Izibonelo zemibuzo mayelana nokusetshenziswa komthetho wokuqala we-thermodynamics ezinqubweni ezahlukahlukene ze-thermodynamic (i-isobaric, i-isothermal, i-isochoric)

11 Izibonelo zemibuzo mayelana nokusetshenziswa komthetho wokuqala we-thermodynamics ezinqubweni ezahlukene ze-thermodynamic (i-isobaric, i-isothermal, i-isochoric)

1. Igrafu engezansi ikhombisa umjikelezo we-thermodynamic obonwa yigesi. Umsebenzi owenziwa yigesi enqubweni i-ABCD…

Imibuzo eyisibonelo mayelana nokusetshenziswa komthetho wokuqala we-thermodynamics ezinqubweni ezahlukahlukene ze-thermodynamic (i-isobaric, i-isothermal, i-isochoric) - 1Ingxoxo
I-Diketahui :
Ingcindezi 1 (P)1) = 2 x 105 Pa
Ingcindezi 2 (P)2) = 4 x 105 Pa
Umqulu 1 (V)1= 1m3
Umqulu 2 (V)2= 3m3
Kubuziwe : Umsebenzi owenziwe yigesi enqubweni yomjikelezo we-ABCD
Jawab :
Umsebenzi owenziwe ngegesi = indawo yesikwele i-ABCD.
W = (P)2 - P1)(V)2 - V1)
W = (4 x 105 - 2 x 105)(3 – 1)
W = (2 x 105)(2)
W = 4 x 105 Joule
Umsebenzi owenziwe yigesi enqubweni yomjikelezo we-ABCD u-4 x 105 UJoule.

2. Umsebenzi owenziwe yigesi enqubweni yomjikelezo we-ABC…

Imibuzo eyisibonelo mayelana nokusetshenziswa komthetho wokuqala we-thermodynamics ezinqubweni ezahlukahlukene ze-thermodynamic (i-isobaric, i-isothermal, i-isochoric) - 2Ingxoxo
I-Diketahui :
Ingcindezi 1 (P)1) = 3 x 105 Pa
Ingcindezi 2 (P)2) = 6 x 105 Pa
Umqulu 1 (V)1= 20cm3 = 20 x10-6 m3
Umqulu 2 (V)2= 60cm3 = 60 x10-6 m3
Kubuziwe : Umsebenzi owenziwe yigesi enqubweni yomjikelezo we-ABC
Jawab :
Umsebenzi owenziwe ngegesi = indawo yonxantathu i-ABCD.
W = ½ (P2 - P1)(V)2 - V1)
W = ½ (6 x 105 - 3 x 105)(60 x 10-6 - 20 x 10-6)
W = ½ (3 x 105)(40 x 10-6)
W = ½ (120 x 10-1 uJoule)
W = ½ (amaJoules angu-12)
W = 6 Joule
Umsebenzi owenziwe yigesi enqubweni yomjikelezo we-ABC ungama-Joules ayi-6.

3. Igrafu yokucindezela (P) uma kuqhathaniswa nomthamo (V) wegesi endaweni evaliwe. Ingxenye yegrafu ekhombisa igesi esebenza emvelweni…

Imibuzo eyisibonelo mayelana nokusetshenziswa komthetho wokuqala we-thermodynamics ezinqubweni ezahlukahlukene ze-thermodynamic (i-isobaric, i-isothermal, i-isochoric) - 3Ingxoxo
Inqubo i-AB kanye nenqubo i-DC yizinqubo ze-isobaric. Inqubo i-AD kanye nenqubo i-BC yizinqubo ze-isochoric.
Igesi iyasebenza endaweni ezungezile uma igesi ikhula ukuze ivolumu yesikhala esithathwe yigesi ikhuphuke (inqubo ye-DC). Indawo ezungezile iyasebenza kugesi uma igesi incipha ukuze ivolumu yesikhala esithathwe yigesi inciphe (inqubo ye-BC).

FUNDA FUTHI  Isibonelo somthetho wokuqala kaKirchhoff

4. Wonke amagesi afanele adlula enkambisweni ye-isochoric ngakho...

A. wonke ama-molecule anejubane elifanayo
B. emazingeni okushisa aphezulu isivinini esimaphakathi sama-molecule sikhulu
C. umfutho wegesi uhlala ungaguquki
D. igesi izosebenza
I-E. ayinawo amandla angaphakathi

Ingxoxo
Isochoric = ivolumu engaguquki.
Impendulo efanele ingu-B.

5. Inani legesi elifanele licindezelwa ngenqubo ye-thermodynamic kusukela kusimo 1 kuya kusimo 2 njengoba kuboniswe kugrafu ye-PV elandelayo. Umsebenzi owenziwa yigesi…

A. -180 JIngxoxo yokuhlolwa kukazwelonke kweFiziksi yesikole samabanga aphezulu ka-2015 - 45

B. -90 J

C. -30 J

D. 30 J

E. 90 J

Ingxoxo

Ilitha eli-1 = 0,001 m3

I-Diketahui :

Ingcindezi 1 (P)1) = 10 kPa = 10.000 Pa = 10.000 N/m2

Ingcindezi 2 (P)2) = 20 kPa = 20.000 Pa = 20.000 N/m2

Umqulu 1 (V)1) = 4 amalitha = 4 (0,001 m3= 0,004m3

Umqulu 2 (V)2) = amalitha ayi-10 = 10 (0,001 m3= 0,010m3

Kubuziwe Umsebenzi (W) owenziwe yigesi

Impendulo:

W = P (V)2 - V1) + 1/2 (P2 - P1)(V)2 - V1)

W = 10.000 (0,010-0,004) + 1/2 (20.000-10.000)(0,010-0,004)

W = 10.000 (0,006) + 1/2 (10.000) (0,006)

W = 10 (6) + 1/2 (10) (6)

W = 60 + 1/2 (60)

W = 60 + 30

W = 90 Joule

Impendulo efanele ngu-E.

