Te nekehanga i runga i te papa angiangi me te kaha waku – te whakamahinga o ngā raruraru me ngā otinga o te ture nekehanga a Newton

1. Ngā Mea papatipu = 2 kirokaramu, te whakaterenga nā te kaha ā-papa = 9.8m/s², tauwehenga o te waku pumau = 0.2, te tauwehenga o te waku nekeneke = 0.1. Kei te okioki te mea, kei te whakateretere rānei? Mena kei te whakatereterehia te mea, kimihia (a) te kaha kupenga (b) te rahi me te ahunga o te pouaka whakatere!

otinga

Mōhiotia:

Taumaha (m) = 2 kg

Te whakaterenga nā te kaha ā-papa (g) = 9.8 m/s²

Te tauwehenga o te waku pateko (μ_s) = 0.2

Te tauwehenga o te waku nekeneke (μ_k) = 0.1

Taumaha (w) = mg = (2)(9.8) = 19.6 Niutona

Ko te wāhanga whakapae o te taimaha (w_x) = w sin 30^o = (19.6)(0.5) = 9.8 Ngā Newton

Ko te wāhanga poutū o te taumaha (w_y) = w cos 30^o = (19.6)(0.5√3) = 9.8√3 Ngā Newton

Te kaha noa (N) = w_y = 9.8√3 Nūtene

Te kaha o te waku pumau (f_s) = (0.2)(9.8√3) = 1.96√3 Ngā Newton = 3.39 Ngā Newton

Te kaha o te waku nekeneke (f_k) = (0.1)(9.8√3) = 0.98√3 Ngā Newton = 1.69 Ngā Newton

Rongoā:

Kei te okioki te mea mēnā w_x < f_s, kei te neke te mea ki raro mēnā w_x > wh_s.

w_x = 9.8 Newton me te f_s = 3.39 Ngā Newtoni.

(a) te kaha kupenga

∑F = w_x - f_k = 9.8 – 1.69 = 8.11 Nītona

(b) te rahi me te ahunga o te whakaterenga

∑F = ma

8.11 = (2) he

ki = 4.05

Te rahi o te whakaterenga = 4.05 m/s² ā, ko te ahunga o te whakaterenga = ki raro.

2. Papatipu o te mea = 4 kg, whakaterenga nā te kaha ā-papatipu = 9,8 m/s². Ko te tauwehenga o te waku nekeneke = 0.2 me te tauwehenga o te waku pūmau = 0.4. Te rahi o te kaha F = 40 Newtons. Kei te okioki te mea, kei te paheke rānei ki raro? Mena ka paheke te mea, kimihia (a) te kaha kupenga (b) te rahi me te ahunga o te whakaterenga!

otinga

Mōhiotia:

Taumaha (m) = 4 kg

Te whakaterenga nā te kaha ā-papa (g) = 9.8 m/s²

Te tauwehenga o te waku pateko (μ_s) = 0.4

Te tauwehenga o te waku nekeneke (μ_k) = 0.2

Taumaha (w) = mg = (4)(9.8) = 39.2 Ngā Newton

Ko te wāhanga whakapae o te taumaha (w_x) = w sin 30^o = (39.2)(0.5) = 19.6 Ngā Newton

Ko te wāhanga poutū o te taumaha (w_y) = w cos 30^o = (392)(0..5√3) = 19.6√3 Ngā Newton

Te kaha noa (N) = w_y = 19.6√3 Ngā Newton = 33.95 Ngā Newton

te kaha waku pumau (f_s) = μ_s N= (0,4)(33.95) = 13.58 Ngā Niutona

Te kaha waku nekeneke (f_k) = μ_k N= (0.2)(33.95) = 6.79 Ngā Niutona

F = 40 Newton

Rongoā:

Ka paheke te mea ki raro mēnā ko F < w_x +f_sKa paheke te mea ki runga mēnā ka > w te F_x +f_s.

F = 40 Newton, w_x = 19.6 Newton me te f_s = 13.58 Ngā Newtoni.

He nui ake a F i a w_x +f_s nō reira ka paheke te mea ki runga.

(a) Te kaha kupenga

∑F = F – w_x - f_k = 40 – 19.6 – 6.79 = 13.61 Ngā Newton

(b) Te rahi me te ahunga o te whakaterenga

∑F = ma

6.4 = (4) he

ki = 1.6

Ko te rahi o te whakaterenga he 1.6 m/s² ā, ko te ahunga o te whakaterenga kei runga.

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1. Papatipu me te taumaha
2. Te kaha noa
3. Te ture tuarua o te nekehanga a Newton
4. Te kaha waku
5. Te nekehanga i runga i te mata whakapae me te kore he kaha waku
6. Te nekehanga o ngā tinana e rua me te tere tere ōrite i runga i te mata whakapae taratara me te kaha waku
7. Te nekehanga i runga i te papa whakarara me te kore he kaha waku
8. Te nekehanga i runga i te papa whakarara taratara me te kaha waku
9. Te nekehanga i roto i te ararewa
10. Ka honoa te nekehanga o ngā tinana e ngā taura me ngā pūrere
11. E rua ngā tinana he rite te rahi o te whakaterenga
12. Te whakaawhiwhi i tētahi piko papatahi – ngā nekehanga porowhita
13. Te whakaawhiwhi i tētahi kōpiko peeke – ngā hihiri o te nekehanga porowhita
14. Te nekehanga ōrite i roto i te porowhita whakapae
15. Te kaha pokapū i roto i te nekehanga porowhita ōrite