I-physics

1. Isisindo sento = 2 kg, ukusheshisa ngenxa yamandla adonsela phansi = 9.8 m/s ² , i-coefficient ye -static friction = 0.2, i-coefficient ye-kinetic friction = 0.1. Ingabe into iphumule noma iyasheshisa? Uma into isheshisiwe, thola (a) amandla aphelele (b) ubukhulu kanye nesiqondiso sokusheshisa kwebhokisi!

Isixazululo

Kwaziwa:

Isisindo (m) = 2 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 9.8 m/s ²

I-Coefficient yokungqubuzana okungaguquki ( μs ₎ = 0.2

I-coefficient yokungqubuzana kwe-kinetic ( μk ₎ = 0.1

Isisindo (w) = mg = (2)(9.8) = 19.6 amaNewton

Ingxenye evundlile yesisindo ( w _x ) = w sin 30 ^o = (19.6)(0.5) = 9.8 Newtons

Ingxenye eqondile yesisindo sika-th (w _y ) = w cos 30 ^o = (19.6)(0.5√3) = 9.8√3 AmaNewton

Amandla ajwayelekile (N) = w _y = 9.8√3 AmaNewton

Amandla okungqubuzana okungaguquki (fs ₎ = (0.2)(9.8√3) = 1.96√3 Newton = 3.39 Newton

Amandla okungqubuzana kwe-kinetic (f _k ) = (0.1)(9.8√3) = 0.98√3 Newton = 1.69 Newton

Isixazululo:

Into iphumule uma u-w _x < _fs , into ihamba phansi uma u-w _x > _fs.

w _x = 9.8 AmaNewton kanye no-f _s = 3.39 AmaNewton.

(a) amandla aphelele

∑ F = w _x – f _k = 9.8 – 1.69 = 8.11 AmaNewton

(b) ubukhulu kanye nesiqondiso sokusheshisa

∑ F = ma

8.11 = (2) a

a =4.05

Ubukhulu bokusheshisa = 4.05 m/s ² kanye nesiqondiso sokusheshisa = phansi.

[irp]

2. Isisindo sento = 4 kg, ukusheshisa ngenxa yamandla adonsela phansi = 9,8 m/s ² . I-coefficient ye-kinetic friction = 0.2 kanye ne-coefficient ye-static friction = 0.4. Ubukhulu bamandla F = 40 Newtons. Into iphumule noma ishelela phansi? Uma into ishelela phansi, thola (a) amandla aphelele (b) ubukhulu kanye nesiqondiso sokusheshisa!

Isixazululo

Kwaziwa:

Isisindo (m) = 4 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 9.8 m/s ²

I-coefficient yokungqubuzana okungaguquki ( μs ₎ = 0.4

I-coefficient ye-kinetic friction ( μk ₎ = 0.2

Isisindo (w) = mg = (4)(9.8) = 39.2 amaNewton

Ingxenye evundlile yesisindo (w _x ) = w sin 30 ^o = (39.2)(0.5) = 19.6 Newtons

Ingxenye eqondile yesisindo (w _y ) = w cos 30 ^o = (392)(0..5√3) = 19.6√3 AmaNewton

Amandla ajwayelekile (N) = w _y = 19.6√3 AmaNewton = 33.95 AmaNewton

amandla okungqubuzana okungaguquki (fs ₎ = μs _N = (0,4)(33.95) = 13.58 amaNewton

Amandla okungqubuzana kwe-kinetic (f _k ) = μ _k N = (0.2)(33.95) = 6.79 amaNewton

F = 40 Newton

Isixazululo:

Into ishelela phansi uma F < w _x + fs _. Into ishelela phezulu uma F > w _x + _fs.

F = 40 Newtons, w _x = 19.6 Newtons kanye fs ₌ 13.58 Newtons.

U-F mkhulu kuno-w _x + f _s ngakho into iyashelela phezulu.

(a) Amandla aphelele

∑ F = F – w _x – f _k = 40 – 19.6 – 6.79 = 13.61 amaNewton

(b) Ubukhulu kanye nesiqondiso sokusheshisa

∑ F = ma

6.4 = (4) a

a =1.6

Ubukhulu bokusheshisa buyi-1.6 m/s ² futhi isiqondiso sokusheshisa siphezulu.

