Physics

1. Muviri we 1-kg unodonha zvakasununguka kubva pakuzorora, kubva pakukwirira kwemamita 80. Kukurumidza kunokonzerwa negiravhiti i10 m/s ^2. Chii chinonzi kinetic energy kana muviri warova pasi?

Zvinozivikanwa:

Huremu (m) = 1 kg

Kureba (h) = 80 m

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: simba rekufamba kana muviri warova pasi

Solution:

Simba rekutanga remakanika (ME _o ) = simba regiravhiti (PE)

M E _o = P E = mgh = (1)(10)(80) = 800 maJoules

Simba rekupedzisira remakanika (M E _t ) = simba remakanika (K E )

Nheyo yekuchengetedza simba remakanika :

M E _o = M E _t

P E = K E

800 = K E

Simba rekupedzisira rekinetic i800 Joules.

2. Muviri we4 kg unodonha zvakasununguka kubva pakuzorora, kubva pakukwirira kwemamita gumi. Kukurumidza kunokonzerwa negiravhiti kuri 10 ms ^-2 . Chii chinonzi kinetic energy uye kumhanya kuri pamamita mashanu pamusoro penyika.

Zvinozivikanwa:

Kuchinja kwehurefu (h) = 10 – 5 = 5 metres s

Huremu (m) = 4 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: Kinetic energy iri pamamita mashanu pamusoro penyika uye kumhanya kwemamita mashanu pamusoro penyika

Solution:

(a) Simba reKinetic riri pamamita mashanu kubva pasi

Simba rekutanga remakanika (M E _o ) = simba regiravhiti (P ​​E )

M E _o = P E = mgh = (4)(10)(5) = 200 maJoules

Simba rekupedzisira remakanika (EM _t ) = simba rekinetic (EK)

M E _t = K E

Nheyo yekuchengetedza simba remakanika inoti simba rekutanga remakanika = simba rekupedzisira remakanika.

M E _o = M E _t

200 = K E

Simba reKinetic riri pamamita mashanu pamusoro pevhu i200 Joules.

(b) kumhanya kwemamita mashanu pamusoro pevhu

Simba rekutanga remakanika (M E _o ) = simba rekupedzisira remakanika (M E _t )

P E = K E

200 = ½ mv ²

2(200) / 4 = v ²

100 = v ²

v = √100

v = 10 m/s

Kumhanya kwemuviri pamamita mashanu kubva pasi i10 m/s.

3. Mango inodonha yakasununguka kubva payakagara, kubva pakukwirira kwemamita maviri. Kukurumidza kunokonzerwa negiravhiti i10 ms ^-2 . Sarudza kumhanya kwemango kana yasvika pasi.

Zvinozivikanwa:

Kureba (h) = mamita mashanu s

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: kumhanya kwemango kana yarova pasi.

Solution:

Simba rekutanga remakanika (M E _o ) = simba regiravhiti (P ​​E )

M E = P E = mgh = m (10)(2) = 20 m

Simba rekupedzisira remakanika (M E _t ) = simba remakanika (K E )

M E _t = K E = ½ mv ²

Nheyo yekuchengetedza simba remakanika inoti simba rekutanga remakanika = simba rekupedzisira remakanika.

M E _o = M E _t

20 m = ½ mv ²

20 = ½ v ²

2(20) = ^v2

40 = v ²

v = √40 = √(4)(10) = 2√10 m/ s

[wpdm_package id='1166′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro wakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Munhu anokanda dombo re 1-kg mudenga ne 2 m/s akamira pamucheto pedombo kuitira kuti dombo ridonhe pasi pedombo riri pasi pe 40 metres. Chii chinonzi kinetic energy yedombo iri pamamita gumi pamusoro pevhu? Kukurumidza kunokonzerwa negravity g = 10 m/s ².

Zvinozivikanwa:

Huremu (m) = 1 kg

Kumhanya kwekutanga (v _o ) = 2 m/s

Kuchinja kwehurefu = 40 - 10 = mamita makumi matatu

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: simba remagetsi redombo riri pamusoro pevhu pamamita gumi

Solution:

Simba rekutanga remakanika

Simba rekutanga regiravhiti (EP) = mgh = (1)(10)(30) = 300 Joules

Simba rekutanga rekinetic (KE) = ½ mv _o ² = ½ (1)(2) ² = ½ (4) = 2 Joules

Simba rekutanga remakanika = simba rekutanga regiravhiti + simba rekutanga rekinetic = 300 + 2 = 302 Joules.

Simba rekupedzisira remakanika

Simba rekupedzisira remakanika = simba rekupedzisira rekinetic = simba rekutanga regiravhiti + simba rekutanga rekinetic = 300 + 2 = 302 Joules.

2. Munhu anokanda chinhu chinorema 1-kg mudenga nekumhanya kwekutanga kwe10 m/s. Sarudza (a) simba regiravhiti pakukwirira kwepamusoro (b) kukwirira kwepamusoro.

Kukurumidza kwesimba nekuda kwegiravhiti ndeye 10 m/s ²

Zvinozivikanwa:

Huremu (m) = 1 kg

Kumhanya kwekutanga (v _o ) = 10 m/s

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa : simba rekukwevera pasi pakukwirira kwepamusoro uye kukwirira kwepamusoro

Solution:

(a) simba regiravhiti rinokwevera zvinhu pasi pakakwirira

Simba rekutanga remakanika:

Simba rekutanga remakanika (ME) = simba rekutanga remakanika (KE) = ½ mv _o ² = ½ (1)(10) ² = ½ (100) = 50 Joules.

Simba rekupedzisira remakanika:

Simba rekupedzisira remakanika (ME) = simba regiravhiti (PE)

Nheyo yekuchengetedza simba remakanika:

Simba rekutanga remakanika = simba rekupedzisira remakanika

KE = PE

50 = PE

Simba regiravhiti rinokwanisa kukweva zvinhu i50 Joules.

(b) Kureba kwakanyanya

PE = mgh

50 = (1)(10) h

50 = maawa makumi maviri

h = 50 / 10 = mamita mashanu

Kureba kwakanyanya kwemamita mashanu kubva pasi.

[wpdm_package id='1174′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro wakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Huremu hwe2-kg hwakabatanidzwa nechitubu. Kana kureba kwechitubu kuri 4 cm, tsvaga simba rinogona kuwanikwa nechitubu chinonamira . Kukurumidza kunokonzerwa nekukweva kwesimba remagetsi i10 m/s ².

Zvinozivikanwa:

Huremu (m) = 2 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Huremu (w) = mg = (2)(10) = 20 N

Kureba (x) = 4 cm = 0.04 m

Zvinodiwa: Simba rinogona kuwanikwa muchitubu chinonamira

Solution:

Fomura yemutemo waHooke :

F = kx

F = simba, k = chitubu chisingachinji, x = kuchinja kwehurefu hwechitubu

Chirimo chinogara kwenguva refu:

k = w / x = 20 / 0.04 = 500 N/m

Simba rinogona kuwanikwa muchitubu chinopfava:

PE = ½ kx ² = ½ (500) (0.04) ² = (250) (0.0016) = 0.4 Joules

Imwe mhinduro:

PE = ½ kx ² = ½ (w / x) x ² = ½ wx = ½ mgx

w = huremu, m ​​= huremu, x = kuchinja kwehurefu hwechitubu

PE = ½ (2) (10) (0.04) = (10) (0.04) = 0.4 Joules.

2. Kureba kwechitubu kwakatambanudzwa nesimba F = 50 N i10 cm. Ndeipi simba rinogona kushandiswa nechitubu chinopfava kana kureba kwechitubu kuri 12 cm.

Zvinozivikanwa:

Kureba (x) = 10 cm = 0.1 m

Simba (F) = 50 N

Zvinodiwa : Simba rinogona kuwanikwa muchitubu chinonamira

Solution:

Chirimo chinogara kwenguva refu:

k = F / x = 50 / 0.1 = 500 N/m

Simba rinogona kuwanikwa muchitubu chinonamira kana kureba kwechitubu kuri 12 cm. :

PE = ½ kx ² = ½ (500) (0.12) ² = (250) (0.0144) = 3.6 Joules.

3. Girafu yeF vs x inoratidzwa mumufananidzo uri pazasi. Ndeipi simba rinogona kushandiswa nechitubu chinopfava, kana kureba kwechitubu kuri 10 cm.

