Tauira o te whakawhiti wera mā te whakawhiti wera

3 Ngā tauira o te whakawhiti wera mā te whakawhiti wera

1. Whakamāramahia te tikanga mā te whakamahi i ngā tauira te whakawhiti wera mā te whakawhiti wera ?
Kōrero
Ko te whakawhiti wera whakawhiti he whakawhiti wera e haere tahi ana me te nekehanga o te matū. Hei tauira, whakaarohia te wai i roto i te ipu konumohe e whakamahanahia ana i runga i te oumu. I te tīmatanga, ka whakawhitihia te wera mā te kawe me te irahiko mai i te mura ki te ipu konumohe, kātahi mā te kawe mai i te ipu konumohe ki te wai.
Ka tīmata te whakawhiti wera whakawhiti ina whiwhi te wai e tata ana ki tētahi ipu konumohe i tētahi wera tāpiri, ka whakanui ake i tōna pāmahana, kātahi ka whānui. Ka whakaitihia e tēnei whānui tōna mātotoru, ka mānu te wai ki te mata. Ka whakakapia tēnei wai e te wai he iti ake te pāmahana, he nui ake te mātotoru. Ka haere tonu tēnei tukanga, ka hangaia he ia whakawhiti i roto i te ipu. Ka mutu te tukanga ina tae katoa te wai ki te mata. te pāmahana taua wā anō rānei e koropupū ana te wai.
Ko tētahi atu tauira ko te hau. Ko te hau he hau e neke ana. Ka neke te hau kia taea ai te neke i te wera mai i ngā wāhi he teitei te pāmahana ki ngā wāhi he iti te pāmahana.

Pānuitia atu

Ngā tauira o ngā pātai mō te wera huna, te wera o te hanumi, te wera o te kohu

4 Ngā tauira pātai mō te wera huna, te wera hanumi, te wera o te kohu

1. Ko te nui o te wera me mimiti hei huri i te āhua o te 1 karamu koura mai i te totoka ki te wai ko….. Ko te wera rewa o te koura = 64,5 x 103 J /kg

Kōrero

E mōhiotia ana:

Taumaha o te koura (m) = 1 karamu = 1 x 10 -3 kg

Te wera o te hanumitanga o te koura (L F ) = 64,5 x 103 J /kg

Pātai: Te wera (Q) e mimitia ana e te koura

Whakautu:

Pānuitia atu

He tauira o tētahi pātai ahupūngao mō te uho o ngā tauhohenga hanumi, te pūngao here ngota

9 ngā tauira o ngā pātai ahupūngao karihi mō ngā tauhohenga hanumi me te pūngao here ngota

1. Mātakihia te tauhohenga hanumi karihi e whai ake nei:
1H2 + 1H3 → 2He4 + 0n1 Ā,
Mena te papatipu 1H2 = 2,014 amu, papatipu 1H3 = 3,016 amu, te papatipu o te matūriki α = 4,0026 amu me te papatipu o te niutron = 1,0084 amu, ko te pūngao i puta ko…. (1 amu he ōrite ki te 931 MeV)
A. 18,62 MeV
B. 17,69 MeV
C. 16,76 MeV
D. 15,73 MeV
E. 14,89 MeV
Kōrero

Pānuitia atu

Ngā tauira o ngā pātai motuhake mō te wera me te kaha o te wera

4 ngā tauira o ngā pātai motuhake mō te wera me te kaha o te wera

1. Ko tēhea te mea ka tere ake te wera ina whakamaroketia ngātahi i te rā wera, i te konumohe, i te parahi rānei? Ko te wera motuhake o te konumohe = 900 J/kg o C, ā, ko te wera motuhake o te parahi = 390 J/kg o C.

Kōrero

Ka roa ake te wera o tētahi mea, ka nui ake te wera motuhake. I te taha ke, ka tere ake te wera o tētahi mea, ka iti ake te wera motuhake.

He iti ake te wera motuhake o te parahi i te wera motuhake o te konumohe, nō reira ka tere ake te wera o te parahi.