[irp]

[wpdm_package id='481′]

1. Isisindo kanye nesisindo
2. amandla ajwayelekile
3. Umthetho wesibili wokunyakaza kukaNewton
4. Amandla okungqubuzana
5. Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
6. Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
7. Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
8. Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
9. Ukunyakaza e-lifti
10. Ukunyakaza kwemizimba kuxhunywe ngezintambo nama-pulleys
11. Imizimba emibili enesilinganiso esifanayo sokusheshisa
12. Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
13. Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
14. Ukunyakaza okufanayo kumbuthano ovundlile
15. Amandla aphakathi ahambisanayo ajikelezayo

Funda kabanzi

1. Isisindo sebhokisi = 2 kg, ukusheshisa ngenxa yamandla adonsela phansi = 9.8 m/s ^{2 . Thola (a) amandla aphelele asheshisa ibhokisi liye phansi (b) ubukhulu} bokusheshisa kwebhokisi.

Isixazululo

Kwaziwa:

Isisindo (m) = 2 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 9.8 m/s ²

Isisindo (w) = mg = (2)(9.8) = 19.6 amaNewton

w _x = w isono 30 = (19.6)(0.5) = 9.8 amaNewton

w _y = w cos 30 = (19.6)(0.5√3) = 9.8√3 AmaNewton

Isixazululo:

(a) Inethi ye -ce esheshisa ibhokisi

Indiza egobile ibushelelezi, ngakho-ke awekho amandla okungqubuzana. Amandla odwa asebenza entweni yi-w _x.

∑ F = w _x

∑ F = 9.8 Newton

(b) ubukhulu bokusheshisa

∑ F = ma

9.8 = (2) a

a = 9.8/2

a = 4.9 m/s ²

Ubukhulu bokusheshisa bungu-4.9 m/s ² , isiqondiso sokusheshisa siphansi.

[irp]

2. Indiza egobile ibushelelezi ngakho-ke awekho amandla okungqubuzana . Isisindo sento singama-3 kg, ukusheshisa ngenxa yamandla adonsela phansi kungu-9.8 m/s ² . Thola ubukhulu bamandla F uma (a) into iphumule (b) into ihambela phansi ngokusheshisa okungaguquki okungu-2 m/s ² (c) into ihambela phezulu ngokusheshisa okungaguquki okungu-2 m/s ².

Isixazululo

Kwaziwa:

Isisindo (m) = 3 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 9.8 m/s ²

Isisindo (w) = mg = (3)(9.8) = 29.4 amaNewton

w _x = w isono 30 = (29.4)(0.5) = 14.7 amaNewton

w _y = w cos 30 = (29.4)(0.5√3) = 14.7√3 AmaNewton

Isixazululo:

(a) Ubukhulu bamandla u-F uma into iphumule

Umthetho wokuqala kaNewton wokunyakaza uthi uma into iphumulile, amandla asebenzayo entweni ayi-zero.

∑ F = 0

F – w _x = 0

F = w _x

F = 14.7 Newton

(b) Ubukhulu bamandla F uma into ihamba iyehla ngo-2 m/s oqhubekayo ²

∑ F = ma

w _x – F = ma

14.7 – F = (3)(2)

14.7 – F = 6

F = 14.7–6

F = 8.7 Newton

(c) Ubukhulu bamandla F uma into ihambela phezulu ngo-2 m/s oqhubekayo ²

∑ F = ma

F – w _x = ma

F – 14.7 = (3)(2)

F – 14.7 = 6

F = 14.7 + 6

F = 20.7 Newton

[irp]

[wpdm_package id='479′]

1. Isisindo kanye nesisindo
2. amandla ajwayelekile
3. Umthetho wesibili wokunyakaza kukaNewton
4. Amandla okungqubuzana
5. Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
6. Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
7. Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
8. Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
9. Ukunyakaza e-lifti
10. Ukunyakaza kwemizimba kuxhunywe ngezintambo nama-pulleys
11. Imizimba emibili enesilinganiso esifanayo sokusheshisa
12. Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
13. Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
14. Ukunyakaza okufanayo kumbuthano ovundlile
15. Amandla aphakathi ahambisanayo ajikelezayo

Funda kabanzi

1. Isisindo sebhokisi 1 singama-2 kg, isisindo sebhokisi 2 singama-4 kg, ukusheshisa kwamandla adonsela phansi kungu-10 m/s ² , ubukhulu bamandla F bungu-40 Newton. I-coefficient ye-kinetic friction phakathi kwebhokisi 1 nephansi ingu-0.2 kanti i-coefficient ye-kinetic friction phakathi kwebhokisi 2 nephansi ingu-0.3. Thola (a) Ubukhulu kanye nesiqondiso sokusheshisa kwebhokisi (b) Ubukhulu bamandla asetshenziswa yibhokisi 1 ebhokisini 2 (F ₁₂ ) kanye nobukhulu bamandla asetshenziswa yibhokisi 2 ebhokisini 1 (F ₂₁ ).