Zvinozivikanwa:

Simba (F) = 5 N

Kureba kwechitubu (x) = 2 cm = 0.02 m

Zvinodiwa: Simba rinogona kuwanikwa muchitubu chinopfava kana kureba kwechitubu kuri 0.1 m.

Solution:

Chirimo chinogara kwenguva refu:

k = F / x = 5 / 0.02 = 250 N/m

Simba rinogona kuwanikwa muchitubu chinopfava kana kureba kwechitubu kuri 0.1 m:

PE = ½ kx ² = ½ (250) (0.1) ² = (125) (0.01) = 1.25 Joules.

4. Mutambi anosvetukira pachiridzwa chechirimo chine huremu hwe500 N, chitubu chinopfupika ne4 cm. Sarudza huwandu hwesimba rinogona kumanikidza mutambi.

A. 20 Joule

B. 10 Joule

C. 5 Joule

D. 2 Joule

Zvinozivikanwa:

Simba (F) = 500 N

Kuchinja kwehurefu hwechitubu (Δx) = 4 cm = 0.04 m

Zvinodiwa: Simba rinogona kuwanikwa muchirimo

Solution:

Verenga chisipiti che elastic constant uchishandisa equation yemutemo waHooke:

k = F / Δx = 500 N / 0.04 m = 12500 N/m

Simba rinoita kuti chitubu chive chakasimba:

PE = ½ k Δx ² = ½ (12500) (0.04) ² = (6250) (0.0016)

PE = 10 Joule

Mhinduro chaiyo ndeiyi B.

5. Chitubu kana chakarembera chine huremu hwemagiramu mazana mashanu, kureba kwacho kunowedzera ne5 cm. Sarudza simba rayo risingaperi uye rinokwanisa kushanda.

Zvinozivikanwa:

Huremu hwechinhu (m) = 500 magiramu = (500/1000) kg = 5/10 kg = 0.5 kg

Kukurumidza (g) = 10 m/s ²

Kurema kwechinhu (w) = mg = (0.5 kg)(10 m/s ² ) = 5 kg m/s ² = 5 Newtons

Kuchinja kwehurefu hwechitubu (Δx) = 5 cm = 0.05 m

Zvinodiwa: simba rechirimo (k) uye simba rinogona kushandiswa (PE)

Solution:

Kutanga, verenga chiverengero chechirimo uchishandisa equation yemutemo waHooke:

k = w / Δx = 5 N / 0.05 m = 100 N/m

Kugona kunamira kwechirimo:

PE = ½ k Δx ² = ½ (100) (0.05) ² = (50) (0.0025)

PE = 0.125 Joule

[wpdm_package id='1179′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika pakufamba panzvimbo dzakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Muviri we 1 kg wakadonha kubva pakuzorora, kubva pakukwirira kwemamita gumi.

Sarudza:

( a) Basa rinoitwa nesimba regiravhiti

(b) Kuchinja kwesimba regiravhiti

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinozivikanwa:

Huremu (m) = 1 kg

Kureba (h) = 10 m

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Huremu (w) = mg = (1 kg)(10 m/s ² ) = 10 N

Solution:

(a) Basa rinoitwa nesimba regiravhiti

W = wh = mgh

W = (1)(10)(10) = 100 Joule

(b) Kuchinja kwesimba regiravhiti

Kuchinja kwesimba regiravhiti kwakaenzana nebasa rinoitwa negiravhiti.

Δ EP = 100 Joule

2. Chinhu che10 N chinotsvedza pasi panzvimbo yakatsetseka yakatsetseka nemamita maviri. Tsvaga basa rinoitwa nesimba rehuremu!

Zvinozivikanwa:

huremu (w) = 10 N

w _x = w chivi θ = (10)(chivi 30 ^o ) = (10)(0.5) = 5 N

d = 2 m

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: basa rinoitwa nesimba rinorema

Solution:

W = F d = w _x d = (5)(2) = 10 Joules

Imwe mhinduro:

Chivi 30 ^o = h / d

0.5 = awa / 2

h = (0.5)(2)

h = 1 m

Basa rinoitwa nesimba rinorema;

W = F d = wh = (10 N)(1 m) = 10 N m = 10 Joules

3. Chinhu chinorema magiramu 1,500 chiri pamamita makumi maviri pamusoro pevhu , chinodonha pasi pasina muripo. Chii chinonzi simba regiravhiti rechinhu chacho. Kukurumidza kunokonzerwa negiravhiti i10 m/s ².

Zvinozivikanwa:

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Huremu (m) = 1500 magiramu = 1500/1000 makirogiramu = 1.5 makirogiramu

Kureba (h) = mamita mashanu

Zvinodiwa: Simba regiravhiti

Solution:

PE = mgh = (1.5 kg)(10 m/s ² )(20 m) = 300 kg m ² /s ² = 300 Joules

4. Zvichibva pamufananidzo uri pazasi, kana huremu hwechinhu 1 huri 2 kg uye huremu hwechinhu 2 huri 4 kg, kuenzanisa simba rinogona kuwanikwa rechinhu 1 nechinhu 2 kuri …..

Zvinozivikanwa:

Huremu hwechinhu 1 (m₁) = 2 kg

Huremu hwechinhu 2 (m2 ₎ = makirogiramu mana

Kureba 1 (h1 ₎ = mamita mapfumbamwe

Kureba 2 (h2 ₎ = mamita mapfumbamwe

Zvinodiwa: Kuenzanisa simba rinogona kuwanikwa rechinhu 1 nechinhu 2

Solution:

PE = mgh

m = huremu (chiyero chayo chepasi rose ikirogiramu, kg yakapfupikiswa)

g = kukurumidza kunokonzerwa negiravhiti (chikamu chayo chepasi rose chiri mamita pasekondi imwe chete, chakapfupikiswa m/s ² )

h = kureba (chikamu chayo chepasi rose imita, chakapfupikiswa m)

PE = simba rekukwevera pasi (chikamu chayo chepasi rose i kg m ² /s ² kana Joule)

Simba rekukwevera rechinhu 1:

EP ₁ = m ₁ gh ₁ = (2)(g)(12) = 24 g

Simba rekukwevera rechinhu 2:

EP ₂ = m ₂ gh ₂ = (4)(g)(9) = 36 g

Kuenzanisa kwesimba rinogona kuwanikwa rechinhu 1 nechinhu 2:

PE ₁ : PE ₂

24 g : 36 g

24: 36

12/24: 12/36

2: 3

[wpdm_package id='1175′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro wakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Bhokisi re2-kg rinodzika kubva pa10 m/s kusvika razorora. Chiyero chekukakavadzana kwekinetic i0.2. Kukurumidza kunokonzerwa negiravhiti i10 m/s ^{2. Kukura} kwekuchinjana chii?

Kuzivikanwa;

Huremu (m) = 2 kg

Kumhanya kwekutanga (v _o ) = 10 m/s

Kumhanya kwekupedzisira (v _t ) = 0 m/s

Chiyero chekukweshana kwekinetic ( _μk ) = 0.2

Huremu (w) = mg = (1 kg)(10 m/s ² ) = 10 kg m/s ² = 10 N

Zvinodiwa: Hukuru hwekutama (d)

Solution:

Musimboti wesimba rekushanda nemagetsi :

W _nc = ΔEM

W _nc = ΔEK + ΔEP

W _nc = ½ m (v _t ² – vo ₂ ⁾ + mgh

W _nc = basa rinoitwa nesimba risingachengetedzi richishanda pane chinhu

ΔEK = shanduko musimba remagetsi

ΔEP = shanduko musimba rinogona kuwanikwa

m = huremu

v = kumhanya

g = kukurumidza nekuda kwesimba rinokwevera pasi

h = kuchinja kwehurefu

Kuchinja kwehurefu h = 0 saka ΔEP = 0

W _nc = ΔEK

Basa rinoitwa nemauto asingachengetedze tsika:

W _nc = -F _c d = – μ _k N d = – μ _k wd = – μ _k mgd

W _nc = -(0.2)(2)(10)(s)

W _nc = – (4)(2)

Chiratidzo chekusiya chinoratidza kuti divi resimba rekukweshana kwekinetic rakapesana nedivi rekutama.

