu hwebhora (m) = 500 magiramu = 0.5 kg

Kumhanya kwekutanga (v)_o) = 10 m/s²

Kumhanya kwekupedzisira (v)_t) = 0 (kumhanya kwakanyanya)

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Zvaidiwa: Basa (W) rinoitwa nehuremu

Solution:

Basa remambure rinoitwa nesimba remambure pachinhu = shanduko musimba remambure.

W_mambure = ΔEK = EK_t - EK_o

Wnet = ½ mv_t² – ½ mv_o² = ½ m (v)_t² - v_o²)

KE_t = simba rekupedzisira rekinetic, KE_o = simba rekutanga rekinetic, m = huremu hwechinhu, v_t = kumhanya kwekupedzisira kwechinhu, v_o = kumhanya kwekutanga kwechinhu.

Network:

W_mambure = ½ m (v)_t² - v_o²) = ½ (0.5)(0² - 10²)

W_mambure = (0.25)(-100) = -25 Joule

Chiratidzo chekudzima chinoratidza kuti bhora rakananga kure kure neuremu hwaro. Bhora rakananga rakamira uye huremu hwaro hwakamira kure.

10. Chinhu chinorema 1 kg chinodonha chisina kusimba nekukwirira kwakasiyana = 2.5 metres. Kukurumidza kunokonzerwa negiravhiti i10 ms^-2Chii chakaitwa pachinhu chacho?

Zvinozivikanwa:

Huremu hwebhora (m) = 1 kg

Kumhanya kwekutanga (v)_o) = 0 m/s

Kureba (h) = mamita mashanu

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Zvaidiwa: Network panguva yekutama

Solution:

Kumhanya kwekupedzisira kwebhora (v_t)

Kuverengerwa uchishandisa equation yekufamba kwemahara kwekudonha. Zvinozivikanwa: Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s², Kuchinja kwehurefu hwebhora (h) = 2.5 metres. Zvaidiwa: Kumhanya kwekupedzisira.

v_t² = 2 gh = 2(10)(2.5) = 2(25)

v_t = √2(25)

v_t = 5√2

Basa reNet = shanduko musimba rekinetic

W_mambure = ΔEK = ½ m (v)_t² - v_o²) = ½ (1){(5√2)² - 0²}

W_mambure = ½ (25)(2) = 25 Joule

11. Chinhu chinorema 2 kg chinofamba ne72 km/awa. Mushure mekufamba mamita 400, kumhanya kwekupedzisira kwechinhu chacho i144 km/awa. Kumhanya kunokonzerwa negiravhiti i10 ms^-2Tsvaga network.

Zvinozivikanwa:

Huremu hwechinhu (m) = 2 kg

Kumhanya kwekutanga (v)_o) = 72 km/awa = 20 m/s

Kumhanya kwekupedzisira (v)_t) = 144 km/awa = 40 m/s

mufambo (s) = mamita mazana maviri nemaviri

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Zvaidiwa: Network

Solution:

Basa remagetsi = shanduko dzesimba remagetsi

W_mambure = ΔEK = ½ m (v)_t² - v_o²) = ½ (2)(40² - 20²}

W_mambure = ½ (2)(1600 - 400) = 1200 Joules

12. Chinhu chinorema 2 kg chinofamba ne 2 ms^-1Basa rinoitwa pachinhu ichi i21 Joules. Chii chinonzi kumhanya kwekupedzisira kwechinhu?

Zvinozivikanwa:

Huremu (m) = 2 kg

Kumhanya kwekutanga (v)_o) = 2 m/s

Basa (W) = 21 Joule

Zvaidiwa: kumhanya kwekupedzisira (v)_t)

Solution:

W_mambure= ΔEK

W_mambure= 1/2 mv_t² -1/2 mv_o²

W_mambure = 1/2 m (v)_t² - v_o²)

21 = 1/2 (2) (v)_t² - 2²)

21 = (v)_t² - 2²)

21 = v_t² - 4

v_t² = 21 + 4 = 25

v_t = √25

v_t = 5 m/s

13Simba risingaperi re8 N rinoshanda pachinhu chine huremu hwe16 kg. Kana chinhu chacho chikatanga chakamira, tarisa kumhanya kwechinhu mushure mekunge simba racho rashanda pachinhu chacho kwemasekonzi mana.

