20 Ngā tauira o ngā pātai hiko pateko
Te Mana Hiko
1. Kei roto te Pūwāhi A i tētahi mara hiko . Ko te kaha o te mara hiko i te pūwāhi A he 0,5 NC -1 . Mena ka whakanohoia he mea he 0,25 C te utu ki te pūwāhi A, ka puta he kaha Coulomb o...
A. 0,125 N
B. 0,25 N
C. 0,35 N
D. 0,40 N
E. 0,70 N
Kōrero
E mōhiotia ana:
Te kaha o te mara hiko i te pūwāhi A = 0,5 NC -1
Te utu hiko i te pūwāhi A = 0,25 C
Pātai: Te kaha Coulomb e pā ana ki tētahi mea e utua ana e te hiko
Whakautu:
Ko te tātai e whakaatu ana i te whanaungatanga i waenga i te kaha hiko (F), te papa hiko (E) me te utu hiko (q) ko:
F = q E
F = (0,25 C)(0,5 NC -1 )
F = 0,125N
Ko te whakautu tika ko A.
2. E 3 m te tawhiti o ngā utu e rua, he 5 C me te 4 C. Mēnā ko k = 9 × 10 9 Nm 2 C –2 , ko te rahi o te kaha Coulomb e pāngia ana e ngā utu e rua ko…
A. 2 × 10 9 N
B. 60 × 10 9 N
C. 2 × 10 10 N
D. 6 × 10 10 N
E. 20 × 10 10 N
Kōrero
E mōhiotia ana:
Utu 1 (q 1 ) = 5 C
Utu 2 (q 2 ) = 4 C
Ko te tawhiti i waenga i ngā kawenga 1 me te 2 (r) = 3 mita.
Pūmau Coulomb (k) = 9 × 10 9 Nm 2 C –2
Pātai: Te rahi o te kaha Coulomb (F)
Whakautu:
Ko te whakautu tika ko C.
3. Kua wehea ngā utu hiko +q 1 = 10 μC; +q 2 = 20 μC; me q 3 e whakaaturia ana i te pikitia i raro nei. Nō reira, ko te kaha Coulomb e pā ana ki te utu q 2 = kore; ko te utu q 3 ko…
A. +2,5 µC
B. –2,5 μC
C. +25 μC
D. –25 μC
E. +4 μC
Kōrero
E mōhiotia ana:
Utu 1 (q 1 ) = 10 μC = 10 x 10 -6 C
Utu 2 (q 2 ) = 20 μC = 20 x 10 -6 C
Pātai: He aha te utu q 3 kia rite ai te kaha Coulomb e pā ana ki te utu q 2 ki te kore (F 2 = 0).
Whakautu:
E rua ngā kaha e pā ana ki +q 2.
Ko te kaha tuatahi ko te kaha pana i waenganui i te utu +q 1 me te utu +q 2 , arā, ko F 12 , e anga ana ki te taha matau.
Kia kore ai te kaha hiko e puta mai ana i runga i te q2 , me utu kino te q3 . Nō reira, ko te kaha tuarua ko te kaha kukume i waenganui i ngā utu +q2 me te -q3 , arā, ko te F23 , e anga ana ki te taha maui. He rite te rahi o ēnei kaha e rua e mahi ana i runga i te q2 engari he rerekē ngā ahunga.
Ko te kaha hua i runga i te +q 2 he ōrite ki te kore.
Ko te whakautu tika ko B.
4. Ko te utu hiko o ngā pūwāhi A me B he −10 μC me te +40 μC. I te tīmatanga ka whakatakotoria ngā utu e rua kia 0,5 mita te tawhiti kia puta ai he kaha Coulomb F Newton. Mena ka hurihia te tawhiti i waenganui i a A me B ki te 1,5 mita, ko te kaha Coulomb e puta ake ana ko...
A. 1 / 9 F
B. 1 / 3 F
C. 3 / 2 F
D. 3 F
E. 9 F
Kōrero
Whakatauritea te matapakinga o te pātai nama 9.
Ka whakarerekētia te tawhiti i waenganui i a A me B ki te 1,5 mita, arā, ki te 3 ngā whakarea o te tawhiti taketake.
He rite whakamuri te kaha ki te tapawhā o te tawhiti:
Ko te kaha Coulomb e puta ake ana ko te 1/9 F.
Ko te whakautu tika ko A.