Kuchinja kwesimba rekinetic:

ΔEK = ½ m (v _t ² – v _o ² ) = ½ (2) (0 – 10 ² ) = 0 – 100 = -100

Kukura kwekutama:

W _nc = ΔEK

– masekondi mana = – zana

s = -100/-4

s = 25 m

2. Bhurukwa rinotsvedza pasi padivi rakarerekera. Chiyero chekukweshana kwekinetic i0.4. Kukurumidza kunokonzerwa negiravhiti g = 10 ms ^-2 . Sarudza kumhanya kwekupedzisira apo bhurukwa rinorova pasi.

Zvinozivikanwa:

Kureba kwekutanga (h _o ) = 6 m

Kureba kwekupedzisira (h _t ) = 0 m

Kumhanya kwekutanga (v _o ) = 0

Chiyero chekukweshana kwekinetic ( _μk ) = 0.4

Kukurumidza kunokonzerwa negiravhiti (g) = 10 ms ^-2

cos θ = 8/10

Chikamu chehuremu chakamira = w _y = w cos θ = mg cos θ = m (10) (8/10) = m (10)(4/5) = m (40/5) = 8 m

Simba rakajairika = N = w _y = 8 m

Simba rekukweshana kwekinetic = f _k = μ _k N = μ _k w _y = (0.4)(8 m) = 3.2 m

Zvinodiwa: Kumhanya kwekupedzisira (v _t )

Solution:

Musimboti wesimba rekushanda nemagetsi:

W _nc = Δ EM

W _nc = Δ EK + Δ EP

Kuchinja kwesimba rekinetic:

ΔEK = 1/2 m (v)_t² - v_o²) = 1/2 m (v)_t² - 0) = 1/2 mv_t²

Kuchinja kwesimba rinogona kushandiswa:

Δ EP = mg (h _t – ho ₎ = m (10)(0-6) = m (10)(-6) = – 60 m

Basa rinoitwa nesimba rekukweshana kwekinetic:

W _nc = – f _ks = – ( 3.2 m)(10) = – 32 m

Chiratidzo chekusiya chinoratidza kuti divi resimba rekukweshana kwekinetic rakapesana nedivi rekutama.

Kumhanya kwekupedzisira (v _t ):

W _nc = Δ EK + Δ EP

– 32 m = 1/2 mv _t ² – 60 m

– 32 m = m (1/2 v _t ² – 60)

– 32 = 1/2 v _t ² – 60

– 32 + 60 = 1/2 v _t ²

28 = 1/2 v _t ²

2 (28) = v _t ²

56 = v _t ²

v _t = √4.14

v _t = 2 √14 ms ^-1

3. Bhiriko rinotsvedza pasi padenderedzwa rakakombama. Kumhanya kwekutanga i0 m/s uye kumhanya kwekupedzisira i10 ms ^-1 . Kana simba rekukweshana kwekinetic riri 2 N uye kukurumidza nekuda kwegiravhiti g = 10 ms ^-2 , chii chinonzi kureba (h)?

Zvinozivikanwa:

Huremu (m) = 1 kg

Kumhanya kwekutanga (v _o ) = 0 (kuzorora kwebhuroko)

Kumhanya kwekupedzisira (v _t ) = 10 ms ^-1

Kureba kwekutanga (h _o ) = h

Kureba kwekupedzisira (h _t ) = 0

Simba rekukweshana kwekinetic (f _k ) = 2 N

Kukurumidza kunokonzerwa negiravhiti (g) = 10 ms ^-2

Zvinodiwa: Kureba (h)

Solution:

Basa rinoitwa nesimba rekukweshana kwekinetic:

W _nc = – f _ks = – (2 )(15) = – 30

Chiratidzo chekusiya chinoratidza kuti divi resimba rekukweshana kwekinetic rakapesana nedivi rekutama.

Kuchinja kwesimba rekinetic:

ΔEK = 1/2 m (v)_t² - v_o²) = 1/2 (1)(10² - 0) = 1/2 (10²) = 1/2 (100= = 50

Kuchinja kwesimba rinogona kushandiswa:

Δ EP = mg (h _t – ho ₎ = (1)(10)(0-h) = (10)(-h) = -10 maawa

Musimboti wesimba rekushanda nemagetsi:

W _nc = Δ EK + Δ EP

– 30 = 50 – 10 maawa

Maawa gumi = 50 + 30

10 maawa = 80

h = 80/10

h = 8 m

4Kana bhokisi richifamba pasi rakarerekera zvakanyanya, saka….
A. Basa rinoitwa nesimba regiravhiti pabhuroko rakakura kupfuura shanduko yesimba ringangoitika rebhuroko
B. Simba remakanika rinowedzera
C. Huwandu hwesimba rekinetic uye simba raro rinogoneka zvinoderedzwa
D. Basa rinoitwa nesimba rekukweshana rakaenzana nekuchinja kwesimba rekinetic reblock
mhinduro

A haina kururama

Basa rinoitwa nesimba regiravhiti pabhuroko rakaenzana nekuchinja kwesimba regiravhiti rebhuroko.

B haana kururama

Kana plane ine c yakatsetseka, simba remuchina rebloki rinoramba riripo. Kana riri pamusoro peplane yakatsveyama uye risati rafamba, simba remuchina rebloki rakaenzana nesimba regravitational potential. Block richiripo saka simba rayo rekinetic harisi zero. Pakufamba pasi peplane yakatsveyama, kukwirira kwebloki kunoderedzwa saka simba regravitational potential rinoderedzwawo. Simba regravitational potential rinoderera nekuti rinochinja kuenda kusimba rekinetic. Kunyangwe simba regravitational potential richichinja kuita simba rekinetic, simba remuchina rinogara riripo.

Kana denderedzwa rakakombama rakashata, simba remuchina weblock rinodzikira nekuda kwebasa rakaipa rinoitwa nechisimba chemuchina. Simba remuchina we ...

C yakarurama

Nzvimbo yakakombama yakakombama saka pane simba rekukweshana rinoedza mafambiro eblock. Simba rekukweshana isimba risingachengetedzi. Theorem work-mechanical energy inoti basa rinoitwa nesimba risingachengetedzi (semuenzaniso simba rekukweshana) rakaenzana nekuchinja kwesimba remakanika. Mukutsvaga uku, simba remakanika riri kudzikira.

Simba remuchina reblock = simba regiravhiti + simba rekinetic.

D haana kururama.

Basa rinoitwa nesimba rekukweshana pabhuroko rakaenzana nekuchinja kwesimba remuchina rebhuroko, kwete kuchinja kwesimba remuchina rebhuroko. Ichokwadi kuti simba rekukweshana rinopikisa kufamba kwebhuroko saka rinoderedza kumhanya kwebhuroko uye rinoderedza simba remuchina rebhuroko. Asi ziva kuti simba remuchina rebhuroko rinobva kusimba regiravhiti. Saka ichokwadi kuti basa rinoitwa nesimba rekukweshana rakaenzana nekuchinja kwesimba remuchina (simba remuchina rinoderera).

Mhinduro chaiyo ndeinoti C.

5. Chinhu chiri paburiro rakashata chinorohwa saka chinofamba kwemasekonzi matatu chobva chamira. Kana huremu hunozivikanwa hwechinhu chacho huri magiramu gumi, simba rekukweshana pakati pechinhu chacho neburiro i2 kilodyne. Sarudza basa rinoitwa nesimba rekukweshana.

A. 0.18 J

B. -0.18 J

C. 0.36 J

D. -0.36 J

Zvinozivikanwa:

Nguva yepakati (t) = masekondi gumi nemashanu

Kumhanya kwekupedzisira (v _t ) = 0 m/s (nzvimbo yekuzorora kwechinhu)

Huremu hwechinhu (m) = magiramu gumi = 10/1000 kg = 1/100 kg = 0.01 kg

Friction force (F) = 2 kilodynes = 2 x 10 ³ dynes

Zvinodiwa: Basa (W) rinoitwa nesimba rekukweshana

Solution:

Kushandurwa kwezvikamu zvesimba:

1 Newton = 1 x 10 ⁵ dyne

1 dyne = 1 / 10 ⁵ Newtons = 1 x 10 ^-5 Newtons = 10 ^-5 Newtons

Simba rekukweshana (F) = 2 x 10 ³ dyne = 2 x 10 ³ x 10 ^-5 Newton = 2 x 10 ^-2 Newton = 2/100 Newton = 0.02 Newton

Theorem work-mechanical energy inotaura kuti basa rinoitwa nesimba risingachengetedzeki pachinhu chakaenzana nekuchinja kwesimba remechanical rechinhu chacho.

