1. E rua ngā utunga pūwāhi, QA = +8 μC me te QB = -5 μC, e wehea ana e te tawhiti r = 10 cm. He aha te rahi o te te kaha hiko. Ko te pūmau k = 8.988 x 109 Nm2C-2 = 9x109 Nm2C-2.
![]()
Mōhiotia:
Utu A (q A ) = +8 μC = +8 x 10 -6 C
Utu B (q B ) = -5 μC = -5 x 10 -6 C
k = 9 x 10 9 Nm 2 C −2
Ko te tawhiti i waenganui i ngā utu A me B (r AB ) = 10 cm = 0.1 m
E hiahiatia ana : Te rahi o te kaha hiko
Rongoā:
Te tauira o te ture a Coulomb :
![]()
Te rahi o te kaha hiko:

[irp]
2. E rua ngā matūriki kua utua, e whakaaturia ana i te pikitia i raro nei. Ko Q P = +10 μC me Q q = +20 μC e wehea ana e te tawhiti r = 10 cm. He aha te rahi o te kaha hiko-pūmau?
![]()
Mōhiotia:
Utu P (Q P ) = +10 μC = +10 x 10 -6 C
Utu Q (Q Q ) = +20 μC = +20 x 10 -6 C
k = 9 x 10 9 Nm 2 C −2
Ko te tawhiti i waenganui i ngā utu P me Q (r PQ ) = 12 cm = 0.12 m = 12 x 10 -2 m
E hiahiatia ana: Te rahi o te kaha hiko
Rongoā:

[irp]
3. E toru ngā matūriki kua whakarārangihia kia rite ki te pikitia i raro nei. Utu A = -5 μC, utu B = +10 μC me utu C = -12 μC. Tātaihia te kaha hiko pūmau ki runga i te matūriki B nā ngā utu e rua e toe ana.
![]()
Mōhiotia:
Utu A (q A ) = -5 μC = -5 x 10 -6 C
Utu B (q B ) = +10 μC = +10 x 10 -6 C
Utu C (q C ) = -12 μC = -12 x 10 -6 C
k = 9 x 10 9 Nm 2 C −2
Ko te tawhiti i waenganui i ngā matūriki A me B (r AB ) = 6 cm = 0.06 m = 6 x 10 -2 m
Ko te tawhiti i waenganui i ngā matūriki B me C (r BC ) = 4 cm = 0.04 m = 4 x 10 -2 m
E hiahiatia ana: Te rahi me te ahunga o te kaha hikohiko kupenga i runga i te matūriki B
Rongoā:
Ko te kaha kupenga i runga i te matūriki B ko te tapeke whārite o te kaha F BA i pā ki te matūriki B e te matūriki A me te kaha F BC i pā ki te matūriki B e te matūriki C.
Ko te kaha F BA i pā ki te matūriki B e te matūriki A:

Ko te ahunga o te kaha hikohiko e tohu ana ki te matūriki A (e tohu ana ki te maui).
Ko te kaha F BC i pā ki te matūriki B e te matūriki A:

Ko te ahunga o te kaha hikohiko e tohu ana ki te matūriki C (tohu ki te taha matau).
Ko te kaha hiko pūmau kupenga i runga i te matūriki B :
F B = F AB – F BC = 675 N – 125 N = 550 Ngā Newton.
Ko te ahunga o te kaha hiko pūmau i runga i te matūriki B e tohu ana ki te matūriki C (e tohu ana ki te taha matau).
[irp]
4. Kua wehea a +Q 1 = 10 μC, +Q 2 = 50 μC me Q 3 e ai ki te pikitia i raro nei. He aha te utu hiko pūmau i runga i te matūriki 3 mēnā he kore te kaha hiko pūmau kupenga i runga i te matūriki 2.

Mōhiotia:
Utu 1 (q 1 ) = +10 μC = +10 x 10 -6 C
Utu 2 (q 2 ) = +50 μC = +50 x 10 -6 C
Ko te tawhiti i waenganui i ngā utu 1 me te 2 (r 12 ) = 2 cm = 0.02 m = 2 x 10 -2 m
Ko te tawhiti i waenganui i te utu 2 me te utu 3 (r 23 ) = 6 cm = 0.06 m = 6 x 10 -2 m
Ko te kaha hiko pūmau kupenga i runga i te matūriki 2 (F 2 ) = 0
E hiahiatia ana : utu 3 (q 3 )
Rongoā:
Ko te kaha kupenga i runga i te matūriki 2 ko te tapeke whārite o te kaha F 21 i pā ki te matūriki 2 e te matūriki 1 me te kaha F 23 i pā ki te matūriki 2 e te matūriki 3.
Ko te kaha F 21 i pā ki te matūriki 2 e te matūriki 1:

Ko te ahunga o te kaha hikohiko e tohu ana ki te matūriki 3 (tohu ki te taha matau).
Te kaha F23 i pāngia e te matūriki 3 ki te matūriki 2: 
Ko te ahunga o te kaha hikohiko e tohu ana ki te matūriki 1 (tohu ki te maui).
Ko te kaha hiko pūmau kupenga i runga i te matūriki 2 = 0:
