Imibuzo Eyisibonelo Ekhuluma Ngamagagasi E-Electromagnetic
Amagagasi kagesi angamagagasi akhiwa ngokuzulazula kwamasimu kagesi namagnetic asakazeka nge-vacuum ngesivinini sokukhanya. Lawa magagasi abalulekile ezicini ezahlukene zokuphila, kusukela ekuxhumaneni kuya empilweni. Ukuze siqonde kangcono lo mqondo, sizoxoxa ngezibonelo eziningana zezinkinga mayelana namagagasi kagesi kanye nezincazelo zawo.
Umbuzo 1: Ukubala Ubude Bamagagasi
Igagasi likagesi linomsinga ongu-500 MHz. Thola ubude balo begagasi!
Ingxoxo:
Imvamisa (f) = 500 MHz = 500 x 10^6 Hz
Isivinini sokukhanya (c) = 3 x 10^8 m/s
Ubude be-Wavelength (λ) bungabalwa kusetshenziswa ifomula:
\[ \lambda = \frac{c}{f} \]
Nansi imininingwane yokubala:
\[ \lambda = \frac{3 \times 10^8 \, \text{m/s}}{500 \times 10^6 \, \text{Hz}} \]
\[ \lambda = \frac{3 \times 10^8}{5 \times 10^8} \]
\[ \lambda = 0.6 \, \text{meter} \]
Ngakho-ke, ubude be-wave ye-electromagnetic buyi-0.6 metres.
Umbuzo 2: Amandla e-Photon
Iyini amandla e-photon enemvamisa engu-6 x 10^14 Hz?
Ingxoxo:
Amandla (E) e-photon angabalwa kusetshenziswa ifomula kaPlanck:
\[ E = hf \]
Di mana:
– u-h uyinto engaguquki kaPlanck = 6.626 x 10^-34 J·s
– u-f uvame = 6 x 10^14 Hz
Ngakho-ke,
\[ E = (6.626 \izikhathi 10^{-34} \, \umbhalo{J·s}) \izikhathi (6 \izikhathi 10^{14} \, \umbhalo{Hz}) \]
\[ E = 3.9756 \izikhathi 10^{-19} \, \umbhalo{J} \]
Ngakho-ke, amandla e-photon angama-3.9756 x 10^-19 joules.
Umbuzo 3: Isivinini samagagasi kagesi ku-Medium
Uma ijubane lokukhanya ku-vacuum lingu-3 x 10^8 m/s kanye ne-refractive index ye-medium ingu-1.5, liyini ijubane lokukhanya kuleyo medium?
Ingxoxo:
Ijubane lokukhanya ku-medium (v) lingabalwa kusetshenziswa inkomba yokukhanya (n):
\[ n = \frac{c}{v} \]
Di mana:
– c ijubane lokukhanya endaweni engenalutho = 3 x 10^8 m/s
– n yinkomba yokubheka emuva = 1.5
Ukubala i-v:
\[ v = \frac{c}{n} \]
\[ v = \frac{3 \times 10^8 \, \text{m/s}}{1.5} \]
\[ v = 2 \izikhathi 10^8 \, \umbhalo{m/s} \]
Ngakho-ke, ijubane lokukhanya kule ndlela yokusebenza liyi-2 x 10^8 amamitha ngomzuzwana.
Umbuzo 4: Amagagasi e-Electromagnetic kuma-Radio Frequencies
Isiteshi somsakazo u-X sisakaza ngesivinini esingu-100 MHz. Ungakanani ubude be-wavelength yesiginali?
Ingxoxo:
Imvamisa (f) = 100 MHz = 100 x 10^6 Hz
Isivinini sokukhanya (c) = 3 x 10^8 m/s
Ubude be-Wavelength (λ) bungabalwa kusetshenziswa ifomula:
\[ \lambda = \frac{c}{f} \]
Ngakho-ke,
\[ \lambda = \frac{3 \times 10^8 \, \text{m/s}}{100 \times 10^6 \, \text{Hz}} \]
\[ \lambda = \frac{3 \times 10^8}{1 \times 10^8} \]
\[ \lambda = 3 \, \text{meter} \]
Ngakho-ke, ubude be-wavelength yesignali yomsakazo bungamamitha amathathu.
Umbuzo 5: Amandla Atholwa Yi-Antenna
I-antenna ithola isignali yegagasi likagesi enamandla angu-0.1 W ngemvamisa engu-2.4 GHz. Mangaki ama-photon ngomzuzwana i-antenna etholayo?
Ingxoxo:
Amandla (P) = 0.1 W = 0.1 J/s
Imvamisa (f) = 2.4 GHz = 2.4 x 10^9 Hz
Amandla e-photon eyodwa (E) angabalwa kusetshenziswa ifomula:
\[ E = hf \]
\[ E = (6.626 \izikhathi 10^{-34} \, \umbhalo{J·s}) \izikhathi (2.4 \izikhathi 10^9 \, \umbhalo{Hz}) \]
\[ E = 1.59024 \izikhathi 10^{-24} \, \umbhalo{J} \]
Inani lama-photon ngomzuzwana (N) lingabalwa ngokuhlukanisa amandla ngamandla nge-photon ngayinye:
\[ N = \frac{P}{E} \]
\[ N = \frac{0.1 \, \text{J/s}}{1.59024 \times 10^{-24} \, \text{J}} \]
\[ N = 6.29 \izikhathi ezingu-10^{22} \, \umbhalo{ama-photon/s} \]
Ngakho-ke, i-antenna ithola cishe ama-photon angu-6.29 x 10^22 ngomzuzwana.
Isiphetho
Ingxoxo ngamagagasi kagesi ihlukahlukene kakhulu futhi ihlanganisa izici eziningi, kusukela ekubaleni ubude be-wavelength, amandla e-photon, kuya kusivinini samagagasi endaweni ephakathi nendawo. Izinkinga zesibonelo kanye nezincazelo zazo ezingenhla kulindeleke ukuthi zikusize uqonde umqondo wamagagasi kagesi ngokujula okukhulu kanye nokusetshenziswa kwawo. Ngethemba ukuthi lesi sihloko siwusizo futhi sandisa ukuqonda kwabafundi ngamagagasi kagesi.
