Tauira o ngā pātai Āhuatanga

21 Ngā Tauira o Ngā Pātai Āhuatanga

Te Whakanuia o te Roa

1. Ka piki ake te roa o tētahi tokotoko ōrite, he L te roa, ina tōia ki te kaha F.

Nō reira, ka eke te roa ki te 4 ΔL, ko te rahi o te kaha kume ko...

A. 1/4 F

B. 1/2 F

C. 2 F

D. 4 F

E. 16 F

Kōrero

E mōhiotia ana:

Te kaha kume 1 (F ₁ ) = F

Te pikinga o te roa 1 (∆L ₁ ) = ∆L

Te pikinga o te roa 2 (∆L ₂ ) = 4 ∆L

Pātai: Te kaha kukume 2 (F ₂ )

Whakautu:

Te tauira ture a Hooke:

k = F / ΔL

Whakaahuatanga: k = pūmau rapa, F = kaha kume, ΔL = pikinga o te roa

He rite tonu ngā tokotoko i whakamahia, kia rite ai te pūmau rapa (k).

k1 = _k2​

F ₁ / ∆L ₁ = F ₂ / ∆L ₂

F / ΔL = F ₂ / 4ΔL

Wh / 1 = Wh ₂ / 4

F = F ₂ / 4

F ₂ = 4F

Ko te whakautu tika ko D.

2. E toru ngā puna ōrite, he 200 N/m te pūmau o ia puna, kua whakaritea kia rite ki te pikitia. Ina hoatu he kawenga 100 karamu (te whakaterenga ā-papatipu g = 10 m/s), ko te pikinga o te roa o te huihuinga puna ko...

A. x = 0,50 cm

B. x = 0,75 henimita

C. x = 0,85 henimita

D. x = 1,00 cm

E. x = 1,50 cm

Kōrero

E mōhiotia ana :

Papatipu kawenga (m) = 100 karamu = 0,1 kg

k1 = k2 ₌ k3 _{= 200} N/m

w = mg = (0,1 kg)(10 m/s² ⁾ = 1 kg m/s² ⁼ 1 Newton

I pātaihia Te pikinga o te roa whānui o te puna ?

Whakautu :

Te whakatau i te pūmau puna whakakapinga

Koanga 2 (k₂) me te puna 3 (k₃) kua whakaritea kia whakarara. Ko te pūmau puna ōrite ko:

kp ₌ k2 + k3 ₌ 200 + 200 = 400 _Nm ⁻¹

Kua whakaritea te puna 1 (k1 ₎ me te puna whakakapinga whakarara (kP _{) kia raupapa. Ko te pūmau puna whakakapinga ko:}

1/k _s = 1/k _p + 1/k ₁ = 1/400 + 1/200 = 1/400 + 2/400 = 3/400

k _s = 400/3 Nm ⁻¹

Ko te pūmau puna ōrite mō te whakaritenga puna raupapa-whakarara ko 400/3 Nm ^-1

Te whakatau i te pikinga o te roa o te puna

Te tauira ture a Hooke:

= F / k = w / k

Ko te pikinga o te roa o te puna ko:

= w / k

= 1 : 400/3 = 1 x 3/400 = 3/400 = 0,0075 mita = 0,75 henimita

Ko te whakautu tika ko B.

Pūmau Puna

3. I roto i tētahi whakamātautau mō te ngāwari o tētahi puna, i riro mai ngā raraunga e whakaaturia ana i te ripanga i raro nei. Ka taea te whakatau ko te uara o te pūmau puna ko….

A. 1.002 N/m

B. 1.201 N/m

C. 1.225 N/m

D. 1.245 N/m

E. 1.250 N/m

Kōrero

Te tauira ture a Hooke:

k = F / Δx

Pūmau puna:

k = 0,98/0,0008 = 1,96/0,0016 = 2,94/0,0024 = 3,92/0,0032 = 1.225 N/m

Ko te whakautu tika ko C.