Zvinozivikanwa:

Simba risingaperi (F) = 8 Newton

Huremu hwechinhu (m) = 16 kg

Kumhanya kwekutanga kwechinhu (v)_o) = 0 m/s

Simba rinoita basa pachinhu (t) = masekondi mana.

Zvaidiwa: Kumhanya kwekupedzisira (v)_t)

Solution:

Basa = Kuchinja kwesimba rekinetic

W = KE yekupedzisira – KE yekutanga

W = ½ mv_t² – ½ mv_o²

W = ½ mv_t² - 0

W = ½ mv_t² —— Equation 1

Basa = Simba x Kudzingwa

W = F d

W = 8 d

Shandisa equation yekufamba kwemutsara kusingaenderane iri pazasi kuti uverenge displacement (d):

d = v_o t + ½ pa²

d = kutama, v_o = kumhanya kwekutanga, t = nguva yepakati, a = kumhanya

d = 0 + ½ pa² = ½ pa² —-> a = (v)_t - v_o) / t = v_t /t

d = ½ (v)_t / t) t²

^d = ½ (v)_t) t

Chinja displacement (d) pa equation yeBasa ne displacement (d) mu equation iyi:

W = 8 d

W = 8(1/2)(v)_t(t)

W = (4)(v)_t)(t) —— equation 2

Equation 1 = Equation 2

W = W

½ mv_t² = (4)(v)_t(t)

½ mv_t = (4)(t)

½ (16)(v)_t) = 4(4)

8 v_t = 16

v_t = 16/8

v_t = mamita maviri/sekondi

14Kuti uwedzere kumhanya kwechinhu kakapetwa kaviri pane kumhanya kwekutanga, sarudza basa rinodiwa mukuita…

Zvinozivikanwa:

Huremu hwechinhu (m) = 1 kg

Kumhanya kwekutanga (v)_o) = 1 m/s

Kumhanya kwekupedzisira (v)_t) = 2 x kumhanya kwekutanga = 2 x 1 = 2 m/s

Zvaidiwa: basa

Solution:

Simba rekutanga rekinetic:

Chinyorwa chekutanga cheKE = ½ mv_o² = ½ (1)(1)² = ½ (1)(1) = ½ (1) = 0.5

Simba rekupedzisira rekinetic kana kumhanya kwechinhu kwava kaviri kupfuura kumhanya kwacho kwekutanga:

KE yekupedzisira = ½ mv_t² = ½ (1)(2)² = ½ (4) = 2

Dzidziso yesimba rekushanda-kinetic:

Basa = Kuchinja kwesimba rekinetic

Basa = Simba rekupedzisira rekinetic – simba rekutanga rekinetic

Basa = 2 – 0.5

Basa = 1.5

Simba rekutanga rekinetic = 0.5

Basa = 3 x 0.5 = 1.5

Inodiwa kuti ishande ka3 kupfuura simba rayo rekutanga rekinetic.

15Mota ine huremu hwe1500 kg inofamba nekumhanya kwe36 km/awa mumugwagwa wakatwasuka uye wakatsetseka. Mota yacho yakakurumidza kusvika 72 km/awa. Sarudza basa rinodiwa kuti mota imhanye.

Zvinozivikanwa:

Huremu hwemota (m) = 1500 kg

Kumhanya kwekutanga kwemotokari (v)_o) = 36 km/awa = 36,000 metres / 3600 seconds = 10 metres/sekondi

Kumhanya kwekupedzisira kwemotokari (v)_t) = 72 km/awa = 72,000 metres / 3600 seconds = 20 metres/sekondi

Zvaidiwa: Basa rinodiwa kuti mota imhanye nekukurumidza

Solution:

Dzidziso yesimba rekushanda-kinetic:

W = EK yekupedzisira – EK yekutanga

W = ½ mv_t² – ½ mv_o² = ½ m (v)_t² –v_o²)

W = ½ (1500)(20)² - 10²)

W = ½ (1500)(400 - 100)

W = ½ (1500)(300)

W = (1500)(150)

W = 225,000 Joules

16Chinhu chine huremu hwe2 kg chinotanga kufamba nekumhanya kwe72 km awa^-1Mushure mekufamba mumugwagwa wakatwasuka kusvika pamamita mazana mana, kumhanya kwechinhu chacho i144 km.^-1Sarudza basa rose pachinhu chacho.