Kana chinhu chichifamba padenderedzwa rakanamira, simba remagetsi (ME) = simba regiravhiti (PE) + simba remagetsi (KE). Asi kana chinhu chichifamba padenderedzwa rakanamira chete saka hapana shanduko pakukwirira, simba remagetsi = simba remagetsi. Padenderedzwa rakanamira, simba regiravhiti harisi zero nekuti hapana shanduko pakukwirira.

Simba rekukweshana isimba risingachengetedzi. Simba rekukweshana rinowanzo kuderedza kumhanya kwechinhu uye simba rekukweshana rechinhu. Tinogona kugumisa kuti basa rinoitwa nesimba rekukweshana pachinhu rakaenzana nekuderera kwesimba remakanika.

Pamasvomhu:

Basa (W) = Kuchinja kwesimba remakanika (ΔEM)

F s = ΔEP + ΔEK

F s = mg Δh + ½ m (v _t ² – _vo ² )

F s = mg (0) + ½ m (0 ² – _vo ² )

Fs = 0 + ½ m (– (v _o ² ))

Fs = – ½ mv _o ² ———— Equation 1

Tsananguro: F = simba rekukweshana, d = kutama, m = huremu, v _o = kumhanya kwekutanga

Kuchinja (d) uye kumhanya kwekutanga (vo _o ) hazvisati zvazivikanwa nekuti tanga waverenga v _o kana d. Basa rinoitwa nesimba rekukweshana rakaverengwa uchishandisa imwe ye equation mushure mekuzivikanwa v _o kana d.

Equation yekutama (d) pakufamba kwemutsara kusingaenderane:

v _t ² = vo ₂ ⁺ 2 (-a) s

Kumhanya kwekupedzisira (v _t ) = 0 uye kukurumidza (a) kunosainwa negative nekuti chinhu chacho chaderera (kumhanya kwechinhu kwadzikira).

0 = v_o² - 2 kushambadzira

v_o² = 2 kushambadza

d = vo ₂ ^/ 2 a ———— Equation 2

Chinja d muequation 2 na d muequation 1:

F d = – ½ mv _o ²

F (v _o ² /2a) = – ½ mv _o ²

(F/2a) v _o ² = – ½ mv _o ²

F/2a = – ½ m

F = (2)(a)(-1/2)(m)

F = – (a)(m)

a = – (F / m)

a = – 0.02 Newtons / 0.01 kg

a = – 2 Newton/kilogiramu

a = – 2 m/s ²

Equation yekuverenga kumhanya kwekutanga (v _o ) mukufamba kwemutsara kusingaenderane:

v _t = vo _o + pa —–> Kumhanya kwekupedzisira (v _t ) = 0, Kukurumidza (a) = 2 m/s ² , nguva yechinguva (t) = masekondi matatu

0 = vo ₊ (-2)(3)

0 = v _o – 6

v _o = mamita matanhatu/sekondi

Basa (W) rinoitwa nechisimba chemagetsi:

W = – ½ mv _o ² = -1/2 (0.01)(6 ² ) = -1/2 (0.01)(36)

W = -1/2 (0.36)

W = – 0.18 Joule

Basa rinoitwa nechisimba rinosainwa nechiratidzo chekuti harina simba zvichireva kuti basa racho rinoderedza simba remuchina wechinhu chacho.

Kana zvikazivikanwa d basa rinogona kuverengerwa uchishandisa equation yaW = F d.

Mhinduro chaiyo ndeiyi B.

[wpdm_package id='1178′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro wakakombama
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

Read more

Simba reKinetic reBasa :

1. Mota inorema 5000 kg yakakurumidza kubva pakuzorora kusvika 20 m/s. Sarudza basa rakagadzirwa pamota.

Zvinozivikanwa:

Huremu (m) = 5000 kg

Kumhanya kwekutanga (vo _o ) = 0 m/s ( kuzorora kwemotokari )

Kumhanya kwekupedzisira (v _t ) = 20 m/s

Zvinodiwa : network

Solution:

Musimboti wesimba rekushanda-kinetic :

W _net = Δ EK

Mambure = ½ m (v _{t 2} ^– v _o ² )

W _net = basa remambure

Δ EK = shanduko musimba rekinetic

m = huremu (kg),

v _t = kumhanya kwekupedzisira (m/s),

v _o = kumhanya kwekutanga (m/s).

Network:

Mambure = ½ m (v _{t 2} ^– v _o ² )

W _mambure = ½ (5000) (20 ² - 0 ² )

W _net = (2500)(400 - 0)

W _net = (2500)(400)

W _net = 1000,000 Joule

2. Chinhu chinorema 10 kg chakakurumidziswa kubva pa5 m/s kusvika pa10 m/s. Sarudza basa remambure rakaitwa pachinhu chacho!

Zvinozivikanwa:

Huremu (m) = 10 kg

Kumhanya kwekutanga (v _o ) = 5 m/s

Kumhanya kwekupedzisira (v _t ) = 10 m/s

Zvinodiwa : network

Solution:

Network:

W _net = Δ EK

Mambure = ½ m (v _{t 2} ^– v _o ² )

W _mambure = ½ (10) (10 ² - 5 ² )

W _net = (5)(100 - 25)

W _net = (5)(75)

W _net = 375 Joule

3. Mota inorema 2000 kg inoderera kubva pa10 m/s kusvika pa5 m/s. Basa rei rinoitwa pamota iyi?

Zvinozivikanwa:

Huremu hwemota (m) = 2000 kg

Kumhanya kwekutanga (v _o ) = 10 m/s

Kumhanya kwekupedzisira (v _t ) = 5 m/s

Zvinodiwa: network

Solution:

Network:

W _net = Δ EK

Mambure = ½ m (v _{t 2} ^– v _o ² )

W _mambure = ½ (2000) (5 ² - 10 ² )

W _net = (1000)(25 - 100)

W _net = (1000)(-75)

W _net = -75,000 Joule

Chiratidzo chekusiya chinoratidza kuti nzira yekutama yakatarisana nenzira yesimba remagetsi.

4. Simba risingaperi re60-N rinoitwa pachinhu chinorema 10-kg kwemasekonzi gumi nemaviri. Kumhanya kwekutanga kwechinhu i6 m/s uye kutungamira kwechinhu kwakafanana nekutungamira kwesimba.

(1) Basa rakaitwa pachinhu ichi i30,240 Joules

(2) Simba rekupedzisira rekinetic i30,240 joules

(3) Simba i2,520 Watts

(4) Kuwedzera kwesimba rekinetic rechinhu ichi i180 Joules

Mashoko echokwadi ndeekuti…

Zvinozivikanwa:

Simba (F) = 60 N

Nguva yepakati (t) = masekondi gumi nemashanu

Huremu hwechinhu (m) = 10 kg

Kumhanya kwekutanga (v _o ) = 6 m/s

Zvinodiwa: Mashoko akarurama

Solution:

Kukurumidzisa kwechinhu:

∑F = ma

60 = 10 a

a = 60 / 10 = 6 m/s ²

Kumhanya kwekupedzisira:

v _t = vo ₊ pa

v _t = 6 + (6)(12)

v _t = 6 + 72

v _t = 78 m/s

Nharaunda yakafambwa mumasekonzi gumi nemaviri:

s = vot ₊ 1/2 pa ²

s = (6)(12) + 1/2 (6)(12) ²

s = 72 + (3)(144)

s = 72 + 432

s = mamita gumi

(1) Basa rinoitwa nechisimba

W = F s = (60)(504) = 30,240 Joules

(2) Simba rekupedzisira rekufamba kwemhepo

KE = 1/2 mv _t ² = 1/2 (10) (78) ² = (5) (6084) = 30,420 Joules

(3) Simba

P = W / t = 30,240 / 12 = 2,520 Joules/sekondi

(4) Kuwedzera kwesimba remagetsi

ΔKE = 1/2 mv _t ² – 1/2 mv _o ² = 1/2 m (v _t ² – v _o ² ) = 1/2 (10) (78 ² – 6 ² ) = 5 (6084 –36) = 5 (6048)

ΔKE = 30,240 Joule

5. Basa guru rinoitwa nenhamba yechinhu…

Solution:

Basa reNet = shanduko yesimba reKinetic

Mambure = ½ m (v _{t 2} ^– v _o ² )

Basa guru:

W ₁ = ½ (8)(4 ² – 2 ² ) = (4)(16 – 4) = (4)(12) = 48 Joules

W ₂ = ½ (8)(5 ² –3 ² ) = (4)(25 – 9) = (4)(16) = 64 Joules

W ₃ = ½ (10)(6 ² – 5 ² ) = (5)(36 – 25) = (5)(11) = 55 Joules

W ₄ = ½ (10)(4 ² – 0 ² ) = (5)(16 – 0) = (5)(16) = 80 Joules

W ₅ = ½ (20)(3 ² – 3 ² ) = (10)(9 – 9) = (10)(0) = 0 Joules

6. Mota inorema 4000 kg inofamba nemutsetse wakatwasuka pa25 m/s. Mota inoderedzwa speed zvekuti kumhanya kwekupedzisira kwemota kuri 15 m/s. Basa rakaitwa pamota nderei?

