Mienzaniso yemibvunzo pamusoro pebasa nesimba

Mienzaniso gumi nematanhatu yeMibvunzo yeBasa neSimba

Theorem Simba reKinetic reBasa

1. Simba risingaperi re60 N rinoshanda kwemasekonzi gumi nemaviri pachinhu chine huremu hwe10 kg. Chinhu chacho

ine kumhanya kwekutanga kwe6 m/sec munzira imwecheteyo nesimba.

(1) Basa rakaitwa pachinhu ichi i30.240 joules

(2) Simba rekupedzisira rekinetic rechinhu ichi i30.240 joules.

(3) Simba rinogadzirwa i2.520 watts

(4) Kuwedzera kwesimba rekufamba kwechinhu ichi i180 joules.

Mhinduro chaiyo ndeyekuti…

A. 1, 2 na3

B. 1 ne3

C. 1 ne4

D. 4 chete

E. zvese zvakarurama

Kukurukurirana

Zvinozivikanwa kuti:

Simba (F) = 60 N

Nguva (t) = masekondi gumi nemaviri

Huremu hwechinhu (m) = 10 kg

Kumhanya kwekutanga (vo ₎ = 6 m/s

Mubvunzo: Ndechipi chirevo chakarurama?

Mhinduro:

Kukurumidzisa kwechinhu:

∑ F = ma

60 = 10 a

a = 60 / 10 = 6 m/s ²

Kumhanya kwekupedzisira:

v _t = vo ₊ pa

v _t = 6 + (6)(12)

v _t = 6 + 72

v _t = 78 m/s

Kufamba daro mumasekondi gumi nemaviri:

s = vot ₊ 1/2 pa ²

s = (6)(12) + 1/2 (6)(12) ²

s = 72 + (3)(144)

s = 72 + 432

s = mamita zana

(1) Basa raitwa

W = F s = (60)(504) = 30.240 Joules

(2) Simba rekupedzisira rekinetic rechinhu chacho

EK = 1/2 mv _t ² = 1/2 (10) (78) ² = (5) (6084) = 30.420 Joules

(3) Simba rinogadzirwa

P = W / t = 30.240 / 12 = 2.520 Joules/sekondi

(4) Kuwedzera kwesimba remagetsi

ΔEK = 1/2 mv _t ² – 1/2 mv _o ² = 1/2 m (v _t ² – v _o ² ) = 1/2 (10) (78 ² – 6 ² ) = 5 (6084 –36) = 5 (6048)

ΔEK = 30.240 Joules

Mhinduro chaiyo ndeiyi B.

2. Ruzivo pamusoro pekuchinja kwespeed yechinhu chinofamba mumutsara wakatwasuka rwunoratidzwa seizvi. Basa guru rinoitwa nenhamba yechinhu….

A. 1

B. 2

C. 3

D. 4

E. 5

Kukurukurirana

Dzidziso yesimba rekushanda-kinetic:

Basa rose = shanduko musimba rekinetic

Huwandu _hwese = ½ m (v _t ² – _vo ² )

Mabhizinesi makuru ndeaya:

W ₁ = ½ (8)(4 ² – 2 ² ) = (4)(16 – 4) = (4)(12) = 48 Joules

W ₂ = ½ (8)(5 ² –3 ² ) = (4)(25 – 9) = (4)(16) = 64 Joules

W ₃ = ½ (10)(6 ² – 5 ² ) = (5)(36 – 25) = (5)(11) = 55 Joules

W ₄ = ½ (10)(4 ² – 0 ² ) = (5)(16 – 0) = (5)(16) = 80 Joules

W ₅ = ½ (20)(3 ² – 3 ² ) = (10)(9 – 9) = (10)(0) = 0 Joules

Mhinduro chaiyo ndiD.

3. Odi ari kutyaira mota ine huremu hwe4000 kg mumugwagwa wakatwasuka nekumhanya kwe25 m/s. Achiona mota yakawandisa iri kure, anobhureki mota kuitira kuti kumhanya kwemotokari kudzikire nguva nenguva kusvika 15 m/s. Basa rinoitwa nechikwata chebhureki….

A. 200 kJ

B. 300 kJ

C. 400 kJ

D. 700 kJ

E. 800 kJ

Kukurukurirana

Zvinozivikanwa kuti :

Huremu hwemota (m) = 4000 kg

Kumhanya kwekutanga kwemotokari (vo ₎ = 25 m/s

Kumhanya kwekupedzisira kwemotokari (v _t ) = 15 m/s

Mubvunzo : Basa (W) pamotokari?

Mhinduro :

Dzidziso yesimba rekushanda-kinetic:

Huwandu _hwese = ½ m (v _t ² – vo ₂ ⁾ = ½(4000)(15 ² -25 ² ) = (2000)(225-625) = (2000)(-400) = -800.000 Majoules = -800 kilos Majoules.

Mhinduro chaiyo ndiE.

4. Bhora rine huremu hwe 0,1 kg rinokandwa rakatwasuka nekumhanya kwe 6 m/s kubva padenga rechivako chakareba mamita mashanu. Kana kukwira kwesimba nekuda kwegiravhiti panzvimbo iyoyo kuri 10 m/s ² , saka simba rekufamba kwebhora pakukwirira kwemamita maviri ndiro….

A. 6,8 J

B. 4,8 J

C. 3,8 J

D. 3 J

E. 2 J

Kukurukurirana

Zvinozivikanwa kuti :

Huremu (m) = 0,1 kg

Kuchinja kwehurefu (h) = 5 m – 2 m = 3 metres

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Mubvunzo : kinetic energy (EK) pakukwirira kwemamita maviri?

Mhinduro :

Nzira yebhora iri sezvakaratidzwa mumufananidzo uri pazasi.

Kufamba kweparabolic sezvakaratidzwa mumufananidzo uri pamusoro apa musanganiswa wemafambiro maviri anogona kuongororwa zvakasiyana, uko kufamba munzira yakatwasuka kuri muchimiro chekufamba kwakatwasuka kwakajairika uye kufamba munzira yakatwasuka kuri muchimiro chekufamba kwemahara kwekudonha.

Dambudziko iri rinogadziriswa uchishandisa mutemo wekuchengetedza simba remakanika, saka tinongofunga nezvekufamba kwakatwasuka muchimiro chekufamba kwemahara.

Chinhu chega chega chinofamba mukudonha kwakasununguka hachina kumhanya kwekutanga (v _o = 0) saka simba rekutanga rekufamba kwechinhu i zero (EK = ½ mv ² = 0). Kune rumwe rutivi, chinhu chinotanga kufamba kubva pakukwirira kwemamita mashanu pamusoro pevhu saka chinhu chine simba rekukwevera. Saka simba rekutanga remakeniki rebhora isimba rekukwevera. Bhora parinotanga kufamba pasi, simba rekukwevera rebhora rinoshanduka kuita simba rekukwevera. Simba rekukwevera rinoshanduka rinoita simba rekukwevera kana bhora richifamba kubva pakukwirira kwemamita mashanu pamusoro pevhu kuenda pakukwirira kwemamita maviri pamusoro pevhu ndeiri: EP = mgh = (0,1)(10)(3) = 3 Joules. Kana bhora riri pakukwirira kwemamita maviri pamusoro pevhu, simba rekukwevera rebhora i3 Joules.

Mhinduro chaiyo ndiD.

5. Mota ine huremu hwetani imwe inotanga kubva payakamira. Nguva pfupi yadarika, kumhanya kwayo kuri 5 m/s ^-1 . Huwandu hwebasa rinoitwa neinjini yemota...

A. 1000 Joule

B. 2.500 Joule

C. 5.000 Joule

D. 12.500 Joule

E. 25.000 Joules

Kukurukurirana

Zvinozivikanwa kuti :

Huremu (m) = tani imwe = 1000 kg

Kumhanya kwekutanga (vo _o ) = 0 (mota inotanga kubva pakuzorora)

Kumhanya kwekupedzisira (v _t ) = 5 m/s

Mubvunzo : Injini yemotokari inogadzira basa rakawanda sei (W)?

Mhinduro :

Dzidziso yesimba rekushanda-kinetic:

Huwandu _hwese = ½ m (v _t ² – _vo ² )

Basa rinoitwa neinjini yemotokari nderinotevera:

Huwandu _hwese = ½ (1000)(5 ² – 0 ² ) = (500)(25 – 0) = (500)(25) = 12.500 Joules

Mhinduro chaiyo ndiD.

6. Bhora rine huremu hwemagiramu mazana mashanu rinokandwa rakamira kumusoro kubva pasi nekumhanya kwekutanga kwe10 ms ^-2 . Kana g = 10 ms ^-2 , saka basa rinoitwa negiravhiti yebhora kana rasvika pakukwirira kwaro kwakanyanya...

A. 2,5 J

B. 5,0 J

C. 25 J

D. 50 J

E. 500 J

Kukurukurirana

Usafuratira kuramba kwemhepo.

Zvinozivikanwa kuti :

Huremu hwebhora (m) = magiramu mashanu = 0,5 kg

Kumhanya kwekutanga (v _o ) = 10 m/s ²

Kumhanya kwekupedzisira (v _t ) = 0. Pakukwirira kwakanyanya, chinhu chacho chinomira kwechinguva chisati chadzokera shure.

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Zvinodiwa : Basa (W) rinoitwa nehukuru hwebhora

Mhinduro :

Dzidziso yesimba rekushanda-kinetic :

Dzidziso yesimba rekushanda-kinetic inoti basa rose kana simba rinoitwa nesimba rinobuda pachinhu rakaenzana nekuchinja kwesimba rekufamba-famba rechinhu. Fomura yedzidziso yesimba rekushanda-kinetic ndeiyi:

W _zvachose = ΔEK = EK _t - EK _o

Huwandu _hwese = ½ mv _t ² – ½ mv _o ² = ½ m (v _t ² – _vo ² )

Information :

EK _t = simba rekupedzisira rekinetic, EK _o = simba rekutanga rekinetic, m = huremu hwechinhu, v _t = kumhanya kwekupedzisira kwechinhu, v _o = kumhanya kwekutanga kwechinhu.

Kushanda nesimba kwakazara :

Basa rinoitwa nehuremu hwebhora kubva panguva iyo bhora rakakandwa kusvika bhora rasvika pakukwirira kwaro nderiri:

Huwandu _hwese = ½ m (v _t ² – vo ₂ ⁾ = ½ (0,5)(0 ² – 10 ² )

Huwandu _{hwese hweW} = (0,25)(-100) = -25 Joules

Chiratidzo chekuramba chinoratidza kuti bhora rakananga kure kure kure kure kure kure kure kure kure. Kufamba kwebhora kwakananga kumusoro, ukuwo bhora rakananga kure kure kure kure kure kure kure kure kure kure. Simba rinokwevera pasi rinoita basa rekuramba richikwevera pasi, zvichireva kuti basa rinoitwa nesimba rinokwevera pasi rinowedzera simba rinokwevera pasi rebhora uye rinoderedza simba raro rekumhanya. Simba rinokwevera pasi rinoita basa rakanaka kana bhora rakananga kure kure kure kure kure kure kure kure kure (bhora richifamba richidzika).

Mhinduro chaiyo ndiC.

7. Bhora rine huremu hwe1 kg rinodonhedzwa pasina kumhanya kwekutanga kubva pamusoro pechivakwa kuburikidza nehwindo A riri pamusoro peimba kuenda kuhwindo B riri pasi rine musiyano wekukwirira kwe2,5 m (g = 10 ms ^-2 ). Basa rakawanda sei rinoitwa kufambisa bhora kubva pahwindo A kuenda kuhwindo B?

A. 5 Joule

B. 15 Joule

C. 20 Joule

D. 25 Joule

E. 50 Joules

Kukurukurirana

Zvinozivikanwa kuti :

Huremu hwebhora (m) = 1 kg

Kumhanya kwekutanga (vo ₎ = 0 m/s

Kureba (h) = mamita makumi maviri

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Mubvunzo : Kushanda nesimba panguva yekufamba kwebhora

Mhinduro :

Kumhanya kwekupedzisira kwebhora (v _t )

Bhora rinodonha pasina kumhanya kwekutanga, saka kufamba kwebhora kunenge kuri kudonha pasina kumhanya. Kutanga, verenga kumhanya kwekupedzisira kwebhora uchishandisa fomura yekudonha pasina kumhanya. Zvichienderana nekumhanya kunokonzerwa negiravhiti (g) = 10 m/s ² , shanduko mukukwirira kwebhora (h) = 2,5 metres, uye kumhanya kwekupedzisira (v _t ) kunobvunzwa, saka shandisa fomura v _t ² = 2 gh

v _t ² = 2 gh = 2(10)(2,5) = 2(25)

v _t = √2(25) = 5√2

Saka kumhanya kwekupedzisira kwebhora i5√2 m/s

Basa rose = shanduko musimba rekinetic

W _yose = ΔEK = ½ m (v _t ² – vo ₂ ⁾ = ½ (1){(5√2) ² – 0 ² }

Huwandu _hwese = ½ (25)(2) = 25 Joules

Mhinduro chaiyo ndiD.

8. Chinhu chine huremu hwe2 kg chinotanga kufamba nekumhanya kwe72 km/h ^-1 . Mushure mekufamba 400 m, kumhanya kwechinhu kunova 144 km/h ^-1 uye (g = 10 m/s ^-2 ). Basa rose rinoitwa nechinhu panguva iyoyo...

A. 20 J

B. 60 J

C. 1.200 J

D. 2.000 J

E. 2.400 J

Kukurukurirana

Zvinozivikanwa kuti :

Huremu hwechinhu (m) = 2 kg

Kumhanya kwekutanga (v _o ) = 72 km/h = 20 m/s

Kumhanya kwekupedzisira (v _t ) = 144 km/h = 40 m/s

Kureba (s) kwakafambwa = mamita mazana mana

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s ²

Akabvunzwa : Kuedza kwakazara

Mhinduro :

Basa rose = shanduko musimba rekinetic

W _yose = ΔEK = ½ m (v _t ² – vo ₂ ⁾ = ½ (2)(40 ² – 20 ² }

Huwandu _hwese = ½ (2)(1600 - 400) = 1200 Joules

Mhinduro chaiyo ndiC.

9. Chinhu chinorema 2 kg chinofamba panzvimbo yakatsetseka nekumhanya kwe2 m/s ^-1 . Kana majoules makumi maviri nerimwe ebasa akaitwa pachinhu chacho, kumhanya kwechinhu chacho kuchachinja kuita…

A. 1 ms ^–1

B. 2 ms ^–1

C. 3 ms ^–1

D. 5 ms ^–1

E. 17 ms ^–1

Kukurukurirana

Zvinozivikanwa kuti:

Huremu (m) = 2 kg

Kumhanya kwekutanga (vo ₎ = 2 m/s

Basa (W) = 21 Joules

Mubvunzo: Kumhanya kwekupedzisira (v _t )

Mhinduro:

Dzidziso yesimba rekushanda-kinetic inoti basa rose rinoitwa pachinhu rakaenzana nekuchinja kwesimba rekinetic rechinhu.

Huwandu = ΔEK

Huwandu = 1/2 mv _t ² -1/2 mv _o ²

Huwandu = 1/2 m (v _t ² – _vo ² )

21 = 1/2 (2) (v _t ² – 2 ² )

21 = (v _t ² – 2 ² )

21 = v _t ² – 4

v _t ² = 21 + 4 = 25

v _t = √25

v _t = 5 m/s

Mhinduro chaiyo ndiD.

10. Bhora rine huremu hwemagiramu mazana mashanu rinokandwa rakamira kumusoro kubva pasi nekumhanya kwekutanga kwe10 ms ^-2 . Kana g = 10 ms ^-2 , saka basa rinoitwa negiravhiti yebhora kana rasvika pakukwirira kwaro kwakanyanya...

A. 2,5 J
B. 5,0 J
C. 25 J
D. 50 J
E. 500 J

Kukurukurirana
Usafuratira kuramba kwemhepo.
Zvinozivikanwa :
Huremu hwebhora (m) = magiramu mashanu = 0,5 kg
Kumhanya kwekutanga (v)_o) = 10 m/s²
Kumhanya kwekupedzisira (v)_t) = 0. Kana yareba zvakanyanya, chinhu chacho chinomira kwechinguva chisati chadzokera shure.
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²
Akabvunzwa : Basa (W) rinoitwa nehukuru hwebhora
Jawab :

Dzidziso yesimba rekushanda-kinetic :
Iyo work-kinetic energy theorem inotaura kuti basa rese kana business Fomura yedzidziso yesimba rekushanda-kinetic resimba rinobuda pachinhu yakafanana nekuchinja kwesimba rekinetic rechinhu.
W_chizere = ΔEK = EK_t - EK_o
W_chizere = ½ mv_t² – ½ mv_o² = ½ m (v)_t² - v_o²)
Information :
EK_t = simba rekupedzisira rekinetic, EK_o = simba rekutanga rekinetic, m = huremu hwechinhu, v_t = speed kuguma kwechinhu, v_o = kumhanya kwekutanga kwechinhu.
Kuedza kwakazara :
Basa rinoitwa nehuremu hwebhora kubva panguva iyo bhora rakakandwa kusvika bhora rasvika pakukwirira kwaro nderiri:
W_chizere = ½ m (v)_t² - v_o²) = ½ (0,5)(0² - 10²)
W_chizere = (0,25)(-100) = -25 Joule
Chiratidzo chekuramba chinoratidza kuti bhora rakananga kure ... Simba regiravhiti Kuita basa rekusashanda zvakanaka pabhora zvinoreva kuti basa rinoitwa nesimba regiravhiti rinoita kuti simba regiravhiti rebhora riwedzere uye simba rebhora rekufamba naro riderere. Simba regiravhiti rinoita basa rakanaka kana gwara regiravhiti rebhora rakafanana negwara rekufamba naro kwebhora (bhora richidzika pasi).
Mhinduro chaiyo ndiC.

11. Bhora rine huremu hwe1 kg rinodonhedzwa pasina kumhanya kwekutanga kubva pamusoro pechivakwa kuburikidza nehwindo A riri pamusoro peimba kuenda kuhwindo B riri pasi rine musiyano wekukwirira kwe2,5 m (g = 10 ms ^-2 ). Basa rakawanda sei rinoitwa kufambisa bhora kubva pahwindo A kuenda kuhwindo B?

A. 5 Joule
B. 15 Joule
C. 20 Joule
D. 25 Joule
E. 50 Joules

Kukurukurirana
Zvinozivikanwa :
Huremu hwebhora (m) = 1 kg
Kumhanya kwekutanga (v)_o) = 0 m/s
Kureba (h) = mamita makumi maviri
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²
Akabvunzwa : Basa rose panguva yekufamba kwebhora
Jawab :
Kumhanya kwekupedzisira kwebhora (v)_t)
Bhora rinodonha pasina kumhanya kwekutanga, saka kufamba kwebhora kunoonekwa sekudonha kwakasununguka. Kutanga, verenga kumhanya kwekupedzisira kwebhora uchishandisa fomura kufamba kwemahara kwekudonhaZvinozivikanwa kuti kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s², kuchinja kwehurefu hwebhora (h) = mamita 2,5 uye kumhanya kwekupedzisira (v) kunobvunzwa_tsaka shandisa fomura v_t² = 2 gh
v_t² = 2 gh = 2(10)(2,5) = 2(25)
v_t = √2(25) = 5√2
Saka kumhanya kwekupedzisira kwebhora i5√2 m/s
Basa rose = shanduko musimba rekinetic
W_chizere = ΔEK = ½ m (v)_t² - v_o²) = ½ (1){(5√2)² - 0²}
W_chizere = ½ (25)(2) = 25 Joule
Mhinduro chaiyo ndiD.

12. Chinhu chine huremu hwe2 kg chinotanga kufamba nekumhanya kwe72 km/awa.^-1Mushure mekufamba 400 m, kumhanya kwechinhu chacho kunosvika 144 km/h.^-1 uye (g = 10 ms^-2). Basa rose rakaitwa nechinhu panguva iyoyo ndiro…
A. 20 J
B. 60 J
C. 1.200 J
D. 2.000 J
E. 2.400 J
Kukurukurirana
Zvinozivikanwa :
Huremu hwechinhu (m) = 2 kg
Kumhanya kwekutanga (v)_o) = 72 km/awa = 20 m/s
Kumhanya kwekupedzisira (v)_t) = 144 km/awa = 40 m/s
Kureba (s) kwakafambwa = mamita mazana mana
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²
Akabvunzwa : Kuedza kwakazara
Jawab :
Basa rose = shanduko musimba rekinetic
W_chizere = ΔEK = ½ m (v)_t² - v_o²) = ½ (2)(40² - 20²}
W_chizere = ½ (2)(1600 - 400) = 1200 Joules
Mhinduro chaiyo ndiC.

Dzidziso yesimba rekushanda-kinetic

13. Mota ine huremu hwetani imwe inotanga kubva payakagara. Nguva pfupi inotevera kumhanya kwayo i5 m/s ^-1 . Huwandu hwebasa rinoitwa neinjini yemota...

A. 1000 Joule
B. 2.500 Joule
C. 5.000 Joule
D. 12.500 Joule
E. 25.000 Joules

Kukurukurirana

Zvinozivikanwa :
Huremu (m) = tani imwe = 1000 kg
Kumhanya kwekutanga (v)_o) = 0 (mota inofamba kubva panzvimbo isina kumira)
Kumhanya kwekupedzisira (v)_t) = 5 m/s
Akabvunzwa : Ndeipi basa (W) rinoitwa neinjini yemotokari?
Jawab :

Dzidziso yesimba rekushanda-kinetic:
W_chizere = ½ m (v)_t² - v_o²)
Basa rinoitwa neinjini yemotokari nderinotevera:
W_chizere = ½ (1000)(5² - 0²) = (500)(25 – 0) = (500)(25) = 12.500 Joules
Mhinduro chaiyo ndiD.

Dzidziso yeMashandiro eMuchina-Simba

14. Tarisa mufananidzo wekufamba kwezvinhu zviri pazasi!

Huremu hwechinhu = 1 kg. Kana coefficient ye kinetic friction pakati peblock nefloor iri 0,2, saka kukosha kwe displacement (s) yechinhu i… g = 10 m/s^2\

A. 10 m
B. 15 m
C. 20 m
D. 25 m
E. 30 m
Kukurukurirana:
Zvinozivikanwa :
m = 1 kg, g = 10 m/s²mu_o = 10 m/s, v_t = 0
Akabvunzwa :
Chii chinonzi kuchinjika kwechinhu (zvinhu)?
Jawab :
Basa - dzidziso yesimba remakanika :
Basa rinoitwa nesimba risingachinji = shanduko musimba remagetsi rechinhu.
W_NC = EM₂ - EM₁
W_NC = (EP + EK)₂ – (EP + EK)₁ —- Equation 1
Simba risingachengetedzi rinoita basa pachinhu ndiro simba rekinetic friction:
W_NC = f_k s —- Equation 2
Fomura yekukweshana kweKinetic :

Tsiva f_k muequation 2 na f_k muchikamu chechitatu:
W_NC = f_k s = 2 p
Paunenge uchifamba, chinhu chinosangana nekuchinja kwesimba remagetsi (simba remagetsi rinodzikira) nepo simba remagetsi rinokwevera chinhu risingachinji (kuchinja kwesimba remagetsi rinokwevera chinhu izero).
W_NC = (EK)₂ – (EK)₁ = ½ mv_t² – ½ mv_o² = ½ m (v)_t² - v_o²)
2 s = ½(1)(0² - 10²)
2 s = (0,5)(100)
masekondi makumi maviri = makumi mashanu
s = 50 / 2 = mamita makumi maviri nemashanu
Mhinduro chaiyo ndiD.

Mutemo wekuchengetedza simba remakanika

15. Mutambi anotsvedza muchando achibva pakakwirira A sezvakaratidzwa mumufananidzo unotevera:
Kana kumhanya kwekutanga kwemutambi weskier = zero uye kukurumidza nekuda kwegiravhiti kuri 10 ms^-2, ipapo kumhanya kwemutambi pakukwirira B ndiko...

A. √2 ms^-1
B. 5√2 ms^-1
C. 10√2 ms^-1
D. 20√2 ms^-1
E. 25√2 ms^-1

Kukurukurirana
Zvinozivikanwa :
Kumhanya kwekutanga (v)_o= = 0
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²
Kuchinja kwekukwirira = mamita makumi mashanu - mamita gumi = mamita makumi mana
Akabvunzwa : kumhanya kwemutambi pakukwirira B?
Jawab :
Mutemo wekuchengetedza simba remakanika Inotaura izvozvo simba rekutanga remakanika = simba rekupedzisira remakanika.
Kana munhu achitanga kufamba kubva panzvimbo A, kumhanya kwekutanga kwemutsvigiri = v_o = 0 kuitira kuti simba rekutanga rekinetic = EK_o = ½ mv_o² = 0. Kusiyana neizvi, kana paA, muskier ane simba rekutanga rekukwevera pasi = EP_o = mgh, apo h = mamita makumi mashanu. Saka simba rekutanga remakanika (EM)_o) = simba rekutanga rekukwevera pasi (EP)_o). Pakufamba kubva paA kuenda kuB, kukwirira kwemutsvi wepasi kunoderera, saka simba regiravhiti rinoderera. Simba regiravhiti harirasike asi rinoshandurwa kuita simba rekinetic. Kuwedzera kwesimba rekinetic kunoratidzwa nekuwedzera kwekumhanya kwemutsvi wepasi. Kana mutsvi wepasi akasvika pasi pekutsvedza, simba rese regiravhiti rinoshandurwa kuita simba rekinetic. Pasi pekutsvedza, simba regiravhiti rinova zero, nepo simba rekinetic riri pahuwandu hwaro. Saka simba rekupedzisira remakanika (EM) ndiro_t) = simba rekupedzisira rekinetic (EK)_t).

Zvakadini nesimba regiravhiti uye simba rekinetic panzvimbo B? Panzvimbo B, rimwe resimba regiravhiti rinoderedzwa uye rinoshandurwa kuita simba rekinetic. Kunyanya, simba rekinetic panzvimbo B = kuderedzwa kwesimba regiravhiti kana chinhu chikafungidzirwa kuti chiri kudonha zvakasununguka kubva pakukwirira kwemamita makumi mana. Sei usingashandise kureba kwenzira yakatsveyama asi kureba kwemamita makumi mana? Kana usinganzwisise izvi, unofanirwa kudzidza zvinyorwa pamusoro pemasimba anochengetedza uye hukama hwawo nesimba rinokwanisa uye mutemo wekuchengetedza simba remakanika.

Kumhanya kwemuskier pakukwirira B:
Simba rekupedzisira remakanika = simba rekutanga remakanika
Simba reKinetic panzvimbo B = simba rekukwevera pasi pakakwirira kwemamita makumi mana
EK = EP
½ mv_t² = mgh
½ v_t² = gh
½ v_t² = (10)(50-10)
½ v_t² = (10)(40)
½ v_t² = 400
v_t² = (2)(400) = 800
v_t = √800 = √(2)(400) = 20√2 m/s
Mhinduro chaiyo ndiD.

16. Chinhu chinofamba kubva panzvimbo A pasina kumhanya kwekutanga. Kana pasina kukweshana panguva yekufamba, kumhanya kwechinhu panzvimbo yakaderera ndiko...
A. 8 ms^-1
B. 12 ms^-1
C. 20 ms^-1
D. 24 ms^-1
E. 30 ms^-1
Kukurukurirana
Zvinozivikanwa :
Huremu hwechinhu = m
Kumhanya kwekutanga (v)_o= = 0
Kureba (h) = mamita makumi maviri
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s²
Akabvunzwa : kumhanya kwekupedzisira (v)_t)?
Jawab :
Simba rekutanga remakanika (EM)₁) = simba rekukwevera pasi paA (EP)_A) = mgh = (m)(10)(20) = 200 m
Simba remagetsi rekupedzisira (EM)₂) = simba rekinetic (EK) = ½ mv_t²
Kumhanya kwechinhu panzvimbo yakaderera kana kumhanya kwekupedzisira kwechinhu v_t)?
Mutemo wekuchengetedza simba remakanika:
EM₁ = EM₂
200 m = ½ mv_t²
200 = ½ v_t²
400 = v_t²
v_t= 20 m/s
Mhinduro chaiyo ndiC.

 

Kwakabva mubvunzo:

Mibvunzo yeNational Examination Physics yeChikoro Chesekondari/Chikoro Chepamusoro Chebasa