Ukusetshenziswa komthetho wokuqala we-thermodynamics kwezinye izinqubo ze-thermodynamic (i-Isobaric Isothermal Isochoric)

30 Ukusetshenziswa komthetho wokuqala we-thermodynamics kwezinye izinqubo ze-thermodynamic (i-Isobaric Isothermal Isochoric) 1. Igrafu engezansi ikhombisa umjikelezo we-thermodynamic obonwa yigesi. Umsebenzi owenziwe yigesi enqubweni i-ABCD … Yaziwa: Ingcindezi 1 (P1) = 2 x 105 Pa Ingcindezi 2 (P2) = 4 x 105 … Funda kabanzi

Umthetho wokuqala we-thermodynamics - izinkinga nezixazululo

30 Umthetho wokuqala we-thermodynamics – izinkinga nezixazululo 1. 3000 J wokushisa uyengezwa ohlelweni kanti 2500 J womsebenzi wenziwa uhlelo. Luyini ushintsho lwamandla angaphakathi ohlelweni? Okwaziwayo: Ukushisa (Q) = +3000 Joules Umsebenzi (W) = +2500 Joules Okufunwayo: ushintsho … Funda kabanzi

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo

1. Ngiphatha amagesi esitsheni esivaliwe ekuqaleni nginomthamo u-V kanye nomfutho u -P . Uma umfutho wokugcina ungu-4P futhi umthamo ugcinwa ungaguquguquki, siyini isilinganiso samandla okuqala e-kinetic namandla okugcina e-kinetic.

Kwaziwa:

Ingcindezi yokuqala (P 1 ) = P

Ukucindezela kokugcina (P 2 ) = 4P

Umthamo wokuqala (V 1 ) = V

Umqulu wokugcina (V 2 ) = V

Okufunwayo: Isilinganiso samandla okuqala e-kinetic namandla okugcina e-kinetic (K E 1 : K E 2 )

Isixazululo:

Ubudlelwano phakathi kwengcindezi (P), ivolumu (V) kanye namandla e-kinetic (KE) yamagesi afanele :

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo 18

Isilinganiso samandla okuqala e-kinetic namandla okugcina e-kinetic:

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo 19

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2. Iyini isilinganiso samandla e-kinetic esijwayelekile sama-molecule kugesi efanelekile ku-57 o C.

Kwaziwa:

Izinga lokushisa legesi (T) = 57 o C + 273 = 330 Kelvin

I- Boltzmann 's constant (k) = 1.38 x 10 -23 Joule/Kelvin

Okufunwayo: Amandla ajwayelekile e-kinetic okuhumusha

Isixazululo:

Ubudlelwano phakathi kwamandla e-kinetic (KE) kanye nokushisa kwegesi (T):

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo 3

Amandla ajwayelekile e-kinetic okuhumusha:

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo 4

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3. Igesi ku- 27 ° C esitsheni esivaliwe . Uma amandla e-kinetic egesi enyuka ngokuphindwe kabili kunamandla okuqala e-kinetic, ngakho-ke izinga lokushisa lokugcina legesi li...

Kwaziwa:

Izinga lokushisa lokuqala (T 1 ) = 27 o C + 273 = 300 K

Amandla okuqala e-kinetic = KE

Amandla okugcina e-kinetic = 4 K E

Okufunwayo: Izinga lokushisa lokugcina ( T2 )

Isixazululo:

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo 5

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4. Igesi efanelekile isesitsheni esivaliwe, iyashiswa ukuze ijubane lokugcina elimaphakathi lezinhlayiya zegesi likhuphuke ngokuphindwe kathathu kunejubane lokuqala elimaphakathi. Uma izinga lokushisa lokuqala legesi lingu- 27 ° C, khona-ke izinga lokushisa lokugcina legesi efanelekile lingu…

Kwaziwa:

Izinga lokushisa lokuqala = 27 o C + 273 = 300 Kelvin

Ijubane lokuqala = v

Ijubane lokugcina = 2v

Okufunwayo : Izinga lokushisa lokugcina legesi elifanele

Isixazululo:

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo 20

Ijubane lokugcina elimaphakathi = 2 x ijubane lokuqala elimaphakathi

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo 7

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5. Ama-mole amathathu egesi asendaweni yomthamo wamalitha angu-36. I-molecule ngayinye yegesi inamandla e-kinetic angu-5 x 10 -21 Joules. I-Universal gas constant = 8.315 J/mole.K kanye ne-Boltzmann's constant = 1.38 x 10 -23 J/K. Iyini ingcindezi yegesi esitsheni.