5. Ka whakatakotoria he pūnaha me ngā utu kore utu e toru, he rite te rahi, kia taurite ai, pērā i te pikitia. Mēnā ka nekehia a Q 3 kia 1/3 x kia tata atu ki a Q 2 , ka noho te ōwehenga o te kaha Coulomb F 2 : F 1 hei….
A. 1 : 3
B. 2 : 3
C. 3 : 4
D. 9 : 1
E. 9 : 4
Kōrero
E mōhiotia ana :
Ko te tawhiti i waenganui i a q 1 me q 2 = x
Ko te tawhiti i waenganui i a q 2 me q 3 = 2/3 x
I pātaihia : F 2 : F 1 = …. ?
Whakautu :
Te tauira ture a Coulomb:
Whakaahuatanga: k = pūmau, q 1 = utu 1, q 2 = utu 2, r = tawhiti i waenganui i te utu 1 me te utu 2
Te whakataurite i te rahi o te kaha Coulomb
He ōrite a q 1 , q 2 me q 3 , nō reira ka tangohia atu i te whārite. He ōrite hoki te rahi o k me x 2 , ā, kei te taha maui me te taha matau rātou, nō reira ka tangohia atu i te whārite.
Ko te whakautu tika ko E.
6. Tirohia te ahua i raro nei. Kei roto i te rārangi kotahi ngā utu hiko e toru, arā, q1 , q, me q2 . Mena ko q = 5,0 μC, ā, ko d = 30 cm, ko te rahi me te ahunga o te kaha hiko e pā ana ki te utu q ko… (k = 9 x 109 N m2 C -2 )
A. 7,5 N ki te taha q1
B. 7,5 N ki te taha q 2
C. 15 N ki te taha q 1
D. 22,5 N ki te taha q 1
E. 22,5 N ki te taha q 2
Kōrero
E mōhiotia ana:
Utu 1 (q 1 ) = 30 μC = 30 x 10 -6 C
Utu 2 (q 2 ) = 60 μC = 60 x 10 -6 C
Utu 3 (q) = 5 μC = 5 x 10 -6 C
Te tawhiti i waenganui i a q 1 me q = d
Te tawhiti i waenganui i a q 2 me q = 2d
d = 30 cm = 0,3 mita
d 2 = (0,3) 2 = 0,09
Te pūmau o Coulomb (k) = 9 x 10 9 N m 2 C -2
Pātai: Te rahi me te ahunga o te kaha hiko e pā ana ki tētahi utu hiko
Whakautu:
E rua ngā kaha e pā ana ki a q, arā, kei te taha matau a F1 (he pai te utu o q me q1 , nō reira kei tawhiti atu a F1 i a q me q1 ) ā , kei te taha maui a F2 ( he pai te utu o q me q2, nō reira kei tawhiti atu a F2 i a q me q2 ) . Tuatahi, tatauhia a F1 me F2.
Te kaha hua:
Σ F = 15 – 7,5 = 7,5
Ko te kaha hua ko te 7,5 Newton. He rite tonu tōna ahunga ki te F 1 , arā, ki te taha matau ki te q 2.
Ko te whakautu tika ko B.
Papa Hiko
7. Kei te pūwāhi P te utunga pūwāhi q i roto i tētahi āpure hiko i hangaia e tētahi utunga (+) kia pāngia ai e te kaha o te 0,05 N i te ahunga ki te utunga. Mena ko te kaha o te āpure i te pūwāhi P he 2 x 10 –2 NC –1 , ko te rahi me te momo utu e whakaputa ana i te āpure ko…
A. 5,0 C, pai
B. 5,0 C, kino
C. 3,0 C, pai
D. 2,5 C, kino
E. 2,5 C, pai
Kōrero
E mōhiotia ana:
Te kaha hiko (F) = 0,05 N
Te kaha o te mara hiko (E) = 2 x 10 –2 NC –1 = 0,02 NC –1
I pātaihia: Te rahi me te momo utu e hanga ana i te mara
Whakautu:
Ka tatauhia te utu hiko mā te whakamahi i tētahi tātai e whakaatu ana i te whanaungatanga i waenga i te kaha hiko (F), te papa hiko (E) me te utu hiko (q):
F = q E
q = F / E = 0,05 N / 0,02 NC –1 = 2,5 Coulombs
Ka pāngia te utu q e te kaha hiko e anga atu ana ki te utu (+) ka hanga he āpure hiko, nō reira he tohu kino tō te utu q.
Ko te whakautu tika ko D.