6. Bheka umdwebo we-PV ohlangothini!

Umsebenzi owenziwe enqubweni ye-thermodynamic emjikelezweni owodwa…

FUNDA FUTHI  Imibono Yokuqala Neyesibili Ka-Einstein

A. 100 kJIngxoxo yokuhlolwa kukazwelonke kweFiziksi yesikole samabanga aphezulu ka-2015 - 46

B. 200 kJ

C. 300 kJ

D. 400 kJ

E. 600 kJ

Ingxoxo

I-Diketahui :

Ingcindezi 1 (P)1) = 1 x 105 Pa = 1 x 105 N / m2

Ingcindezi 2 (P)2) = 3 x 105 Pa = 3 x 105 N / m2

Umqulu 1 (V)1= 2m3

Umqulu 2 (V)2= 4m3

Kubuziwe : Umsebenzi (W) okhiqizwe.

Jawab :

Umsebenzi owenziwe = indawo ye-quadrilateral abcd.

W = (P)2 - P1)(V)2 - V1)

W = (3 x 105 - 1 x 105)(4 – 2)

W = (2 x 105)(2)

W = 4 x 105 Joule

W = 400.000 Joule

W = 400 kilogram Joule

Impendulo efanele ngu-D.

7. Igesi efanelekile idlula enkambisweni njengoba kuboniswe kumdwebo we-PV ongezansi. Umsebenzi owenziwe kule nqubo…

A. 35 JIngxoxo yokuhlolwa kukazwelonke kweFiziksi yesikole samabanga aphezulu ka-2015 - 47

B. 24 J

C. 15 J

D. 12 J

E. 6 J

Ingxoxo

I-Diketahui :

Ingcindezi 1 (P)1) = 1 N/m2

Ingcindezi 2 (P)2) = 7 N/m2

Umqulu 1 (V)1= 1m3

Umqulu 2 (V)2= 5m3

Kubuziwe: Umsebenzi (W) usuqedile.

Impendulo:

Umsebenzi owenziwe = indawo kanxantathu i-ABC.

W = ½ (P2 - P1)(V)2 - V1)

W = ½ (7-1)(5-1)

W = ½ (6)(4)

W = ½ (24)

W = 12 Joule

Impendulo efanele ngu-D.

8. I-0,02 mol yegesi ye-monatomic ku-350 K isesitsheni esivaliwe. Kungakanani ukushisa okudingekayo ukuze kwandiswe izinga lokushisa legesi libe ngu-400 K? I-universal gas constant, R = 8,31 J mol-1 K-1.
A. 10 Joule
B. 12,5 Joule
C. 14 Joule
D. 15,5 Joule
E. 17 AmaJoule
Ingxoxo:
I-Diketahui :
n = 0,02 mol
T1 = 350K
T2 = 400K
R = 8,31 J/mol K
Kubuziwe :
Ukushisa (Q)?
Jawab :
Enqubweni ye-isochoric (ivolumu eqhubekayo), Q = delta U
Incazelo: Q = ukushisa, i-delta U = ushintsho emandleni angaphakathi, U = amandla angaphakathi

FUNDA FUTHI  Ifomula yamandla adonsela phansi

inqubo ye-thermodynamic ye-isochoric 1

9. Ama-mole amabili egesi ye-monatomic ekushiseni okungu-20 oC kanye nokucindezela 2 × 105 I-Pa idlula enkambisweni ye-isochoric kuze kube yilapho ingcindezi iba ngu-4 × 105 I-Pa. Uma igesi evamile = 8,31 J/mol K, khona-ke ushintsho lwamandla angaphakathi egesi…
A. 7304 J
B. 6200 J
C. 2291 J
D. 2128 J
E. 1208 J
Ingxoxo:
I-Diketahui :
n = 2 mol
T1 = 20 + 273 = 293 K
P1 = 2 x105 Pa
P2 = 4 x105 Pa
R = 8,31 J/mol K
Kubuziwe :
Ushintsho kumandla angaphakathi (i-delta U)?
Jawab :
i-delta U = 3/2 nR(T2-T1)
Isibalo T2 okokuqala sebenzisa ifomula yomthetho kaGay-Lussac (ivolumu eqhubekayo)

inqubo ye-thermodynamic 2

10. Ingxenye yegrafu yokucindezela (P) – ivolumu (V) ekhombisa umsebenzi wangaphandle wokwamukela igesi...
A. AB
I-CD ye-B.
C. BC
D. DA
I-E. AC

Umthetho woku-2 we-thermodynamics 1
Ingxoxo :
Uma kwenziwa umsebenzi kugesi, ivolumu yayo iyanda. Ngokuphambene nalokho, uma kwenziwa umsebenzi kugesi ovela emthonjeni wangaphandle, ivolumu yayo iyancipha. Inqubo eboniswe kugrafu ngenhla ekhombisa ukwehla kwevolumu yegesi yi-process CD.
Ngakho impendulo efanele ingu-B.

11. Amagrafu angezansi abonisa ubudlelwano phakathi kwengcindezi (P) kanye nomthamo (V) wegesi eqhubeka nenqubo.
 Umthetho woku-2 we-thermodynamics 2
Inqubo ekhiqiza umzamo omkhulu iboniswe enombolweni yegrafu ...
A. (1)
B. (2)
C. (3)
D. (4)
Ingxoxo :
Umsebenzi owenziwe = indawo. Uma indawo inkulu, umsebenzi owenziwe uba mkhulu. Indawo enkulu iboniswe kugrafu 3.
Impendulo efanele ngu-C.

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