4. E toru ngā puna kua whakaritea e whakaaturia ana i te pikitia e whai ake nei. Mēnā ko ngā pūmau puna k ₁ = k ₂ = 3 Nm ⁻¹ me k ³ = 6 Nm ⁻¹ , ko te pūmau puna ko…..

A. 1 Nm^-1

B. 3 Nm ⁻¹

C. 7,5 Nm ⁻¹

D. 12 Nm ⁻¹

E. 15 Nm ⁻¹

Kōrero

E mōhiotia ana:

Pūmau puna 1 (k ₁ ) = pūmau puna 2 (k ₂ ) = 3 Nm ⁻¹

Pūmau puna 3 (k ₃ ) = 6 Nm ⁻¹

I pātaihia: pūmau puna (k)

Whakautu:

Kei te whakarite whakarara te puna 1 (k1 ₎ me te puna 2 (k2 _{) . Ko te pūmau puna ōrite ko:}

kp ₌ k1 + k2 ₌ 3 + 3 = 6 _Nm ⁻¹

Kua whakaritea te puna whakakapinga whakarara (kP ₎ me te puna 3 (k3 _{) kia raupapa. Ko te pūmau puna whakakapinga ko:}

1/k _s = 1/k _p + 1/k ₃ = 1/6 + 1/3 = 1/6 + 2/6 = 3/6

k _s = 6/2 = 3 Nm ⁻¹

Ko te pūmau puna ōrite mō te whakaritenga puna raupapa-whakarara i runga ake nei ko 3 Nm ⁻¹

Ko te whakautu tika ko B.

5. Ka tōia he puna, ko te roa o L, e te kawenga w i ia wā, ā, ko ngā raraunga i riro mai koia ēnei kei roto i te ripanga e whai ake nei. I runga i ngā raraunga o te ripanga, ka taea te whakatau ko te rahi o te pūmau puna ko….

A. 300 Nm^-1

B. 500 Nm ^-1

C. 600 Nm ^-1

D. 800 Nm ^-1

E. 1000 Nm ^-1

Kōrero

Te tauira ture a Hooke:

k = F /

Pūmau puna:

k = 10/0,02 = 20/0,04 = 30/0,06 = 40/0,08 = 500 Nm ^-1

Ko te whakautu tika ko B.

6. Ko ngā raraunga kei roto i te ripanga whakamātautau e whai ake nei ko ngā hua o tētahi whakamātautau e pā ana ki te ngāwari o ngā mea. I roto i te whakamātautau, ko te rauemi rapa i whakamahia he ngongo o roto o te motopaika. (g = 10 m/s ² ). I runga i te ripanga i runga ake nei, ka taea te whakatau ko te pūmau ngāwari o te rauemi rapa he….

A. 122 N/m

B. 96 N/m

C. 69 N/m

D. 56 N/m

E. 40 N/m

Kōrero

Te tauira ture a Hooke :

k = F / = w / = mg /

Whakaahuatanga: k = pūmau ngāwari, w = kaha ā-papa, m = papatipu, g = te whakaterenga nā te kaha ā-papa, = te pikinga o te roa o te rapa

Pūmau puna:

k = 2/0,05 = 4/0,1 = 6/0,15 = 8/0,20 = 10/0,25 = 40 N/m

Ko te whakautu tika ko E.

7. E toru ngā puna kua whakaritea e whakaaturia ana i te pikitia e whai ake nei. Mena ko te pūmau puna K1 ₌ 4K, ko te uara o te pūmau whakaritenga puna ko ….

