Isibonelo Semibuzo Yengxoxo Ngezimoto Zikagesi

Isibonelo Semibuzo Yengxoxo Ngezimoto Zikagesi

Injini kagesi umshini oguqula amandla kagesi abe amandla omshini. Uyingxenye ebalulekile ezinhlotsheni ezahlukene zezimboni, ezentengiselwano, kanye nezicelo zasekhaya. Ukuqonda izimiso kanye nokusebenza kwama-motor kagesi kubalulekile, ikakhulukazi kubafundi bobunjiniyela kanye nochwepheshe emkhakheni kagesi. Kulesi sihloko, sizoxoxa ngezibonelo eziningana zezinkinga kanye nezingxoxo ezihlobene nama-motor kagesi ukuze sisize ekujuleni ukuqonda kwethu.

Izimiso Eziyisisekelo Zezimoto Zikagesi

Ngaphambi kokuba singene emibuzweni, kuyasiza ukubukeza izimiso eziyisisekelo zama-motor kagesi. Ama-motor kagesi asebenza ngesimiso se-electromagnetism, lapho ugesi odlula kukhoyili ukhiqiza insimu yamagnetic esebenzisana nensimu yamagnetic yomthombo wangaphandle ukuze ikhiqize ukunyakaza. Ngokuvamile, ama-motor kagesi ahlukaniswe ngezinhlobo ezimbili eziyinhloko: ama-motor aqondile (DC) kanye nama-motor ashintshanayo (AC).

Izingxenye Eziyinhloko Zemoto Kagesi

1. I-Stator: Ingxenye engaguquki yemoto evame ukuba namakhoyili ensimbi noma omazibuthe abangapheli.
2. I-Rotor: Ingxenye ejikelezayo yemoto evame ukuba nama-coil ensimbi noma omaginethi.
3. Ikhoyili: Ucingo oluzungezwe i-rotor noma i-stator ukuze kukhiqizwe insimu yamagnetic.
4. Umthombo Wamandla: Ihlinzeka ngogesi odingekayo ukushayela injini.

Imibuzo Eyisibonelo Nengxoxo

Umbuzo 1: Ukubala Isivinini Semoto ye-DC
Umbuzo: Imoto ye-DC enama-turn angu-500 nge-coil ngayinye isebenza ku-24V kanye no-5A. Uma i-motor constant \( K_m \) ingu-0.02 Nm/A, bala ijubane lokujikeleza kwe-rotor uma i-torque ephumayo ingu-1 Nm.

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Ingxoxo:
Kuyaziwa:
– Inani lamajika (N) = 500
– I-Voltage (V) = 24V
– Ugesi (I) = 5A
– I-motor constant \( K_m \) = 0.02 Nm/A
– I-Torque (T) = 1 Nm

Kusukela ku-equation eyisisekelo yemoto ye-DC, siyazi:
\[ T = K_m \cdot I \]
\[ 1 Nm = 0.02 Nm/A \cdot 5 A \]
\[ 1 Nm = 0.1 Nm \]

Lokhu kusho ukuthi i-torque constant edingekayo ukukhiqiza i-1 Nm kugesi ongu-5 A ilungile.

Okulandelayo, ukubala isivinini sokujikeleza (\( \omega \)):
\[ E = K_m \cdot \omega \]
\[ V = E \]
\[ 24V = 0.02 Nm/A \cdot \omega \]

Kusukela lapha, singabala ijubane (\( \omega \)):
\[ \omega = \frac{V}{K_m} \]
\[ \omega = \frac{24V}{0.02 Nm/A} \]
\[ \omega = 1200 rad/s \]

Umbuzo 2: Ukusebenza kahle kweMoto Yokungenisa I-AC
Umbuzo: Injini yokungenisa enezigaba ezintathu inamandla okufaka angu-30 kW kanye namandla okukhipha angu-27 kW. Bala ukusebenza kahle kwenjini.

Ingxoxo:
Kuyaziwa:
– Amandla okufaka (P_in) = 30 kW
– Amandla okukhipha (P_out) = 27 kW

Ukusebenza kahle (\( \eta \)) kwenjini kungabalwa kusetshenziswa ifomula:
\[ \eta = \left( \frac{P_{out}}{P_{in}} \right) \times 100\% \]
\[ \eta = \kwesobunxele( \frac{27 kW}{30 kW} \kwesokudla) \izikhathi eziyi-100\% \]
\[ \eta = 0.9 \izikhathi eziyi-100\% \]
\[ \eta = 90\% \]

Ngakho-ke, ukusebenza kahle kwenjini yokungenisa kungu-90%.