8. Ko te tawhiti i waenganui i ngā utu e rua A me B he 4 m. Kei waenganui i ngā utu e rua te Pūwāhi C, 1 m mai i A. Mena ko Q A = –300 μC, ko Q B = 600 μC. 1/4 π ε 0 = 9 × 10 9 N m 2 C –2 , ko te kaha o te papa hiko i te pūwāhi C nā te awe o ngā utu e rua ko…
A. 9 × 10 5 NC –1
B. 18 × 10 5 NC –1
C. 33 × 10 5 NC –1
D. 45 × 10 5 NC –1
E. 54 × 10 5 NC –1
Kōrero
E mōhiotia ana:
Ko te tawhiti i waenganui i ngā kawenga A me B (r AB ) = 4 mita
Ko te tawhiti i waenganui i te pūwāhi C me te utu A (r AC ) = 1 mita
Ko te tawhiti i waenganui i te pūwāhi C me te utu B (r BC ) = 3 mita
Utu A (q A ) = –300 μC = -300 x 10 -6 C = -3 x 10 -4 Coulomb
Utu B (q B ) = 600 μC = 600 x 10 -6 C = 6 x 10 -4 Coulomb
Pūmau (k) = 9 × 10 9 N m 2 C –2
Pātai: te kaha o te papa hiko i te pūwāhi C
Whakautu:
Ko te papa hiko i hangaia e te utu A i te pūwāhi C:
He kino te utu A, nō reira ko te ahunga o te papa hiko e anga atu ana ki te utu A, engari e matara atu ana i te utu B (ki te taha mauī).
Ko te papa hiko i hangaia e te utu B i te pūwāhi C:
He pai te utu B, nō reira kei tawhiti atu te ahunga o te papa hiko i te utu B, ka anga atu ki te utu A (ki te taha mauī).
Te hua o te mara hiko i te pūwāhi A:
Kei te ahunga kotahi a E A me E B , nō reira ka tāpirihia ngātahitia rāua.
E = EA + EB
E = (27 x 10 5 ) + (6 x 10 5 )
E = 33 x 10 5 N/C
Ko te ahunga o te papa hiko e anga ana ki te utunga A, ā, e matara atu ana i te utunga B (ki te taha mauī).
Ko te whakautu tika ko C.
9. Ka taea e te maramara puehu kotahi mirikaramu te mānu i te rangi nā te mea he papa hiko e pupuri ana i te puehu. Mena ko te utu o te puehu he 0,5 μC, ā, ko te whakaterenga nā te kaha ā-papa he 10 m/s2 , whakatauhia te rahi o te papa hiko ka taea te pupuri i te puehu.
A. 5 N/C
B. 10 N/C
C. 20 N/C
D. 25 N/C
E. 40 N/C
Kōrero
E mōhiotia ana:
Papatipu puehu (m) = 1 mirikaramu = 1 x 10 -6 kg
Te utu puehu (q) = 0,5 μC = 0,5 x 10 -6 C
Te whakaterenga nā te kaha ā-papa (g) = 10 m/s 2
Pātai: Te kaha o te papa hiko e pupuri ana i te puehu
Whakautu:
Tātai taumaha:
w = mg
Whakaahuatanga: w = taumaha o te puehu, m = papatipu o te puehu, g = whakaterenga nā te kaha ā-papatipu
Ka tatauhia te kaha ā-papa e pā ana ki te puehu, te taumaha rānei o te puehu mā te whakamahi i te tātai taumaha:
w = mg = (1 x 10 -6 kg)(10 m/s 2 ) = 10 x 10 -6 kg m/s 2 = 10 x 10 -6 Newton
Te tātai kaha o te mara hiko:
E = F/q
Whakaahuatanga: E = te kaha o te papa hiko, F = te kaha hiko, q = te utu hiko
Ka mānu te puehu i te rangi, nō reira me kore te kaha e pā ana ki te puehu. Ka anga whakararo te kaha o te puehu, nō reira me anga whakarunga te kaha hiko, ā, me ōrite te rahi o te kaha o te puehu ki te rahi o te kaha hiko, kia kore ai te kaha e puta mai ana ki te puehu. Nō reira, ka taea te whakakapi i te F i roto i te tātai kaha o te mara hiko ki te w i roto i te tātai taumaha.
E = F/q = w/q
E = (10 x 10 -6 N) / (0,5 x 10 -6 C)
E = 10 N / 0,5 C
E = 20 N/C
Ko te whakautu tika ko C.