Zvinozivikanwa:

Huremu (m) = 4000 kg

Kumhanya kwekutanga (v _o ) = 25 m/s

Kumhanya kwekupedzisira (v _t ) = 15 m/s

Zvaidiwa : Basa rakaitwa pamotokari

Solution:

W _net = ½ m (v _t ² – vo ₂ ⁾ = ½(4000)(15 ² -25 ² ) = (2000)(225-625) = (2000)(-400) = -800,000 Joules = -800 kJ

7. 0.1-kg inokandwa yakatwasuka pa 6 m/s kubva pakukwirira kwemamita mashanu. Kana kukurumidza kwegiravhiti kuri 10 m/s ² , saka chii chinonzi kinetic energy yebhora pakukwirira kwemamita maviri.

Zvinozivikanwa:

Huremu (m) = 0.1 kg

Kuchinja kwehurefu (h) = 5 m – 2 m = 3 metres

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: Simba rekufamba kwemhepo riri pakakwirira mamita maviri.

Solution:

Kufamba kweprojectile kunogona kunzwisiswa nekuongorora zvikamu zvekufamba zvakatwasuka uye zvakatwasuka zvakasiyana. Kufamba kwakatwasuka kunoongororwa sekufamba kwevelocity nguva dzose uye kufamba kwakatwasuka kunoongororwa sekufamba kwefree fall kana kufamba kwakatwasuka.

Simba rekutanga remakanika = simba regiravhiti.

PE = mgh = (0.1)(10)(3) = 3 maJoules.

Simba rekupedzisira remakanika = simba rekinetic.

KE = 3 maJoules.

8. Mota inorema 1000 kg inomhanya nekukurumidza kubva pakuzorora uye inofamba ne5 m/s. Ndeipi basa rinoitwa nemota?

Zvinozivikanwa:

Huremu (m) = 1000 kg

Kumhanya kwekutanga (v _o ) = 0

Kumhanya kwekupedzisira (v _t ) = 5 m/s

Zvaidiwa: Basa (W) rinoitwa nemotokari

Solution:

Mambure = ½ m (v _{t 2} ^– v _o ² )

Basa rinoitwa nemota:

W _net = ½ (1000)(5 ² – 0 ² ) = (500)(25 – 0) = (500)(25) = 12,500 Joules

9. Bhora remagiramu mazana mashanu rinokandwa rakamira mudenga kubva pamusoro penyika nekumhanya kwekutanga kwe10 m/s ² . Kukurumidza kunokonzerwa negiravhiti i10 ms ^-2 . Ndeipi basa rinoitwa nesimba rinorema kana bhora rasvika pakukwirira kwakanyanya.

Zvinozivikanwa :

Huremu hwebhora (m) = 500 magiramu = 0.5 kg

Kumhanya kwekutanga (v _o ) = 10 m/s ²

Kumhanya kwekupedzisira (v _t ) = 0 (kumhanya kwepamusoro-soro)

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Kudiwa: Basa (W) don neuremu

Solution:

Basa remambure rinoitwa nesimba remambure pachinhu = shanduko musimba remambure.

W _net = ΔEK = EK _t – EK _o

Wnet = ½ mv _t ² – ½ mv _o ² = ½ m (v _t ² – v _o ² )

KE _t = simba rekupedzisira rekinetic, KE _o = simba rekutanga rekinetic, m = huremu hwechinhu, v _t = kumhanya kwekupedzisira kwechinhu, v _o = kumhanya kwekutanga kwechinhu.

Network:

W _mambure = ½ m (v _t ² – v _o ² ) = ½ (0.5) (0 ² – 10 ² )

W _net = (0.25)(-100) = -25 Joules

Chiratidzo chekudzima chinoratidza kuti bhora rakananga kure kure neuremu hwaro. Bhora rakananga rakamira uye huremu hwaro hwakamira kure.

10. Chinhu chinorema 1-kg chinodonha chisina kusimba nekukwirira kwakasiyana = 2.5 metres. Kukurumidza kunokonzerwa negiravhiti i10 ms ^-2 . Basa rakaitwa pachinhu chacho nderei?

Zvinozivikanwa:

Huremu hwebhora (m) = 1 kg

Kumhanya kwekutanga (v _o ) = 0 m/s

Kureba (h) = mamita mashanu

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: Basa repaindaneti panguva yekudzingwa

Solution:

Kumhanya kwekupedzisira kwebhora (v _t )

Yakaverengerwa uchishandisa equation yekufamba kwemahara. Inozivikanwa: Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ² , Kuchinja kwehurefu hwebhora (h) = 2.5 metres. Inodiwa: Kumhanya kwekupedzisira.

v _t ² = 2 gh = 2(10)(2.5) = 2(25)

v _t = √2(25)

v _t = 5√2

Basa reNet = shanduko musimba rekinetic

W _mambure = ΔEK = ½ m (v _t ² – v _o ² ) = ½ (1){(5√2) ² – 0 ² }

W _net = ½ (25)(2) = 25 Joule

11. Chinhu chinorema 2 kg chinofamba ne72 km/awa. Mushure mekufamba mamita 400, kumhanya kwekupedzisira kwechinhu chacho i144 km/awa. Kukurumidza kunokonzerwa negiravhiti i10 ms ^-2 . Tsvaga basa remambure.

Zvinozivikanwa:

Huremu hwechinhu (m) = 2 kg

Kumhanya kwekutanga (v _o ) = 72 km/awa = 20 m/s

Kumhanya kwekupedzisira (v _t ) = 144 km/h = 40 m/s

Nhambwe (s) = mamita mazana mana

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: Network

Solution:

Basa remagetsi = shanduko dzesimba remagetsi

W _mambure = ΔEK = ½ m (v _t ² – v _o ² ) = ½ (2) (40 ² – 20 ² }

W _net = ½ (2)(1600 - 400) = 1200 Joules

12. Chinhu chinorema 2-kg chinofamba ne2 ms ^-1 . Basa rinoitwa pachinhu ichi i21 Joules. Chii chinonzi kumhanya kwekupedzisira kwechinhu?

Zvinozivikanwa:

Huremu (m) = 2 kg

Kumhanya kwekutanga (v _o ) = 2 m/s

Basa (W) = 21 Joule

Zvinodiwa: kumhanya kwekupedzisira (v _t )

Solution:

W _net = ΔEK

W _net = 1/2 mv _t ² -1/2 mv _o ²

W _mambure = 1/2 m (v _t ² – v _o ² )

21 = 1/2 (2) (v _t ² – 2 ² )

21 = (v _t ² – 2 ² )

21 = v _t ² – 4

v _t ² = 21 + 4 = 25

v _t = √25

v _t = 5 m/s

1 3. Simba risingaperi re8 N rinoshanda pachinhu chine huremu hwe16 kg. Kana chinhu chacho chikatanga chakamira, saka tarisa kumhanya kwechinhu mushure mekunge simba racho rashanda pachinhu chacho kwemasekondi mana.

Zvinozivikanwa:

Simba risingaperi (F) = 8 Newton

Huremu hwechinhu (m) = 16 kg

Kumhanya kwekutanga kwechinhu (vo ₎ = 0 m/s

Simba rinoita basa pachinhu (t) = masekondi mana.