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Umbuzo 3: Injini Ehambisanayo
Umbuzo: Injini ehambisanayo inamapali amane futhi inikezwa imvamisa engu-60 Hz. Bala isivinini esihambisanayo senjini.

Ingxoxo:
Kuyaziwa:
– Inani lezinsika (P) = 4
– Imvamisa (f) = 60 Hz

Ijubane elihambisanayo (n_s) lenjini ehambisanayo lingabalwa kusetshenziswa ifomula:
\[ n_s = \frac{120 \cdot f}{P} \]
\[ n_s = \frac{120 \cdot 60}{4} \]
\[ n_s = \frac{7200}{4} \]
\[ n_s = 1800 \, RPM \]

Ngakho-ke, ijubane elihambisanayo lenjini ehambisanayo lingu-1800 RPM.

Umbuzo 4: I-Torque Yemoto Ewuchungechunge lwe-DC
Umbuzo: Injini yochungechunge lwe-DC inokumelana kwekhoyili okungu-0.5 ohms futhi ihlinzekwa nge-voltage engu-120V. Uma ukugeleza kwamandla kagesi kungu-10A, bala i-torque uma i-torque engaguquki ingu-0.1 Nm/A².

Ingxoxo:
Kuyaziwa:
– Ukumelana nekhoyili (R) = 0.5 ohm
– I-voltage yokunikezela (V) = 120V
– Ugesi (I) = 10A
– I-torque engaguquki \( K_t \) = 0.1 Nm/A²

Okokuqala, bala ukwehla kwamandla kagesi kukhoyili:
\[ V_R = I \cdot R \]
\[ V_R = 10A \cdot 0.5 \Omega \]
\[ V_R = 5V \]

I-voltage esebenzayo (V_eff) esebenza kumotha:
\[ V_eff = V – V_R \]
\[ V_eff = 120V – 5V \]
\[ V_eff = 115V \]

I-Torque (T) ingabalwa kusetshenziswa ifomula:
\[ T = K_t \cdot I^2 \]
\[ T = 0.1 Nm/A² \cdot (10A)^2 \]
\[ T = 0.1 Nm/A² \cdot 100 A² \]
\[ T = 10 Nm \]

Ngakho-ke, i-torque ekhiqizwa yi-DC motor yochungechunge ingu-10 Nm.

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Umbuzo 5: Isiqalisi Semoto Yokungenisa
Umbuzo: Uchwepheshe ufaka i-star-delta starter ku-50 kW induction motor. Bala i-start current yokuqala uma i-voltage yokusebenza ingu-400 V futhi i-motor inamandla angu-92%.

Ingxoxo:
Kuyaziwa:
– Amandla enjini (P) = 50 kW
– I-Voltage (V) = 400V
– Ukusebenza kahle (\( \eta \)) = 92%

Okokuqala, sibala amandla okufaka (P_in):
\[ P_{in} = \frac{P}{\eta} \]
\[ P_{in} = \frac{50 kW}{0.92} \]
\[ P_{in} = 54.35 kW \]

Njengoba injini isebenzisa uhlelo lwe-star-delta, ugesi oqalayo enkanyezini uzoba ngaphansi kunogesi ngesikhathi sokusebenza kwe-delta. Kodwa-ke, ukuze sibale ugesi ojwayelekile, singasebenzisa i-P_in kanye ne-V:
\[ I_{nom} = \frac{P_{in}}{\sqrt{3} \cdot V} \]
\[ I_{nom} = \frac{54.35 kW}{\sqrt{3} \cdot 400V} \]
\[ I_{nom} = \frac{54350}{692.82} \]
\[ I_{nom} \cishe 78.44 A \]

Ukuze uqale amandla kagesi uma usebenzisa isekethe yezinkanyezi:
\[ I_{start\_star} = \frac{I_{nom}}{\sqrt{3}} \]
\[ I_{start\_star} \cishe \frac{78.44A}{\sqrt{3}} \]
\[ I_{start\_star} \cishe kube ngu-45.28 A \]

Ngakho-ke, ugesi wokuqala oqalayo kumjikelezo wezinkanyezi cishe u-45.28 A.

Isiphetho

Ukuqonda izibalo eziyisisekelo zezinhlobo ezahlukene zama-motor kagesi kubalulekile kulabo abasebenza kubunjiniyela kagesi nobemishini. Izibonelo zezinkinga ezingenhla zibonisa ukuthi amapharamitha ahlukahlukene njenge-voltage, i-current, i-torque, kanye nokusebenza kahle adlala kanjani indima ekunqumeni ukusebenza kwe-motor kagesi. Ngokuzijwayeza njalo, ikhono lokuxazulula izinkinga ezinjengalezi lizoba usizo kakhulu ekusetshenzisweni okusebenzayo nasemsebenzini.

Shiya amazwana