10. E rua ngā utu, q 1 = 32 μC me q 2 = -214 μC, e wehea ana e te tawhiti x i a rātou anō e whakaaturia ana i te pikitia i runga ake nei. Mēnā kei te pūwāhi p, arā, he 10 cm te tawhiti mai i q 2, ko te kaha o te mara hiko ka puta ko te kore. Kātahi ko te rahi o x ko….
A. 20 henemita
B. 30 henemita
C. 40 henimita
D. 50 henimita
E. 60 henimita
Kōrero
E mōhiotia ana:
Utu 1 (Q 1 ) = 32 μC
Utu 2 (Q 2 ) = -214 μC
Te tawhiti o te pūwāhi p mai i q 1 = x + 10 cm
Te tawhiti o te pūwāhi p mai i q 2 = 10 cm
I pātaihia: x
Whakautu:
Ko E 1 te mara hiko i hangaia e te utu Q 1. Kei tawhiti atu te ahunga o te mara hiko i a Q 1 nā te mea he utu pai a Q 1. Ko E 2 te mara hiko i hangaia e te utu Q 2. Kei te anga atu te ahunga o te mara hiko ki a Q 2 nā te mea he utu kino a Q 2 .
I te pūwāhi p, e 10 cm te tawhiti mai i Q 2 , ko te kaha o te mara hiko ka puta ko te kore.
Whakamahia te tātai ABC:
11. Kei te pūwāhi P te pūwāhi me te utu q i roto i te āpure hiko i hangaia e te utu (+), ā, ka pāngia e te kaha o te 0,05 N. Mena ko te rahi o te utu he +5 × l0 –6 Coulomb, ko te rahi o te āpure hiko i te pūwāhi P he…
A. 2,5 × 10 3 NC –1
B. 3.0 × 10 3 NC –1
C. 4,5 × l0 3 NC –1
D. 8,0 × 10 3 NC –1
E. 10 4 NC –1
Kōrero
E mōhiotia ana:
Te kaha hiko (F) = 0,05 Newton
Utu hiko (Q) = +5 × l0 –6 Coulomb = 0,000005
Pātai: He aha te rahi o te āpure hiko i te pūwāhi P?
Whakautu:
Ko te tātai e whakaatu ana i te whanaungatanga i waenga i te papa hiko, te kaha hiko me te utu hiko:
E = F / Q
E = 0,05 Newton / 0,000005 Coulomb
E = 5 Newton / 0,0005 Coulomb
E = 10.000 Newton/Coulomb
E = 10 4 N/C
E = 10 4 NC -1
Ko te whakautu tika ko E.
12. E toru ngā utu kua whakaritea e whakaaturia ana i te pikitia i raro nei. Ko te kaha Coulomb e pāngia ana e te utu B ko …. (k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)
A. 09 x 101 Utu N ki C
B. 09 x 101 N hei utu i a A
C. 18 x 101 Utu N ki C
D. 18 x 101 N hei utu i a A
E. 36 x 101 Utu N ki C
Kōrero
E mōhiotia ana :
qA = 10 µC = 10 x 10-6 C=10-5 Coulomb
qB = 10 µC = 10 x 10-6 = 10-5 Coulomb
qC = 20 µC = 20 x 10-6 = 2x10-5 Coulomb
rAB = 0,1 mita = 10-1 mita
rBC = 0,1 mita = 10-1 mita
k = 9 x 109 Nm2C-2
I pātaihia Te kaha Coulomb e pāngia ana e te utu B
Whakautu :
E rua ngā kaha Coulomb, arā, ngā kaha hiko e pā ana ki te utu B, arā, ko te kaha Coulomb i waenganui i ngā utu A me B (F AB ) me te kaha Coulomb i waenganui i ngā utu B me C (F BC ). Ko te kaha Coulomb e pāngia ana e te utu B ko te hua o F AB me F BC.
Te kaha Coulomb i waenganui i ngā utu A me B:
He tohu pai tō te utunga A, ā, he tohu pai tō te utunga B, nō reira ko FAB ki te utu C.
Te kaha Coulomb i waenganui i ngā utu B me C:
He pai te utu B, ā, he pai te utu C, nō reira ko FBC ki te utu A.
Te kaha Coulomb e pāngia ana e te utu B:
FB =FBC - FAB = 180 – 90 = 90 N
Te rahi o te kaha Coulomb e pāngia ana e te utunga B (FB) he 90 Newton. Ko te ahunga o FB rite tonu ki te ahunga FBC arā, e anga ana ki te utu A.