A. 3/4K

B. 3K/4

C. 4K/3

D. 3K

E. 4K

Kōrero

E rua ngā puna e whakarite ana kia whakarara. Ko te pūmau puna ōrite o ngā puna e rua e whakarite ana kia whakarara ko:

kp ₌ K + K = 2K

E rua ngā puna e raupapa ana. Ko te pūmau puna ōrite o ngā puna e rua e raupapa ana ko:

1/k _s = 1/k _p + 1/K ₁ = 1/2K + 1/4K = 2/4K + 1/4K = 3/4K

k _s = 4K/3

Ko te pūmau puna ōrite mō te whakaritenga puna i runga ake nei ko 4K/3

Ko te whakautu tika ko C.

8. Ka whakairihia he here rapa, ko te roa o L, ki tētahi kawenga kia rite ai ngā raraunga e whiwhihia ana ki te ripanga. I runga i te ripanga, ka taea te whakatau ko te rahi o te pūmau puna ko….

A. 250 Nm^-1

B. 360 Nm ^—1

C. 400 Nm ^—1

D. 450 Nm ^—1

E. 480 Nm ^—1

Kōrero

Te tauira ture a Hooke:

k = F /

Pūmau puna:

k = 2/0,0050 = 3/0,0075 = 4/0,01 = 400 Nm ^-1

Ko te whakautu tika ko C.

9. Mātakihia ngā raraunga whakamātautau o ngā momo potae rapa e rima, A, B, C, D, me E, e tōia ana ki te kaha F kia roa ake ai tō rātou roa. Ko te potae rapa me te pūmau puna iti rawa ko…

Kōrero

Te tauira ture a Hooke:

k = F / Δx

Whakaahuatanga: k = pūmau rapa, F = kaha, Δx = pikinga o te roa o te rapa

Te pūmau o te ngāwari o te rapa:

k _A = F / Δx = 1 / 0,05 = 20 N/m

kB = F / Δx = 2 / 0,025 = 80 N/ _m

kC = F / Δx = 1 / 0,025 = 40 N/ _m

k _D = F / Δx = 2 / 0,05 = 40 N/m

k _E = F / Δx = 2 / 0,25 = 8 N/m

Ko te whakautu tika ko E.

10. Mai i te whakamātautau hei whakatau i te ngāwari o te rapa mā te whakamahi i te rapa potae, ko ngā raraunga i whiwhihia koia kei roto i te ripanga e whai ake nei. Ka taea te whakatau ko te uara pūmau nui rawa atu ko te whakamātautau….

Kōrero

Te tauira ture a Hooke:

k = F / Δx

Pūmau puna:

k _A = 7/0,035 = 200 Nm ^-1

kB = 8/0,025 = 320 _Nm ^-1

kC = 6/0,020 = 300 _Nm ^-1

kD = 9/0,045 = 200 _Nm ^-1

k _E = 10/0,033 = 303 Nm ^-1

Ko te pūmau rapa nui rawa atu ko 320 Nm ^-1.

Ko te whakautu tika ko B.

11. E whakaatu ana te kauwhata i raro nei i te whanaungatanga i waenga i te huringa o te kawenga (ΔF) me te pikinga o te roa (ΔX), te kauwhata e whakaatu ana i te uara iti rawa o te pūmau rapa...

Kōrero

Te tauira ture a Hooke

k = F / Δx

Ngā Mōhiohio:

Δx = te pikinga o te roa, F = te kaha, k = te pūmau rapa

Pūmau te ngāwari

k _A = F / Δx = 1 / 8 = 0,125

k _B = F / Δx = 8 / 3 = 2,7

kC = F / Δx = 6 / 6 = ₁

k _D = F / Δx = 3 / 5 = 0,6

k _E = F / Δx = 2 / 4 = 0,5

Ko te whakautu tika ko A.

12. Tirohia te kauwhata o te whanaungatanga i waenga i te kaha (F) me te pikinga roa (ΔX) i raro nei! Ko tēhea te mea kei a ia te pūmau rapa nui rawa atu?

Kōrero

Pūmau te ngāwari

kA ₌ F / Δx = 50 / 10 = 5

k _B = F / Δx = 50 / 0,1 = 500

kC = F / Δx = 5 / 0,1 = ₅₀

k _D = F / Δx = 500 / 0,1 = 5000

k _E = F / Δx = 500 / 10 = 50

Ko te whakautu tika ko D.