Zvinozivikanwa:

Huremu hwechinhu (m) = 2 kg

Kumhanya kwekutanga (v)_o) = 72 km/awa = 72,000 metres / 3600 seconds = 20 m/s

Kumhanya kwekupedzisira (v)_t) = 144 km/awa = 144,000 metres / 3600 seconds = 40 m/s

Kutamiswa kwechinhu = mamita mazana mana

Zvaidiwa: Network pane chinhu

Solution:

Dzidziso yesimba rekushanda-kinetic inoti basa remagetsi rinoshanda pachinhu zvakafanana nekuchinja kwesimba remagetsi rechinhu.

W net = KUSVIKA pakupera – KUSVIKA pakutanga

W net = ½ mv_t² – ½ mv_o²

W net = ½ m (v)_t² - v_o²)

W net = ½ (2)(40² - 20²)

W net = 1600 - 400

W net = 1200 Joule

Description:

W = Basa, KE = simba remagetsi

Kinetic simba

17. Bara remagiramu gumi richifamba ne100 m/s. Chii chinonzi kinetic energy yebara.

Zvinozivikanwa:

Huremu hwebara (m) = magiramu gumi = 10/1000 makirogiramu = 1/100 makirogiramu = 0.01 makirogiramu

Kumhanya kwebara (v) = mamita zana pasekondi

Kuda: Kinetic simba

Solution:

KE = 1/2 mv²

KE = Chikamu chimwe chete (0,01 kg)(100 m/s)²

KE = 1/2 (0,01 kg)(10.000 m²/s²)

KE = (0,01 kg)(5000 m²/s²)

KE = 50 kg m²/s²

KE = 50 Joule

[wpdm_package id='1191′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro pekona
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Munhu anodhonza bhokisi 2 m pamusoro penzvimbo yakatambanuka nesimba risingaperi F = 20 N. Sarudza basa rakaitwa nechisimba F ari kushanda pabhokisi.

Zvinozivikanwa:

Simba (F) = 20 N

Displacement (s) = 2 m

Angle (θ)) = 0

Wanted Basa (W)

Solution:

W = F d cos θ = (20)(2)(cos 0) = (20)(2)(1) = 40 Joules

2. Simba F = 10 N richishanda pabhokisi 1 m rakatevedza nzvimbo yakatwasuka. Simba iri rinoshanda pa30^o kona sezvakaratidzwa mumufananidzo uri pazasi. Sarudza basa rinoitwa nesimba F!

Inozivikanwa :

Simba (F) = 10 N

Simba rakatwasuka (F)_x) = F cos 30^o = (10)(0.5√3) = 5√3 N

Kutamiswa (d) = mita imwe

Wanted : Basa (W) ?

mhinduro :

W = F_x d = (5√3)(1) = 5√3 Joule

3. Mutumbi unodonha zvakasununguka kubva pakuzorora, kubva pakukwirira kwemamita maviri. Kana kukurumidza nekuda kwegiravhiti iri 10 m/s², sarudza basa rinoitwa ne simba regiravhiti!

Zvinozivikanwa:

Chinhu uremu (m) = 1 kg

Kureba (h) = 2 m

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Zvaidiwa: Basa rinoitwa nesimba regiravhiti (W)

Solution:

W = F d = wh = mgh

W = (1)(10)(2) = 20 Joule

W = basa, F = simba, d = daro, w = uremu, h = kureba, m ​​= huremu, g = kukurumidza nekuda kwegiravhiti.