Ko te whakautu tika ko B.
13. Ko te rahi me te ahunga o te kaha Coulomb i runga i te utu B ko... (k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)
A. 2,5 k Q2 r-2 ki te taha maui
B. 2,5 k Q2 r-2 ki te taha matau
C. 2 k Q2 r-2 ki te taha maui
D. 2 k Q2 r-2 ki te taha matau
E. 1 k Q2 r-2 ki te taha maui
Kōrero
E mōhiotia ana :
Utu A (qA) = +Q
Utu B (qB) = -2Q
Utu C (qC) = -Q
Te tawhiti i waenganui i ngā utu A me B (rAB) = r
Te tawhiti i waenganui i ngā utu B me C (rBC) = 2r
k = 9 x 109 Nm2C-2
I pātaihia : te rahi me te ahunga o te kaha Coulomb i runga i te utu B
Whakautu :
Te kaha Coulomb i waenganui i te utu A me te utu B:
He pai te utu A, ā, he kino te utu B, nō reira ko te ahunga ko FAB ki te utu A
Te kaha Coulomb i waenganui i te utu B me te utu C:
He kino te utu B, ā, he kino te utu C, nō reira ko te ahunga o FBC ki te utu A
Ko te kaha hua e pā ana ki te utu B:
F = FAB +FBC = 2 k Q2/r2 + 0,5 k Q2/r2 = 2,5 k Q2/r2 = 2,5 k Q2 r-2
Ko te ahunga o te kaha Coulomb e anga ana ki te utunga A, ki maui rānei.
Ko te whakautu tika ko A.
Papa Hiko
14. Tirohia te pikitia o ngā utu pūwāhi e rua i raro nei! Kei hea te pūwāhi P e tū ai kia ōrite te kaha o te papa hiko i te pūwāhi P ki te kore? (k = 9 x 109 Nm2C-2, 1 μC = 10-6 C)
A. kei waenganui tonu o Q1 me te Q2
B. 6 cm ki te taha matau o Q2
C. 6 cm ki te taha maui o Q1
D. 2 cm ki te taha matau o Q2
E. 2 cm ki te taha maui o Q1
Kōrero
Hei tatau i te kaha o te papa hiko i te pūwāhi P, me kī he utu whakamātautau pai kei te pūwāhi P. Q1 pai me te Q2 tōraro, nō reira me noho te pūwāhi P ki te taha matau o Q2 ki te taha maui rānei o Q1. Mena kei te taha maui o Q te pūwāhi P1; te papa hiko i hangaia i te pūwāhi Q1 kei te pūwāhi P kei te taha mauī te ahunga (kei tawhiti atu i a Q1) me te mara hiko i hangaia e Q2 kei te pūwāhi P te ahunga kei te taha matau (ki Q)1Nā te mea he rerekē te ahunga o te mara hiko, ka whakakorea e ngā mea e rua tetahi i tetahi kia kore ai te kaha o te mara hiko i te pūwāhi P.
E mōhiotia ana :
Q1 = +9 μC = +9 x 10-6 C
Q2 = -4 μC = -4 x 10-6 C
k = 9 x 109 Nm2C-2
Ko te tawhiti i waenganui i te utu 1 me te utu 2 = 3 cm
Te tawhiti i waenganui i a Q1 me te pūwāhi P (r1P) = a
Te tawhiti i waenganui i a Q2 me te pūwāhi P (r2P) = 3 + a
I pātaihia Kei hea te pūwāhi P e tū ai kia ōrite te kaha o te papa hiko i te pūwāhi P ki te kore?
Whakautu :
Kei te taha maui o Q te Pūwāhi P1.
Ko te mara hiko i hangaia e Q1 i te pūwāhi P :
Te utu whakamātautau pai me te Q1 pai kia anga mauī ai te ahunga o te papa hiko.
Ko te mara hiko i hangaia e Q2 i te pūwāhi P :
Te utu whakamātautau pai me te Q2 tōraro kia anga matau ai te ahunga o te papa hiko.
Te hua o te mara hiko i te pūwāhi A :
E1 me E2 te taha whakamuri.
E1 - E2 = 0
E1 =E2
Whakamahia te tātai ABC hei whakatau i te uara o te a.
a = -1,25, b = -13,5, c = -20,25
Kāore e taea te waiho hei mea kino.
Te tawhiti i waenganui i a Q2 me te pūwāhi P (r2P) = 3 + a = 3 – 1,8 = 1,2 henemita.
Kei te tawhiti o te pūwāhi P he 1,2 cm ki te taha matau o Q.2.
15. Tirohia te pikitia e whai ake nei! Utuhia te q3 whakatakotoria ki te tawhiti o te 5 cm mai i te q2, kātahi ka te kaha o te papa hiko i te utunga q3 ko… (1 µC = 10-6 C)
A. 4,6 x 107 NC-1
B. 3,6 x 107 NC-1
C. 1,6 x 107 NC-1
D. 1,4 x 107 NC-1
E. 1,3 x 107 NC-1
Kōrero
Utu q3 whakatakotoria ki te tawhiti o te 5 cm mai i te q2, ko te tikanga kāore i te taha maui o q2 engari i te taha matau q2. Ki te mea kei te taha maui q2 kātahi ka kore te hua o te mara hiko. Nā te mea ko te tawhiti i waenga i ngā utu q3 me te utu q1 me te q2 he 5 cm te roa, ā, ko te rahi o te utu he q1 he ōrite ki te utu q2.
Nā te mea he pai te utu q 3 , ko te ahunga o te mara hiko i te utu q 3 e anga atu ana ki te utu kino q 2 (E 2 ) ā, e matara atu ana i te utu pai q 1 (E 1 ). Ko te mara hiko ka puta ko te tapeke o ngā kaha o te mara hiko E 1 me E 2.
E mōhiotia ana :
Utu q1 = 5 µC = 5 x 10-6 Coulomb
Utu q2 = 5 µC = -5 x 10-6 Coulomb
Te tawhiti i waenga i ngā utu q1 me te utu q3 (r1) = 15 henimita = 0,15 m = 15 x 10-2 mita
Te tawhiti i waenga i ngā utu q2 me te utu q3 (r2) = 5 henimita = 0,05 m = 5 x 10-2 mita
k = 9 x 109 N m2 C-2
I pātaihia : Te kaha o te papa hiko i te utunga q3
Whakautu :
Te kaha o te mara hiko 1
E1 = kq1 /r12
E1 = (9 x 109)(5 x 10-6) / (15 x 10-2)2
E1 = (45 x 103) / (225 x 10-4)
E1 = 0,2x107 N / C
Te kaha o te mara hiko 2
E2 = kq2 /r22
E2 = (9 x 109)(5 x 10-6) / (5 x 10-2)2
E2 = (45 x 103) / (25 x 10-4)
E2 = 1,8x107 N / C
Te kaha o te mara hiko e puta mai ana
Te kaha o te mara hiko i te utu q3 ko:
E = E2 - E1 = (1,8 x 107)– (0,2 x 107) = 1,6 x 107 N / C
Kei te taha mauī, kei te taha E rānei te ahunga o te papa hiko2.
Ko te whakautu tika ko C.
16. E rua ngā utu hiko e wehea ana e whakaaturia ana i te pikitia. Ko te kaha o te mara i te pūwāhi P ko… (k = 9 x 109 N m2 C-2)
A. 9,0 x 109 NC-1
B. 4,5 x 109 NC-1
C. 3,6 x 109 NC-1
D. 5,4 x 109 NC-1
E. 4,5 x 109 NC-1
Kōrero
E mōhiotia ana :
Utu qA = +2,5 C
Utu qB = -2 C
Te tawhiti i waenga i ngā utu qA me te pūwāhi P (rA) = 5 mita
Te tawhiti i waenga i ngā utu qB me te pūwāhi P (rB) = 2 mita
k = 9 x 109 N m2 C-2
I pātaihia Te kaha o te papa hiko i te pūwāhi P
Whakautu :
Te kaha o te mara hiko A
EA = kqA /rA2
EA = (9 x 109)(2,5) / (5)2
EA = (22,5 x 109) / 25
EA = 0,9x109 N / C
Te kaha o te mara hiko B
EB = kqB /rB2
EB = (9 x 109)(2) / (2)2
EB = (18 x 109) / 4
EB = 4,5x109 N / C
Te kaha o te mara hiko e puta mai ana
Ko te kaha o te mara hiko i puta mai i te pūwāhi P ko:
E = EB - EA = (4,5 – 0,9) x 109 = 3,6x109 N / C
Kei te taha mauī, kei te taha E rānei te ahunga o te papa hikoB.
Ko te whakautu tika ko C.
