Izibonelo eziyi-15 zezinkinga ze-Static Fluid
Ukucindezela Okungamanzi
1. Umehluko ekucindezelweni kwegazi okungaguquki phakathi kobuchopho kanye nezinyawo zomuntu omude ngamasentimitha angu-165 uthi… (Ake sithi ubuningi begazi bungu-1,0 × 10 3 kg/m3 kanye no-g = 10 m/ s2 )
A. 1,65 × 10 2 N/m 2
B. 1,65 × 10 3 N/m 2
C. 1,65 × 10 4 N/m 2.
D. 0,83 × 10 4 N/m 3
E. 0,83 × 10 3 N/m 2
Ingxoxo
Kuyaziwa ukuthi:
Yisho wonke amayunithi ohlelweni lwamazwe ngamazwe
Ukuphakama (h) = 165 cm = 165/100 amamitha = 1,65 amamitha
Ubuningi begazi ( ρ) = 1,0 × 10 3 kg/ m3
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Kubuziwe: Umfutho we-hydrostatic
Impendulo:

Izitsha Ezixhumanisayo
2. Bheka isithombe esilandelayo:
I-U-tube iqale igcwaliswe ngamanzi anobukhulu obungu-1000 kg.m -3 , bese kuthi uwoyela wokupheka uthululwe kwelinye lamapayipi ukuze indawo ezinzile ibukeke njengesithombe. Uma ukuphakama kwekholomu yamafutha kungu-8 cm kanti ikholomu yamanzi ingu-5 cm, ubukhulu bamafutha okupheka...
A. 520 kg.m-3
B. 525 kg.m -3
C. 600 kg.m -3
D. 625 kg.m -3
E. 720 kg.m -3
Ingxoxo
Kuyaziwa ukuthi:
Ubuningi bamanzi = 1000 kg.m -3
Ukuphakama kwamanzi = 5 cm
Ukuphakama kwamafutha okupheka = 8 cm
Umbuzo: Ubuningi bamafutha okupheka
Impendulo:

Impendulo efanele ngu-D.
Ukuqina
3. Itshe elinomthamo ongu-0,5 m 3 licwiliswa ngokuphelele oketshezini olunobukhulu obungu-1,5 g cm –3 . Uma ukusheshisa ngenxa yamandla adonsela phansi = 10 ms –2 , khona-ke itshe lizozwa amandla aphezulu angu…..
A. 1.500 N
B. 3.000 N
C. 4.500 N
D. 7.500 N
E. 9.000 N
Ingxoxo
Kuyaziwa ukuthi:
Umthamo wetshe (V) = 0,5 m 3
Ubuningi boketshezi ( ρ) = 1,5 gr cm –3 = 1500 kg m -3
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 ms -2
Umbuzo: Amandla anamandla (FA ) atholwa yitshe
Impendulo:
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Impendulo efanele ngu-D.
Izinto Ezintantayo
4. Ingcezu yeqhwa entanta olwandle ifana nesithombe. Uma ubukhulu bamanzi olwandle bungu-1,2 gr cm –3 kanti ubukhulu bengcezu yeqhwa bungu-0,9 gr c –3 khona-ke ubukhulu bengcezu yeqhwa elicwiliswa (lingena) emanzini olwandle bulingana no….. ubukhulu obuvelayo.
A. izikhathi ezimbili
B. izikhathi ezintathu
C. izikhathi ezine
D. izikhathi ezi-5
E. izikhathi ezingu-6
Ingxoxo
Kuyaziwa ukuthi:
Ubuningi bamanzi olwandle ( ρ ulwandle ) = 1,2 gr cm –3
Ukuminyana kweqhwa (ρ es ) = 0,9 gr c –3
Umbuzo: Umthamo weqhwa elicwiliswe emanzini olwandle ufana nomthamo ovelayo.
Impendulo:

