1. He pōro 0.2-kg te taumaha, e piri ana ki te pito o tētahi taura whakapae, e hurihia ana i roto i tētahi porowhita he 1 mita te whānui, ā, ko te tere mōrahi o te pōro he 10 rpm. He aha te rahi o te whakaterenga pokapū me te rahi o te kaha kume?
Mōhiotia:
Mass (m) = 0.2 kg
Pūtoro (r) = 1 m
Te orite angular (ω) = 10 whakahuri/mene = 10 whakahuri/60 s = 0.17 whakahuri/s = (0.17)(6.28 rad)/s = 1 rad/s
tere (v) = r ω = (1 m)(1 rad/s) = 1 m/s
E hiahiatia ana: as dan ΣF
Rongoā:
(a) Te rahi o te whakaterenga ā-pokapū
(b) Te rahi o te kaha kume
ΣF = ma
T = mās
T = (0.2 kg)(1 m/s)2)
T = 0.2 kg m/s2
T = 0.2 N
2. Kei te porowhita whakapae te pōro 1-kg i te pito o te aho, he 1 m te whānui o te porowhita. Ka motu te taura ina neke atu te kukū o roto i te 100 N. He aha te tere mōrahi ka taea e te pōro te eke?
Mōhiotia:
Taumaha (m) = 1 kg
Pūtoro (r) = 1 mita
Te kaha kume (T) = kaha centripetal (ΣF) = 100 N
Hiahia: mōrahi v
Rongoā:
[wpdm_package id='499′]
- Papatipu me te taumaha
- Te kaha noa
- Te ture tuarua o te nekehanga a Newton
- Te kaha waku
- Te nekehanga i runga i te mata whakapae me te kore he kaha waku
- Ko te nekehanga o ngā tinana e rua me te tere tere ōrite i runga i te mata whakapae taratara me te kaha waku
- Te nekehanga i runga i te papa whakarara me te kore he kaha waku
- Te nekehanga i runga i te papa whakarara taratara me te kaha waku
- Te nekehanga i roto i te ararewa
- Ka honoa te nekehanga o ngā tinana e ngā taura me ngā pūrere
- E rua ngā tinana he rite te rahi o te whakaterenga
- Te whakaawhiwhi i tētahi piko papatahi – ngā nekehanga porowhita
- Te whakaawhiwhi i tētahi kōpiko peeke – ngā hihiri o te nekehanga porowhita
- Te nekehanga ōrite i roto i te porowhita whakapae
- Te kaha pokapū i roto i te nekehanga porowhita ōrite