17. E rua ngā utu hiko, he utu Q tō ia utu.1 = -40 µC me te Q2 = Kei te tūranga e whakaaturia ana i te pikitia te +5 µC (k = 9 x 109 Nm2.C-2 ā, 1 µC = 10-6 C), ko te kaha o te papa hiko i te pūwāhi P ko…
A. 2,25 x 106 NC-1
B. 2,45 x 106 NC-1
C. 5,25 x 106 NC-1
D. 6,75 x 106 NC-1
E. 9,00 x 106 NC-1
Kōrero
E mōhiotia ana :
Utu q1 = -40 µC = -40 x 10-6 C
Utu q2 = +5 µC = +5 x 10-6 C
Te tawhiti i waenga i ngā utu q1 me te pūwāhi P (r1) = 40 henimita = 0,4 m = 4 x 10-1 m
Te tawhiti i waenga i ngā utu q2 me te pūwāhi P (r2) = 10 henimita = 0,1 = 1 x 10-1 m
k = 9 x 109 N m2 C-2
I pātaihia Te kaha o te papa hiko i te pūwāhi P
Whakautu :
Te kaha o te mara hiko 1
E1 = kq1 /r12
E1 = (9 x 109)(40 x 10-6) / (4 x 10-1)2
E1 = (360 x 103) / (16 x 10-2)
E1 = 22,5x105 N / C
Te kaha o te mara hiko 2
E2 = kq2 /r22
E2 = (9 x 109)(5 x 10-6) / (1 x 10-1)2
E2 = (45 x 103) / 1 x 10-2
E2 = 45x105 N / C
Te kaha o te mara hiko e puta mai ana
Ko te kaha o te mara hiko i puta mai i te pūwāhi P ko:
E = E2 - E1 = (45 – 22,5) x 105 = 22,5x105 N / C
E = 2,25 x 106 N / C
Kei te taha matau, kei te taha rānei o E te ahunga o te mara hiko2.
Ko te whakautu tika ko A.
18. E rua ngā utu hiko e whakanohoia motuhaketia ana e ai ki te pikitia. Ko te utu i A he 8 µC, ā, ko te kaha kukume e pā ana ki ngā utu e rua he 45 N. Mēnā ka nekehia te utu A ki te taha matau mā te 1 cm, ā, ko k = 9.109 Nm2.C-2, kātahi ko te kaha kukume e pā ana ki ngā utu e rua ko...
A. 45 N
B. 60 N
C. 80 N
D. 90 N
E. 120 N
Kōrero
E mōhiotia ana :
Ko te utu hiko i A (qA) = 8 µC = 8 x 10-6 Coulomb
Ko te kaha hiko i waenganui i ngā utu e rua (F) = 45 Newton
Ko te tawhiti i waenganui i ngā utu e rua (rAB) = 4 henimita = 0,04 mita = 4 x 10-2 mita
Pūmau (k) = 9 x 109 Nm2.C-2
I pātaihia Ko te kaha hiko i waenganui i ngā utu e rua mēnā ka nekehia te utu A ki te taha matau mā te 1 cm, 0,01 mita rānei
Whakautu :
Tuatahi, tatauhia te utu hiko i B, kātahi ka tatau i te kaha hiko i waenganui i ngā utu hiko e rua, mēnā ka nekehia te utu hiko i A ki te taha matau mā te 1 cm.
Utu hiko i B :
Te tātai ture a Coulomb :
F = k (qA)(qB) / r2
F r2 = k (qA)(qB)
qB = F r2 /k (qA)
Utu hiko i B :
qB = (45)(4 x 10-2)2 / (9 x 109)(8 x 10-6)
qB = (45)(16 x 10-4) / 72 x 103
qB = (720 x 10-4) / (72 x 103)
qB = 10x10-7 Coulomb
Te kaha hiko i waenganui i ngā utu hiko A me B :
Ki te nekehia te utu i A ki te taha matau mā te 1 cm, ka noho te tawhiti i waenganui i ngā utu e rua hei 3 cm = 0,03 mita = 3 x 10-2 mita
F = k (qA)(qB) / r2
F = (9 x 109)(8 x 10-6)(10 x 10-7) / (3 x 10-2)2
F = (9 x 109)(80 x 10-13) / (9 x 10-4)
F = (1 x 109)(80 x 10-13) / (1 x 10-4)
F = (80 x 10-4) / (1 x 10-4)
F = 80 Newton
Ko te whakautu tika ko C.
19. E rua ngā utu hiko P me Q, he 10 cm te tawhiti, ka pāngia e te kaha kukume o te 8 N. Mēnā ka nekehia te utu Q ki te 5 cm ki te utu P (1 µC = 10-6 C me k = 9 x 109 Nm2.C-2), kātahi ko te kaha hiko e puta ana ko...
