Kushandiswa kwekuchengetedza simba remakanika kuti munhu afambe akasununguka - matambudziko nemhinduro

1. A 1-kg body falls freely from rest, from a height of 80 m. Kuwedzera nekuda kwegiravhiti is 10 m / s²Chii chinonzi simba reinetic when the body hits the ground.

Zvinozivikanwa:

Misa (m) = 1 kg

urefu (h) = 80 m

Kuwedzera nekuda kwegiravhiti (g) = 10 m/s²

Kuda: kinetic energy when the body hits the ground

Solution:

The kwokutanga michina simba (Ini_o) = simba regiravhiti (FOOT)

ME_o =PE = m g h = (1)(10)(80) = 800 Joule

Simba rekupedzisira remakanika (ME_t) = simba reinetic (KE)

Musimboti we kuchengetedzwa kwesimba remakanika :

ME_o =ME_t

PE =KE

800=KE

The final kinetic energy is 800 Joule.

2. Muviri we4 kg free-fall from rest, from a height of 10 m. Acceleration due to gravity is 10 m s^-2. What is the kinetic energy and the velocity at 5 meters above the ground.

Zvinozivikanwa:

The change in height (h) = 10 – 5 = 5 meters

Huremu (m) = 4 kg

Kuwedzera nekuda kwegiravhiti (g) = 10 m/s²

Kuda: Kinetic energy at 5 meters above the ground and the velocity at 5 meters above the ground

Solution:

(A) Kinetic energy at 5 meters above the ground

Simba rekutanga remakanika (ME_o) = simba regiravhiti (PE)

ME_o =PE = m g h = (4)(10)(5) = 200 Joule

Simba rekupedzisira remakanika (EM_t) = simba reinetic (EK)

ME_t =KE

The principle of conservation of mechanical energy states that the initial mechanical energy = the final mechanical energy.

ME_o =ME_t

200=KE

Kinetic energy at 5 meters above the ground is 200 Joule.

(B) velocity at 5 mamitas above the ground

Simba rekutanga remakanika (ME_o) = simba rekupedzisira remakanika (ME_t)

PE =KE

200 = ½ mv²

2(200) / 4 = v²

100 = v²

v = √100

v = 10 m / s

Body’s velocity at 5 meters above the ground is 10 m/s.

3. A mango falls freely from rest, from a height of 2 meters. Acceleration due to gravity is 10 m s^-2. Determine mango’s velocity when hits the ground.

Zvinozivikanwa:

urefu (h) = mamita mashanus

Kuwedzera nekuda kwegiravhiti (g) = 10 m/s²

Zvaidiwa: mango’s velocity when hits the ground.

Solution:

Simba rekutanga remakanika (ME_o) = simba regiravhiti (PE)

ME =PE = m g h = m (10)(2) = 20 m

Simba rekupedzisira remakanika (ME_t) = the kinetic energy (KE)

ME_t =KE = ½ mv²

Principle of conservation of mechanical energy states that the initial mechanical energy = the final mechanical energy.

ME_o =ME_t

20 m = ½ mv²

20 = ½ v²

2(20) = v²

40 = v²

v = √40 = √(4)(10) = 2√10 m/s

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1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro wakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro