Imibuzo Yesibonelo Samandla e-Coulomb

Izibonelo ezingu-9 zemibuzo ye-Coulomb Force

1. Imithwalo emithathu ihlelwe njengoba kuboniswe esithombeni esingezansi. Amandla e-Coulomb atholakala ngokushaja u-B angu …. (k = 9 x 109 Nm2C-2, 1 μC = 10-6 C)
Isibonelo se-Coulomb Force Umbuzo 1

A. 09 x 10 1 N ukushaja C

B. 09 x 10 1 N ukushaja u- A

C. 18 x 10 1 N ukushaja C

D. 18 x 10 1 N ukushaja u-A

E. 36 x 10 1 N ukushaja C

Ingxoxo

Kuyaziwa ukuthi :

q A = 10 µC = 10 x 10 -6 C = 10 -5 Ama-Coulomb

q B = 10 µC = 10 x 10 -6 = 10 -5 Ama-Coulomb

q C = 20 µC = 20 x 10 -6 = 2 x 10 -5 Ama-Coulomb

r AB = amamitha angu-0,1 = amamitha angu -10 -1

r BC = amamitha angu-0,1 = amamitha angu -10 -1

k = 9 x 10 9 Nm 2 C −2

Kubuziwe : Ibutho laseCoulomb elibhekene necala B

Impendulo :

Kunezinhlobo ezimbili zamandla kagesi e-Coulomb noma amandla kagesi asebenza ngokushaja u-B, okungukuthi amandla e-Coulomb aphakathi kwamacala u-A no-B (F AB ) kanye namandla e-Coulomb aphakathi kwamacala u-B no-C (F BC ). Amandla e-Coulomb atholakala ngokushaja u-B abangelwa yi-F AB kanye ne-F BC.

Amandla e-Coulomb phakathi kwezindleko A no-B:

Isibonelo se-Coulomb Force Umbuzo 2

Ishaja A ilungile kanti ishaja B ilungile ukuze i-F AB iye kushaja C.

Amandla e-Coulomb phakathi kwamacala B no-C:

Isibonelo se-Coulomb Force Umbuzo 3

Ishaja B ilungile kanti ishaja C ilungile ukuze i-F BC iye kushaja A.

Amandla e-Coulomb atholakala ngokushaja B:

F B = F BC – F AB = 180-90 = 90 N

Ubukhulu bamandla e-Coulomb atholakala ngeshaja B (F B ) bungama-Newton angu-90. Isiqondiso se-F B sifana nesiqondiso se-F BC , okungukuthi sibheke ngeshaja A.

Impendulo efanele ingu-B.

2. Ubukhulu kanye nesiqondiso samandla e-Coulomb ashaja u-B... ( k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)

Isibonelo se-Coulomb Force Umbuzo 4

A. 2,5 k Q 2 r -2 ngakwesobunxele

B. 2,5 k Q 2 r -2 ngakwesokudla

C. 2 k Q 2 r -2 ngakwesobunxele

D. 2 k Q 2 r -2 ngakwesokudla

E. 1 k Q 2 r -2 ngakwesobunxele

Ingxoxo

Kuyaziwa ukuthi :

Ishaja A (q A ) = +Q

Ishaja B (q B ) = -2Q

Ishaja C (q C ) = -Q

Ibanga phakathi kwezindleko A kanye no-B (r AB ) = r

Ibanga phakathi kwezindleko B kanye no-C (r BC ) = 2r

k = 9 x 10 9 Nm 2 C −2

Kubuziwe : ubukhulu kanye nesiqondiso sebutho laseCoulomb eliphethe u-B

Impendulo :

Amandla e-Coulomb phakathi kweshaja A kanye neshaja B:

Isibonelo se-Coulomb Force Umbuzo 5

Ishaja A ilungile kanti ishaja B imbi ukuze isiqondiso se-F AB sibheke eshaja A

Amandla e-Coulomb phakathi kweshaja B kanye neshaja C:

Isibonelo se-Coulomb Force Umbuzo 6

Ishaja B i-negative kanti ishaja C i-negative ngakho-ke isiqondiso se-F BC sibheke kushaja A

Amandla aphumelayo asebenza enkantolo B:

F = F AB + F BC = 2 k Q 2 /r 2 + 0,5 k Q 2 /r 2 = 2,5 k Q 2 /r 2 = 2,5 k Q 2 r -2

Isiqondiso samandla e-Coulomb sibheke eshajeni A noma ngakwesobunxele.

Impendulo efanele ngu-A.

3. Amashaji amabili kagesi abekwe ngokwehlukana njengoba kuboniswe esithombeni. Ishaja ku-A ingu-8 µC kanti amandla akhangayo asebenza kuzo zombili ishaja angu-45 N. Uma ishaja u-A ishintshelwa ngakwesokudla ngo-1 cm kanye no-k = 9.10 9 Nm 2 .C -2 , khona-ke amandla akhangayo asebenza kuzo zombili ishaja…

A. 45 NIsibonelo se-Coulomb Force Umbuzo 7

B. 60 N

C. 80 N

D. 90 N

E. 120 N

Ingxoxo

Kuyaziwa ukuthi :

Ishaja kagesi ku-A (q A ) = 8 µC = 8 x 10 -6 Ama-Coulomb

Amandla kagesi phakathi kwamacala amabili (F) = 45 Newton

Ibanga phakathi kwamacala amabili (r AB ) = 4 cm = 0,04 amamitha = 4 x 10 -2 amamitha

Okungaguquki (k) = 9 x 10 9 Nm 2 .C -2

Umbuzo : Amandla kagesi phakathi kwamacala amabili uma ishaja u-A idluliselwa ngakwesokudla ngo-1 cm noma amamitha angu-0,01

Impendulo :

Okokuqala bala ishaja kagesi ku-B, bese ubala amandla kagesi phakathi kwamacala amabili kagesi, uma ishaja kagesi ku-A ishintshelwa kwesokudla ngo-1 cm.

Ukushaja kukagesi ku-B :

Ifomula Umthetho kaCoulomb :

F = k (q A )(q B ) / r 2

Fr r 2 = k (q A )(q B )

q B = F r 2 / k (q A )

Ukushaja kukagesi ku-B :

q B = (45)(4 x 10 -2 ) 2 / (9 x 10 9 )(8 x 10 -6 )

q B = (45)(16 x 10 -4 ) / 72 x 10 3

q B = (720 x 10 -4 ) / (72 x 10 3 )

q B = 10 x 10 -7 Ama-Coulomb

Amandla kagesi phakathi kwamacala kagesi u-A no-B :

Uma ukushaja ku-A kushintshwa ngakwesokudla ngo-1 cm, ibanga eliphakathi kwala mashaja amabili liba ngu-3 cm = 0,03 amamitha = 3 x 10 -2 amamitha

F = k (q A )(q B ) / r 2

F = (9 x 10 9 )(8 x 10 -6 )(10 x 10 -7 ) / (3 x 10 -2 ) 2

F = (9 x 10 9 )(80 x 10 -13 ) / (9 x 10 -4 )

F = (1 x 10 9 )(80 x 10 -13 ) / (1 x 10 -4 )

F = (80 x 10 -4 ) / (1 x 10 -4 )

F = 80 Newton

Impendulo efanele ngu-C.

4. Amashaja kagesi amabili u-P no-Q aqhelelene ngamasentimitha ayi-10 athola amandla akhangayo angu-8 N. Uma ishaja u-Q ishintshwa ngamasentimitha ayi-5 iye kushaja u-P (1 µC = 10 -6 C kanye no-k = 9 x 10 9 Nm 2 .C -2 ), khona-ke amandla kagesi akhona...

A. 8 NIsibonelo se-Coulomb Force Umbuzo 8

B. 16 N

C. 32 N

D. 40 N

E. 56 N

Ingxoxo

Kuyaziwa ukuthi :

Ibanga phakathi kwezindleko P kanye no-Q (r PQ ) = 10 cm = 0,1 m = 1 x 10 -1 m

Amandla kagesi phakathi kwamacala P kanye no-Q (F) = 8 N

Ishaja kagesi Q (q Q ) = 40 µC = 40 x 10 -6 C

Okungaguquki (k) = 9 x 10 9 Nm 2 .C -2

Umbuzo : Amandla kagesi phakathi kwamashaja u-P no-Q uma ishaja u-Q ishintshelwa ku-5 cm iye kushaja u-P

Impendulo :

Okokuqala bala ishaja kagesi P, bese ubala amandla kagesi phakathi kwamacala amabili kagesi, uma ishaja kagesi Q ishintshelwe ku-5 cm iye kushaja P.

Ishaja kagesi P :

q P = F r 2 / k (q Q )

q P = (8)(1 x 10 -1 ) 2 / (9 x 10 9 )(40 x 10 -6 )

q P = (8)(1 x 10 -2 ) / 360 x 10 3

q P = (8 x 10 -2 ) / (36 x 10 4 )

q P = (1 x 10 -2 ) / (4,5 x 10 4 )

q P = (1/4,5) x 10 -6 Coulomb

Amandla kagesi phakathi kwamacala kagesi u-P no-Q :

Uma ukushaja ku-Q kushintshelwa kwesobunxele ngo-5 cm, ibanga eliphakathi kwala mashaja amabili liba ngu-5 cm = 0,05 amamitha = 5 x 10 -2 amamitha

F = k (q P )(q Q ) / r 2

F = (9 x 10 9 )((1/4,5) x 10 -6 )(40 x 10 -6 ) / (5 x 10 -2 ) 2

F = (2 x 10 3 )(40 x 10 -6 ) / (25 x 10 -4 )

F = (80 x 10 -3 ) / (25 x 10 -4 )

F = 3,2 x 10 1

F = 32 Newton

Impendulo efanele ngu-C.

5. Bheka isithombe esilandelayo samacala kagesi. Amandla kagesi atholakala ngokushaja u-q B angama-8 N (1 µC = 10 -6 C) kanye (k = 9.10 9 Nm 2 .C -2 ). Uma ukushaja u-q B kushintshelwa ku-4 cm ukusuka ku-A, khona-ke amandla kagesi atholakala ku-q B manje…

A. 2 NIsibonelo se-Coulomb Force Umbuzo 9

B. 4 N

C. 6 N

D. 8 N

E. 10 N

Ingxoxo

Kuyaziwa ukuthi :

Ibanga phakathi kwezindleko A kanye no-B (r AB ) = 2 cm = 0,02 m = 2 x 10 -2 m

Amandla kagesi phakathi kwamacala u-A no-B (F) = 8 N

Ishaja kagesi A (q A ) = 2 µC = 2 x 10 -6 C

Okungaguquki (k) = 9 x 10 9 Nm 2 .C -2

Umbuzo : Amandla kagesi phakathi kwamashaji A no-B uma ibanga phakathi kwamashaji amabili lingu-4 cm

Impendulo :

Okokuqala bala ishaja kagesi B, bese ubala amandla kagesi phakathi kwamacala amabili kagesi uma ibanga phakathi kwamacala amabili kagesi lingu-4 cm = 0,04 amamitha = 4 x 10 -2 amamitha.

Ishaja kagesi B :

q B = F r 2 / k (q A )

q B = (8)(2 x 10 -2 ) 2 / (9 x 10 9 )(2 x 10 -6 )

q B = (8)(4 x 10 -4 ) / (18 x 10 3 )

q B = (32 x 10 -4 ) / (18 x 10 3 )

q B = (32/18) x 10 -7

q B = (16/9) x 10 -7 Ama-Coulomb

Amandla kagesi phakathi kwezindleko A no-B :

F = k (q A )(q B ) / r 2

F = (9 x 10 9 )(2 x 10 -6 )((16/9) x 10 -7 ) / (4 x 10 -2 ) 2

F = (18 x 10 3 )((16/9) x 10 -7 ) / (16 x 10 -4 )

F = (2 x 10 3 )(16 x 10 -7 ) / (16 x 10 -4 )

F = (2 x 10 3 )(1 x 10 -7 ) / (1 x 10 -4 )

F = (2 x 10 -4 ) / (1 x 10 -4 )

F = 2 Newton

Impendulo efanele ngu-A.

6. Amashaja kagesi amathathu abekwe ekhoneni likanxantathu i-ABC enobude obuseceleni i-AB = BC = 20 cm kanye nobukhulu beshaja obufanayo (q = 2µC) njengasesithombeni ohlangothini (k = 9.10 9 Nm 2 .C -2 , 1 µ = 10 -6 ). Ubukhulu bamandla kagesi asebenza endaweni B bungu….

A. 0,9√3 NIsibonelo se-Coulomb Force Umbuzo 10

B. 0,9√2 N

C. 0,9 N

D. 0,81 N

E. 0,4 N

Ingxoxo

Kuyaziwa ukuthi:

Ukushaja endaweni A (q A ) = 2 µC = 2 x 10 -6 Coulomb

Ukushaja endaweni B (q B ) = 2 µC = 2 x 10 -6 Coulomb

Shaja endaweni C (q C ) = 2 µC = 2 x 10 -6 Coulomb

Ibanga B kuya ku-C (r BC ) = 20 cm = 0,2 amamitha = 2 x 10 -1 amamitha

Ibanga B kuya ku-A (r BA ) = 20 cm = 0,2 amamitha = 2 x 10 -1 amamitha

k = 9.10 9 Nm 2 .C -2

Umbuzo: Ubukhulu bamandla kagesi asebenza endaweni B

Impendulo:

Amandla kagesi phakathi kwamacala kumaphuzu B no-C:

F BC = k (q B )(q C ) / r BC 2

F BC = (9 x 10 9 )(2 x 10 -6 )(2 x 10 -6 ) / (2 x 10 -1 ) 2

F BC = (9 x 10 9 )(4 x 10 -12 ) / (4 x 10 -2 )

F BC = (36 x 10 -3 ) / (4 x 10 -2 )

F BC = 9 x 10 -1

F BC = 0,9 Newton

Ishaja kagesi kumaphuzu B no-C inhle, ngakho-ke isiqondiso samandla kagesi i-F BC singakwesobunxele, kude nephuzu C.

Amandla kagesi phakathi kwamacala kumaphuzu B no-A:

F BA = k (q B )(q A ) / r BA 2

I-F BA = (9 x 10 9 )(2 x 10 -6 )(2 x 10 -6 ) / (2 x 10 -1 ) 2

I-F BA = (9 x 10 9 )(4 x 10 -12 ) / (4 x 10 -2 )

I-F BA = (36 x 10 -3 ) / (4 x 10 -2 )

I-F BA = 9 x 10 -1

F BA = 0,9 Newton

Ukushaja kukagesi kumaphuzu B no-A kuhle, ngakho-ke isiqondiso samandla kagesi i-F BA siphansi, kude nephuzu A.

Amandla kagesi amabili akha i-engeli efanele, ngakho-ke amandla kagesi aphumayo asebenza endaweni B abalwa kusetshenziswa ifomula yePythagorean.

Isibonelo se-Coulomb Force Umbuzo 11

Impendulo efanele ingu-B.

7. Bheka isithombe esilandelayo!

Amashaja amathathu Q 1 , Q 2 , kanye no-Q 3 abekwe eziqongweni zonxantathu ongakwesokudla i-ABC. Ubude be-AB = BC = 30 cm. Uma unikezwe u-k = 9.10 9 Nm 2 .C -2 kanye no-1 µ = 10 -6 khona-ke amandla e-Coulomb aphumayo kushaja Q 1 angu….

A. 1 NIsibonelo se-Coulomb Force Umbuzo 12

B. 5 N

C. 7 N

D. 10 N

E. 12 N

Ingxoxo

Kuyaziwa ukuthi:

Ukushaja endaweni A (q A ) = 3 µC = 3 x 10 -6 Coulomb

Ukushaja endaweni B (q B ) = -10 µC = -10 x 10 -6 Coulomb

Shaja endaweni C (q C ) = 4 µC = 4 x 10 -6 Coulomb

Ibanga B kuya ku-C (r BC ) = 30 cm = 0,3 amamitha = 3 x 10 -1 amamitha

Ibanga B kuya ku-A (r BA ) = 30 cm = 0,3 amamitha = 3 x 10 -1 amamitha

k = 9.10 9 Nm 2 .C -2

Umbuzo: Amandla e-Coulomb aphumela endaweni B

Impendulo:

Amandla kagesi phakathi kwamacala kumaphuzu B no-C:

F BC = k (q B )(q C ) / r BC 2

F BC = (9 x 10 9 )(10 x 10 -6 )(4 x 10 -6 ) / (3 x 10 -1 ) 2

F BC = (9 x 10 9 )(40 x 10 -12 ) / (9 x 10 -2 )

F BC = (360 x 10 -3 ) / (9 x 10 -2 )

F BC = 40 x 10 -1

F BC = 4 Newton

Ishaja kagesi ephuzwini B ayilungile kanti ishaja kagesi ephuzwini C iyilungile, ngakho-ke isiqondiso samandla kagesi i-F BC singakwesokudla ngasephuzwini C.

Amandla kagesi phakathi kwamacala kumaphuzu B no-A:

F BA = k (q B )(q A ) / r BA 2

I-F BA = (9 x 10 9 )(10 x 10 -6 )(3 x 10 -6 ) / (3 x 10 -1 ) 2

I-F BA = (9 x 10 9 )(30 x 10 -12 ) / (9 x 10 -2 )

I-F BA = (270 x 10 -3 ) / (9 x 10 -2 )

I-F BA = 30 x 10 -1

F BA = 3 Newton

Ishaja kagesi ephuzwini B ayilungile kanti ishaja kagesi ephuzwini A iyilungile, ngakho-ke isiqondiso samandla kagesi i-F BA siphezulu sibheke ephuzwini A.

Amandla kagesi amabili akha i-engeli efanele, ngakho-ke amandla kagesi aphumayo asebenza endaweni B abalwa kusetshenziswa ifomula yePythagorean.

Isibonelo se-Coulomb Force Umbuzo 13

Impendulo efanele ingu-B.

8. Amashaja amathathu kagesi abekwe ekhoneni likanxantathu i-ABC enobude obuseceleni i-AB = BC = 20 cm kanye nosayizi ofanayo weshaja (q = 2µC) njengasesithombeni ohlangothini (k = 9.109 I-Nm2.C-2, 1 µ = 10-6). Ubukhulu bamandla kagesi Isibonelo se-Coulomb Force Umbuzo 14ukusebenza endaweni B kuyinto….

  1. 0,9√3 N
  2. 0,9√2 N
  3. I-0,9 N
  4. I-0,81 N
  5. I-0,4 N

Ingxoxo

Kuyaziwa ukuthi:
Inkokhelo endaweni A (q)A) = 2 µC = 2 x 10-6 I-Coulomb
Inkokhelo endaweni B (q)B) = 2 µC = 2 x 10-6 I-Coulomb
Inkokhelo endaweni C (q)C) = 2 µC = 2 x 10-6 I-Coulomb
Ibanga ukusuka ku-B kuya ku-C (r)BC) = 20 cm = 0,2 amamitha = 2 x 10-1 imitha
Ibanga ukusuka ku-B kuya ku-A (r)BA) = 20 cm = 0,2 amamitha = 2 x 10-1 imitha
k =9.109 I-Nm2.C-2
Kubuziwe: Ubukhulu bamandla kagesi asebenza endaweni B
Impendulo:

Amandla kagesi phakathi kwamacala kumaphuzu B no-C:
FBC = k (qB)(qC) /rBC2
FBC = (9 x 109)(2 x 10-6)(2 x 10-6) / (2 x 10-1)2
FBC = (9 x 109)(4 x 10-12) / (4 x 10-2)
FBC = (36 x 10-3) / (4 x 10-2)
FBC = 9 x10-1
FBC = 0,9 uNewton
Ukushaja kukagesi kumaphuzu B no-C kuhle, ngakho-ke isiqondiso samandla kagesi u-F siwukuthiBC ngakwesobunxele, kude nephuzu C.

Amandla kagesi phakathi kwamacala kumaphuzu B no-A:
FBA = k (qB)(qA) /rBA2
FBA = (9 x 109)(2 x 10-6)(2 x 10-6) / (2 x 10-1)2
FBA = (9 x 109)(4 x 10-12) / (4 x 10-2)
FBA = (36 x 10-3) / (4 x 10-2)
FBA = 9 x10-1
FBA = 0,9 uNewton
Ukushaja kukagesi kumaphuzu B no-A kuhle, ngakho-ke isiqondiso samandla kagesi u-F siwukuthiBA phansi, kude nephuzu A.

Amandla kagesi amabili akha i-engeli efanele, ngakho-ke amandla kagesi aphumayo asebenza endaweni B abalwa kusetshenziswa ifomula yePythagorean.
Isibonelo se-Coulomb Force Umbuzo 15Impendulo efanele ingu-B.

9. Bheka isithombe esilandelayo!
Izindleko ezintathu Q1,Q2, kanye no-Q3 isemaphethelweni kanxantathu wesokudla i-ABC. Ubude buka-AB = BC = 30 cm. Kuyaziwa ukuthi Isibonelo se-Coulomb Force Umbuzo 16k =9.109 I-Nm2.C-2 kanye no-1 µ = 10-6 bese kuba yibutho likaCoulomb eliphethe u-Q1 kuyinto….

  1. I-1 N
  2. I-5 N
  3. I-7 N
  4. I-10 N
  5. I-12 N

Ingxoxo
Kuyaziwa ukuthi:
Inkokhelo endaweni A (q)A) = 3 µC = 3 x 10-6 I-Coulomb
Inkokhelo endaweni B (q)B) = -10 µC = -10 x 10-6 I-Coulomb
Inkokhelo endaweni C (q)C) = 4 µC = 4 x 10-6 I-Coulomb
Ibanga ukusuka ku-B kuya ku-C (r)BC) = 30 cm = 0,3 amamitha = 3 x 10-1 imitha
Ibanga ukusuka ku-B kuya ku-A (r)BA) = 30 cm = 0,3 amamitha = 3 x 10-1 imitha
k =9.109 I-Nm2.C-2
Kubuziwe: Amandla e-Coulomb aphumela endaweni B
Impendulo:
Amandla kagesi phakathi kwamacala kumaphuzu B no-C:
FBC = k (qB)(qC) /rBC2
FBC = (9 x 109)(10 x 10-6)(4 x 10-6) / (3 x 10-1)2
FBC = (9 x 109)(40 x 10-12) / (9 x 10-2)
FBC = (360 x 10-3) / (9 x 10-2)
FBC = 40 x10-1
FBC = 4 uNewton
Ishaja kagesi endaweni B ayilungile kanti ishaja kagesi endaweni C iyilungile, ngakho-ke isiqondiso samandla kagesi F siyiBC ngakwesokudla ngasephuzwini C.

Amandla kagesi phakathi kwamacala kumaphuzu B no-A:
FBA = k (qB)(qA) /rBA2
FBA = (9 x 109)(10 x 10-6)(3 x 10-6) / (3 x 10-1)2
FBA = (9 x 109)(30 x 10-12) / (9 x 10-2)
FBA = (270 x 10-3) / (9 x 10-2)
FBA = 30 x10-1
FBA = 3 uNewton
Ishaja kagesi endaweni B ayilungile kanti ishaja kagesi endaweni A iyinhle, ngakho-ke isiqondiso samandla kagesi F siyiBA kuze kufike ephuzwini A.
 
Amandla kagesi amabili akha i-engeli efanele, ngakho-ke amandla kagesi aphumayo asebenza endaweni B abalwa kusetshenziswa ifomula yePythagorean.
Isibonelo se-Coulomb Force Umbuzo 18Impendulo efanele ingu-B.

Umthombo wombuzo:

Imibuzo Yefiziksi Yezivivinyo Zikazwelonke Zesikole Samabanga Aphezulu/Isikole Samabanga Aphezulu Sokufundela Umsebenzi

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