Kudiwa: Kumhanya kwekupedzisira (v _t )

Solution:

Basa = Kuchinja kwesimba rekinetic

W = KE yekupedzisira – KE yekutanga

W = ½ mv _t ² – ½ mv _o ²

W = ½ mv _t ² – 0

W = ½ mv _t ² —— Equation 1

Basa = Simba x Kudzingwa

W = F d

W = 8 d

Shandisa equation yekufamba kwemutsara kusingaenderane iri pazasi kuti uverenge displacement (d):

d = vot ₊ ½ pa ²

d = kufamba, v _o = kumhanya kwekutanga, t = nguva yepakati, a = kukurumidza

d = 0 + ½ pa2 ⁼ ½ ^pa2 —-> a = (v _t – vo _o ) / t = v _t / t

d = ½ (v _t / t) t ²

^d = ½ (v _t ) t

Chinja displacement (d) pa equation yeBasa ne displacement (d) mu equation iyi:

W = 8 d

W = 8(1/2)(v _t )(t)

W = (4)(v _t )(t) —— equation 2

Equation 1 = Equation 2

W = W

½ mv _t ² = (4)(v _t )(t)

½ mv _t = (4)(t)

½ (16)(v _t ) = 4(4)

8 v _t = 16

v _t = 16 / 8

v _t = 2 mamita/sekondi

14. Kuti uwedzere kumhanya kwechinhu ka2 kupfuura kumhanya kwekutanga, sarudza basa rinodiwa mukuita…

Zvinozivikanwa:

Huremu hwechinhu (m) = 1 kg

Kumhanya kwekutanga (vo ₎ = 1 m/s

Kumhanya kwekupedzisira (v _t ) = 2 x kumhanya kwekutanga = 2 x 1 = 2 m/s

Zvinodiwa: Basa

Solution:

Simba rekutanga rekinetic:

KE kutanga = ½ mv _o ² = ½ (1) (1) ² = ½ (1) (1) = ½ (1) = 0.5

Simba rekupedzisira rekinetic kana kumhanya kwechinhu kwava kaviri kupfuura kumhanya kwacho kwekutanga:

KUNA yekupedzisira = ½ mv _t ² = ½ (1)(2) ² = ½ (4) = 2

Dzidziso yesimba rekushanda-kinetic:

Basa = Kuchinja kwesimba rekinetic

Basa = Simba rekupedzisira rekinetic – simba rekutanga rekinetic

Basa = 2 – 0.5

Basa = 1.5

Simba rekutanga rekinetic = 0.5

Basa = 3 x 0.5 = 1.5

Inodiwa kuti ishande ka3 kupfuura simba rayo rekutanga rekinetic.

15. Mota ine huremu hwe1500 kg inofamba nekumhanya kwe36 km/awa mumugwagwa wakatwasuka uye wakatsetseka. Mota yacho yakakurumidza kusvika 72 km/awa. Sarudza basa rinodiwa kuti mota imhanye.

Zvinozivikanwa:

Huremu hwemota (m) = 1500 kg

Kumhanya kwekutanga kwemotokari (v _o ) = 36 km/awa = 36,000 metres / 3600 second = 10 metres/second

Kumhanya kwekupedzisira kwemotokari (v _t ) = 72 km/awa = 72,000 metres / 3600 seconds = 20 metres/sekondi

Zvinodiwa: Basa rinodiwa kuti mota imhanye nekukurumidza

Solution:

Dzidziso yesimba rekushanda-kinetic:

W = EK yekupedzisira – EK yekutanga

W = ½ mv _t ² – ½ mv _o ² = ½ m (v _t ² –v _o ² )

W = ½ (1500)(20 ² - 10 ² )

W = ½ (1500)(400 - 100)

W = ½ (1500)(300)

W = (1500)(150)

W = 225,000 Joules

16. Chinhu chine huremu hwe2 kg chinotanga kufamba nekumhanya kwe72 km. awa ^-1 . Mushure mekufamba mumugwagwa wakatwasuka kusvika 400 m, kumhanya kwechinhu chacho i144 km. awa ^-1 . Sarudza basa rose pachinhu chacho.

Zvinozivikanwa:

Huremu hwechinhu (m) = 2 kg

Kumhanya kwekutanga (v _o ) = 72 km/awa = 72,000 metres / 3600 seconds = 20 m/s

Kumhanya kwekupedzisira (v _t ) = 144 km/awa = 144,000 metres / 3600 seconds = 40 m/s

Kutamiswa kwechinhu = mamita mazana mana

Zvaidiwa: Basa reNet pachinhu chacho

Solution:

Dzidziso yesimba rekushanda-kinetic inoti basa remagetsi rinoshanda pachinhu zvakafanana nekuchinja kwesimba remagetsi rechinhu.

W net = KUSVIKA pakupera – KUSVIKA pakutanga

W net = ½ mv _t ² – ½ mv _o ²

Mambure = ½ m (v _t ² – v _o ² )

W mambure = ½ (2) (40 ² – 20 ² )

W net = 1600 - 400

W net = 1200 Joule

Description:

W = Basa, KE = simba remagetsi

Kinetic simba

17. Bara remagiramu gumi richifamba ne100 m/s. Chii chinonzi kinetic energy yebara.

Zvinozivikanwa:

Huremu hwebara (m) = magiramu gumi = 10/1000 makirogiramu = 1/100 makirogiramu = 0.01 makirogiramu

Kumhanya kwebara (v) = mamita zana pasekondi

Zvinodiwa: Kinetic energy

Solution:

KE = 1/2 mv ²

KE = 1/2 (0,01 kg)(100 m/s) ²

KE = 1/2 (0,01 kg)(10.000 m2 ^/ s ² )

KE = (0,01 kg)(5000 m ² /s ² )

KE = 50 kg m ² /s ²

KE = 50 Joule

[wpdm_package id='1191′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro pekona
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Munhu anodhonza bhokisi 2 m pamusoro penzvimbo yakatambanuka nesimba risingaperi F = 20 N. Sarudza basa rinoitwa nesimba F richishanda pabhokisi.

Zvinozivikanwa:

Simba (F) = 20 N

Kutamiswa (s) = 2 m

Angle (θ ) = 0

Kudiwa : Basa (W)

Solution:

W = F d cos θ = (20)(2)(cos 0) = (20)(2)(1) = 40 Joules

2. Simba F = 10 N richishanda pabhokisi 1 m pamwe chete nenzvimbo yakatambanuka. Simba iri rinoshanda pakona ye30 ^o sezvakaratidzwa mumufananidzo uri pazasi. Sarudza basa rinoitwa nesimba F!

Zvinozivikanwa :

Simba (F) = 10 N

Simba rakatwasuka (F _x ) = F cos 30 ^o = (10)(0.5√3) = 5√3 N

Kutamiswa (d) = mita imwe

Wanted : Basa (W)?

Mhinduro :

W = F _x d = (5√3)(1) = 5√3 Joules

3. Muviri unodonha zvakasununguka kubva pakuzorora, kubva pakukwirira kwemamita maviri. Kana kukurumidza nekuda kwesimba rinokwevera pasi kuri 10 m/s ² , sarudza basa rinoitwa nesimba rinokwevera pasi!

Zvinozivikanwa:

Huremu hwechinhu (m) = 1 kg

Kureba (h) = 2 m

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa: Basa rinoitwa nesimba regiravhiti (W)

Solution:

W = F d = wh = mgh

W = (1)(10)(2) = 20 Joule

W = basa, F = simba, d = daro, w = huremu , h = kureba, m ​​= huremu, g = kukurumidza nekuda kwegiravhiti.

4. Chinhu chinorema 1-kg chinosungirirwa pachitubu saka chinoreba 2 cm. Kana kumhanyisa nekuda kwesimba rekukwevera pasi kuri 10 m/s ² , sarudza (a) chitubu chinogara chiripo (b) basa rinoitwa nesimba rechitubu pachinhu chacho

Zvinozivikanwa:

Huremu (m) = 1 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Kureba (x) = 2 cm = 0.02 m

Huremu (w) = mg = (1 kg)(10 m/s ² ) = 10 kg m/s ² = 10 N

Zvinodiwa: Nguva yechirimo uye basa rinoitwa nechisimba chechirimo

Solution:

(a) Chitubu chinogara kwenguva refu

Fomura yemutemo waHooke :

F = k x.

k = F / x = w / x = mg / x

k = (1)(10) / 0.02 = 10 / 0.02

k = 500 N/m

(b) basa rinoitwa nechisimba chemvura

W = – ½ kx ²

W = – ½ (500)(0.02) ²

W = – (250)(0.0004)

W = -0.1 Joule

Chiratidzo chekusiya chinoratidza kuti divi resimba rechitubu rakapesana nedivi rekuti chinhu chinosuduruka sei.

5. Simba F = 10 N rinokurumidzisa bhokisi pamusoro pechinhambwe chemamita maviri. Pasi pakaoma uye rine simba rekukweshana F _k = 2 N. Sarudza basa remambure rakaitwa pabhokisi.

