Isayensi

Funda ngezibonelo zezinkinga zokuphazamiseka kanye nokusabalala kokukhanya - i-diffraction grating , bese usebenza ngezinkinga zokuphazamiseka kanye nokusabalala kokukhanya.

1. I-diffraction grating enemigqa engu-4000 njalo nge-1 cm ifakiwe ebangeni elingamamitha angu-1 ukusuka endaweni ekhanyisiwe. Bala ubude bokukhanya uma isithombe esiphezulu se-oda lokuqala singama-30 cm ukusuka endaweni ekhanyisiwe.
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Kuyaziwa ukuthi:
d = 1 / (imigqa engu-4000 / cm) = 0,00025 cm = 2,5 x 10^-4 cm = 2,5 x 10^-6 m
l = 1 m
y = 30 cm = 0,3 m
Kubuziwe: ubude be-wavelength (lambda)

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4 Izibonelo zesivinini esimaphakathi kanye nesivinini esimaphakathi

1. Imoto ihamba iqonde empumalanga amamitha ayi-100 ngemizuzwana emi-4 bese iqonda entshonalanga amamitha angama-50 ngomzuzwana owodwa. Thola ukuthi imoto iqonde empumalanga amamitha ayi-100 ngemizuzwana emi-4. isivinini esimaphakathi dan isivinini esimaphakathi imoto.
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Ibanga = amamitha ayi-100 + amamitha angama-50 = amamitha ayi-150
Inani lokufuduka = ​​amamitha ayi-100 – amamitha angama-50 = amamitha angama-50 futhi indlela yokufuduka ibheke empumalanga.
Isikhathi esiphelele = imizuzwana emi-4 + isekhondi eli-1 = imizuzwana emi-5.

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4 Izibonelo zemibuzo yebanga kanye nokufuduka

1. Imoto iqonde empumalanga amamitha ayi-100 bese iqonda entshonalanga amamitha angama-50. Thola ibanga kanye nokufuduka kwemoto kusukela endaweni yayo yokuqala.
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Ibanga = amamitha ayi-100 + amamitha angama-50 = amamitha ayi-150
Inani lokufuduka = ​​amamitha ayi-100 – amamitha angama-50 = amamitha angama-50 futhi indlela yokufuduka ibheke empumalanga.

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Izibonelo eziyi-10 zokunyakaza okuqondile okusheshiswa ngokulinganayo

1. Imoto iqala ingami. Ngemva kwemizuzwana emi-10, ijubane lemoto liyakhuphuka lifike ku-20 m/s. Nquma ukusheshisa kwemoto!
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Ayikho ifomula (sebenzisa i-logic) :
Ijubane lemoto lishintsha libe ngu-20 m/s ngemva kwemizuzwana eyi-10. Lokhu kusho ukuthi ijubane lemoto likhuphuka ngo-2 m/s njalo ngomzuzwana. Ngakho-ke, ukusheshisa kwemoto kungu-2 m/s ngomzuzwana = 2 m/s ngomzuzwana = 2 m/s².
Ukusebenzisa ifomula :
Kuyaziwa ukuthi:
Ijubane lokuqala (v)_o) = 0 (imoto ayimi)

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Izibonelo Ezi-7 Zezinkinga Zokunyakaza Okulinganayo Okuqondile

1. Isithuthuthu sihamba emgqeni oqondile ngesivinini esingaguquki esingu-10 m/s. Thola ibanga elihanjwe yisithuthuthu ngemva kwemizuzwana eyi-10 nemizuzwana engama-60.

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Isivinini esingaguquki = 10 m/s noma amamitha ayi-10 ngomzuzwana kusho ukuthi isithuthuthu sihamba amamitha ayi-10 njalo ngomzuzwana.
Ngemva kwemizuzwana emi-2, isithuthuthu sihamba amamitha angama-20,
Ngemva kwemizuzwana emi-5, isithuthuthu sihamba amamitha angama-50,
Ngemva kwemizuzwana engama-10, isithuthuthu sihamba amamitha angama-100.,
Ngemva kwemizuzwana engama-60, isithuthuthu sihamba amamitha angama-600..

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Izibonelo eziyi-19 zemibuzo yokunyakaza okuqondile

1. Bheka igrafu yejubane (v) ngesikhathi (t) sento ehamba emgqeni oqondile. Ubukhulu bokwehla kwejubane okubonwa yinto….
A. 2,5 ms^-2
B. 3,5 ms^-2
C. 4,0 ms^-2
D. 5,0 ms^-2
E. 6,0 ms^-2
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Izibonelo ezi-3 zemithetho kaKepler

1. Ibanga elijwayelekile ukusuka eplanethini yoMhlaba ukuya elangeni lingu-149,6 x 10⁶ km kanti isikhathi sokuguquka koMhlaba singunyaka owodwa. Iyini isilinganiso esingaguquki sesikwele sesikhathi ne-cube yebanga eliphakathi ukusuka eMhlabeni kuya eLangeni?
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Lo mbuzo uhlobene no Imithetho kaKepler.
Kuyaziwa ukuthi:
T = unyaka ongu-1, r = 149,6 x 10⁶ km
Kubuziwe: T² /r³ = … ?
Impendulo:

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Izibonelo ezi-4 zezinkinga zokusheshisa amandla adonsela phansi

1. Kukhulu kangakanani ukusheshisa kwamandla adonsela phansi ebusweni benyanga? Ubunzima benyanga = 7,35 x 10²² kg, irediyasi yenyanga = amamitha ayi-1.740.000, i-universal gravitational constant (G) = 6,67 x 10^-11 N m² /kg²
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Ifomula yomthetho wesibili kaNewton:

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Izibonelo ezi-3 zoMthetho kaNewton wamandla adonsela phansi

1. Amandla adonsela phansi amakhulu kangakanani phakathi komfundi onobunzima obungama-40 kg nomfundi wesifazane onobunzima obungama-30 kg abaqhelelene ngamamitha ama-2? I-universal gravitational constant = 6,67 x 10 ^-11 N m ² / kg ²

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Lo mbuzo uhlobene no Umthetho kaNewton wamandla adonsela phansi
Kuyaziwa ukuthi:
m₁ = 40 kg, m₂ = 30 kg, r = 2 m, G = 6,67 x 10^-11 N m² /kg²
Umbuzo: Amandla adonsela phansi (F) makhulu kangakanani?

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