Ngakho-ke umthamo weqhwa elicwiliswe emanzini olwandle ulingana nomthamo ophindwe kathathu kunomthamo ovelayo (3 x 0,25 = 0,75).
Impendulo efanele ingu-B.
5. Into intanta oketshezini olunengxenye yesithathu yento ecwiliswe emanzini. Uma ubukhulu bento bungu-0,6 g cm 3 , khona-ke ubukhulu boketshezi bungu….
A. 1.800 kg m 3
B. 1.500 kg m 3
C. 1.200 kg m 3
D. 900 kg m 3
E. 600 kg m 3
Ingxoxo
Kuyaziwa ukuthi:
Ingxenye yento ecwiliswe emanzini = 2/3
Ubuningi bento = 0,6 gr cm 3 = 600 kg m 3
Umbuzo: Ubuningi boketshezi (x)
Impendulo:
Ingxenye yento ecwiliswe emanzini ilingana nesilinganiso sobuningi:

Ubuningi boketshezi bungu-900 kg m3
Impendulo efanele ngu-D.
6. Ucezu lwezinkuni luyantanta kanti ingxenye yalo engu-3/5 icwiliswe emanzini. Uma ubuningi bamanzi bungu-1 × 10 3 kg/m3 , khona-ke ubuningi bezinkuni bungu…
A. 2 × 10 2 kg/ m3
B. 4 × 10 2 kg/m 3
C. 6 × 10 2 kg / m3
D. 8 × 10 2 kg/m 3
E. 10 × 10 2 kg/m 3
Ingxoxo
Kuyaziwa ukuthi:
Ingxenye yento ecwiliswe emanzini = 3/5
Ubuningi bamanzi = 1×10 3 kg/m 3 = 1000 kg/m 3
Umbuzo: Ubuningi bokhuni (x)
Impendulo:
Ingxenye yento ecwiliswe emanzini ilingana nesilinganiso sobuningi:

Ubuningi bokhuni bungu-600 kg/m 3 = 6 x 10 2 kg/m 3
Impendulo efanele ngu-C.
7. Bheka isithombe sebhulokhi esilandelayo!
Ibhulokhi licwiliswa koketshezi olubili oluhlukene. Uma licwiliswa kuketshezi A, u-0,6 webhulokhi uyacwiliswa. Uma licwiliswa kuketshezi B, u-0,5 webhulokhi uyacwiliswa. Isilinganiso sobuningi boketshezi A no-B…
A. 1: 1
B. 4: 5
C. 5: 4
D. 5: 6
Isahluko 6: 5
Ingxoxo
Kuyaziwa ukuthi:
Ubuningi bebhulokhi = x
Ingxenye yento ecwiliswe oketshezini A = 0,6
Ubuningi boketshezi A = y
Ingxenye yento ecwiliswe oketshezini B = 0,5
Ubuningi boketshezi B = z
Umbuzo: Ukuqhathaniswa kobuningi boketshezi u-A no-B (y : z)
Impendulo:
Ingxenye yento ecwiliswe oketshezini ilingana nesilinganiso sobuningi bento nobuningi boketshezi.

Faka u-x ku- equation 2 esikhundleni sika-x ku- equation 1 :

Impendulo efanele ngu-D.
8. Bheka isithombe!
Into uma ifakwa ku-P ewuketshezi iyantanta nge-1/2 yevolumu yayo ngaphansi kobuso boketshezi futhi uma ifakwa ku-Q ewuketshezi into iyantanta. Isilinganiso sobuningi boketshezi u-P no-Q…
A. 1: 2
B. 2: 1
C. 2: 3
D. 3: 1
Isahluko 3: 4
Ingxoxo
Kuyaziwa ukuthi:
Ubuningi bento = x
Ingxenye yento ecwiliswe oketshezini P = 1/2 = 0,5
Ubuningi boketshezi P = y
Ingxenye yento ecwiliswe oketshezini Q = 1 (zonke izingxenye zento zicwilisiwe)
Ubuningi boketshezi Q = z
Umbuzo: Ukuqhathaniswa kobuningi boketshezi u-P no-Q (y : z)
Impendulo:
Ingxenye yento ecwiliswe oketshezini ilingana nesilinganiso sobuningi bento nobuningi boketshezi.