Pūngao Pūmanawa o te Koanga

13. E whakaatu ana te kauwhata (Fx) i te whanaungatanga i waenga i te kaha me te pikinga o te roa o te puna. Ko te rahi o te pūngao pūmanawa o te puna i runga i te kauwhata i runga ake nei ko...

A. 20 joule

B. 16 joule

C. 3,2 joule

D. 1,6 joule

E. 1,2 joules

Kōrero

E mōhiotia ana:

F = 40N

x = 0,08 mita

Pātai: Te pūngao pūmanawa o te puna

Whakautu:

Pūmau puna:

k = F / Δx = 40/0,08 = 500 N/m

Pūngao pūmanawa o te puna:

EP = 1/2 kx ² = 1/2 (500)(0,08) = (250)(0,08) = 20 Joule

Ko te whakautu tika ko A.

14. Ka tukuna he kawenga ki tētahi puna e 2 kg te taumaha, e ai ki te pikitia e whai ake nei. Mēnā ka piki ake te roa o te puna e 5 cm, ā, ko te whakaterenga nā te kaha ā-papa he 10 ms ^-2 , ko te kaha pūmanawa pūmau o te puna ko...

A. 4,0 J

B. 3,0 J

C. 2,5 J

D. 1,0 J

E. 0,5 J

E mōhiotia ana :

Te pikinga o te roa (Δx) = 5 cm = 0,05 mita

Te whakaterenga nā te kaha ā-papa (g) = 10 m/s ²

Papatipu o te kawenga (m) = 2 kg

Taumaha kawenga (w) = mg = (2)(10) = 20 Newton

Pātai : Te pūngao pūmanawa o te rapa?

E mōhiotia ana :

Te pikinga o te roa (Δx) = 5 cm = 0,05 mita

Te whakaterenga nā te kaha ā-papa (g) = 10 m/s ²

Papatipu o te kawenga (m) = 2 kg

Taumaha kawenga (w) = mg = (2)(10) = 20 Newton

Pātai : Te pūngao pūmanawa o te rapa?

15. Hei totoro i tētahi puna kia 5 cm, me whakamahi he kaha 20 N. Ko te kaha pūmanawa o te puna ina totoro kia 10 cm ko...

A. 2 Joules

B. 4 Joules

C. 20 Joule

D. 50 Joule

E. 100 Joule

Kōrero

E mōhiotia ana :

Te pikinga o te roa (Δx) = 5 cm = 0,05 mita

Te Kaha (F) = 20 Newton

Pātai : He aha te EP o te puna ina totoro te puna ki te 10 cm?

Whakautu :

Pūmau puna:

k = F / Δx = 20 / 0,05 = 400 N/m

Ko te pūngao pūmanawa o te puna ina Δx = 10 cm = 0,1 mita:

EP = ½ k Δx ² = ½ (400)(0,1) ² = (200)(0,01)

EP = 2 Joule

Ko te whakautu tika ko A.

Berat Beban

16. 

A. 6 N

B. 12 N

C. 30 N

D. 45 N

E. 60 N

E whā ngā puna ōrite, ia puna he pūmau rapa o te 800 Nm ⁻¹ , kua whakaritea kia raupapa, kia whakarara hoki (tirohia te pikitia). Mā te kawenga iri w ka piki ake te roa o te pūnaha puna ki te 5 cm. Ko te taumaha o te kawenga w ko…

Kōrero

E mōhiotia ana :

k1 = k2 ₌ k3 ₌ k4 _{= 800} N m ⁻¹

= 5 henimita = 0,05 mita

I pātaihia : te taumaha o te kawenga (w)?

