Te tere koki me te tere rārangi – ngā raruraru me ngā otinga

1. Kei te porowhita whakapae te porowhita i te pito o te aho, he 2 mita te whānui o te pūtoro i te tere koki pumau 10 rad/s. Tātaihia te rahi o te tere rārangi o tētahi pūwāhi kei:

(a) 0.5 mita mai i te pokapū

(b) 1 mita mai i te pokapū

(c) 2 mita mai i te pokapū

Mōhiotia:

pūtoro (r) = 0.5 mitas, 1 mita, 3 mita

Te tere koki = 10 rātianas/seāhuatanga

E hiahiatia ana: te tere rārangi

Rongoā:

v = r ω

v= te tere rārangi, r = pūtoro, ω = te tere koki

(a) Ko te tere rārangi (v) o tētahi pūwāhi kei r = 0.5 mita

v = r ω = (0.5 mitas)(10 rad/s) = 5 mitas/seāhuatanga

(B) Te tere raina (V) o tētahi pūwāhi kei r = 1 mita

v = r ω = (1 mita)(10 rad/s) = 10 mitas/seāhuatanga

(c) Te tere raina (V) o tētahi pūwāhi kei r = 2 mitas

v = r ω = (2 mitas)(10 rad/s) = 20 mitas/seāhuatanga

A hi'o atoa  Ngā ngaru whakawhiti me ngā ngaru roa – ngā raruraru me ngā otinga

2. Ka huri ngā mata o te mīhini whakaranu i te tere o te 5000 rpm. Tātaihia te rahi o te tere raina:

(a) he pūwāhi kei te 5 cm mai i te pokapū

(B) he pūwāhi kei te 10 cm mai i te pokapū

Mōhiotia:

pūtoro (r) = 5 henimita me 10 cm

Te tere koki (ω) = 5000 hurihanga / 60 hēkonaoro = 83.3 hurihanga / seāhuatanga = (83.3)(6.28 ngā rātiana) / seāhuatanga = 523.3 rātianas / seāhuatanga

E hiahiatia ana: Te rahi o te tere rārangi

Rongoā:

(a) Te rahi o te tere rārangi o tētahi pūwāhi kei te 0.05 m mai i te pokapū

v = r ω = (0.05 m)(523.3 (rad/s) = 26 m/s

(B) Te rahi o te tere rārangi o tētahi pūwāhi kei te 0,1 m mai i te pokapū

v = r ω = (0.1 m)(523.3 (rad/s) = 52 m/s

3. He pūwāhi i te taha o te wira 30 cm i roto i te radius, huri noa i tētahi porowhita i te tere pumau 10 mita/hekona.

He aha te rahi o te tere koki?

Mōhiotia:

Pūtoro (r) = 30 cm = 0.3 mitas

Te tere raina (v) = 10 mitas/seāhuatanga

E hiahiatia ana: te tere koki

Rongoā:

ω = v / r = 10 / 0.3 = 33 ngā rātianas/seāhuatanga

A hi'o atoa  Ohm's law - problems and solutions

4. He motuka he 50 henimita te whānui o ngā potae haerels 10 mita ki roto 1 tuarua. He aha te tere koki?

Mōhiotia:

pūtoro (r) = 0.25 mita

Te tere rārangi o tētahi te pito i te taha o te potae (v) = 10 mitas/seāhuatanga

Hiahia: Te tere koki

Rongoā:

ω = v / r = 10 / 0.25 = 40 ngā rātianas/seāhuatanga

5. Ko te tere koki o te wira 20 cm i roto i ngā rātiana he 120 rpm. He aha te tawhiti mēnā ka haere te motuka i roto i te 10 hēkona.

Mōhiotia:

pūtoro (r) = 20 henimita = 0.2 mitas

Te tere koki = 120 whakahou / 60 hēkonangā āhuatanga = 2 whakahou / seāhuatanga = (2)(6.28) rātianas / seāhuatanga = 12.56 rātianas / seāhuatanga

E hiahiatia ana: tawhiti

Rongoā:

tere o te taha o te wira:

v = r ω = (0.2 mitas)(12.56 rātianas/seāhuatanga) = 2.5 mitas/seāhuatanga

2.5 mitas / seKo te tikanga o te cond he pūwāhi kei te taha o te haere o te wira. 2.5 mitas ia hēkona kotahi. I muri 10ngā āhuatanga, ka haere te pūwāhi 25 mitas.

Na ko te tawhiti 25 mitas.

A hi'o atoa  Manometer tube – problems and solutions

[wpdm_package id='427′]

[wpdm_package id='439′]

  1. Te huri i ngā waeine koki hei tauira mō ngā raruraru me ngā otinga
  2. Ngā tauira raruraru me ngā otinga mō te nekehanga koki me te nekehanga rārangi
  3. Ngā tauira rapanga tere koki me te tere raina me ngā otinga
  4. Ngā tauira rapanga whakaterenga koki me te whakaterenga raina me ngā otinga
  5. Ngā tauira rapanga nekehanga porowhita ōrite me ngā otinga
  6. Ngā raruraru tauira whakaterenga pūrua me ngā otinga
  7. Ngā tauira o ngā nekehanga porowhita kore-taurite me ngā otinga

Waiho i te Comment