1. Nhabvu inokandwa inobuda pasi nekona θ = 30 o nekumhanya kwekutanga kwe10 m/s. Huremu hwebhora = 0.1 kg. Kukurumidza kunokonzerwa negiravhiti i1 0 m/s 2 . Sarudza (a) Simba regiravhiti rinogona kukweva panzvimbo yepamusoro (b) Nzvimbo yepamusoro kana kukwirira kwakanyanya
Zvinozivikanwa:
Huremu (m) = 0.1 kg
Kumhanya kwekutanga (v o ) = 10 m/s
Angle = 30 o
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
Solution:
(a) Simba regiravhiti

Verenga chikamu chakatarwa (v ox ) uye chikamu chakatwasuka (v oy ) chekukurumidza kwekutanga.

vox =vo cos θ = (10)(cos 30o) = (10)(0.5√3) = 5√3 m/s
v oy = v o chivi θ = (10)(chivi 30 o ) = (10)( 0.5) = 5 m/s
Simba rekutanga remakanika
Simba rekutanga remakanika (ME o ) = simba rekinetic (KE)
ME o = KE = ½ mv o 2 = ½ (0.1) (10) 2 = ½ (0.1) (100) = ½ (10) = 5 Joules
Simba rekupedzisira remakanika
Kinetic simba panzvimbo yepamusoro:
KE = ½ mv mombe 2 = ½ (0.1)(5√3) 2 = ½ (0.1)((25)(3)) = ½ (0.1)(75) = 3.75 Joules
Nheyo yekuchengetedza simba remakanika
Simba rekutanga remakanika (ME o ) = simba rekupedzisira remakanika (ME t )
KE = PE + KE
5 = EP + 3.75
PE = 5 – 3.75 = 1.25 Joule
Simba regiravhiti rinogona kukweva panzvimbo yakakwirira i1.25 Joules.
(b) Nzvimbo yepamusoro-soro kana kuti kukwirira kwakanyanya
PE = mgh
1.25 = (0.1)(10) h
1.25 = awa
Kureba kwakanyanya i1.25 metres.
2. Bhora re 0.1-kg rinotaridzwa rakatwasuka ne velocity yekutanga v o = 10 m/s kubva pachivako chakareba mamita gumi. Kukurumidza kunokonzerwa negravity i10 m/s 2. Tsvaga simba rekufamba kwebhora kana rasvika pasi.
Zvinozivikanwa:
Huremu (m) = 0.1 kg
Kumhanya kwekutanga (v o ) = 10 m/s
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
Kuchinja kwehurefu (h) = 10 – 2 = 8 m
Zvinodiwa: simba remagetsi riri pamusoro pevhu mamita maviri
Solution:
Simba regiravhiti (PE) = mgh = (0.1)(10)(10) = 10 Joules
Simba rekutanga rekinetic (KE)= ½ mv o 2 = ½ (0.1)(10) 2 = ½ (0.1)(100) = ½ (10) = 5 Joules
Simba rekupedzisira rekinetic = simba rekutanga regiravhiti + simba rekutanga rekinetic = 10 + 5 = 15 Joules
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