Pānuitia atu

He tauira o ngā pātai mō te whakawhānui i te rōrahi

5 ngā tauira o ngā pātai whakawhanui rōrahi

1. He pōro totoka he mea hanga ki te konumohe, ā, ko te tauwehenga whānui rārangi he 24 x 10 -6° C -1 . Mena he 30 cm³ te rōrahi o te pōro i te pāmahana 30 ° C , me whakamahana te pōro ki te pāmahana o….. ° C kia piki ake ai te rōrahi o te pōro ki te 30,5 cm³.

Kōrero

E mōhiotia ana:

Tauwehenga o te whakawhanuitanga rārangi (α ) = 24 x 10 -6 o C -1

Tauwehenga whānui rōrahi (γ ) = 3 a = 3 x 24 x 10 -6 o C -1 = 72 x 10 -6 o C -1

Pānuitia atu

He tauira o ngā pātai mō te whakawhānui i te rohe

3 Ngā tauira pātai mō te whakawhānui i te rohe

1. He 50 cm te roa o tētahi rau maitai i te pāmahana o te 20 ° C, ā, he 30 cm te whānui. Mēnā ko te tauwehenga whānui raina o te maitai he 10 -5 ° C -1 , ko te pikinga o te horahanga me te horahanga katoa i te pāmahana o te 60 ° C ko….

Kōrero

E mōhiotia ana:

Te pāmahana tīmatanga (T 1 ) = 20 ° C

Te pāmahana whakamutunga (T 2 ) = 60 ° C

Huringa pāmahana (ΔT ) = 60 ° C – 20 ° C = 40 ° C

Te horahanga tīmatanga (A 1 ) = Te roa x te whānui = 50 henimita x 30 henimita = 1500 henimita 2

Ko te tauwehenga whānui rārangi o te maitai (α ) = 10 -5 o C -1

Pānuitia atu

He tauira o ngā pātai whakawhanui roa

5 Ngā tauira pātai mō te whakawhanui i te roa

1. He pae rino i te pāmahana o te 20oE 40 cm te roa o C. Ko te tauwehenga whānui raina o te maitai he 10-5 oC-1. Ko te pikinga o te roa o te maitai me te roa whakamutunga o te maitai i te pāmahana 70oKo C te……
Kōrero
E mōhiotia ana:
Te pikinga o te pāmahana (ΔT) = 70oC - 20oC=50oC
Te roa tīmatanga (L)1) = 40 henemita
Tauwehenga o te whakawhanuitanga rārangi o te maitai (a) = 10-5 oC-1
I pātaihia: Te pikinga o te roa (ΔL) me te roa whakamutunga (L2)
Whakautu:
a) Te pikinga o te roa (ΔL)
ΔL = αL1 ΔT
ΔL = (10-5 oC-1)(40 henimita)(50oC)
ΔL = (10-5)(2 x 103) henimita
ΔL = 2 x 10-2 cm
ΔL = 2 / 102 cm
ΔL = 2 / 100 cm
ΔL = 0,02 henimita

Pānuitia atu

Tauira o ngā pātai hurihanga tauine pāmahana: tauine Celsius, tauine Fahrenheit, tauine Kelvin

6 Ngā tauira o ngā pātai hurihanga pāmahana: te tauine Celsius, te tauine Fahrenheit, te tauine Kelvin

1. 50oC = … oF?
Kōrero
I te pēhanga hau o te 1 āhuarangi, ko te pāmahana hukapapa mō te inemahana Celsius he 0.oC, engari te whakamahana Ko te tauine Fahrenheit he 32oF. I te pēhanga hau o te 1 āhuarangi, ko te pāmahana pūwāhi kohu mō te inemahana Celsius he 100oC, ko te inemahana o te tauine Fahrenheit he 212oF.
Nō reira, 0oC=32oF me te 100oC=212oF.

I te tauine Celsius, e 100 ngā nekehanga i waenga i te 0 ° C me te 100 ° C . I te tauine Fahrenheit, e 180 ngā nekehanga i waenga i te 32 ° F me te 212 ° F . Hei whiwhi i te pāmahana Fahrenheit (T ° F), whakareatia te pāmahana Celsius (T ° C) ki te 9/5, kātahi ka tāpirihia te 32 °C.

Pānuitia atu