Isixazululo

Kwaziwa:

Isisindo sebhokisi 1 (m1 ₎ = 2 kg

Isisindo sebhokisi 2 (m2 ₎ = 4 kg

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s ² ,

Amandla F = 40 Newton,

I-coefficient yokungqubuzana kwe-kinetic phakathi kwebhokisi 1 kanye nephansi ( μ _k1 ) = 0.2

I-coefficient yokungqubuzana kwe-kinetic phakathi kwebhokisi 2 kanye nephansi ( μ _k2 ) = 0.3

Isisindo sebhokisi 1 (w ₁ ) = m ₁ g = (2)(10) = 20 Newtons

Isisindo sebhokisi 2 (w ₂ ) = m ₂ g = (4)(10) = 40 Newtons

Amandla avamile asetshenziswa ebhokisini 1 (N ₁ ) = w ₁ = 20 amaNewton

Amandla avamile asetshenziswa ebhokisini 2 (N ₂ ) = w ₂ = 40 Newtons

Amandla okungqubuzana kwe-kinetic asebenza ebhokisini 1 (f _k1 ) = ( μ _k1 )(N ₁ ) = (0.2)(20) = 4 AmaNewton

Amandla okungqubuzana kwe-kinetic asebenza ebhokisini 2 (f _k2 ) = ( μ _k1 )(N ₂ ) = (0.3)(40) = 12 AmaNewton

Isixazululo:

(a) Ubukhulu kanye nesiqondiso sokusheshisa kwebhokisi

ΣF = ma

F – f _k1 – f _k2 = (m ₁ + m ₂ ) a

40 – 4 – 12 = (2 + 4) a

24 = 6 a

a = 24/6

a = 4 m/s ²

Isiqondiso sokusheshisa = isiqondiso samandla aphelele = kwesokudla.

(b) Ubukhulu bamandla asetshenziswa yibhokisi 1 ebhokisini 2 (F ₁₂ ) kanye nobukhulu bamandla asetshenziswa yibhokisi 2 ebhokisini 1 (F ₂₁ ).

Bala ubukhulu be-F ₁₂ :

ΣF = ma

F ₁₂ – f _k2 = (m ₂ ) a

F ₁₂ – 12 = (4)(4)

F ₁₂ – 12 = 16

F ₁₂ = 16 + 12

F ₁₂ = 28 Newton

I-F ₁₂ kanye ne-F ₂₁ amandla esenzo kanye nokusabela asebenza ezintweni ezahlukene. I-F ₁₂ kanye ne-F ₂₁ zinobukhulu obufanayo kanye nesiqondiso esiphambene.

F ₁₂ = 28 AmaNewton = F ₂₁ = 28 AmaNewton.

[irp]

2. Isisindo sebhokisi 1 singama-2 kg, isisindo sebhokisi 2 singama-4 kg, ukusheshisa kwamandla adonsela phansi kungu-10 m/s ² , amandla u-F angama-40 N. I-coefficient ye-kinetic friction phakathi kwebhokisi 1 kanye nephansi ingu-0.2 kanti i-coefficient ye-kinetic friction phakathi kwebhokisi 2 kanye nephansi ingu-0.3. Nquma (a) Ubukhulu kanye nesiqondiso sokusheshisa (b) Ukucindezeleka entanjeni exhumanisa amabhokisi. Unganaki isisindo sentambo.