A. 8 N
B. 16 N
C. 32 N
D. 40 N
E. 56 N
Kōrero
E mōhiotia ana :
Te tawhiti i waenganui i ngā utu P me Q (rPQ) = 10 henimita = 0,1 m = 1 x 10-1 m
Ko te kaha hiko i waenganui i ngā utu P me Q (F) = 8 N
Utu hiko Q (qQ) = 40 µC = 40 x 10-6 C
Pūmau (k) = 9 x 109 Nm2.C-2
I pātaihia Ko te kaha hiko i waenganui i ngā utu P me Q mēnā ka nekehia te utu Q kia 5 cm te anga atu ki te utu P
Whakautu :
Tuatahi, tatauhia te utu hiko P, kātahi ka tatauhia te kaha hiko i waenganui i ngā utu hiko e rua, mēnā ka nekehia te utu hiko Q kia 5 cm te anga atu ki te utu P.
Utu hiko P :
qP = F r2 /k (qQ)
qP = (8)(1 x 10-1)2 / (9 x 109)(40 x 10-6)
qP = (8)(1 x 10-2) / 360 x 103
qP = (8 x 10-2) / (36 x 104)
qP = (1 x 10-2) / (4,5 x 104)
qP = (1/4,5) x 10-6 Coulomb
Te kaha hiko i waenganui i ngā utu hiko P me Q :
Ki te nekehia te utu i Q ki te taha mauī mā te 5 cm, ka noho te tawhiti i waenganui i ngā utu e rua hei 5 cm = 0,05 mita = 5 x 10-2 mita
F = k (qP)(qQ) / r2
F = (9 x 109)( (1/4,5) x 10-6)(40 x 10-6) / (5 x 10-2)2
F = (2 x 103)(40 x 10-6) / (25 x 10-4)
F = (80 x 10-3) / (25 x 10-4)
F = 3,2 x 101
F = 32 Newton
Ko te whakautu tika ko C.
20. Tirohia te ahua o te utu hiko e whai ake nei. Ko te kaha hiko e pāngia ana e te utu q koB ko 8 N (1 µC = 10-6 C) me (k = 9.109 Nm2.C-2). Mēnā ko te utu qB nekehia ki te 4 cm mai i A, kātahi ko te kaha hiko e pāngia ana ko qB inaianei ko…
A. 2 N
B. 4 N
C. 6 N
D. 8 N
E. 10 N
Kōrero
E mōhiotia ana :
Te tawhiti i waenganui i ngā utu A me B (rAB) = 2 henimita = 0,02 m = 2 x 10-2 m
Ko te kaha hiko i waenganui i ngā utu A me B (F) = 8 N
Utu hiko A (q)A) = 2 µC = 2 x 10-6 C
Pūmau (k) = 9 x 109 Nm2.C-2
I pātaihia Ko te kaha hiko i waenganui i ngā utu A me B mēnā he 4 cm te tawhiti i waenganui i ngā utu e rua
Whakautu :
Tuatahi, tatauhia te utu hiko B, kātahi ka tatauhia te kaha hiko i waenganui i ngā utu hiko e rua mēnā ko te tawhiti i waenganui i ngā utu hiko e rua he 4 cm = 0,04 mita = 4 x 10-2 mita.
Utu hiko B :
qB = F r2 /k (qA)
qB = (8)(2 x 10-2)2 / (9 x 109)(2 x 10-6)
qB = (8)(4 x 10-4)/ (18 x 103)
qB = (32 x 10-4) / (18 x 103)
qB = (32/18) x 10-7
qB = (16/9) x 10-7 Coulomb
Te kaha hiko i waenganui i ngā utu A me B :
F = k (qA)(qB) / r2
F = (9 x 109)(2 x 10-6)( (16/9) x 10-7) / (4 x 10-2)2
F = (18 x 103)( (16/9) x 10-7) / (16 x 10-4)
F = (2 x 103)(16 x 10-7) / (16 x 10-4)
F = (2 x 103)(1 x 10-7) / (1 x 10-4)
F = (2 x 10-4) / (1 x 10-4)
F = 2 Newton
Ko te whakautu tika ko A.
Pūtake pātai:
Ngā Pātai Ahupūngao Whakamātautau ā-Motu mō te Kura Tuarua/Kura Tuarua Mahi-ā-ringa