Kwaziwa:

Inani lama-moles (n) = ama-moles angu-3

Umthamo = amalitha angu-36 = 36 dm 3 = 36 x 10 -3 m 3

I-Boltzmann's constant (k) = 1.38 x 10 -23 J/K

Amandla e-Kinetic (KE) = 5 x 10 –21 Joules

I-gesi engaguquki yonke (R) = 8.315 J/mole.K

Okufunwayo : Umfutho wegesi (P)

Isixazululo:

Bala izinga lokushisa usebenzisa i-equation yamandla e-kinetic egesi.

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo 8

Bala ingcindezi yegesi usebenzisa i-th equation yomthetho wegesi ofanele (ngenani lama-moles, n):

I-PV = n RT

P (36 x 10 -3 ) = (3)(8.315)(241.5)

P (36 x 10 -3 ) = 6024.22

Ithiyori ye-kinetic yamagesi - izinkinga nezixazululo 9

Umfutho wegesi ungu-1.67 x 10 5 Pascal noma i-atmospheres engu-1.67.

Funda kabanzi

Umthetho wegesi ofanele - izinkinga nezixazululo

1. Ngikhipha amagesi esitsheni esivaliwe ekuqaleni nginomthamo u-V kanye nokushisa u-T. Izinga lokushisa lokugcina lingu-5/4T kanti ingcindezi yokugcina ingu-2P. Iyini ivolumu yokugcina yegesi?

Kwaziwa:

Umthamo wokuqala (V 1 ) = V

Izinga lokushisa lokuqala (T1 ) = T

Izinga lokushisa lokugcina (T2 ) = 5/4 T

Ingcindezi yokuqala (P 1 ) = P

Ukucindezela kokugcina (P 2 ) = 2P

Okufunwayo: Umqulu Wokugcina (V 2 )

Isixazululo:

Umthetho wegesi ofanele - izinkinga nezixazululo 1

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2. Thola ivolumu yama-mol angu-2.00 wamagesi (igesi ekahle) ku-STP. I-STP = Izinga Lokushisa Elijwayelekile kanye Nokucindezela.

Kwaziwa:

Ama-moles egesi (n) = ama-moles amabili eqhwa

Izinga lokushisa elijwayelekile (T) = 0 o C = 0 + 273 = 273 Kelvin

Ukucindezela okujwayelekile (P) = 1 atm = 1.013 x 10 5 Pa

I-Universal gas constant (R) = 8.315 Joule/mol e .Kelvin

Okufunwayo : Umthamo wamagesi (V)

Isixazululo:

Isilinganiso somthetho wegesi ofanele (ngenani lama-moles, n)

Umthetho wegesi ofanele - izinkinga nezixazululo 2

Umthamo wama-moles amabili amagesi ungamalitha angu-44.8.

Umthamo we-mole eyi-1 yamagesi ungamalitha angu-45.4 / 2 = amalitha angu-22.4.

Umthamo we-mole eyi-1 yanoma iyiphi igesi ungamalitha angu-22.4.

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3. Amalitha angu-4 egesi yomoya-mpilo anokushisa okungu-27°C kanye nokucindezela okungu-2 atm (1 atm = 10 5 Pa) esitsheni esivaliwe. I-Universal gas constant (R) = 8.314 J.mol e −1 .K −1 kanye nenombolo ka-Avogadro ( N ​​A ) = 6.02 x 10 23 ama-molecule/mol e . Ayini ama-molecule egesi yomoya-mpilo esitsheni?

Kwaziwa:

Umthamo wamagesi (V) = 4 amalitha = 4 dm 3 = 4 x 10 -3 m 3

Izinga lokushisa lamagesi (T) = 27 o C = 27 + 273 = 300 Kelvin

Ukucindezela kwamagesi (P) = 2 atm = 2 x 10 5 Pa

I-Universal gas constant (R) = 8.314 J.mol e −1 .K −1

Inombolo ka-Avogadro (N A ) = 6.02 x 10 23

Okufunwayo : Yimaphi ama-molecule amagesi e-oxygen esitsheni (N)

Isixazululo:

Umthetho wegesi ofanele - izinkinga nezixazululo 3

Ku-molecule eyodwa yamagesi e-oxygen, kune-molecule ye-oxygen engu-1.93 x 10 23.