Kwaziwa:

Isisindo sebhokisi 1 (m1 ₎ = 2 kg

Isisindo sebhokisi 2 (m2 ₎ = 4 kg

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s ² ,

Amandla F = 40 Newton,

I-coefficient yokungqubuzana kwe-kinetic phakathi kwebhokisi 1 kanye nephansi ingu-0.2 ( μ _k1 ) = 0.2

I-coefficient yokungqubuzana kwe-kinetic phakathi kwebhokisi 2 kanye nephansi ingu-0.2 ( μ _k2 ) = 0.3

Isisindo sebhokisi 1 (w ₁ ) = m ₁ g = (2)(10) = 20 Newtons

Isisindo sebhokisi 2 (w ₂ ) = m ₂ g = (4)(10) = 40 Newtons

Amandla avamile asetshenziswa ebhokisini 1 (N ₁ ) = w ₁ = 20 Newtons

Amandla avamile asetshenziswa ebhokisini 2 (N ₂ ) = w ₂ = 40 Newtons

Amandla okungqubuzana kwe-kinetic asebenza ebhokisini 1 (f _k1 ) = ( μ _k1 )(N ₁ ) = (0.2)(20) = 4 AmaNewton

Amandla okungqubuzana kwe-kinetic asebenza ebhokisini 2 (f _k2 ) = ( μ _k1 )(N ₂ ) = (0.3)(40) = 12 AmaNewton

Isixazululo:

(a) ubukhulu kanye nesiqondiso sokusheshisa

ΣF = ma

F – f _k1 – f _k2 = (m ₁ + m ₂ ) a

40 – 4 – 12 = (2 + 4) a

24 = 6 a

a = 24/6

a = 4 m/s ²

Ubukhulu bokusheshisa buyi-4 m/s ² , isiqondiso sokusheshisa = isiqondiso samandla aphelele = kwesokudla.

(b) Ukucindezeleka entanjeni

Amandla asebenza ebhokisini 1 ohlangothini oluvundlile ukucindezela 1 (T ₁ ) ngakwesokudla kanye namandla okungqubuzana kwe-kinetic 1 (f _k1 ) ngakwesokunxele. Sebenzisa umthetho wesibili kaNewton:

ΣF = ma

T ₁ – f _k1 = m ₁ a

I-T ₁ – 4 = (2)(4)

Isigaba ₁ – 4 = 8

I-T ₁ = 8 + 4 = 12 Newton

Amandla asebenza ebhokisini 2 ohlangothini oluvundlile yi-tension 2 (T ₂ ) eya ngakwesobunxele kanye namandla e-kinetic friction 2 (f _k2 ) eya kwesokudla. Sebenzisa umthetho wesibili kaNewton :

ΣF = ma

F – T ₂ – f _k2 = m ₂ a

40 – I-T ₂ – 12 = (4)(4)

28 – T ₂ = 16

I-T ₂ = 28 – 16 = 12 uNewton

Ukucindezeleka entanjeni exhumanisa amabhokisi = T ₁ = T ₂ = T = 12 Newtons.

[irp]

[wpdm_package id='493′]

1. Isisindo kanye nesisindo
2. amandla ajwayelekile
3. Umthetho wesibili wokunyakaza kukaNewton
4. Amandla okungqubuzana
5. Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
6. Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
7. Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
8. Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
9. Ukunyakaza e-lifti
10. Ukunyakaza kwemizimba exhunywe ngezintambo nama-pulley
11. Imizimba emibili enesilinganiso esifanayo sokusheshisa
12. Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
13. Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
14. Ukunyakaza okufanayo kumbuthano ovundlile
15. Amandla aphakathi ahambisanayo ajikelezayo

Funda kabanzi

1. Isisindo sento 1 singama-2 kg, isisindo sento 2 singama-4 kg, ukusheshisa kwamandla adonsela phansi kungu-10 m/s ² , ubukhulu bamandla u-F bungama-Newton ayi-12. Thola ubukhulu kanye nesiqondiso sokusheshisa kwezinto.

Kwaziwa:

m ₁ = 2 kg, m ₂ = 4 kg, g = 10 m/s ² , F = 12 Newtons

Kufunwa : a

Isixazululo:

Σ F = ma

F = (m ₁ + m ₂ ) a

12 = (2 + 4) a

12 = 6 a

a = 12/6

a = 2 m/s ²

Ubukhulu bokusheshisa buyi-2 m/s ² , isiqondiso sokusheshisa = isiqondiso samandla aphelele = kwesokudla.

[irp]

2. Isisindo sento 1 singama-2 kg, isisindo sento 2 singama-4 kg, ukusheshisa kwamandla adonsela phansi kungu-10 m/s ² , ubukhulu bamandla u-F bungama-24 N. Thola ubukhulu kanye nesiqondiso sokusheshisa.