4. Chinhu chinorema 1-kg chinosungirirwa pachitubu saka chinoreba 2 cm. Kana kumhanyisa nekuda kwesimba regiravhiti kuri 10 m/s², sarudza (a) chisimbiso chechitubu (b) basa rinoitwa nesimba rechitubu pachinhu

Zvinozivikanwa:

Huremu (m) = 1 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Kureba (x) = 2 cm = 0.02 m

Huremu (w) = mg = (1 kg)(10 m/s²) = 10 kg m/s² = 10N

Zvaidiwa: Nguva yechirimo uye basa rinoitwa nechisimba chechirimo

Solution:

(a) Chitubu chinogara kwenguva refu

Fomura ye Mutemo waHooke :

F = k x.

k = F / x = w / x = mg / x

k = (1)(10) / 0.02 = 10 / 0.02

k = 500 N/m

(b) basa rinoitwa nechisimba chemvura

W = – ½ kx²

W = – ½ (500)(0.02)²

W = – (250)(0.0004)

W = -0.1 Joule

Chiratidzo chekusiya chinoratidza kuti divi resimba rechitubu rakapesana nedivi rekuti chinhu chinosuduruka sei.

5. Simba F = 10 N rinokurumidzisa bhokisi pamusoro pechinhambwe chemamita maviri. Pasi pakaoma uye rine simba simba rekukweshana F_k = 2 N. Sarudza basa remambure rakaitwa pabhokisi.

Zvinozivikanwa:

Simba (F) = 10 N

Simba rekukweshana kwekinetic (F)_k) = 2 N

Kutamiswa (d) = 2 m

Zvaidiwa: Network (W)_mambure)

Solution:

Basa rakaitwa nesimba F:

W₁ = F d cos 0 = (10)(2)(1) = 20 Joules

Basa rinoitwa nesimba rekukweshana kwekinetic (F)_k):

W₂ =F_k d = (2)(2)(cos 180) = (2)(2)(-1) = -4 Joules

Network:

W_mambure =W₁ - W₂

W_mambure = 20 - 4

W_mambure = 16 Joule

6Chii chakaitwa nechisimba F pabhuroko?

Zvinozivikanwa:

Simba (F) = 12 Newton

Kutamiswa (d) = mamita mana

Kuda: Basa (W)

Solution:

W = F d = (12 Newton)(mamita 4) = 48 N m = 48 Joules

7. Bhokisi rinosundwa nesimba re200 N. Kufamba kwebhokisi iri mamita maviri. Basa rakaitwa pabhokisi iri nderei?

Zvinozivikanwa:

Simba (F) = 200 Newton

Kutamiswa (d) = mamita mana

Kuda: Basa (W)

Solution:

Basa:

W = F s

W = (200 Newton)(mamita maviri)

W = 400 N m

W = 400 Joule

8. Mutyairi wemota iyi anoda kumisa mota yake 0.5 m chaiyo pamberi pemota iyi, iri pa10 m kubva panzvimbo yemota iyi. Ndeipi basa rinodiwa nemota iyi?

Zvinozivikanwa:

Kutamiswa (d) = mamita gumi - mamita 0.5 = mamita 9.5

Simba (F) = 50 Newton

Zvaidiwa: Basa (W)

Solution:

W = F s

W = (50 Newton)(mamita maviri)

W = 475 N m

W = 475 Joule

9.

Basa rakaitwa naTom naJerry kuitira kuti mota ikwanise kufamba kusvika pamamita mana. Masimba anoshandiswa naTom naJerry nde50 N uye 70 N.

Zvinozivikanwa:

Kutama (s) = mamita mana

Simba reNet (F) = 50 Newtons + 70 Newtons = 120 Newtons

Kuda: Basa (W)

Solution:

W = F s = (120 Newton)(mamita mana) = 480 N m = 480 Joules

10Mutyairi anodhonza mota zvekuti mota inofamba kusvika pa1000 cm. Ndeipi basa rinoitwa pamotokari?

Zvinozivikanwa:

Simba (F) = 250 Newton

Kutamiswa (s) = 1000 cm = 1000/100 metres = 10 metres

Zvaidiwa: Basa (W)

Solution:

W = F s = (250 Newton)(mamita mana) = 2500 N m = 2500 Joules

11. Zvichibva pamufananidzo uri pazasi, kana basa rinoitwa nemauto emagetsi riri 375 Joules, sarudza kusuduruka kwechinhu.

