Basa rinoitwa nechisimba - matambudziko nemhinduro

1. Munhu anodhonza bhokisi 2 m pamusoro penzvimbo yakatambanuka nesimba risingaperi F = 20 N. Sarudza basa rinoitwa nesimba F richishanda pabhokisi.

Zvinozivikanwa:

Simba (F) = 20 N

Kutamiswa (s) = 2 m

Angle (θ ) = 0

Kudiwa : Basa (W)

Solution:

W = F d cos θ = (20)(2)(cos 0) = (20)(2)(1) = 40 Joules

2. Simba F = 10 N richishanda pabhokisi 1 m pamwe chete nenzvimbo yakatambanuka. Simba iri rinoshanda pakona ye30 ^o sezvakaratidzwa mumufananidzo uri pazasi. Sarudza basa rinoitwa nesimba F!

Zvinozivikanwa :

Simba (F) = 10 N

Simba rakatwasuka (F _x ) = F cos 30 ^o = (10)(0.5√3) = 5√3 N

Kutamiswa (d) = mita imwe

Wanted : Basa (W)?

Mhinduro :

W = F _x d = (5√3)(1) = 5√3 Joules

3. Muviri unodonha zvakasununguka kubva pakuzorora, kubva pakukwirira kwemamita maviri. Kana kukurumidza nekuda kwesimba rinokwevera pasi kuri 10 m/s ² , sarudza basa rinoitwa nesimba rinokwevera pasi!

Zvinozivikanwa:

Huremu hwechinhu (m) = 1 kg

Kureba (h) = 2 m

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: Basa rinoitwa nesimba regiravhiti (W)

Solution:

W = F d = wh = mgh

W = (1)(10)(2) = 20 Joule

W = basa, F = simba, d = daro, w = huremu , h = kureba, m ​​= huremu, g = kukurumidza nekuda kwegiravhiti.

4. Chinhu chinorema 1-kg chinosungirirwa pachitubu saka chinoreba 2 cm. Kana kumhanyisa nekuda kwesimba rekukwevera pasi kuri 10 m/s ² , sarudza (a) chitubu chinogara chiripo (b) basa rinoitwa nesimba rechitubu pachinhu chacho

Zvinozivikanwa:

Huremu (m) = 1 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Kureba (x) = 2 cm = 0.02 m

Huremu (w) = mg = (1 kg)(10 m/s ² ) = 10 kg m/s ² = 10 N

Zvinodiwa: Nguva yechirimo uye basa rinoitwa nechisimba chechirimo

Solution:

(a) Chitubu chinogara kwenguva refu

Fomura yemutemo waHooke :

F = k x.

k = F / x = w / x = mg / x

k = (1)(10) / 0.02 = 10 / 0.02

k = 500 N/m

(b) basa rinoitwa nechisimba chemvura

W = – ½ kx ²

W = – ½ (500)(0.02) ²

W = – (250)(0.0004)

W = -0.1 Joule

Chiratidzo chekusiya chinoratidza kuti divi resimba rechitubu rakapesana nedivi rekuti chinhu chinosuduruka sei.

5. Simba F = 10 N rinokurumidzisa bhokisi pamusoro pechinhambwe chemamita maviri. Pasi pakaoma uye rine simba rekukweshana F _k = 2 N. Sarudza basa remambure rakaitwa pabhokisi.

Zvinozivikanwa:

Simba (F) = 10 N

Simba rekukweshana kwekinetic (F _k ) = 2 N

Kutamiswa (d) = 2 m

Zvinodiwa: Network (W _net )

Solution:

Basa rakaitwa nesimba F:

W ₁ = F d cos 0 = (10)(2)(1) = 20 Joules

Basa rinoitwa nesimba rekukweshana kwekinetic (F _k ):

W ₂ = F _k d = (2)(2)(cos 180) = (2)(2)(-1) = -4 Joules

Network:

W _net = W ₁ – W ₂

W _net = 20 – 4

W _net = 16 Joule

6. Ndeipi basa rinoitwa nechisimba F pabhuroko?

Zvinozivikanwa:

Simba (F) = 12 Newton

Kutamiswa (d) = mamita mana

Kudiwa: Basa (W)

Solution:

W = F d = (12 Newton)(mamita 4) = 48 N m = 48 Joules

7. Bhokisi rinosundwa nesimba re200 N. Kufamba kwebhokisi iri mamita maviri. Basa rakaitwa pabhokisi iri nderei?

Zvinozivikanwa:

Simba (F) = 200 Newton

Kutamiswa (d) = mamita mana

Kudiwa: Basa (W)

Solution:

Basa:

W = F s

W = (200 Newton)(mamita maviri)

W = 400 N m

W = 400 Joule

8. Mutyairi wemota ye sedan anoda kumisa mota yake 0.5 m chaiyo pamberi perori iri pa10 m kubva panzvimbo yemota ye sedan. Ndeipi basa rinodiwa nemota ye sedan?

