Umkhiqizo we-Dot usebenzisa izingxenye ze-vector zeyunithi

Izinto Zokuphindaphinda Amachashazi Ezisebenzisa Izingxenye Zevektha Yeyunithi

Singabala umkhiqizo we-scalar ngqo uma sazi izingxenye ze-x, y kanye ne-z zama-vectors u-A no -B (ama-vectors aziwayo).

Ukuze senze umkhiqizo wechashazi ngale ndlela, siqala ngokwenza umkhiqizo wechashazi wamavektha eyunithi, ngemva kwalokho siveza amavektha u-A no -B ezingxenyeni zawo, sihlukanise umkhiqizo bese sisebenzisa umkhiqizo wamavektha eyunithi.

Amavekhtha eyunithi u-i , u-j, no -k aqondene, okwenza izibalo zibe lula. Sisebenzisa i-scalar multiplication equation etholakala ngenhla ( AB = AB cos theta ), sithola:

i. i = j . j = k . k = (1)(1) cos 0 = 1

i. j = i. k = j. k = (1)(1) cos 90 o = 0

Manje siveza amavekhtha u-A no-B ngokwezakhi zawo, sihlukanise umkhiqizo wawo bese sisebenzisa umkhiqizo wamavekhtha eyunithi.

A . B = Axi . Bxi + Axi . Byj + Axi . Bzk +

Ayj . Bxi + Ayj . Byj + Ayj . Bzk +

Azk . Bxi + Azk . Byj + Azk . Bzk

A . B = AxBx (i . i) + AxBy (i . j) + Ax Bz (i . k) +

AyBx (j . i) + AyBy (j . j) + AyBz (j . k) +

AzBx (k . i) + AzBy (k . j) + AzBz (k . k)

UKarena i . i = j . j = k . k = 1 kanye i . j = i . k = j . k = 0, bese kuba:

A . B = AxBx (1) + AxBy (0) + Ax Bz (0) +

AyBx (0) + AyBy (1) + AyBz (0) +

AzBx (0) + AzBy (0) + AzBz (1)

A. B = A x B x ( 1) + 0 + 0 +

0 + A y By y (1) + 0 +

0 + 0 + A z B z (1)

A . B = AxBx + AyBy + AzBz

Ngokusekelwe emiphumeleni yalesi sibalo, kungaphethwa ngokuthi umkhiqizo we-scalar noma umkhiqizo we-dot wama-vector amabili yisamba semikhiqizo yezingxenye zawo ezifanayo.

Isibonelo Sombuzo 1:

Umkhiqizo we-dot usebenzisa izingxenye ze-vector yeyunithi 1Ivektha enkulu A dan B ngokulandelana ziyi-5 kanye ne-4, njengoba kuboniswe esithombeni esingezansi. I-engeli eyakhiwe ingu-90o. Yibale umkhiqizo wamachashazi womabili ama-vector.

Ingxoxo

Ngaphambi kokuba sibale umkhiqizo wamachashazi wamavekhtha u-A no-B, sidinga kuqala ukwazi izingxenye zevekhtha yesibili.

A x = (5) cos 0 o = (5) (1) = 5

A y = (5) isono 0 o = (5) (0) = 0

A z = 0

B x = (4) cos 90 o = (4) (0) = 0

B y = (4) isono 90 o = (4) (1) = 4

B z = 0

Ivekhtha A inezingxenye zevekhtha kuphela ku-x-axis kanti ivekhtha B inezingxenye zevekhtha kuphela ku-y-axis. Ingxenye ka-z ingu-zero ngoba amavekhtha u- A no -B asendizeni ye-xy.

Manje sibala umkhiqizo wamachashazi phakathi kwamavekhtha u-A no -B sisebenzisa i-dot product equation namavekhtha ezingxenye:

A. B = Ax Bx + AyBy + AzBz

A. B = (5) (0) + (0) (4) + 0

A. B = 0 + 0 + 0

A. B = 0

Ake siqhathanise nendlela yokuqala

AB = AB cos theta

AB = (4)(5) cos 90

I-AB = (4) (5) (0)

AB = 0

Umphumela uyafana.

Isibonelo Sombuzo 2:

Umkhiqizo we-dot usebenzisa izingxenye ze-vector yeyunithi 2Ivektha enkulu A dan B zingu-5 no-4 ngokulandelana, njengoba kuboniswe esithombeni esingezansi. Bala umkhiqizo wamachashazi womabili amavekhtha, uma i-engeli eyakhiwe ingu-30o

Ingxoxo

Ngaphambi kokuba sibale umkhiqizo wamachashazi wamavekhtha u-A no-B, sidinga kuqala ukwazi izingxenye zevekhtha yesibili.

Umkhiqizo we-dot usebenzisa izingxenye ze-vector yeyunithi 3

Ingxenye ka-z ingu-zero ngoba amavektha u-A no -B asendizeni ye-xy.

Manje sibala umkhiqizo wamachashazi phakathi kwamavekhtha u-A no -B sisebenzisa i-dot product equation namavekhtha ezingxenye:

Umkhiqizo we-dot usebenzisa izingxenye ze-vector yeyunithi 4

Qhathanisa nendlela yokuqala.

Umkhiqizo we-dot usebenzisa izingxenye ze-vector yeyunithi 5

Shiya amazwana