1. Amanye amagesi afanele ekuqaleni anomfutho u -P kanye nomthamo u-V. Uma igesi idlula enkambisweni ye-isothermal ukuze umfutho wokugcina ube ngokuphindwe kane kunomfutho wokuqala, khona-ke umthamo wokugcina wegesi…
Kwaziwa:
Ingcindezi yokuqala (P 1 ) = P
Ukucindezela kokugcina (P 2 ) = 4P
Umthamo wokuqala (V 1 ) = V
Okufunwayo: Umqulu Wokugcina (V 2 )
Isixazululo:
Ifomula yomthetho kaBoyle :
I-PV = okungaguquki
P 1 V 1 = P 2 V 2
(P)(V) = (4P)(V 2 )
V = 4 V 2
V 2 = V / 4 = ¼ V
Umthamo wokugcina wamagesi uphindwe kane kunomthamo wokuqala.
2. Esitsheni esivaliwe, igesi iyakhula ukuze ivolumu yokugcina ibe kabili kunevolumu yokuqala (V = ivolumu yokuqala, P = ingcindezi yokuqala). Ingcindezi yokugcina yamagesi…
Kwaziwa:
Ingcindezi yokuqala (P 1 ) = P
Umthamo wokuqala (V 1 ) = V
Umthamo wokugcina (V 2 ) = 2V
Okufunwayo : Ingcindezi yokugcina (P 2 )
Isixazululo:
P 1 V 1 = P 2 V 2
I-PV = P 2 (2V)
P = P 2 (2)
P 2 = P / 2 = ½ P
Umfutho wegesi uba ngokuphindwe ka-½ kunomfutho wokuqala.
3. Esitsheni esivaliwe, amagesi anomfutho ongu-2 atm kanye nomthamo welitha eli-1. Uma umfutho wegesi uba ngu-4 atm khona-ke umthamo wegesi uba...
Kwaziwa:
Ingcindezi yokuqala (P 1 ) = 2 atm = 2 x 10 5 Pa
Ingcindezi yokugcina (P 2 ) = 4 atm = 4 x 10 5 Pa
Umthamo wokuqala (V 1 ) = 1 ilitha = 1 dm 3 = 1 x 10 -3 m 3
Okufunwayo : Umqulu wokugcina (V 2 )
Isixazululo:
P 1 V 1 = P 2 V 2
( 2 x 10 5 )(1 x 10 -3 ) = (4 x 10 5 ) V 2
( 1)(1 x 10 -3 ) = (2) V 2
1 x 10 -3 = (2) V 2
V 2 = ½ x 10 -3
V 2 = 0.5 x 10 -3 m 3 = 0.5 dm 3 = 0.5 litre s