Zvinozivikanwa:

Kutamiswa (d) = mamita gumi - mamita 0.5 = mamita 9.5

Simba (F) = 50 Newton

Kudiwa: Basa (W)

Solution:

W = F s

W = (50 Newton)(mamita maviri)

W = 475 N m

W = 475 Joule

9.

Basa rakaitwa naTom naJerry kuitira kuti mota ikwanise kufamba kusvika pamamita mana. Masimba anoshandiswa naTom naJerry nde50 N uye 70 N.

Zvinozivikanwa:

Kutama (s) = mamita mana

Simba reNet (F) = 50 Newtons + 70 Newtons = 120 Newtons

Kudiwa: Basa (W)

Solution:

W = F s = (120 Newton)(mamita mana) = 480 N m = 480 Joules

10. Mutyairi anodhonza mota zvekuti mota inofamba kusvika pa1000 cm. Ndeipi basa rinoitwa pamotokari?

Zvinozivikanwa:

Simba (F) = 250 Newton

Kutamiswa (s) = 1000 cm = 1000/100 metres = 10 metres

Kudiwa: Basa (W)

Solution:

W = F s = (250 Newton)(mamita mana) = 2500 N m = 2500 Joules

11. Zvichibva pamufananidzo uri pazasi, kana basa rinoitwa nemagetsi ari maJoules mazana matatu nemakumi manomwe nemashanu (375 Joules), tsvaga kusuduruka kwechinhu.

Zvinozivikanwa:

Basa (W) = 375 Joule

Simba remambure ( ΣF) = 40 N + 10 N – 25 N = 25 Newtons ( kurudyi )

Kudiwa: Kudzingwa ( d )

Solution:

Kuenzanisa kwebasa:

W = F s

Kubviswa kwechinhu:

d = W / F = 375 Joules / 25 Newtons

d = mamita gumi nemashanu s

12. Mabasa ari pazasi asingashande ndeaya …

A. Sunda chinhu kusvika kure nemamita gumi

B. Sundidzira mota kusvika yafamba

C. Sunda madziro

D. Akadhonza bhokisi

Solution:

Kuenzanisa kwebasa:

W = ΣF s

W = basa , F = simba , d = kusuduruka

Zvichibva pafomura iri pamusoro apa, basa rinoitwa nechisimba uye pane kuchinjika.

Mhinduro chaiyo ndeinoti C.

1 3. Andrew anosunda chinhu nesimba re20 N saka chinhu chinofamba nekufamba kwedenderedzwa neredhiyo yemamita manomwe. Sarudza basa rakaitwa naAndrew rekufamba kwedenderedzwa kaviri.

A. 0 Joule

B. 1400 Joule

C. 1540 Joule

D. 1760 Joule

Solution:

Kana munhu akasunda wiricheya kaviri achitenderera, munhu wacho newiricheya vanodzokera panzvimbo yavo yekutanga, saka kusuduruka kwemunhu wacho kunenge kuri zero.

Kutamiswa = 0 saka basa = 0.

Mhinduro chaiyo ndeinoti A.

14. Mumwe munhu anosundira chinhu pasi nesimba re350 N. Pasi rine simba rekukweshana re70 N. Sarudza basa rinoitwa nesimba rekufambisa chinhu kusvika pamamita matanhatu.

A. 45 J

B. 72 J

C. 1680 J

D. 2580 J

Zvinozivikanwa:

Simba rekusunda (F) = 350 Newtons

Simba rekukweshana (F _fric ) = 70 Newtons

Kutamiswa kwechinhu (s) = mamita matanhatu

Kudiwa: Basa (W)

Solution:

Kune masimba maviri anoshanda pachinhu, simba rekusunda (F) uye simba rekukweshana (F _fric ). Simba rekusunda rine gwara rakafanana nerekubviswa kwechinhu nekuti simba rekusunda rinoita basa rakanaka. Mune rimwe divi, simba rekukweshana rine gwara rakasiyana nerekubviswa kwechinhu zvekuti simba rekukweshana rinoita basa rakaipa.

