Imibuzo eyisibonelo exoxa ngencazelo ye-stoichiometry

Imibuzo Yesibonelo kanye Nengxoxo Ngencazelo Ye-Stoichiometry

I-Stoichiometry iyigatsha lekhemistri elifunda ubuningi bezinto ezihilelekile ekusabeleni kwamakhemikhali. Igama elithi 'stoichiometry' ngokwalo livela emagameni esiGreki athi "stoicheion," okusho i-element, kanye nelithi "metron," okusho isilinganiso. I-Stoichiometry igxile esilinganisweni sama-moles, isisindo, ivolumu, kanye nezinhlayiya ekusabeleni kwamakhemikhali. I-Stoichiometry ibalulekile ekhemistri ngoba inikeza isisekelo sokuhlaziywa kokusabela futhi isiza ososayensi ukunquma inani lezinto ezidingekayo noma ezikhiqizwa ekusabeleni kwamakhemikhali.

Ukuze siqonde kangcono umqondo we-stoichiometry, ake sixoxe ngemibuzo ethile eyisibonelo kanye nezingxoxo zayo.

Imibuzo Yesibonelo Se-Stoichiometry

Umbuzo 1: Ukusabela okulula kwamakhemikhali

Cabanga ngendlela elandelayo yokusabela:

\[ \text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O} \]

Uma siqala ngama-moles angu-4 e-H₂ kanye nama-moles angu-4 e-O₂, mangaki ama-moles e-H₂O azokwakhiwa? Ingabe ama-reactants azosetshenziswa wonke, noma ingabe kukhona okusele?

Ingxoxo:

Isinyathelo sokuqala ukubhala i-equation yamakhemikhali elinganiselayo:

\[ \umbhalo{2H}_2 + \umbhalo{O}_2 \umcibisholo \umbhalo{2H}_2\umbhalo{O} \]

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Lesi sibalo sibonisa ukuthi ama-moles amabili e-H₂ asabela ne-moles eyodwa ye-O₂ ukuze akhiqize ama-moles amabili e-H₂O. Kulokhu, singathola inani lama-moles e-H₂O akhiqizwa kusetshenziswa i-stoichiometry.

1. Thola ama-moles amaningi kanye nalawo asetshenzisiwe:

Kuwo wonke ama-moles amabili e-H₂, sidinga i-moles eyodwa ye-O₂. Siqala ngama-moles amane e-H₂ kanye nama-moles amane e-O₂.
– \( \frac{4 \text{ mol H₂}}{2} = 2 \text{ mol O₂} \) kuyadingeka.
– Njengoba sinezinhlayiya ezine ze-O₂, i-O₂ iyisithako esisele.

2. Bala inani lemikhiqizo:
Ngokufanayo, ama-moles angu-4 e-H₂ azokhiqiza inani elifanayo lama-moles e-H₂O ngoba wonke ama-moles amabili e-H₂ asabelayo akhiqiza ama-moles amabili e-H₂O.

\[ 4\umbhalo{ mol H₂} \izikhathi \frac{2 \umbhalo{ mol H}_2\umbhalo{O}}{2 \umbhalo{ mol H}_2} = 4 \umbhalo{ mol H}_2\umbhalo{O} \]

Ngakho-ke, kuzokwakhiwa ama-moles amane amanzi, kanti i-O₂ esele ngeke isetshenziswe.

Umbuzo 2: Ukusabela Kokushisa

I-Benzene (C₆H₆) iyasha emoyeni ukuze ikhiqize i-carbon dioxide namanzi kanje:

\[ 2\umbhalo{ C}_6\umbhalo{H}_6 + 15\umbhalo{ O}_2 \umcibisholo ongakwesokudla 12\umbhalo{ CO}_2 + 6\umbhalo{ H}_2\umbhalo{O} \]

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Uma kushiswa i-molecule eyodwa ye-C₆H₆, kuzokwakhiwa ama-moles amangaki e-CO₂ kanye ne-H₂O? Kudingeka ama-moles amangaki e-O₂?

Ingxoxo:

Sebenzisa i-equation ye-stoichiometric engenhla ukuxazulula inkinga:

1. Thola ama-moles e-CO₂ kanye ne-H₂O akhiqizwayo:

\[ \umbhalo{C}_6\umbhalo{H}_6 \]
\[ 1 \text{ mol C}_6\text{H}_6 \text{ ilingana no-} 12 \text{ mol CO}_2 (ye-2 mol C}_6\text{H}_6) \]

Kusukela ku-stoichiometric ratio:

\[ 1 \umbhalo{ mol C}_6\umbhalo{H}_6 = \frac{12 \umbhalo{ mol CO}_2}{2} \]
\[ = 6 \umbhalo{ mol CO}_2 \]

Ngokufanayo ne-H₂O:

\[ 1 \umbhalo{ mol C}_6\umbhalo{H}_6 = \frac{6 \umbhalo{ mol H}_2\umbhalo{O}}{2} \]
\[ = 3 \umbhalo{ mol H}_2\umbhalo{O} \]

2. Thola ama-moles e-O₂ adingekayo:

\[ 1 \umbhalo{ mol C}_6\umbhalo{H}_6 = \umbhalo{15 \umbhalo{ mol O}_2}{2} \]
\[ = 7.5 \umbhalo{ mol O}_2 \]

Umbuzo 3: Ukusabela Kokungathathi-hlangothi Kwe-Acid-Base

Mangaki amalitha egesi ye-CO₂ akhiqizwayo (ngaphansi kwezimo ezijwayelekile) lapho ama-5 g e-sodium carbonate (Na₂CO₃) esabela nge-hydrochloric acid eningi ngokwendlela yokusabela:

\[ \text{Na}_2\text{CO}_3 + 2\text{HCl} \rightarrow 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_2 \]

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Ingxoxo:

1. Thola ama-moles e-Na₂CO₃:

Isisindo se-molar se-Na₂CO₃:

\[ (2 \izikhathi ezingu-23) + 12 + (3 \izikhathi ezingu-16) = 106 \umbhalo{g/mol} \]

Ama-moles e-Na₂CO₃ atholakalayo:

\[ \frac{5 \umbhalo{ g Na₂CO₃}}{106 \umbhalo{ g/mol}} = 0.047 \umbhalo{ mol Na₂CO₃} \]

2. Mangaki ama-moles e-CO₂ akhiwayo:

\[ 1 \umbhalo{ mol Na₂CO₃} ukhiqiza 1 \umbhalo{ mol CO}_2 \]
Ngakho-ke i-0.047 mol ye-Na₂CO₃ izokhiqiza:

\[ 0.047 \umbhalo{ mol CO}_2 \]

Ngaphansi kwezimo ezijwayelekile (STP: 22.4 L/mol):

\[ 0.047 \umbhalo{ mol } \izikhathi 22.4 \umbhalo{ L/mol} = 1.05 \umbhalo{ L CO}_2 \]

Isiphetho

Kusukela enkingeni yesibonelo engenhla, singabona ukuthi i-stoichiometry ihilela izinyathelo eziningana ezibalulekile: ukuguqula isisindo sibe ama-moles, ukusebenzisa izilinganiso zama-molar ezivela kuma-equation alinganisiwe, bese ekugcineni ukuguqula sibuyele kumayunithi adingekayo. Ukuqonda i-stoichiometry kubalulekile ukuze kuphumelele ekuhlaziyeni ukusabela kwamakhemikhali nokuhlela ukwenziwa kwamakhemikhali. Ngokuqhubeka nokuzijwayeza, i-stoichiometry izoba ithuluzi eliwusizo kakhulu emhlabeni we-chemistry.

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