Zvinozivikanwa:

basa (W) = 375 Joule

Simba reNet (ΣF) = 40 N + 10 N – 25 N = 25 Newtons (kurudyi)

Zvaidiwa: Displacement (d)

Solution:

Kuenzanisa kwebasa:

W = F s

Kubviswa kwechinhu:

d = W / F = 375 Joules / 25 Newtons

d = 15 mamitas

12. Mabasa ari pazasi apahich usaita basa is ...

A. Sunda chinhu kusvika kure nemamita gumi

B. Sundidzira mota kusvika yafamba

C. Sunda madziro

D. Akadhonza bhokisi

Solution:

Kuenzanisa kwebasa:

W = ΣF s

W= basa, F = simba, d = kudzingiswa

Bsezvakatsanangurwa pamusoro apa, basa rinoitwa nechisimba uye pane kuchinjika.

Mhinduro chaiyo ndeinoti C.

13Andrew anosunda chinhu nesimba re20 N kuitira kuti chinhu chifambe mukufamba kwedenderedzwa neredhiyo yemamita manomwe. Sarudza basa rakaitwa naAndrew kaviri. tenderera inofamba.

A. 0 Joule

B. 1400 Joule

C. 1540 Joule

D. 1760 Joule

Solution:

Kana munhu wacho akasunda wiricheya Kwekufamba kwedenderedzwa kaviri, munhu wacho newiricheya vanodzokera panzvimbo yavo yekutanga, saka kusuduruka kwemunhu wacho kuri zero.

Kutamiswa = 0 saka basa = 0.

Mhinduro chaiyo ndeinoti A.

14Mumwe munhu anosundira chinhu pasi nesimba re350 N. Pasi rine simba rekukweshana re70 N. Sarudza basa rinoitwa nesimba rekufambisa chinhu kusvika pamamita matanhatu.

A. 45 J

B. 72 J

C. 1680 J

D. 2580 J

Zvinozivikanwa:

Simba rekusunda (F) = 350 Newtons

Simba rekukweshana (F)_mari) = 70 Newton

Kutamiswa kwechinhu (s) = mamita matanhatu

Kuda: Basa (W)

Solution:

Kune masimba maviri anoshanda pachinhu, simba rekusunda (F) uye simba rekukweshana (F)._mari). Simba rekusunda rine gwara rakafanana nerekusuduruka kwechinhu nekuti simba rekusunda rinoita basa rakanaka. Kune rumwe rutivi, simba rekusuduruka rine gwara rakasiyana nerekusuduruka kwechinhu kuitira kuti simba rekusuduruka riite basa rakaipa.

Basa rinoitwa nechisimba chekusundidzira:

W = F d = (350 Newton)(6 metres) = 2100 Newton-mita = 2100 Joules

Basa rinoitwa nesimba rekukweshana:

W = – (F)_mari)(s) = – (70 Newton)(6 metres) = – 420 Newton-mita = – 420 Joules

Network:

W net = 2100 Joules – 420 Joules

W net = 1680 Joule

Mhinduro chaiyo ndeinoti C.

15Chinhu chinosundwa nesimba rakatambanuka remaNewton gumi nemana pasi rakasimba nesimba rekukweshana remaNewton gumi. Sarudza kuti chinhu chacho chinofambiswa sei kusvika pamamita masere.

A. 0.5 Joule

B. 3 Joule

C. 32 Joule

D. 192 Joule

Zvinozivikanwa:

Simba rekusundidzira (F) = 14 Newton

Simba rekukweshana (F)_mari) = 10 Newton

Kutamiswa kwechinhu (d) = mamita masere

Kuda: Basa (W)

Solution:

Kune masimba maviri anoshanda pachinhu, simba rekusunda (F) uye simba rekukweshana (F)._mari).

Simba rekusunda rine gwara rakafanana nerekusuduruka kwechinhu kuitira kuti simba rekusunda riite basa rakanaka. Kune rumwe rutivi, simba rekusuduruka rine gwara rakasiyana nerekusuduruka kwechinhu kuitira kuti simba rekusuduruka riite basa rakaipa.

Basa rinoitwa nechisimba chekusundidzira:

W = F s = (14 Newton)(mamita 8) = 112 Newton metres = 112 Joules

Basa rinoitwa nesimba rekukweshana:

W = – (F)_mari)(s) = – (10 Newton)(mamita 8) = – 80 Newton metres = – 80 Joules

Network:

W net = 112 Joules – 80 Joules

W net = 32 Joule

Mhinduro chaiyo ndeinoti C.