Basa rinoitwa nechisimba chekusundidzira:

W = F d = (350 Newton)(6 metres) = 2100 Newton-mita = 2100 Joules

Basa rinoitwa nesimba rekukweshana:

W = – (F _fric )(s) = – (70 Newton)(6 metres) = – 420 Newton-meters = – 420 Joules

Network:

W net = 2100 Joules – 420 Joules

W net = 1680 Joule

Mhinduro chaiyo ndeinoti C.

15. Chinhu chinosundwa nesimba rakatambanuka remaNewton gumi nemana pasi rakasimba nesimba rekukweshana remaNewton gumi. Sarudza basa rekufambisa chinhu kusvika pamamita masere.

A. 0.5 Joule

B. 3 Joule

C. 32 Joule

D. 192 Joule

Zvinozivikanwa:

Simba rekusundidzira (F) = 14 Newton

Simba rekukweshana (F _fric ) = 10 Newtons

Kutamiswa kwechinhu (d) = mamita masere

Kudiwa: Basa (W)

Solution:

Kune masimba maviri anoshanda pachinhu, simba rekusunda (F) uye simba rekukweshana (F _fric ).

Simba rekusunda rine gwara rakafanana nerekusuduruka kwechinhu kuitira kuti simba rekusunda riite basa rakanaka. Kune rumwe rutivi, simba rekusuduruka rine gwara rakasiyana nerekusuduruka kwechinhu kuitira kuti simba rekusuduruka riite basa rakaipa.

Basa rinoitwa nechisimba chekusundidzira:

W = F s = (14 Newton)(mamita 8) = 112 Newton metres = 112 Joules

Basa rinoitwa nesimba rekukweshana:

W = – (F _fric )(s) = – (10 Newton)(mamita 8) = – 80 Newton metres = – 80 Joules

Network:

W net = 112 Joules – 80 Joules

W net = 32 Joule

Mhinduro chaiyo ndeinoti C.

16. Sarudza basa remambure zvichibva pamufananidzo uri pazasi.

A. 360 Joule

B. 450 Joule

C. 600 Joule

D. 750 Joule

Solution:

Basa = Simba (F) x kutama (d)

Basa = Nzvimbo yetriangle 1 + nzvimbo yerectangle + nzvimbo yetriangle 2

Work = 1/2(40-0)(3-0) + (40-0)(9-3) + 1/2(40-0)(12-9)

Basa = 1/2(40)(3) + (40)(6) + 1/2(40)(3)

Basa = (20)(3) + 240 + (20)(3)

Basa = 60 + 240 + 60

Basa = 360 Joule

Mhinduro chaiyo ndeinoti A.

17. Chidimbu chehuni chine hurefu hwemasendimita makumi matanhatu chakanamirwa pasi. Huni inorohwa nenyundo ye10-kg kubva pakakwirira kwe40 cm pamusoro pehuni. Kana simba rekudzivirira pasi riri 2 x 10 3 ^N uye kumhanya kunokonzerwa negiravhiti kuri 10 m/s ² , ipapo huni huchapinda muvhu zvachose mushure…. kurova.

A. 4

B. 16

C. 28

D. 30

Zvinozivikanwa:

Huremu hwenyundo (m) = 10 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/ s ²

Kurema kwenyundo (w) = mg = (10)(10) = 100 kg m/s ²

Kubviswa kwenyundo usati warova huni (d) = 40 cm = 0.4 metres

Kudzivirira kwehuni (F) = 2 x 10 ³ N = 2000 N

Kureba kwehuni = 60 cm = 0.6 metres

Zvaidiwa: Huni dzichapinda muvhu rose mushure mekunge… dzarohwa.

Solution:

Basa rinoitwa panyundo kana nyundo ichifamba kusvika pamamita 0.4 nderinotevera:

W = F d = ws = (100 N)(0.4 m) = 40 Nm = 40 Joules

Basa rinoitwa nesimba rekudzivirira repasi:

W = F d = (2000 N)(0.6 m) = 1200 Nm = 1200 Joules

Huni dzichapinda muvhu rose mushure mekunge… dzarohwa.

1200 Joules / 40 Joules = 30

Mhinduro chaiyo ndiD.

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