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4. Isitsha esinegesi ye-neon (Ne, isisindo se-athomu = 20 u) ekushiseni okujwayelekile kanye nokucindezela (STP ) sinomthamo ongu-2 m 3. Thola isisindo segesi ye-neon!

Kwaziwa:

Isisindo se-athomu se-neon = 20 gram/mol e = 0,02 kg/mol e

Izinga lokushisa elijwayelekile (T) = 0 o C = 273 Kelvin

Ukucindezela okujwayelekile (P) = 1 atm = 1.013 x 10 5 Pascal

Umthamo (V) = 2 m 3

Okufunwayo : isisindo (m) segesi ye-neon

Isixazululo:

Kumazinga okushisa ajwayelekile kanye nengcindezi (STP), 1 mole kwanoma yimaphi amagesi, faka igesi ye-neon, inomthamo I-22.4 ilithas = 22.4 dm3 = 0.0448m3.

Umthetho wegesi ofanele - izinkinga nezixazululo 4

Ku-2 m3 , kune -44.6 moles yegesi ye-neon.

Isisindo se-athomu segesi ye-neon singamagremu angu-20 nge-mole.

Lokhu kusho ukuthi ku-mole eyodwa kukhona amagremu angu-20 noma u-0.02 kg wegesi ye-neon. Ngoba ku-mole eyodwa kukhona u-0.02 kg wegesi ye-neon bese kuthi ku-mole engu-44.6 kukhona ama-moles angu-44.6 x 0.02 kg/mole = 0.892 kg = 892 amagremu wegesi ye-neon.

Funda kabanzi

Umthetho kaGay-Lussac (umthamo oqhubekayo) – izinkinga nezixazululo

1. Ngiqala ngisebenzisa amagesi anomfutho u- P kanye nokushisa u -T. Igesi idlula enkambisweni ye-isochoric ukuze umfutho wokugcina ube ngokuphindwe kane kunomfutho wokuqala. Liyini izinga lokushisa lokugcina legesi?

Kwaziwa:

Ingcindezi yokuqala (P 1 ) = P

Ukucindezela kokugcina (P 2 ) = 4P

Izinga lokushisa lokuqala (T1 ) = T

Okufunwayo: Izinga lokushisa lokugcina ( T2 )

Isixazululo:

Ifomula yomthetho kaGay-Lussac :

Umthetho kaGay-Lussac (umthamo oqhubekayo) - izinkinga nezixazululo 1

Izinga lokushisa lokugcina liba liphindwe kane kunezinga lokushisa lokuqala.

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2. Esitsheni esivaliwe, amagesi afanele ekuqaleni anokushisa okungu-27 ° C. Uma ingcindezi yokugcina iba kabili kunengcindezi yokuqala, iyini izinga lokushisa lokugcina?

Kwaziwa:

Ingcindezi yokuqala (P 1 ) = P

Ukucindezela kokugcina (P 2 ) = 2P

Izinga lokushisa lokuqala (T 1 ) = 27 o C + 273 = 300 K

Okufunwayo: Izinga lokushisa lokugcina ( T2 )

Isixazululo:

Umthetho kaGay-Lussac (umthamo oqhubekayo) - izinkinga nezixazululo 2

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3. Ithayi ligcwaliswa ngomfutho ongu-2 atm ku-27°C. Ngemva kokushayela, izinga lokushisa ngaphakathi kwethayi lenyuka laya ku-47°C. Ingakanani ingcindezi ngaphakathi kwethayi manje?

Kwaziwa:

Ingcindezi yomoya = 1 atm = 1 x 10 5 Pa

Ingcindezi yokuqala yegeji = 2 atm = 2 x 10 5 Pa

Ingcindezi yokuqala ephelele (P 1 ) = 1 atm + 2 atm = 3 atm = 3 x 10 5 Pa

Izinga lokushisa lokuqala (T1 ) = 27 o C + 273 = 300 K

Izinga lokushisa lokugcina (T 1 ) = 47 o C + 273 = 320 K

Okufunwayo: Izinga lokushisa lokugcina

Isixazululo:

Umthetho kaGay-Lussac (umthamo oqhubekayo) - izinkinga nezixazululo 3

Ingcindezi yokugcina = ingcindezi yokugcina ephelele – ingcindezi yomoya

Ingcindezi yokugcina yegeyiji = 3.2 atm – 1 atm

Ingcindezi yegeyiji yokugcina = 2.2 atm

Funda kabanzi

Umthetho kaCharles (ingcindezi eqhubekayo) – izinkinga nezixazululo

1. Esitsheni esivaliwe, igesi iyakhula ukuze ivolumu yokugcina ibe yivolumu yokuqala ephindwe kathathu (V = ivolumu yokuqala, T = izinga lokushisa lokuqala ). Liyini izinga lokushisa lokugcina?

Kwaziwa:

Umthamo wokuqala (V 1 ) = V

Umthamo wokugcina (V 2 ) = 3V

Izinga lokushisa lokuqala (T1 ) = T

Okufunwayo: Izinga lokushisa lokugcina ( T2 )

Isixazululo:

Ifomula yomthetho kaCharles :

Umthetho kaCharles (ukucindezela okuqhubekayo) - izinkinga nezixazululo 1

Izinga lokushisa lokugcina lamagesi liba liphindwe kathathu kunezinga lokushisa lokuqala.

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2. Ngiqala ngokubheka amagesi anomthamo u-V kanye nokushisa u-T. Uma igesi idlula enkambisweni ye-isobaric ukuze izinga lokushisa libe liphindwe kabili kunezinga lokushisa lokuqala khona-ke umthamo wokugcina wamagesi…

Kwaziwa:

Umthamo wokuqala (V 1 ) = V

Izinga lokushisa lokuqala (T1 ) = T

Izinga lokushisa lokugcina (T2 ) = 2T

Okufunwayo: ivolumu yokugcina (V 2 )

Isixazululo:

Umthetho kaCharles (ukucindezela okuqhubekayo) - izinkinga nezixazululo 2

Umthamo wokugcina wamagesi uba kabili kunomthamo wokuqala.

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3. Esitsheni esivaliwe, amagesi afanele ekuqaleni anomthamo wamalitha ama-2 kanye nokushisa okungu-27 ° C. Uma umthamo wokugcina wamagesi uba ngamalitha ama-3 khona-ke izinga lokushisa lokugcina li...

Kwaziwa:

Umthamo wokuqala (V 1 ) = 2 amalitha = 2 dm 3 = 2 x 10 -3 m 3

Umthamo wokugcina (V 2 ) = amalitha ama-3 = 3 dm 3 = 3 x 10 -3 m 3

Izinga lokushisa lokuqala (T 1 ) = 27 o C + 273 = 300 K

Okufunwayo: Izinga lokushisa lokugcina ( T2 )

Isixazululo:

Umthetho kaCharles (ukucindezela okuqhubekayo) - izinkinga nezixazululo 3

Izinga lokushisa lokugcina lingu-177 o C noma u-177 + 273 = 450 Kelvin.

Funda kabanzi

Umthetho kaBoyle (izinga lokushisa elingaguquki) – izinkinga nezixazululo

1. Amanye amagesi afanele ekuqaleni anomfutho u -P kanye nomthamo u-V. Uma igesi idlula enkambisweni ye-isothermal ukuze umfutho wokugcina ube ngokuphindwe kane kunomfutho wokuqala, khona-ke umthamo wokugcina wegesi…

Kwaziwa:

Ingcindezi yokuqala (P 1 ) = P

Ukucindezela kokugcina (P 2 ) = 4P

Umthamo wokuqala (V 1 ) = V

Okufunwayo: Umqulu Wokugcina (V 2 )

Isixazululo:

Ifomula yomthetho kaBoyle :

I-PV = okungaguquki

P 1 V 1 = P 2 V 2

(P)(V) = (4P)(V 2 )

V = 4 V 2

V 2 = V / 4 = ¼ V

Umthamo wokugcina wamagesi uphindwe kane kunomthamo wokuqala.

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2. Esitsheni esivaliwe, igesi iyakhula ukuze ivolumu yokugcina ibe kabili kunevolumu yokuqala (V = ivolumu yokuqala, P = ingcindezi yokuqala). Ingcindezi yokugcina yamagesi…

Kwaziwa:

Ingcindezi yokuqala (P 1 ) = P

Umthamo wokuqala (V 1 ) = V

Umthamo wokugcina (V 2 ) = 2V

Okufunwayo : Ingcindezi yokugcina (P 2 )

Isixazululo:

P 1 V 1 = P 2 V 2

I-PV = P 2 (2V)

P = P 2 (2)

P 2 = P / 2 = ½ P

Umfutho wegesi uba ngokuphindwe ka-½ kunomfutho wokuqala.

