Izinto Zokuphindaphinda Ezihlanganisiwe Ezisebenzisa Izingxenye I-Unit Vector
Singabala umkhiqizo oxubile ngqo uma sazi izingxenye zamavektha. Ukuhleleka kuyafana nokuthi umkhiqizo wamachashaziOkokuqala, senza ukuphindaphinda phakathi kwamavektha eyunithi. i, j dan kUmkhiqizo wevektha phakathi kwamavektha eyunithi efanayo ungu-zero.
i x i = j x j = k x k = 0
Ngokubhekisela ku-equation yokuphindaphinda kwevektha etholakale ngaphambilini (A x B = AB Isono θ) kanye nempahla evimbela ukuguquguquka kwe- ukuphindaphinda kwevektha (A x B = - B x A), bese sithola:
i x j = -j x i = k
j x k = -k x j = i
k x i = -i x k = j
Manje sesisho i-vector A dan B zibe izingxenye zayo, zihlukanise ukuphindaphinda kwayo bese zisebenzisa ukuphindaphinda kwama-vector ayo eyunithi.
A x B= (Axi + Ayj + Azk) x (Bxi + Byj + Bzk)
A x B = Axi x Bxi + Axi x Byj + Axi x Bzk +
Ayj x Bxi + Ayj x Byj + Ayj x Bzk +
Azk x Bxi + Azk x Byj + Azk x Bzk
A x B = AxBx (i x i) + AxBy (i x j) + Ax Bz (i x k) +
AyBx (j x i) + AyBy (j x j) + AyBz (j x k) +
AzBx (k x i) + AzBy (k x j) + AzBz (k x k)
UKarena i x i = j x j = k x k = 0 dan i x j = -j x i = k, j x k = -k x j = i, k x i = -i x k = j, ngakho-ke:
A x B = AxBx (0) + AxBy (k+ Ax Bz (-j+
AyBx (-k+ AyBy (0) + AyBz (i+
AzBx (j+ AzBy (-i+ AzBz (0)
A x B = AxBy (k+ Ax Bz (-j+
AyBx (-k+ AyBz (i+
AzBx (j+ AzBy (-i)
A x B = AxBy (k+ Ax Bz (-j+ AyBx (-k+ AyBz (i+ AzBx (j+ AzBy (-i)
A x B = ((AyBz - AzBy)i + (AzBx - Ax Bz)j + (AxBy - AyBx )k
Uma C = A x B bese kuba izingxenye ze C yilezi ezilandelayo:
Cx = AyBz - AzBy
Cy = AzBx - Ax Bz
Cz = AxBy - AyBx