Whakautu :

Te whakatau i te pūmau puna whakakapinga

Koanga 1 (k₁), puna 2 (k₂) me te puna 3 (k₃) kua whakaritea kia whakarara. Ko te pūmau puna ōrite ko:

kp ₌ k1 ₊ k2 + k3 ₌ 800 + 800 + 800 = 2400 _Nm ⁻¹

Kua whakaritea te puna whakakapinga whakarara (kP ₎ me ngā puna e 4 (k4 _{) kia raupapa. Ko te pūmau puna whakakapinga ko:}

1/k _s = 1/k _p + 1/k ₄ = 1/2400 + 1/800 = 1/2400 + 3/2400 = 4/2400

k _s = 2400/4 = 600 Nm ⁻¹

Ko te pūmau puna ōrite mō te whakaritenga puna raupapa-whakarara i runga ake nei ko 600 Nm ^-1

Te whakatau i te taumaha o te kawenga

Te tauira ture a Hooke:

F = k rānei w = k

Ko te taumaha o te kawenga ko:

w = (600 Nm ^-1 )(0,05 m) = 30 Ngā Niutona

Ko te taumaha o te kawenga he 30 Newtons.

Ko te whakautu tika ko C.

17. E whā ngā puna ōrite, he 1600 N/m te pūmau rapa o ia puna, kua whakaritea kia raupapa, kia whakarara hoki (tirohia te pikitia). Nā te kawenga iri w ka piki ake te roa o te pūnaha puna ki te 5 cm. Ko te taumaha o te kawenga w ko….

A. 60 N

B. 120 N

C. 300 N

D. 450 N

E. 600 N

Kōrero

E mōhiotia ana :

k1 = k2 ₌ k3 ₌ k4 _{= 1600} N m ⁻¹

= 5 henimita = 0,05 mita

I pātaihia : te taumaha o te kawenga (w)?

Whakautu :

Te whakatau i te pūmau puna whakakapinga

Kei te whakarite whakarara te puna 1 (k1 ₎ , te puna 2 (k2 ₎ me te puna 3 (k3 _{) . Ko te pūmau puna ōrite ko:}

k _P = k ₁ + k ₂ + k ₃ = 1600 + 1600 + 1600 = 4800 Nm ⁻¹

Kua whakaritea te puna whakakapinga whakarara (kP ₎ me ngā puna e 4 (k4 _{) kia raupapa. Ko te pūmau puna whakakapinga ko:}

1/k _s = 1/k _p + 1/k ₄ = 1/4800 + 1/1600 = 1/4800 + 3/4800 = 4/4800

k _s = 4800/4 = 1200 Nm ⁻¹

Ko te pūmau puna ōrite mō te whakaritenga puna raupapa-whakarara ko 1200 Nm ^-1

Te whakatau i te taumaha o te kawenga

Te tauira ture a Hooke:

F = k rānei w = k

Ko te taumaha o te kawenga ko:

w = (1200 Nm ^-1 )(0,05 m) = 60 Ngā Niutona

Ko te taumaha o te kawenga he 60 Newtons.

Ko te whakautu tika ko A.

Te rapa me te kirihou

18. Tirohia te kauwhata o te whanaungatanga i waenga i te kaha ΔF me te pikinga o te roa Δx i runga i te puna i raro nei!

E ai ki te kauwhata, ka noho pīngore tonu te puna i te kaha kume o te….

A. 0 ki te 4 N

B. 0 ki te 8 N

C. 0 ki te 12 N

D. 8 N ki te 12 N

E. 8 ki te 16 ki te Raki

Kōrero

Ka noho pūmau te puna ki te ngāwari mena ka pā tonu te ture a Hooke ki a ia. Mā te pāngarau, ka whakaatuhia te ture a Hooke e te tātai:

k = ΔF / Δx

Whakaahuatanga tātai:

k = pūmau rapa, ΔF = kaha, Δx = roa o te puna

E ai ki te ture a Hooke, he pumau tonu te ōwehenga o te huringa o te kaha (ΔF) ki te huringa o te roa (Δx) o te puna. Mēnā ka huri te uara o k, kāore te ture a Hooke e pā ki te puna, ā, e tohu ana tēnei kāore te puna e ngāwari ana.