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3. Esitsheni esivaliwe, amagesi anomfutho ongu-2 atm kanye nomthamo welitha eli-1. Uma umfutho wegesi uba ngu-4 atm khona-ke umthamo wegesi uba...

Kwaziwa:

Ingcindezi yokuqala (P 1 ) = 2 atm = 2 x 10 5 Pa

Ingcindezi yokugcina (P 2 ) = 4 atm = 4 x 10 5 Pa

Umthamo wokuqala (V 1 ) = 1 ilitha = 1 dm 3 = 1 x 10 -3 m 3

Okufunwayo : Umqulu wokugcina (V 2 )

Isixazululo:

P 1 V 1 = P 2 V 2

( 2 x 10 5 )(1 x 10 -3 ) = (4 x 10 5 ) V 2

( 1)(1 x 10 -3 ) = (2) V 2

1 x 10 -3 = (2) V 2

V 2 = ½ x 10 -3

V 2 = 0.5 x 10 -3 m 3 = 0.5 dm 3 = 0.5 litre s

Funda kabanzi

Ama-capacitor alandelanayo nahambisanayo - izinkinga nezixazululo

1. Ama-capacitor amathathu, C 1 = 2 μF, C 2 = 4 μF, C 3 = 4 μF, axhunywe ngochungechunge nangokuhambisana . Nquma umthamo we-capacitor eyodwa ozoba nomphumela ofanayo nokuhlanganiswa.

Ama-capacitor alandelanayo nahambisanayo - izinkinga nezixazululo 1Kwaziwa:

I-Capacitor C 1 = 2 μ F

I-Capacitor C 2 = 4 μ F

I-Capacitor C 3 = 4 μ F

Okufunwayo: I-capacitance elinganayo (C)

Isixazululo:

Ama-Capacitor C2 kanye ne- C3 axhunywe ngokulingana. Amandla afanayo:

C P = C 2 + C 3 = 4 + 4 = 8 μ F

Ama-Capacitor C1 kanye ne-C p axhunyiwe ochungechungeni. Amandla afanayo:

1/C = 1/C 1 + 1/ C P = 1/2 + 1/8 = 4/8 + 1/8 = 5/8

C = 8/5 μ F

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2. Ama-capacitor amahlanu , C 1 = 2 μF, C 2 = 4 μF, C 3 = 6 μF, C 4 = 5 μF, C 5 = 10 μF, axhunyiwe ngochungechunge nangokuhambisana. Thola amandla e-capacitor eyodwa azoba nomphumela ofanayo nenhlanganisela.

Kwaziwa:

Ama-capacitor alandelanayo nahambisanayo - izinkinga nezixazululo 2I-Capacitor C1 = 2 μF

I-Capacitor C 2 = 4 μ F

I-Capacitor C 3 = 6 μ F

I-Capacitor C 4 = 5 μ F

I-Capacitor C 5 = 10 μ F

Okufunwayo: I-capacitance elinganayo (C)

Isixazululo:

Ama-Capacitor C2 kanye ne- C3 axhunywe ngokulingana. Amandla afanayo:

I -CP = C2 + C3

I-CP = 4 + 6

I-CP = 10 μ F

Ama-Capacitor C1 , CP , C4 kanye no-C5 axhunyiwe ngochungechunge . Amandla afanayo:

1/C = 1/C 1 + 1/ C P + 1/ C 4 + 1/ C 5

1 / C = 1/2 + 1/10 + 1/5 + 1/10

1/C = 5/10 + 1/10 + 2/10 + 1/10

1/C = 9/10

C = 10/9 μ F

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I-3. C1 = 3 μF, C2 = 4 μF kanye C3 = 3 μF, zixhunywe ngochungechunge nangokuhambisana. Thola ukuthi amandla kagesi use izifunda.

