1. Muviri we 1-kg unodonha zvakasununguka kubva pakuzorora, kubva pakukwirira kwemamita 80. Kukurumidza kunokonzerwa negiravhiti i10 m/s 2. Chii chinonzi kinetic energy kana muviri warova pasi?
Zvinozivikanwa:
Huremu (m) = 1 kg
Kureba (h) = 80 m
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
Zvinodiwa: simba rekufamba kana muviri warova pasi
Solution:
Simba rekutanga remakanika (ME o ) = simba regiravhiti (PE)
M E o = P E = mgh = (1)(10)(80) = 800 maJoules
Simba rekupedzisira remakanika (M E t ) = simba remakanika (K E )
Nheyo yekuchengetedza simba remakanika :
M E o = M E t
P E = K E
800 = K E
Simba rekupedzisira rekinetic i800 Joules.
2. Muviri we4 kg unodonha zvakasununguka kubva pakuzorora, kubva pakukwirira kwemamita gumi. Kukurumidza kunokonzerwa negiravhiti kuri 10 ms -2 . Chii chinonzi kinetic energy uye kumhanya kuri pamamita mashanu pamusoro penyika.
Zvinozivikanwa:
Kuchinja kwehurefu (h) = 10 – 5 = 5 metres s
Huremu (m) = 4 kg
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
Zvinodiwa: Kinetic energy iri pamamita mashanu pamusoro penyika uye kumhanya kwemamita mashanu pamusoro penyika
Solution:
(a) Simba reKinetic riri pamamita mashanu kubva pasi
Simba rekutanga remakanika (M E o ) = simba regiravhiti (P E )
M E o = P E = mgh = (4)(10)(5) = 200 maJoules
Simba rekupedzisira remakanika (EM t ) = simba rekinetic (EK)
M E t = K E
Nheyo yekuchengetedza simba remakanika inoti simba rekutanga remakanika = simba rekupedzisira remakanika.
M E o = M E t
200 = K E
Simba reKinetic riri pamamita mashanu pamusoro pevhu i200 Joules.
(b) kumhanya kwemamita mashanu pamusoro pevhu
Simba rekutanga remakanika (M E o ) = simba rekupedzisira remakanika (M E t )
P E = K E
200 = ½ mv 2
2(200) / 4 = v 2
100 = v 2
v = √100
v = 10 m/s
Kumhanya kwemuviri pamamita mashanu kubva pasi i10 m/s.
3. Mango inodonha yakasununguka kubva payakagara, kubva pakukwirira kwemamita maviri. Kukurumidza kunokonzerwa negiravhiti i10 ms -2 . Sarudza kumhanya kwemango kana yasvika pasi.
Zvinozivikanwa:
Kureba (h) = mamita mashanu s
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
Zvinodiwa: kumhanya kwemango kana yarova pasi.
Solution:
Simba rekutanga remakanika (M E o ) = simba regiravhiti (P E )
M E = P E = mgh = m (10)(2) = 20 m
Simba rekupedzisira remakanika (M E t ) = simba remakanika (K E )
M E t = K E = ½ mv 2
Nheyo yekuchengetedza simba remakanika inoti simba rekutanga remakanika = simba rekupedzisira remakanika.
M E o = M E t
20 m = ½ mv 2
20 = ½ v 2
2(20) = v2
40 = v 2
v = √40 = √(4)(10) = 2√10 m/ s
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