Mātakitakina te kauwhata i runga ake nei, kia mārama ai ki ngā tātaitanga e whai ake nei.

k ₁ = ΔF / Δx = 4 / 2 = 2

k ₂ = ΔF / Δx = 8 / 4 = 2

k ₃ = ΔF / Δx = 12 / 7 = 1,7

He pumau te pūmau puna (k) tae noa ki te kaha kume o te 8 Newton. Nō reira, ka noho pūmau te puna i ngā kaha kume o te 0 ki te 8 Newton.

Ko te whakautu tika ko B.

19. E whakaatu ana te kauwhata e whai ake nei i te whanaungatanga i waenga i te pikinga o te roa Δx me te kaha ΔF o te rapa e tōia ana e te kaha. I runga i te kauwhata, ka huri te āhua kirihou o te rapa ina pā te kaha ki te rapa...

A. 0 ki te 2 N

B. 0 ki te 4 N

C. 2 N ki te 6 N

D. 4 N ki te 8 N

E. 6 ki te 8 ki te Raki

Kōrero

Ka noho pūmau tonu te rapa ki te āhua pīwariwari mena ka mau tonu te pūmau pīwariwari. Mena ka tīmata te huri o te pūmau pīwariwari, ka tīmata te rapa ki te huri mai i te pīwariwari ki te kirihou. Ko te tikanga o te pīwariwari, i muri i te tangohanga o te kaha kume, ka hoki te rapa ki tōna āhua taketake. I tetahi atu taha, ko te tikanga o te kirihou, i muri i te tangohanga o te kaha kume, kāore te rapa e hoki ki tōna āhua taketake.

Mātakitakina te kauwhata i runga ake nei, kia mārama ai ki ngā tātaitanga e whai ake nei:

k ₁ = ΔF / Δx = 2 / 2 = 1

k ₂ = ΔF / Δx = 4 / 4 = 1

k ₃ = ΔF / Δx = 6 / 6 = 1

k ₄ = ΔF / Δx = 7 / 8 = 0,87

k ₄ = ΔF / Δx = 8 / 12 = 0,6

Ka rerekē te āhua o te rapa ina pāngia e te kaha o te 6 ki te 8 Newton. Mēnā he nui ake te kaha i te 8 Newton, ka whati te rapa.

20. Tirohia te kauwhata o te whanaungatanga i waenga i te kaha ΔF me te pikinga o te roa Δx i runga i te puna i raro nei!
E ai ki te kauwhata, ka noho pīngore tonu te puna i te kaha kume o te….

A. 0 ki te 4 N
B. 0 ki te 8 N
C. 0 ki te 12 N
D. 8 N ki te 12 N
E. 8 ki te 16 ki te Raki

Kōrero
Ka noho pūmau te puna ki te ngāwari mena ka pā tonu te ture a Hooke ki a ia. Mā te pāngarau, ka whakaatuhia te ture a Hooke e te tātai:
k = ΔF / Δx
Whakaahuatanga tātai:
k = pūmau rapa, ΔF = kaha, Δx = roa o te puna

E ai ki te ture a Hooke, he pumau tonu te ōwehenga o te huringa o te kaha (ΔF) ki te huringa o te roa (Δx) o te puna. Mēnā ka huri te uara o k, kāore te ture a Hooke e pā ki te puna, ā, e tohu ana tēnei kāore te puna e ngāwari ana.