Kwaziwa:

m ₁ = 2 kg, m ₂ = 4 kg, g = 10 m/s ² , F = 24 Newtons

Okufunwayo: ukusheshisa (a)

Isixazululo:

Σ F = ma

F = (m ₁ + m ₂ ) a

24 = (2 + 4) a

24 = 6 a

a = 24/6

a = 4 m/s ²

Isiqondiso sokusheshisa = isiqondiso samandla aphelele = kwesokudla.

[irp]

[wpdm_package id='474′]

1. Isisindo kanye nesisindo
2. amandla ajwayelekile
3. Umthetho wesibili wokunyakaza kukaNewton
4. Amandla okungqubuzana
5. Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
6. Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
7. Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
8. Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
9. Ukunyakaza e-lifti
10. Ukunyakaza kwemizimba kuxhunywe ngezintambo nama-pulleys
11. Imizimba emibili enesilinganiso esifanayo sokusheshisa
12. Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
13. Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
14. Ukunyakaza okufanayo kumbuthano ovundlile
15. Amandla aphakathi ahambisanayo ajikelezayo

Funda kabanzi

Izinkinga ezixazululiwe emithethweni kaNewton yokunyakaza – Amandla okungqubuzana okungaguquki kanye nokujikijelana kwe-kinetic

1. Into iphumule phansi evundlile. I-coefficient yokungqubuzana okungaguquki ingu-0.4 kanti ukusheshisa kwamandla adonsela phansi kungu-9.8 m/s ^2. Thola (a) Amandla aphezulu okungqubuzana okungaguquki (b) Amandla amancane ka-F

Isixazululo

Kwaziwa:

Isisindo (m) = 1 kg

I-coefficient yokungqubuzana okungaguquki (μ _s ) = 0.4

Ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s ²

Isisindo (w) = mg = (1 kg)(10 m/s ² ) = 10 kg m/s ² = 10 AmaNewton

Amandla ajwayelekile (N) = w = 10 amaNewton

Kufunwa:

(a) Amandla aphezulu okungqubuzana okungaguquki (b) Amandla amancane ka-F

Isixazululo:

(a) Amandla aphezulu okungqubuzana okungaguquki

fs = μs N_​​

f _s = (0.4)(9.8 N) = 3.92 amaNewton

(b) Amandla amancane ka-F

Uma amandla u-F esetshenziswa entweni kodwa into ingashukunyiswa, ngakho-ke kumele kube namandla okungqubuzana okungaguquki asetshenziswa phansi entweni. Uma into izoqala ukuhamba, amandla okungqubuzana okungaguquki edlula, kumele kube namandla okungqubuzana okungaguquki. Into iqala ukuhamba uma u-F emkhulu kunamandla amakhulu okungqubuzana okungaguquki.

Ngakho amandla amancane ka-F = amandla amakhulu okungqubuzana okungaguquki = 3.92 amaNewton.

[irp]

2. Ibhokisi elingu-1 kg lidonswa endaweni evundlile ngamandla F, ngakho ibhokisi lihamba ngesivinini esingaguquki. Uma i-kinetic friction coefficient ingu-0.1, thola ubukhulu bamandla F! (g = 9.8 m/s ² )

Kwaziwa:

_{I- kinetic} friction coefficient ( μk ) = 0.1

Isisindo sebhokisi (m) = 1 kg

Ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s ²

Isisindo (w) = mg = (1 kg)(9.8 m/s ² ) = 9.8 kg m/s ² = 9.8 amaNewton

Amandla ajwayelekile (N) = w = 9.8 amaNewton

Kufunwa : F

Isixazululo:

Umthetho wokuqala kaNewton uthi uma kungekho mandla asebenzayo entweni, yonke into iyaqhubeka isesimweni sayo sokuphumula, noma ijubane elingaguquki emgqeni oqondile.

Ngakho-ke uma into ihamba ngesivinini esingaguquki , akumelwe kube khona amandla aphelele ( Σ F = 0) . Amandla F afakwa entweni ngendlela efanele ukuze amandla okungqubuzana kwe-kinetic afakwe entweni ngendlela eya kwesobunxele.