Faka u-x ku- equation 2 esikhundleni sika-x ku- equation 1 :

Impendulo efanele ingu-B.
9. Ucezu lwezinkuni luntanta emafutheni (ubuningi = 800 kg.m -3 ) kuze kube yilapho u-4/5 womthamo walo usemafutheni, bese ubuningi bezinkuni buba....
A. 16 kg.m -3
B. 64 kg.m -3
C. 160 kg.m -3
D. 270 kg.m -3
E. 640 kg.m -3
Ingxoxo
Kuyaziwa ukuthi:
Ubuningi bamafutha ( ρ) = 800 kg.m -3
Ingxenye yento ecwiliswe emanzini = 4/5
Kubuziwe: Ubuningi bokhuni
Impendulo:
Ingxenye yento ecwiliswe emanzini ilingana nesilinganiso sobuningi:

Ubuningi bokhuni bungu-640 kg/ m3.
Impendulo efanele ngu-E.
10. Ibhlokhi emoyeni linesisindo esingu-50 N. Uma lilinganiswa emanzini, isisindo salo siba ngu-30 N. Uma ubukhulu bamanzi = 103 kg.m -3 , khona-ke ubukhulu bebhlokhi...
A. 1500 kg.m -3
B. 2000 kg.m -3
C. 2500 kg.m -3
D. 3000 kg.m -3
E. 4000 kg.m -3
Ingxoxo
Kuyaziwa ukuthi:
Isisindo sebhulokhi emoyeni (w) = 50 N
Isisindo sebhulokhi emanzini (w amanzi ) = 30 N
Ubuningi bamanzi ( ρ amanzi ) = 10 3 kg.m -3 = 1000 kg.m -3
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s 2
Isisindo sebhulokhi emoyeni (m) = w/g = 50/10 = 5 kg
Umbuzo: Ubuningi bebhulokhi ( ρ block )
Impendulo:
Bala amandla okuphaphazela:
F A = w – w amanzi = 50 – 30 = 20 N
Bala ivolumu yebhulokhi ecwiliswe emanzini usebenzisa ifomula yamandla okubutha:
F A = ρ g V
20 = (1000)(10) V
20 = (10.000) V
V = 20/10.000
V = 0,002 m 3
Bala ubuningi bebhulokhi:
ρ = m/V = 5/0,002 = 2500 kg/m 3
Impendulo efanele ngu-C.
Ukucindezela koketshezi
11.
Jabulela ubumnandi!
Ukusheshisa okubangelwa amandla adonsela phansi kungu-10 N/kg, uma indawo yenhlanzi enqamula ingxenye yayo icindezelwe ngamanzi angaphezu kwayo ingu-6 cm2, bese kuba amandla acindezela inhlanzi emanzini angaphezu kwayo….
- I-5,1 N
- I-85 N
- I-8500 N
- I-8600 N
Ingxoxo
Kuyaziwa ukuthi:
Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 N/kg
Indawo yezinhlanzi enqamula ingxenye (A) = 6 cm2 = 6 x10-4 m2
Ubuningi bamanzi = 1 gram/cm3 = 1 (10-3 kg) / 10-6 m3 = 103 kg / m3 = 1000 kg / m3
Ukuphakama kwamanzi = 100 cm – 15 cm = 85 cm = 85 x 10-2 imitha
Kubuziwe: Amandla asunduza inhlanzi emanzini angaphezu kwayo
Impendulo:
Impendulo efanele ngu-A.
Ukuqina kwe-capillarity kanye nokuqina kobuso boketshezi
12. Uma ithonsi eliwuketshezi lincane, kulapho ukuma kwalo kusondela khona ku-sphere. Ngomthamo othile, kungafakazelwa ukuthi i-sphere inendawo encane kakhulu uma kuqhathaniswa nezinye izimo. Umqondo wethonsi eliwuketshezi elisondela ku-sphere uhlobene nomqondo we…
- Ubuningi
- Ukunamathela kanye nobumbano
- Ukungezwani kobuso
- I-Meniscus kanye ne-capillarity
Ingxoxo
Ukuma kwendilinga kwamaconsi oketshezi kuhlobene nomqondo wokuxineka kobuso. Ngokwezibalo, ukuxineka kobuso kungamandla ngobude beyunithi ngayinye. Amandla okukhulunywa ngawo ukuhlangana. Ukuhlangana kungukukhanga phakathi kwama-molecule afanayo, kuyilapho ukunamathela kungukukhanga phakathi kwama-molecule angafani.
