1. Ko te taumaha o te pouaka 1 he 2 kg, ko te taumaha o te pouaka 2 he 4 kg, ko te whakaterenga o te kaha ā-papa he 10 m/s2 , ko te rahi o te kaha F he 40 Newtons. Ko te tauwehenga o te waku nekeneke i waenga i te pouaka 1 me te papa he 0.2, ā, ko te tauwehenga o te waku nekeneke i waenga i te pouaka 2 me te papa he 0.3. Kimihia (a) Te rahi me te ahunga o te whakaterenga o te pouaka (b) Te rahi o te kaha i tukuna e te pouaka 1 ki te pouaka 2 (F 12 ) me te rahi o te kaha i tukuna e te pouaka 2 ki te pouaka 1 (F 21 ).
otinga
Mōhiotia:
Taumaha o te pouaka 1 (m1 ) = 2 kg
Taumaha o te pouaka 2 (m2 ) = 4 kg
Te whakaterenga o te kaha ā-papa (g) = 10 m/ s² ,
Ko te kaha F = 40 Newton,
Te tauwehenga o te waku nekeneke i waenga i te pouaka 1 me te papa ( μ k1 ) = 0.2
Te tauwehenga o te waku nekeneke i waenga i te pouaka 2 me te papa ( μ k2 ) = 0.3
Te taumaha o te pouaka 1 (w1 ) = m1 karamu = (2)(10) = 20 Newton
Te taumaha o te pouaka 2 (w 2 ) = m 2 karamu = (4)(10) = 40 Newtons
Ko te kaha noa i pā ki te pouaka 1 (N 1 ) = w 1 = 20 Newtons
Ko te kaha noa i pā ki te pouaka 2 (N 2 ) = w 2 = 40 Newtons
Ko te kaha o te waku nekeneke i pā ki te pouaka 1 (f k1 ) = ( μ k1 )(N 1 ) = (0.2)(20) = 4 Newtons
Ko te kaha o te waku nekeneke i pā ki te pouaka 2 (f k2 ) = ( μ k1 )(N 2 ) = (0.3)(40) = 12 Newtons
Rongoā:
(a) Te rahi me te ahunga o te whakaterenga o te pouaka
ΣF = ma
F – f k1 – f k2 = (m 1 + m 2 ) a
40 – 4 – 12 = (2 + 4) he
24 = 6
ā = 24 / 6
a = 4 m/s 2
Te ahunga o te whakaterenga = te ahunga o te kaha kupenga = whaka-matau.
(b) Te rahi o te kaha i tukuna e te pouaka 1 ki runga i te pouaka 2 (F 12 ) me te rahi o te kaha i tukuna e te pouaka 2 ki runga i te pouaka 1 (F 21 ).
Tātaihia te rahi o F 12 :
ΣF = ma
F 12 – f k2 = (m 2 ) a
F 12 – 12 = (4)(4)
F 12 – 12 = 16
F 12 = 16 + 12
F 12 = 28 Newton
Ko te F 12 me te F 21 he kaha mahi me te kaha tauhohe e pā ana ki ngā mea rerekē. He rite te rahi o te F 12 me te F 21 , he rite te ahunga, he rerekē hoki.
F 12 = 28 Ngā Newton = F 21 = 28 Ngā Newton.
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2. Ko te taumaha o te pouaka 1 he 2 kg, ko te taumaha o te pouaka 2 he 4 kg, ko te whakaterenga o te kaha ā-papa he 10 m/s² , ko te kaha F he 40 N. Ko te tauwehenga o te waku nekeneke i waenga i te pouaka 1 me te papa he 0.2, ā, ko te tauwehenga o te waku nekeneke i waenga i te pouaka 2 me te papa he 0.3. Whakatauhia (a) Te rahi me te ahunga o te whakaterenga (b) Te kume i roto i te taura e hono ana i ngā pouaka. Kaua e aro ki te taumaha o te taura.
Mōhiotia:
Taumaha o te pouaka 1 (m1 ) = 2 kg
Taumaha o te pouaka 2 (m2 ) = 4 kg
Te whakaterenga o te kaha ā-papa (g) = 10 m/ s² ,
Ko te kaha F = 40 Newton,
Ko te tauwehenga o te waku nekeneke i waenga i te pouaka 1 me te papa he 0.2 ( μ k1 ) = 0.2
Ko te tauwehenga o te waku nekeneke i waenga i te pouaka 2 me te papa he 0.2 ( μ k2 ) = 0.3
Te taumaha o te pouaka 1 (w 1 ) = m 1 karamu = (2)(10) = 20 Newtons
Te taumaha o te pouaka 2 (w 2 ) = m 2 karamu = (4)(10) = 40 Newtons
Ko te kaha noa i pā ki te pouaka 1 (N 1 ) = w 1 = 20 Newtons
Ko te kaha noa i pā ki te pouaka 2 (N 2 ) = w 2 = 40 Newtons
Ko te kaha o te waku nekeneke i pā ki te pouaka 1 (f k1 ) = ( μ k1 )(N 1 ) = (0.2)(20) = 4 Newtons
Ko te kaha o te waku nekeneke i pā ki te pouaka 2 (f k2 ) = ( μ k1 )(N 2 ) = (0.3)(40) = 12 Newtons
Rongoā:
(a) te rahi me te ahunga o te whakaterenga
ΣF = ma
F – f k1 – f k2 = (m 1 + m 2 ) a
40 – 4 – 12 = (2 + 4) he
24 = 6
ā = 24 / 6
a = 4 m/s 2
Ko te rahi o te whakaterenga he 4 m/s² , ko te ahunga o te whakaterenga = te ahunga o te kaha kupenga = whaka-matau.
(b) Te kukū o te taura
Ko ngā kaha e pā ana ki te pouaka 1 i te taha whakapae ko te kume 1 (T 1 ) ki te taha matau, me te kaha o te waku nekeneke 1 (f k 1 ) ki te taha maui. Whakamahia te ture tuarua a Newton:
ΣF = ma
T 1 – f k1 = m 1 a
T 1 – 4 = (2)(4)
T 1 – 4 = 8
T 1 = 8 + 4 = 12 Newton
Ko ngā kaha e pā ana ki te pouaka 2 i te ahunga whakapae ko te kume 2 (T 2 ) ki maui me te kaha o te waku nekeneke 2 (f k 2 ) ki matau. Whakamahia te ture tuarua a Newton :
ΣF = ma
F – T 2 – f k2 = m 2 a
40 – T 2 – 12 = (4)(4)
28 – T 2 = 16
T 2 = 28 – 16 = 12 Newton
Ko te kume i roto i te taura e hono ana i ngā pouaka = T 1 = T 2 = T = 12 Newton.
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- Papatipu me te taumaha
- Te kaha noa
- Te ture tuarua o te nekehanga a Newton
- Te kaha waku
- Te nekehanga i runga i te mata whakapae me te kore he kaha waku
- Te nekehanga o ngā tinana e rua me te tere tere ōrite i runga i te mata whakapae taratara me te kaha waku
- Te nekehanga i runga i te papa whakarara me te kore he kaha waku
- Te nekehanga i runga i te papa whakarara me te kaha waku
- Te nekehanga i roto i te ararewa
- Te nekehanga o ngā tinana e honoa ana e ngā taura me ngā pūrei
- E rua ngā tinana he rite te rahi o te whakaterenga
- Te whakaawhiwhi i tētahi piko papatahi – ngā nekehanga porowhita
- Te whakaawhiwhi i tētahi kōpiko peeke – ngā hihiri o te nekehanga porowhita
- Te nekehanga ōrite i roto i te porowhita whakapae
- Te kaha pokapū i roto i te nekehanga porowhita ōrite