Mātakitakina te kauwhata i runga ake nei, kia mārama ai ki ngā tātaitanga e whai ake nei.
k₁ = ΔF / Δx = 4 / 2 = 2
k₂ = ΔF / Δx = 8 / 4 = 2
k₃ = ΔF / Δx = 12 / 7 = 1,7

He pumau te pūmau puna (k) tae noa ki te kaha kume o te 8 Newton. Nō reira, ka noho pūmau te puna i ngā kaha kume o te 0 ki te 8 Newton.
Ko te whakautu tika ko B.

21. E whakaatu ana te kauwhata e whai ake nei i te whanaungatanga i waenga i te pikinga o te roa Δx me te kaha ΔF o te here rapa e tōia ana e te kaha. I runga i te kauwhata, ka huri te āhua kirihou o te rapa ina pā te kaha ki a ia...

A. 0 ki te 2 N
B. 0 ki te 4 N
C. 2 N ki te 6 N
D. 4 N ki te 8 N
E. 6 ki te 8 ki te Raki

Kōrero
Ka noho pūmau tonu te rapa ki te āhua pīwariwari mena ka mau tonu te pūmau pīwariwari. Mena ka tīmata te huri o te pūmau pīwariwari, ka tīmata te rapa ki te huri mai i te pīwariwari ki te kirihou. Ko te tikanga o te pīwariwari, i muri i te tangohanga o te kaha kume, ka hoki te rapa ki tōna āhua taketake. I tetahi atu taha, ko te tikanga o te kirihou, i muri i te tangohanga o te kaha kume, kāore te rapa e hoki ki tōna āhua taketake.

Mātakitakina te kauwhata i runga ake nei, kia mārama ai ki ngā tātaitanga e whai ake nei:
k₁ = ΔF / Δx = 2 / 2 = 1
k₂ = ΔF / Δx = 4 / 4 = 1
k₃ = ΔF / Δx = 6 / 6 = 1
k₄ = ΔF / Δx = 7 / 8 = 0,87
k₅ = ΔF / Δx = 8 / 12 = 0,6

Ka rerekē te āhua o te rapa ina pāngia e te kaha o te 6 ki te 8 Newton. Mēnā he nui ake te kaha i te 8 Newton, ka whati te rapa.

Ko te whakautu tika ko E.

Pūmau te ngāwari

22. Mātakihia ngā raraunga whakamātautau o ngā momo potae rapa e rima, A, B, C, D me E, e tōia ana ki te kaha F kia roa ake ai tō rātou roa. Ko te potae rapa me te pūmau puna iti rawa ko…
Kōrero

Te tauira ture a Hooke :
k = F / Δx
Whakaahuatanga: k = pūmau ngāwari, F = kāhua, Δx = te pikinga o te roa o te rapa
Te pūmau o te ngāwari o te rapa:
k_A = F / Δx = 1 / 0,05 = 20 N/m
k_B = F / Δx = 2 / 0,025 = 80 N/m
k_C = F / Δx = 1 / 0,025 = 40 N/m
k_D = F / Δx = 2 / 0,05 = 40 N/m
k_E = F / Δx = 2 / 0,25 = 8 N/m
Ko te whakautu tika ko E.

23. Mai i te whakamātautau hei whakatau i te ngāwari o te rapa mā te whakamahi i te rapa potae, ko ngā raraunga i whiwhihia koia kei roto i te ripanga e whai ake nei. Ka taea te whakatau ko te uara pūmau nui rawa atu ko te whakamātautau….
Kōrero
Te tauira ture a Hooke:
k = F / Δx
Pūmau puna:
k_A = 7/0,035 = 200 Nm^-1
k_B = 8/0,025 = 320 Nm^-1
k_C = 6/0,020 = 300 Nm^-1
k_D = 9/0,045 = 200 Nm^-1
k_E = 10/0,033 = 303 Nm^-1
Ko te pūmau rapa nui rawa atu ko te 320 Nm^-1.
Ko te whakautu tika ko B.

Pūtake pātai:

Ngā Pātai Ahupūngao Whakamātautau ā-Motu mō te Kura Tuarua/Kura Tuarua Mahi-ā-ringa