Zvinozivikanwa:

Simba (F) = 10 N

Simba rekukweshana kwekinetic (F _k ) = 2 N

Kutamiswa (d) = 2 m

Zvinodiwa: Network (W _net )

Solution:

Basa rakaitwa nesimba F:

W ₁ = F d cos 0 = (10)(2)(1) = 20 Joules

Basa rinoitwa nesimba rekukweshana kwekinetic (F _k ):

W ₂ = F _k d = (2)(2)(cos 180) = (2)(2)(-1) = -4 Joules

Network:

W _net = W ₁ – W ₂

W _net = 20 – 4

W _net = 16 Joule

6. Ndeipi basa rinoitwa nechisimba F pabhuroko?

Zvinozivikanwa:

Simba (F) = 12 Newton

Kutamiswa (d) = mamita mana

Kudiwa: Basa (W)

Solution:

W = F d = (12 Newton)(mamita 4) = 48 N m = 48 Joules

7. Bhokisi rinosundwa nesimba re200 N. Kufamba kwebhokisi iri mamita maviri. Basa rakaitwa pabhokisi iri nderei?

Zvinozivikanwa:

Simba (F) = 200 Newton

Kutamiswa (d) = mamita mana

Kudiwa: Basa (W)

Solution:

Basa:

W = F s

W = (200 Newton)(mamita maviri)

W = 400 N m

W = 400 Joule

8. Mutyairi wemota ye sedan anoda kumisa mota yake 0.5 m chaiyo pamberi perori iri pa10 m kubva panzvimbo yemota ye sedan. Ndeipi basa rinodiwa nemota ye sedan?

Zvinozivikanwa:

Kutamiswa (d) = mamita gumi - mamita 0.5 = mamita 9.5

Simba (F) = 50 Newton

Kudiwa: Basa (W)

Solution:

W = F s

W = (50 Newton)(mamita maviri)

W = 475 N m

W = 475 Joule

9.

Basa rakaitwa naTom naJerry kuitira kuti mota ikwanise kufamba kusvika pamamita mana. Masimba anoshandiswa naTom naJerry nde50 N uye 70 N.

Zvinozivikanwa:

Kutama (s) = mamita mana

Simba reNet (F) = 50 Newtons + 70 Newtons = 120 Newtons

Kudiwa: Basa (W)

Solution:

W = F s = (120 Newton)(mamita mana) = 480 N m = 480 Joules

10. Mutyairi anodhonza mota zvekuti mota inofamba kusvika pa1000 cm. Ndeipi basa rinoitwa pamotokari?

Zvinozivikanwa:

Simba (F) = 250 Newton

Kutamiswa (s) = 1000 cm = 1000/100 metres = 10 metres

Kudiwa: Basa (W)

Solution:

W = F s = (250 Newton)(mamita mana) = 2500 N m = 2500 Joules

11. Zvichibva pamufananidzo uri pazasi, kana basa rinoitwa nemagetsi ari maJoules mazana matatu nemakumi manomwe nemashanu (375 Joules), tsvaga kusuduruka kwechinhu.

Zvinozivikanwa:

Basa (W) = 375 Joule

Simba remambure ( ΣF) = 40 N + 10 N – 25 N = 25 Newtons ( kurudyi )

Kudiwa: Kudzingwa ( d )

Solution:

Kuenzanisa kwebasa:

W = F s

Kubviswa kwechinhu:

d = W / F = 375 Joules / 25 Newtons

d = mamita gumi nemashanu s

12. Mabasa ari pazasi asingashande ndeaya …

A. Sunda chinhu kusvika kure nemamita gumi

B. Sundidzira mota kusvika yafamba

C. Sunda madziro

D. Akadhonza bhokisi

Solution:

Kuenzanisa kwebasa:

W = ΣF s

W = basa , F = simba , d = kusuduruka

Zvichibva pafomura iri pamusoro apa, basa rinoitwa nechisimba uye pane kuchinjika.

Mhinduro chaiyo ndeinoti C.

1 3. Andrew anosunda chinhu nesimba re20 N saka chinhu chinofamba nekufamba kwedenderedzwa neredhiyo yemamita manomwe. Sarudza basa rakaitwa naAndrew rekufamba kwedenderedzwa kaviri.

A. 0 Joule

B. 1400 Joule

C. 1540 Joule

D. 1760 Joule

Solution:

Kana munhu akasunda wiricheya kaviri achitenderera, munhu wacho newiricheya vanodzokera panzvimbo yavo yekutanga, saka kusuduruka kwemunhu wacho kunenge kuri zero.

Kutamiswa = 0 saka basa = 0.

Mhinduro chaiyo ndeinoti A.

14. Mumwe munhu anosundira chinhu pasi nesimba re350 N. Pasi rine simba rekukweshana re70 N. Sarudza basa rinoitwa nesimba rekufambisa chinhu kusvika pamamita matanhatu.

A. 45 J

B. 72 J

C. 1680 J

D. 2580 J

Zvinozivikanwa:

Simba rekusunda (F) = 350 Newtons

Simba rekukweshana (F _fric ) = 70 Newtons

Kutamiswa kwechinhu (s) = mamita matanhatu

Kudiwa: Basa (W)

Solution:

Kune masimba maviri anoshanda pachinhu, simba rekusunda (F) uye simba rekukweshana (F _fric ). Simba rekusunda rine gwara rakafanana nerekubviswa kwechinhu nekuti simba rekusunda rinoita basa rakanaka. Mune rimwe divi, simba rekukweshana rine gwara rakasiyana nerekubviswa kwechinhu zvekuti simba rekukweshana rinoita basa rakaipa.

Basa rinoitwa nechisimba chekusundidzira:

W = F d = (350 Newton)(6 metres) = 2100 Newton-mita = 2100 Joules

Basa rinoitwa nesimba rekukweshana:

W = – (F _fric )(s) = – (70 Newton)(6 metres) = – 420 Newton-meters = – 420 Joules

Network:

W net = 2100 Joules – 420 Joules

W net = 1680 Joule

Mhinduro chaiyo ndeinoti C.

15. Chinhu chinosundwa nesimba rakatambanuka remaNewton gumi nemana pasi rakasimba nesimba rekukweshana remaNewton gumi. Sarudza basa rekufambisa chinhu kusvika pamamita masere.

A. 0.5 Joule

B. 3 Joule

C. 32 Joule

D. 192 Joule

Zvinozivikanwa:

Simba rekusundidzira (F) = 14 Newton

Simba rekukweshana (F _fric ) = 10 Newtons

Kutamiswa kwechinhu (d) = mamita masere

Kudiwa: Basa (W)

Solution:

Kune masimba maviri anoshanda pachinhu, simba rekusunda (F) uye simba rekukweshana (F _fric ).

Simba rekusunda rine gwara rakafanana nerekusuduruka kwechinhu kuitira kuti simba rekusunda riite basa rakanaka. Kune rumwe rutivi, simba rekusuduruka rine gwara rakasiyana nerekusuduruka kwechinhu kuitira kuti simba rekusuduruka riite basa rakaipa.

Basa rinoitwa nechisimba chekusundidzira:

W = F s = (14 Newton)(mamita 8) = 112 Newton metres = 112 Joules

Basa rinoitwa nesimba rekukweshana:

W = – (F _fric )(s) = – (10 Newton)(mamita 8) = – 80 Newton metres = – 80 Joules

Network:

W net = 112 Joules – 80 Joules

W net = 32 Joule

Mhinduro chaiyo ndeinoti C.

16. Sarudza basa remambure zvichibva pamufananidzo uri pazasi.

A. 360 Joule

B. 450 Joule

C. 600 Joule

D. 750 Joule

Solution:

Basa = Simba (F) x kutama (d)

Basa = Nzvimbo yetriangle 1 + nzvimbo yerectangle + nzvimbo yetriangle 2

Work = 1/2(40-0)(3-0) + (40-0)(9-3) + 1/2(40-0)(12-9)

Basa = 1/2(40)(3) + (40)(6) + 1/2(40)(3)

Basa = (20)(3) + 240 + (20)(3)

Basa = 60 + 240 + 60

Basa = 360 Joule

Mhinduro chaiyo ndeinoti A.