16Sarudza basa remambure zvichibva pamufananidzo uri pazasi.

A. 360 Joule

B. 450 Joule

C. 600 Joule

D. 750 Joule

Solution:

Basa = Simba (F) x kutama (d)

Basa = Nzvimbo yetriangle 1 + nzvimbo yerectangle + nzvimbo yetriangle 2

Work = 1/2(40-0)(3-0) + (40-0)(9-3) + 1/2(40-0)(12-9)

Basa = 1/2(40)(3) + (40)(6) + 1/2(40)(3)

Basa = (20)(3) + 240 + (20)(3)

Basa = 60 + 240 + 60

Basa = 360 Joule

Mhinduro chaiyo ndeinoti A.

17. Huni ine hurefu hwemasendimita makumi matanhatu inonamirwa pasi yakatwasuka. Huni inorohwa nenyundo ye10-kg kubva pakakwirira kwe40 cm pamusoro pehuni. Kana simba rekudzivirira pasi riri 2 x 10³ N uye kukurumidza kunokonzerwa negiravhiti ndeye 10 m/s², ipapo huni dzichapinda muvhu rose mushure mekunge… dzarohwa.

A. 4

B. 16

C. 28

D. 30

Zvinozivikanwa:

Huremu hwenyundo (m) = 10 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²

Kurema kwenyundo (w) = mg = (10)(10) = 100 kg m/s²

Kubviswa kwenyundo usati warova huni (d) = 40 cm = 0.4 metres

Kudzivirira kwehuni (F) = 2 x 10³ N = 2000 N

Kureba kwehuni = 60 cm = 0.6 metres

Zvaidiwa: THuni dzichapinda muvhu rose mushure mekunge… dzarohwa.

Solution:

Basa rinoitwa panyundo kana nyundo ichifamba kusvika pamamita 0.4 nderinotevera:

W = F d = ws = (100 N)(0.4 m) = 40 Nm = 40 Joules

Basa rinoitwa nesimba rekudzivirira repasi:

W = F d = (2000 N)(0.6 m) = 1200 Nm = 1200 Joules

THuni dzichapinda muvhu rose mushure mekunge… dzarohwa.

1200 Joules / 40 Joules = 30

Mhinduro chaiyo ndiD.

[wpdm_package id='1192′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro pekona
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Nyika mufambo kubva kuZuva i149.6 x 10⁶ km uye nguva yekuchinja kwenyika igore rimwe chete. Verenga T² /r³

Zvinozivikanwa:

T = gore 1, r = 149.6 x 10⁶ km

Wanted :T² /r³ = … ?

mhinduro :

k = T² /r³ = 1² / (149.6 x 10⁶)³ = 1 / (3348071.9 x 10¹⁸) = 2.98 x 10^-25 gore²/ km³

2. Nguva dzose (G) = 6.67 x 10^-11 Nm²/ makirogiramu² uye Zuva re1.99 x 10³⁰ kg.

3. Avhareji yedaro reNyika kubva kuZuva i149.6 x 10⁶ km uye avhareji yedaro reMercury kubva kuZuva i57.9 x 10⁶ km. Nguva yekuchinja kwenyika igore rimwe chete, chii chinonzi nguva yekuchinja kwaMercury?

Zvinozivikanwa:

r yePasi = 149.6 x 10⁶ km

r ye mercury = 57.9 x 10⁶ km

T yePasi = gore rimwe chete

Kuda: T yemercury?

Solution:

[wpdm_package id='953′]

1. Mutemo waNewton wematambudziko esimba rinokwevera pasi rose uye mhinduro dzawo
2. Simba resimba rinokwevera pasi, matambudziko ekurema, uye mhinduro
3. Kukurumidza kunokonzerwa nematambudziko egiravhiti nemhinduro
4. Matambudziko eGeosynchronous satellite uye mhinduro dzawo
5. Matambudziko emutemo waKepler nematambudziko ekugadzirisa matambudziko nemhinduro

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1. Ndeupi kukwirira kwesatellite ine geosynchronous pamusoro penyika?

