1. Tātaihia te rahi me te ahunga o te papa hiko i tētahi pūwāhi A kei te 5 cm mai i tētahi utu pūwāhi Q = +10 μC. k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)
Mōhiotia:
Utu hiko (Q) = +10 μC = +10 x 10 -6 C
Ko te tawhiti i waenganui i te pūwāhi A me te utu pūwāhi Q (r A ) = 5 cm = 0.05 m = 5 x 10 -2 m
k = 9 x 10 9 Nm 2 C −2
E hiahiatia ana: Te rahi me te ahunga o te papa hiko i te pūwāhi A
Rongoā:
Ko te ahunga o te papa hiko i te pūwāhi A:
He pai te utu hiko, nō reira kei tawhiti atu te ahunga o te mara hiko i te utu hiko, ā, kei ngā pūwāhi A anō hoki.
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2. Tātaihia te rahi me te ahunga o te papa hiko i tētahi pūwāhi P kei te 10 cm mai i tētahi utu pūwāhi Q = -2 0 μC. k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C.
Mōhiotia:
Utu hiko (q) = -20 μC = -20 x 10 -6 C
Ko te tawhiti i waenganui i te pūwāhi P me te utu hiko (r P ) = 10 cm = 0.1 m = 1 x 10 -1 m
k = 9 x 10 9 Nm 2 C −2
E hiahiatia ana: Te rahi me te ahunga o te papa hiko i te pūwāhi P
Rongoā:
Ko te ahunga o te papa hiko i te pūwāhi A:
He kino te utu hiko, nō reira te ahunga o te āpure hiko ki te utu hiko.
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3. E 40 cm te tawhiti e wehea ana e ngā utu pūwāhi e rua. He aha te rahi me te ahunga o te papa hiko i te pūwāhi P i waenganui i ngā utu e rua, arā, 20 cm te tawhiti mai i te pūwāhi A?
Mōhiotia:
Utu A (q A ) = -2 μC = -2 x 10 -6 C
Utu B (q B ) = + 4 μC = +4 x 10 -6 C
Ko te tawhiti i waenganui i te utunga A me te pūwāhi P (r AP ) = 20 cm = 0.2 m = 2 x 10 -1 m
Ko te tawhiti i waenganui i te utu B me te pūwāhi P (r BP ) = 20 cm = 0.2 m = 2 x 10 -1 m
E hiahiatia ana: Te rahi me te ahunga o te āpure hiko i te pūwāhi P.
Rongoā:
He kino te utunga A, nō reira ko te ahunga o ngā pūwāhi o te mara hiko kei te taha o Q A (ki te taha mauī).
He pai te utunga B, nō reira kei tawhiti atu te ahunga o ngā pūwāhi o te mara hiko i a QB ( ki te taha mauī).
Ko te papa hiko katoa i te pūwāhi A:
E = EA + EB
E = (4.5 x 10 5 ) + (9 x 10 5 )
E = 13.5 x 10 5 N/C
E anga ana te ahunga o te papa hiko ki Q A (ki te taha mauī).
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4. Kore te rahi o te papa hiko i te…
He pai te utu A, he pai hoki te utu B, nō reira ko te rahi o te āpure hiko he kore kei te pūwāhi P, i waenganui i ngā utu e rua.
Mōhiotia:
Utu A (q A ) = + 20 μC = +20 x 10 −6 C
Utu B (q B ) = +40 μC = +40 x 10 −6 C
k = 9 x 10 9 Nm 2 C −2
Ko te tawhiti i waenganui i te utu A me te utu B = 20 cm
Ko te utu i waenganui i te utu A me te pūwāhi P (r AP ) = a
Ko te tawhiti i waenganui i te utunga B me te pūwāhi P (r BP ) = 20 – a
E hiahiatia ana: Ko te rahi o te papa hiko he kore kei te….
Rongoā:
Te rahi o te āpure hiko i hangaia e te utunga A i te pūwāhi P
He pai te utunga A, nō reira kei tawhiti atu te ahunga o ngā pūwāhi o te mara hiko i te utunga A (ki te taha matau).
Te rahi o te āpure hiko i whakaputaina e te utu B i te pūwāhi P:
He pai te utunga B, nō reira kei tawhiti atu te ahunga o ngā pūwāhi o te mara hiko i te utunga B (ki te taha mauī).
Ko te papa hiko katoa i te pūwāhi P = 0:
Ka whakamahia e mātou te tātai tapawhā hei whakatau i te a.
Kore te rahi o te āpure hiko kei te 8 cm mai i te utunga A, 12 cm rānei mai i te utunga B.
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5. I runga i te ahua i raro nei, ko tēhea te pūwāhi P kia kore ai te papa hiko i te pūwāhi P? (k = 9 x 10 9 Nm 2 C −2 , 1 μC = 10 −6 C)
otinga
Ttātaihia te kaha o te papa hiko i te pūwāhi P, me te whakaaro kei te pūwāhi P he utu whakamātautau pai. Q1 he pai, ā, ko Q2 he tōraro, nō reira me noho te pūwāhi P ki te taha matau o Q2 ki te taha maui rānei o Q1. Mena kei te taha maui o Q te pūwāhi P1; te papa hiko i hangaia e Q1 kei te pūwāhi P kei te taha maui (kei tawhiti atu i a Q1) me te papa hiko i hangaia e Q2 i te pūwāhi P ki te taha matau (ki te taha Q1). He rerekē te ahunga o te papa hiko, ā, ka whakakorea ngā papa hiko e rua tetahi i tetahi, ā, ka kore te kaha o te papa hiko i te pūwāhi P.
Mōhiotia:
Q 1 = +9 μC = +9 x 10 −6 C
Q 2 = -4 μC = -4 x 10 −6 C
k = 9 x 10 9 Nm 2 C −2
Te tawhiti i waenganui i te utu 1 me te utu 2 = 3 cm
Te tawhiti i waenganui i a Q 1 me te pūwāhi P (r 1P ) = a
Te tawhiti i waenganui i a Q 2 me te pūwāhi P (r 2P ) = 3 + a
E hiahiatia ana: te taunga o te pūwāhi P kia kore ai te papa hiko i te pūwāhi P
Rongoā:
Kei te taha maui o Q 1 te Pūwāhi P.
Ko te mara hiko i hangaia e Q 1 i te pūwāhi P:
He pai te utu whakamātautau, ā, he pai hoki a Q 1 , nō reira ko te ahunga o te āpure hiko kei te taha mauī.
Ko te mara hiko i hangaia e Q 2 i te pūwāhi P:
He pai te utu whakamātautau, ā, he kino te Q 2 , nō reira kei te taha matau te ahunga o te āpure hiko.
Te mara hiko kupenga i te pūwāhi A:
Whakamahia te tātai tapawhā hei whakatau i te:
a = -1.25, b = -13.5, c = -20.25
Te tawhiti i waenganui i a Q 2 me te pūwāhi P (r 2P ) = 3 + a = 3 – 1.8 = 1.2 cm.
Kei te 1.2 cm te tawhiti o te pūwāhi P ki te taha matau o Q1.
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