17. Chidimbu chehuni chine hurefu hwemasendimita makumi matanhatu chakanamirwa pasi. Huni inorohwa nenyundo ye10-kg kubva pakakwirira kwe40 cm pamusoro pehuni. Kana simba rekudzivirira pasi riri 2 x 10 3 ^N uye kumhanya kunokonzerwa negiravhiti kuri 10 m/s ² , ipapo huni huchapinda muvhu zvachose mushure…. kurova.

A. 4

B. 16

C. 28

D. 30

Zvinozivikanwa:

Huremu hwenyundo (m) = 10 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/ s ²

Kurema kwenyundo (w) = mg = (10)(10) = 100 kg m/s ²

Kubviswa kwenyundo usati warova huni (d) = 40 cm = 0.4 metres

Kudzivirira kwehuni (F) = 2 x 10 ³ N = 2000 N

Kureba kwehuni = 60 cm = 0.6 metres

Zvaidiwa: Huni dzichapinda muvhu rose mushure mekunge… dzarohwa.

Solution:

Basa rinoitwa panyundo kana nyundo ichifamba kusvika pamamita 0.4 nderinotevera:

W = F d = ws = (100 N)(0.4 m) = 40 Nm = 40 Joules

Basa rinoitwa nesimba rekudzivirira repasi:

W = F d = (2000 N)(0.6 m) = 1200 Nm = 1200 Joules

Huni dzichapinda muvhu rose mushure mekunge… dzarohwa.

1200 Joules / 40 Joules = 30

Mhinduro chaiyo ndiD.

[wpdm_package id='1192′]

1. Basa rinoitwa nechisimba matambudziko uye mhinduro
2. Matambudziko esimba rekushanda nemhinduro
3. Matambudziko nemhinduro dzesimba rebasa-remakanika
4. Matambudziko esimba rinogona kukweva simba uye mhinduro dzaro
5. Simba rinogona kuwanikwa mumatambudziko e elastic spring uye mhinduro dzaro
6. Matambudziko emagetsi nemhinduro
7. Kushandiswa kwekuchengetedza simba remakanika kuti kufamba kwemahara kuwa
8. Kushandiswa kwekuchengetedza simba remakanika pakufamba kumusoro nekudzika mukufamba kwemahara kwemvura
9. Kushandiswa kwekuchengetedza simba remakanika kuti rifambe pamusoro pekona
10. Kushandiswa kwekuchengetedza simba remakanika pakufamba mundege yakatsamira
11. Kushandiswa kwekuchengetedza simba remakanika pakufamba kwezviratidziro

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1. Kureba kweNyika kubva kuZuva i149.6 x 10 ⁶ km uye nguva yekuchinja kweNyika igore rimwe chete. Verenga T ² / r ³

Zvinozivikanwa:

T = gore 1, r = 149.6 x 10 ⁶ km

Zvaidiwa : T ² / r ³ = … ?

Mhinduro :

k = T² /r³ = 1² / (149.6 x 10⁶)³ = 1 / (3348071.9 x 10¹⁸) = 2.98 x 10^-25 gore²/ km³

2. Chisingachinji cheUniversal (G) = 6.67 x 10 ^-11 Nm ² /kg ² uye Sun's 1.99 x 10 ³⁰ kg.

3. Avhareji yedaro reNyika kubva kuZuva i149.6 x 10 ⁶ km uye avhareji yedaro reMercury kubva kuZuva i57.9 x 10 ⁶ km. Nguva yekuchinja kwenyika igore rimwe chete, inguvai yekuchinja kweMercury?

Zvinozivikanwa:

r yePasi = 149.6 x 10 ⁶ km

r yemercury = 57.9 x 10 ⁶ km

T yePasi = gore rimwe chete

Wanted: T ye mercury?

Solution:

[wpdm_package id='953′]

1. Mutemo waNewton wematambudziko esimba rinokwevera pasi rose uye mhinduro dzawo
2. Simba resimba rinokwevera pasi, matambudziko ekurema, uye mhinduro
3. Kukurumidza kunokonzerwa nematambudziko egiravhiti nemhinduro
4. Matambudziko eGeosynchronous satellite uye mhinduro dzawo
5. Matambudziko emutemo waKepler nematambudziko ekugadzirisa matambudziko nemhinduro

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1. Ndeupi kukwirira kwesatellite ine geosynchronous pamusoro penyika?

G = chinhu chisingachinji chepasi rose = 6.67 x 10 ^-11 N m ² /kg ²

M = Huremu hwepasi = 5.97 x 10 ²⁴ kg

T = maawa makumi maviri nemana = 24 (masekonzi 3600) = 86,400 masekondi = 8.64 x 10 ⁴ masekondi

mhinduro

Kureba kwesateraiti pamusoro penyika = 4.22 x 10 ⁷ m = 4.22 x 10 ⁴ km = 42,200 km

Kureba kwesateraiti pamusoro penyika = 6.38 x 10 ⁶ m = 6.38 x 10 ³ km = 6380 km

Kureba kwesatellite pamusoro penyika = kureba kwesatellite kubva pakati penyika - radius yenyika

Kureba kwesateraiti pamusoro penyika = 42,200 km – 6380 km

Kureba kwesateraiti pamusoro penyika = 35,820 km

2. Chii chinonzi geosynchronous satellite kumhanya kwayo?

Chisingachinji chepasi rose (G) = 6.67 x 10 ^-11 N m ² /kg ²

Huremu hwepasi (m _E ) = 5.97 x 10 ²⁴ kg

Nhambwe iri pakati pesetiraiti nepakati pePasi (r) = 4.22 x 10 ⁷ m

mhinduro

kana kushandisa equation iyi

[wpdm_package id='949′]

1. Mutemo waNewton wematambudziko esimba rinokwevera pasi rose uye mhinduro dzawo
2. Simba resimba rinokwevera pasi, matambudziko ekurema, uye mhinduro
3. Kukurumidza kunokonzerwa nematambudziko egiravhiti nemhinduro
4. Matambudziko eGeosynchronous satellite uye mhinduro dzawo
5. Matambudziko emutemo waKepler nematambudziko ekugadzirisa matambudziko nemhinduro

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1. Daro riri pakati pemunhu ane 40-kg nemunhu ane 30-kg i2 m. Simba rinokwevera pasi rinoita sei pane rimwe nerimwe? Universal constant = 6.67 x 10 ^-11 N m ² / kg ²

Zvinozivikanwa:

m ₁ = 40 kg, m ₂ = 30 kg, r = 2 m, G = 6.67 x 10 ^-11 N m ² / kg ²

Zvinodiwa: hukuru hwesimba rinokwevera pasi (F)?

Solution:

2. Daro riri pakati peNyika neMwedzi (r) i3.84 x 10 ⁸ m. Simba regiravhiti rinoita sei pane rimwe?

Zvinozivikanwa:

Huremu hwepasi ( m _E ) = 5.97 x 10 ²⁴ kg

Huremu hwemwedzi (m _M ) = 7.35 x 10 ²² kg

Nhambwe iri pakati pepakati peNyika nepakati pemwedzi (r) = 3.84 x 10 ⁸ m

Chisingachinji chepasi rose (G) = 6.67 x 10 ^-11 N m ² / kg ²

Zvinodiwa: Hukuru hwesimba rinokwevera pasi (F)

Solution:

3. Chinhambwe chiri papi kubva kuNyika, hukuru hwesimba rinokwevera pasi renyika nemwedzi izero?

Zvinozivikanwa:

Huremu hwepasi = 5.97 x 10 ²⁴ kg

Huremu hwemwedzi = 7.35 x ¹⁰²² kg

Nhambwe iri pakati pepakati peNyika nepakati pemwedzi (r) = 3.84 x 10 ⁸ m.

Chisingachinji chepasi rose ( G) = 6.67 x 10 ^-11 N m ² / kg ²

Zvinodiwa: chinhambwe kubva kuPasi

Solution:

Simba regiravhiti remagetsi harisi zero.

Shandisa fomura yequadratic:

A = – 6.35

B = – 7.68 x 10 ⁸

C = 87.76 x 10 ^-14

 

[wpdm_package id='955′]

1. Mutemo waNewton wematambudziko esimba rinokwevera pasi rose uye mhinduro dzawo
2. Simba resimba rinokwevera pasi, matambudziko ekurema, uye mhinduro
3. Kukurumidza kunokonzerwa nematambudziko egiravhiti nemhinduro
4. Matambudziko eGeosynchronous satellite uye mhinduro dzawo
5. Matambudziko emutemo waKepler nematambudziko ekugadzirisa matambudziko nemhinduro

 

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