Kwaziwa:

I-Capacitor C1 = 3 μFAma-capacitor alandelanayo nahambisanayo - izinkinga nezixazululo 3

I-Capacitor C 2 = 4 μ F

I-Capacitor C 3 = 3 μ F

Okufunwayo: I-capacitance elinganayo (C)

Isixazululo:

Ama-Capacitor C2 kanye ne- C3 axhunywe ngokulingana. Amandla afanayo:

I -CP = C2 + C3

I-CP = 4 + 3

I-CP = 7 μ F

Ama-Capacitor C1 kanye ne - C P axhunywe ochungechungeni. Amandla afanayo:

1/C = 1/C 1 + 1/ C P

1/C = 1/3 + 1/7

1/C = 7/21 + 3/21

1/C = 10/21

C = 21/10

C = 2.1 μ F

C = 2.1 x 10 -6 F

Amandla kagesi kumasekethe:

E = ½ CV 2

E = ½ ( 2.1 x 10 -6 )(12 2 )

E = ½ (2.1 x 10 -6 ) (144)

E = (2.1 x 10 -6 )(72)

E = 151.2 x 10 -6 amaJoule

E = 1.5 x 10 -4 amaJoule

Funda kabanzi

Ama-capacitor achungechungeni - izinkinga nezixazululo

1. Ama-capacitor amane, C 1 = 2 μF, C 2 = 1 μF, C 3 = 3 μF, C 4 = 4 μF, axhunyiwe ochungechungeni . Thola amandla e- capacitor eyodwa azoba nomphumela ofanayo nenhlanganisela.

Kwaziwa:

I-Capacitor C 1 = 2 μ F

I-Capacitor C 2 = 1 μ F

I-Capacitor C 3 = 3 μ F

I-Capacitor C 3 = 4 μ F

Okufunwayo: Amandla alinganayo

Isixazululo:

I-capacitance efanayo:

1/C = 1/C 1 + 1/C 2 + 1/C 3 + 1/C 4

1/C = 1/2 + 1/1 + 1/3 + 1/4

1/C = 6/12 + 12/12 + 4/12 + 3/12

1/C = 25/12

C = 12/25

C = 0.48

I-capacitance elinganayo yenhlanganisela yonke ingu- 0.48 μF.

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2. Nquma ukushaja ku-capacitor C 1 uma umehluko ongaba khona phakathi kuka -P no- Q ungama -Volts ayi- 12 …

Ama-capacitor ochungechungeni - izinkinga nezixazululo 1Kwaziwa:

I-Capacitor C 1 = 1 0 μ F = 1 0 x 10 -6 F

I-Capacitor C 2 = 2 0 μ F = 2 0 x 10 -6 F

Umehluko ongaba khona (V) = 12 Volts

Okufunwayo: ukushaja ku-capacitor C1 ( Q1 )

Isixazululo:

I-capacitance efanayo:

1/C = 1/C 1 + 1/ C 2

1/C = 1/10 + 1/20 = 2/20 + 1/20 = 3/20

C = 20/3 μ F = (20/3) x 10 -6 F

Ukushaja kukagesi ku-capacitor efanayo:

Q = (C)(V) = (20/3)(12)(10 -6 ) = 80 x 10 -6 C

Q = 80 μC

Ama-capacitor axhunywe ngokulandelana ukuze ishaja kagesi kuma-capacitor alinganayo = ishaja kagesi ku-capacitor C 1 = ishaja kagesi ku-capacitor C 2.

Ishaja kagesi ku-capacitor C 1 ingu-80 μC.

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3. Ama-capacitor amabili, i-C 1 = 2 μF kanye ne-C 2 = 4 μF, axhunyiwe ngokulandelana. Ama-capacitor ayashajwa. Umehluko ongaba khona ku-capacitor C 1 ungama-Volts amabili. Ishaja kagesi ku-capacitor C 2 …

Kwaziwa:

C apa c itor C 1 = 2 μ F = 2 x 10 -6 F

C apa c itor C 2 = 4 μ F = 4 x 10 -6 F

Umehluko ongaba khona ku-capacitor C 1 (V 1 ) = 2 Volts

Okufunwayo : Ukushaja kukagesi ku- capacitor C2.

Isixazululo:

Ukushaja kukagesi ku- capacitor C1 :

Q 1 = C 1 V 1 = (2 x 10 -6 )(2) = 4 x 10 -6 C

Q 1 = 4 μC

Ama-capacitor axhunywe ngokulandelana ukuze ishaja kagesi ku-capacitor C1 = ishaja kagesi ku- capacitor C2.

Ishaja ku-capacitor C2 ingu - 4 μC.

Funda kabanzi

Ama-capacitor ahambisanayo - izinkinga nezixazululo

1. Ama-capacitor amane , C 1 = 2 μF, C 2 = 1 μF, C 3 = 3 μF, C 4 = 4 μF, axhunywe ngokulingana. Thola amandla e-capacitor eyodwa azoba nomphumela ofanayo nenhlanganisela.