Amandla aqinile okuhlangana phakathi kwama-molecule amanzi kanye namandla aqinile okunamathela phakathi kwama-molecule amanzi nama-molecule omoya noma amanye ama-molecule abangela ukuthi wonke ama-molecule amanzi akhangane futhi ahlangane ndawonye. Ama-molecule amanzi angaphakathi kweconsi lamanzi adonsela ama-molecule amanzi angaphandle ukuze asondele ndawonye. Ama-molecule amanzi angaphandle anamandla aqinile okunamathela ngakho adonswa kalula ndawonye. Futhi ukuma kweconsi lamanzi elakhiwe kufana nebhola. Kule nqubo, ubuso beconsi lamanzi bubonakala buqinile ngenxa yamandla akhangayo phakathi kwama-molecule amanzi.
Impendulo efanele ngu-C.
13. Isenzakalo sokukhuphuka kwamanzi epayipini le-capillary kungenxa yokuthi...
- Amandla okunamathela phakathi kwamanzi nengilazi ayakwazi ukudonsa amanzi aye phezulu
- amandla ahlangene phakathi kwamanzi nengilazi ayakwazi ukudonsa amanzi aye phezulu
- ukuba khona kwamandla ka-Archimedes
- ingcindezi ye-hydrostatic ebusweni bamanzi epayipini le-capillary incane kakhulu
Ingxoxo
Ukwanda kwamanzi epayipini le-capillary kwenzeka ngoba amandla okunamathela phakathi kwama-molecule amanzi nama-molecule epayipini le-capillary makhulu kunamandla okunamathelana phakathi kwama-molecule amanzi. Ngakho-ke amandla amakhulu okunamathela phakathi kwama-molecule amanzi nama-molecule epayipini le-capillary ayakwazi ukudonsa amanzi aye phezulu.
Ipayipi le-capillary lingaba yipayipi lengilazi, intambo yesitofu, njll.
Impendulo efanele ngu-A.
Umthetho we-Buoyancy kanye no-Archimedes
14. Umkhumbi ohamba olwandle ungena emfuleni obanzi futhi ojulile. Uma ubuningi bamanzi olwandle bungu-1100 kg/m3 , ubuningi bamanzi ahlanzekile bungu-1000 kg/m3 , khona-ke isilinganiso samandla ka-Archimedes atholwa umkhumbi olwandle nasemfuleni….
- 11: 10
- 10: 11
- 121: 100
- 1: 1
Ingxoxo
Kuyaziwa ukuthi:
Kubuziwe: Ukuqhathaniswa kwamandla e-Achimedes atholwa yimikhumbi olwandle nasemifuleni
Impendulo:
Uma into intanta khona-ke amandla okuphapha (F)A) = amandla adonsela phansi (w):
Umthetho ka-Archimedes uthi amandla ashukumisayo asebenza entweni ecwiliswe oketshezini (amanzi) alingana nesisindo soketshezi (amanzi) olususayo. Umthamo wento ecwiliswe oketshezini (amanzi) ulingana nomthamo woketshezi (amanzi) olususiwe.
Ukuqhathaniswa kwenani lezinto ezicwiliswe emanzini olwandle nasemanzini omfula:
Impendulo efanele ingu-B.
15. Ibhlogo lokhuni licwiliswa emanzini. Kuvela ukuthi u-25% wengxenye ungaphezu kwamanzi kanti u-75% usemanzini. Uma ubuningi bamanzi bungu-1 g/cm3 futhi ukusheshisa ngenxa yamandla adonsela phansi kungu-10 m/s2 , khona-ke ubuningi bebhlogo lokhuni bungu….
- 0,025 kg / m3
- 0,075 g / cm3
- 0,250 kg / m3
- 0,750 g / cm3
Ingxoxo
Kuyaziwa ukuthi:
Ingxenye yebhulokhi ephezu kwamanzi = 25% = 25/100 = 0,25
Ingxenye yebhloko ecwiliswe emanzini = 75% = 75/100 = 0,75
Ubuningi bamanzi = 1 g/cm3 = 1000 kg / m3
Ukusheshisa ngenxa yamandla adonsela phansi = 10 m/s2
Kubuziwe: Ubuningi bamabhulokhi okhuni
Impendulo:
Umthamo webhloko elicwiliswe emanzini = isilinganiso sobuningi bebhloko nobuningi bamanzi
Impendulo efanele ngu-D.
Umthombo wombuzo:
Imibuzo Yefiziksi Yezivivinyo Zikazwelonke Zesikole Samabanga Aphezulu/Isikole Samabanga Aphezulu Sokufundela Umsebenzi
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