G = chisingaperi chepasi rose = 6.67 x 10^-11 N m²/ makirogiramu²

M = Nyika uremu = 5.97 x gumi²⁴ kg

T = maawa makumi maviri nemana = 24 (masekonzi 3600) = 86,400 masekondi = 8.64 x 10⁴ masekondi

mhinduro

Kureba kwesateraiti pamusoro penyika = 4.22 x 10⁷ m = 4.22 x 10⁴ makiromita = 42,200 makiromita

Kureba kwesateraiti pamusoro penyika = 6.38 x 10⁶ m = 6.38 x 10³ makiromita = 6380 makiromita

Kureba kwesatellite pamusoro penyika = satellite mufambo kubva pakati peNyika - radius yeNyika

Kureba kwesatellite pamusoro penyika = makiromita 42,200 – makiromita 6380

Kureba kwesatellite pamusoro penyika = 35,820km

2. Chii chinonzi geosynchronous satellite kumhanya kwayo?

Nguva dzose (G) = 6.67 x 10^-11 N m²/ makirogiramu²

Huremu hwepasi (m_E) = 5.97 x 10²⁴ kg

Nhambwe iri pakati pesatellite nepakati pePasi (r) = 4.22 x 10⁷ m

mhinduro

kana kushandisa equation iyi

[wpdm_package id='949′]

1. Mutemo waNewton wematambudziko esimba rinokwevera pasi rose uye mhinduro dzawo
2. Simba resimba rinokwevera pasi, matambudziko ekurema, uye mhinduro
3. Kukurumidza kunokonzerwa nematambudziko egiravhiti nemhinduro
4. Matambudziko eGeosynchronous satellite uye mhinduro dzawo
5. Matambudziko emutemo waKepler nematambudziko ekugadzirisa matambudziko nemhinduro

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1. The mufambo pakati Munhu anorema 40 kg nemunhu anorema 30 kg akareba mamita maviri. Hukuru hwechinhu ichi hwakaita sei? simba rinokwevera pasi chimwe nechimwe chinoshanda pane chimwe. Universal constant = 6.67 X 10^-11 N m² /kg²

Zvinozivikanwa:

m₁ = 40 kg, m₂ = 30 kg, r = 2 m, G = 6.67 x 10^-11 N m² /kg²

Zvaidiwa: hukuru hwesimba rinokwevera pasi (F) ?

Solution:

2. Nhambwe iri pakati peNyika neMwedzi (r) i3.84 x 10⁸ m. Simba rinokwevera zvinhu pasi rinoita sei pane rimwe?

Zvinozivikanwa:

Pasi uremu (m_E) = 5.97 x 10²⁴ kg

Mwedzi une huremu (m_M) = 7.35 x 10²² kg

Daro riri pakati pepakati peNyika nepakati pemwedzi (r) = 3.84 x 10⁸ m

Chinogara chiripo chepasi rose (G) = 6.67 x 10^-11 N m² /kg²

Kuda: Hukuru hwesimba rinokwevera pasi (F)

Solution:

3. Chinhambwe kubva kuNyika chii, hukuru hwesimba rinokwevera pasi renyika nemwedzi huri zero here?

Zvinozivikanwa:

Huremu hwepasi = 5.97 x gumi²⁴ kg

Mwedzi une huremu = 7.35 x gumi²² kg

Daro riri pakati pepakati peNyika nepakati pemwedzi (r) = 3.84 x 10⁸ m.

Chisingaperi chepasi rose (G) = 6.67 x 10^-11 N m² /kg²

Kuda: chinhambwe kubva paNyika

Solution:

Simba regiravhiti remagetsi harisi zero.

Shandisa fomura yequadratic:

A = – 6.35

B = – 7.68 X 10⁸

C = 87.76 x 10^-14

 

[wpdm_package id='955′]

1. Mutemo waNewton wematambudziko esimba rinokwevera pasi rose uye mhinduro dzawo
2. Simba resimba rinokwevera pasi, matambudziko ekurema, uye mhinduro
3. Kukurumidza kunokonzerwa nematambudziko egiravhiti nemhinduro
4. Matambudziko eGeosynchronous satellite uye mhinduro dzawo
5. Matambudziko emutemo waKepler nematambudziko ekugadzirisa matambudziko nemhinduro

 

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