Simba rekukakavadzana kwesimba uye kinetic - matambudziko nemhinduro

Matambudziko akagadziriswa mumitemo yaNewton yekufamba - Simba rekukweshana kwesimba uye kinetic

1. Chinhu chinogara pasi rakatwasuka. Chiyero chekukakavadzana kwesimba risingachinji i0.4 uye kukurumidza kwegiravhiti i9.8 m/s ^2. Sarudza (a) Simba guru rekukakavadzana kwesimba risingachinji (b) Simba shoma reF

mhinduro

Zvinozivikanwa:

Huremu (m) = 1 kg

Muyero wekukweshana kwesimba (μ _s ) = 0.4

Kukurumidza kwegiravhiti (g) = 9.8 m/s ²

Huremu (w) = mg = (1 kg)(10 m/s ² ) = 10 kg m/s ² = 10 Newtons

Simba rakajairika (N) = w = 10 Newtons

Zvaidiwa:

(a) Simba guru rekukweshana kwakasimba (b) Simba shoma raF

Solution:

(a) Simba guru rekukweshana kwakasimba

fs = μs N_​​

f _s = (0.4)(9.8 N) = 3.92 Newtons

(b) Simba shoma raF

Kana simba F rikaitwa pachinhu asi chinhu chisina kufambiswa, saka panofanira kunge paine simba rekukweshana kusingachinji rinoitwa nepasi pachinhu chacho. Kana chinhu chikatanga kufamba, simba rekukweshana kusingachinji rakapfuudzwa, panofanira kunge paine simba rekukweshana kusingachinji. Chinhu chinotanga kufamba kana F yakakura kupfuura simba guru rekukweshana kusingachinji.

Saka simba shoma raF = simba guru re static friction = 3.92 Newtons.

2. Bhokisi re 1 kg rinodhonzwa pamusoro penzvimbo yakatambanuka ne force F, saka bhokisi riri kufamba ne stroke isingachinji. Kana kinetic friction coefficient iri 0.1, sarudza hukuru hwe force F! (g = 9.8 m/s ² )

Zvinozivikanwa:

_{Chiyero chekukweshana kwekinetic} ( μk ) = 0.1

Huremu hwebhokisi (m) = 1 kg

Kukurumidza kwegiravhiti (g) = 9.8 m/s ²

Huremu (w) = mg = (1 kg)(9.8 m/s ² ) = 9.8 kg m/s ² = 9.8 Newtons

Simba rakajairika (N) = w = 9.8 Newtons

Aida : F

Solution:

Mutemo wekutanga waNewton unoti kana pasina simba rinoshanda pachinhu, chinhu chimwe nechimwe chinoramba chiri mumamiriro acho ekuzorora, kana kuti kumhanya kunogara kwakatwasuka.

Saka kana chinhu chichifamba nespeed isingachinji , hapafanire kuva ne net force ( Σ F = 0) . Force F inoshandiswa pachinhu ichi munzira chaiyo kuitira kuti simba re kinetic friction riiswe pachinhu ichi kuruboshwe.

∑ F = 0

F – f _k = 0

F = f _k

Simba rekukweshana kwekinetic:

f _k = μ _k N = (0.1)(9.8 N) = 0.98 Newtons

chinhu chinofamba nekumhanya kusingachinji, F = f _k = 0.98 maNewton

3. Chinhu chinotsvedza pasi chakarerekera nekumhanya kusingachinji. Tsvaga kinetic friction coefficient ( _μk ) . g = 9.8 m/s ²

mhinduro

w = huremu, w _x = chikamu chakatarwa chehuremu, mapoinzi ari padivi penzvimbo yakatenuka, w _y = chikamu chakamira chehuremu, chakatarisana nendege yakatenuka, N = simba rakajairika, f _k = simba rekukweshana kwekinetic.

Zvinozivikanwa:

Huremu (m) = 1 kg

Kukurumidza kwegiravhiti (g) = 9.8 m/s ²

huremu (w) = mg = (1 kg)(9.8 m/s ² ) = 9.8 kg m/s ² = 9.8 Newtons

w _x = w sin 30 ^o = (9.8 N)(0.5) = 4.9 Newtons

w _y = w cos 30 ^o = (9.8 N)(0.5) √ 3 = 4.9 √ 3 Newtons

Simba rakajairika (N) = w _y = 4.9 √ 3 Newtons

Zvinodiwa : kinetic friction coefficient ( μk ₎

Solution:

Chinhu chinotsvedza pasi chakarerekera nespeed isingachinji kuitira kuti simba remambure = 0.

∑ F = 0

w _x – f _k = 0

w _x = f _k

w _x = μ _k N

5 = μ _k ( 5 √ 3 )

μ _k = 5 / 5 √ 3

μ _k = 1 / √ 3

μk ₌ 0.58

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