Kwaziwa:

I-Capacitor C 1 = 2 μ F

I-Capacitor C 2 = 1 μ F

I-Capacitor C 3 = 3 μ F

I-Capacitor C 3 = 4 μ F

Okufunwayo: Amandla alinganayo

Isixazululo:

I-capacitance efanayo:

C = C 1 + C 2 + C 3

C = 4 μF + 2 μF + 3 μF = 9 μF

Amandla alinganayo alo lonke inhlanganisela angama-9 μF.

[irp]

2. Nquma ukushaja ku-capacitor C 2 uma umehluko ongaba khona phakathi kwamaphoyinti A no-B ungama -Volts angu-9…

Ama-capacitor ahambisanayo - izinkinga nezixazululo 1

Kwaziwa:

C apa c itor C 1 = 20 μ F = 20 x 10 -6 F

C apa c itor C 2 = 30 μ F = 30 x 10 -6 F

Umehluko ongaba khona phakathi kwamaphuzu A no- B (V AB ) = 9 Volts

Okufunwayo : ukushaja ku- capacitor C2 ( Q2 )

Isixazululo:

Umehluko ongaba khona:

Ama-capacitor axhunywe ngokuhambisana ukuze umehluko ongaba khona phakathi kuka-A no-B (V AB ) = umehluko ongaba khona ku-capacitor C 1 (V 1 ) = umehluko ongaba khona ku-capacitor C 2 (V 2 ) = 9 Volts.

Ukushaja kukagesi ku- capacitor C2 :

Q 2 = C 2 V 2 = (30 x 10 -6 )(9) = 270 x 10 -6 C

Q 2 = 270 μC

Ishaja kagesi ku-capacitor C 2 ingu- 27 0 μ C.

[irp]

3. Ama-capacitor amathathu , C 1 = 4 μF, C 2 = 2 μF, C 3 = 3 μF, axhunywe ngokulingana. Ama-capacitor ayashajwa. Umehluko ongaba khona ku-capacitor C 2 ungama-4 Volts. Thola

(a) Ukushaja kukagesi kuma-capacitor C1 , C2 kanye no- C3

(b) Ukushaja kukagesi ku-capacitor elinganayo yenhlanganisela yonke

Kwaziwa:

C apa c itor C 1 = 4 μ F = 4 x 10 -6 F

I-apacitor ye-C C 2 = 2 μ F = 2 x 10 -6 F

I-apacitor ye-C C 3 = 3 μ F = 3 x 10 -6 F

Umehluko ongaba khona ku-capacitor C2 ( V2 ) = 4 Volts

Okufunwayo : Ukushaja kukagesi ku- capacitor C3 ( Q3 )

Isixazululo:

(a) Ukushaja kukagesi ku- capacitor C3

Umehluko ongaba khona ku- capacitor C3 :

Ama-capacitor axhunywe ngokufana ukuze umehluko ongaba khona ku-capacitor C3 (V3) = umehluko ongaba khona ku-capacitor C2 (V2) = umehluko ongaba khona ku-capacitor C1 (V1) = umehluko ongaba khona ku-capacitor elinganayo (V) = 4 Volt

Ukushaja kukagesi ku- capacitor C1 :

Q 1 = C 1 V 1 = (4 x 10 -6 )(4) = 16 x 10 -6 C

Q 1 = 16 μC

Ukushaja kukagesi ku- capacitor C2 :

Q 2 = C 2 V 2 = (2 x 10 -6 )(4) = 8 x 10 -6 C

Q 2 = 8 μC

Ukushaja kukagesi ku- capacitor C3 :

Q 3 = C 3 V 3 = (3 x 10 -6 )(4) = 12 x 10 -6 C

Q 3 = 12 μC

(b) Ishaja kagesi ku-capacitor elinganayo

Q = Q 1 + Q 2 + Q 3

Q = 16 μ C + 8 μ C + 12 μ C = 36 μ C

Isixazululo esihlukile:

I-capacitance efanayo:

C = C 1 + C 2 + C 3

C = 4 μF + 2 μF + 3 μF = 9 μF

C = 9 x 10 -6 F

Umehluko ongaba khona ku-capacitor efanayo:

V 1 = V 2 = V 3 = V = 4 Volt

Ishaja kagesi ku-capacitor efanayo:

Q = I-CV = (9 x 10 -6 )(4) = 36 x 10 -6 C

Q = 36 μC

Funda kabanzi