∑ F = 0

F – f _k = 0

F = f _k

Amandla okungqubuzana kwe-kinetic:

f _k = μ _k N = (0.1)(9.8 N) = 0.98 Newtons

into ihamba ngesivinini esingaguquki, F = f _k = 0.98 amaNewton

[irp]

3. Into ishelela phansi endizeni ethambekele ngesivinini esingaguquki. Thola i-kinetic friction coefficient ( _μk ) . g = 9.8 m/s ²

Isixazululo

w = isisindo, w _x = ingxenye evundlile yesisindo, amaphuzu eceleni kokuthambekela, w _y = ingxenye eqondile yesisindo, eqondile endizeni ethambekele, N = amandla avamile, f _k = amandla okungqubuzana kwe-kinetic.

Kwaziwa:

Isisindo (m) = 1 kg

Ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s ²

isisindo (w) = mg = (1 kg)(9.8 m/s ² ) = 9.8 kg m/s ² = 9.8 amaNewton

w _x = w sin 30 ^o = (9.8 N)(0.5) = 4.9 AmaNewton

w _y = w cos 30 ^o = (9.8 N)(0.5) √ 3 = 4.9 √ 3 AmaNewton

Amandla ajwayelekile (N) = w _y = 4.9 √ 3 amaNewton

Okufunwayo : i-kinetic friction coefficient ( μk ₎

Isixazululo:

Into ishelela phansi endizeni ethambekele ngesivinini esingaguquki ukuze amandla anetha = 0.

∑ F = 0

w _x – f _k = 0

w _x = f _k

w _x = μ _k N

5 = μ _k ( 5 √ 3 )

μ _k = 5 / 5 √ 3

μ _k = 1 / √ 3

μ _k = 0.58

[irp]

[wpdm_package id='472′]

1. Isisindo kanye nesisindo
2. amandla ajwayelekile
3. Umthetho wesibili wokunyakaza kukaNewton
4. Amandla okungqubuzana
5. Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
6. Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
7. Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
8. Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
9. Ukunyakaza e-lifti
10. Ukunyakaza kwemizimba exhunywe ngezintambo nama-pulley
11. Imizimba emibili enesilinganiso esifanayo sokusheshisa
12. Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
13. Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
14. Ukunyakaza okufanayo kumbuthano ovundlile
15. Amandla aphakathi ahambisanayo ajikelezayo

Funda kabanzi

Izinkinga ezixazululiwe emithethweni kaNewton yokunyakaza – umthetho wesibili kaNewton wokunyakaza 

1. Into engu-1 kg isheshiswe ngokulingana okungu-5 m/s ² . Linganisa amandla aphelele adingekayo ukuze kusheshiswe into.

Kwaziwa:

Isisindo (m) = 1 kg

Ukusheshisa (a) = 5 m/s ²

Kufunwa : amandla aphelele (∑F)

Isixazululo:

Sisebenzisa umthetho wesibili kaNewton ukuthola amandla e-net.

∑ F = ma

∑ F = (1 kg)(5 m/s ² ) = 5 kg m/s ² = 5 Newtons

[irp]

2. Isisindo sento = 1 kg, amandla aphelele ∑F = 2 amaNewton. Nquma ubukhulu kanye nesiqondiso sokusheshisa kwento….

Kwaziwa:

Isisindo (m) = 1 kg

Amandla aphelele (∑F) = 2 Newton

Okufunwayo : Ubukhulu kanye nesiqondiso sokusheshisa (a)

Isixazululo:

a = ∑F / m

a = 2/1

a = 2 m/s ²

Isiqondiso sokusheshisa = isiqondiso samandla aphelele (∑F)

[irp]

3. Isisindo sento = 2 kg, F ₁ = 5 Newtons, F ₂ = 3 Newton. Ubukhulu kanye nesiqondiso sokusheshisa…

Kwaziwa:

Isisindo (m) = 2 kg

F ₁ = 5 Newton

F ₂ = 3 Newton

Okufunwayo: Ubukhulu kanye nesiqondiso sokusheshisa (a)

Isixazululo:

amandla aphelele:

∑ F = F ₁ – F ₂ = 5 – 3 = 2 AmaNewton

Ubukhulu bokusheshisa:

a = ∑F / m

a = 2/2

a = 1 m/s ²

Isiqondiso sokusheshisa = isiqondiso samandla aphelele = isiqondiso sika-F ₁

[irp]

4. Isisindo sento = 2 kg, F ₁ = 10 Newtons, F ₂ = 1 Newton. Ubukhulu kanye nesiqondiso sokusheshisa…

Kwaziwa:

Isisindo (m) = 2 kg

F ₂ = 1 Newton

F ₁ = 10 Newton

F _1x = F ₁ cos 60 ^o = (10)(0.5) = 5 Newtons

Okufunwayo : Ubukhulu kanye nesiqondiso sokusheshisa (a)

Isixazululo:

Amandla aphelele:

∑ F = F _1x – F ₂ = 5 – 1 = 4 amaNewton

Ubukhulu bokusheshisa:

a = ∑F / m

a = 4/2

a = 2 m/s ²

Isiqondiso sokusheshisa = isiqondiso samandla aphelele = isiqondiso se-F _1x

[irp]

5. F ₁ = 10 Newtons, F ₂ = 1 Newton, m ₁ = 1 kg, m ₂ = 2 kg. Ubukhulu kanye nesiqondiso sokusheshisa…

Kwaziwa:

Isisindo 1 (m1 ₎ = 1 kg

Isisindo 2 (m2 ₎ = 2 kg

F ₁ = 10 Newton

F ₂ = 1 Newton

Okufunwayo : Ubukhulu kanye nesiqondiso sokusheshisa (a)

Isixazululo:

Amandla aphelele:

∑ F = F ₁ – F ₂ = 10 – 1 = 9 AmaNewton

Ubukhulu bokusheshisa:

a = ∑F / (m ₁ + m ₂ )

a = 9 / (1 + 2)

a = 9/3

a = 3 m/s ²

Isiqondiso sokusheshisa = isiqondiso samandla aphelele = isiqondiso sika-F ₁

[irp]

6.

Ibhulokhi engama-40 kg esheshiswa ngamandla angu-200 N. Ukusheshisa kwebhulokhi kungu-3 m/ s ^2. Thola ubukhulu bamandla okungqubuzana abhekene nebhulokhi.

A. 15 N

B. 40 N

C. 43 N

D. 80 N

Kwaziwa:

Isisindo (m) = 40 kg

Amandla (F) = 200 N

Ukusheshisa (a) = 3 m/s ²

Okufunwayo: Amandla okungqubuzana (F _g )

Isixazululo:

Isilinganiso somthetho wesibili wokunyakaza kaNewton

∑ F = ma

∑ F = amandla aphelele, m = isisindo, a = ukusheshisa

Isiqondiso samandla F ngakwesokudla, isiqondiso samandla okungqubuzana ngakwesobunxele (isiqondiso samandla okungqubuzana siphambene nesiqondiso sokunyakaza kwento).

Khetha okuya kwesokudla okuhle nokuya kwesobunxele njengokubi.

∑ F = ma

F – F _g = ma

200 – F _g = (40)(3)

200 – F _g = 120

F _g = 200 – 120

F _g = 80 Newton

Impendulo efanele ngu-D.

7. Ibhulokhi A enesisindo esingamagremu ayi-100 beka ngaphezu kwebhulokhi B enesisindo esingamagremu angu-300, bese ibhulokhi B icindezelwa ngamandla angu-5 N phezulu. Thola amandla avamile asetshenziswa yibhulokhi B kubhulokhi A.

A. 1 N

B. 1.25 N

C. 2 N

D. 3 N

Kwaziwa:

Amandla (F) = 5 Newton

Isisindo sebhulokhi A (m _A ) = amagremu ayi-100 = 0.1 kg

Isisindo sebhulokhi B (m _B ) = amagremu angu-300 = 0.3 kg

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s ²

Isisindo sebhulokhi A (w _A ) = (0.1 kg)(10 m/s ² ) = 1 kg m/s ² = 1 Newton

Isisindo sebhulokhi B (w _B ) = (0.3 kg)(10 m/s ² ) = 3 kg m/s ² = 3 amaNewton

Okufunwayo: Amandla ajwayelekile asetshenziswa yibhlokhi B ukuze kuvinjwe ibhlokhi A

Isixazululo:

Kunamandla amaningana asebenza kuzo zombili izithiyo, njengoba kuboniswe esithombeni.

F = amandla okusunduza (isenzo kubhlokhi B)

w _A = isisindo sebhulokhi A (isenzo kubhulokhi A)

w _B = isisindo sebhulokhi B (isenzo kubhulokhi B)

N _A = amandla avamile asetshenziswa yibhlokhi B kubhlokhi A (Umthetho kubhlokhi A)

N _A ' = amandla avamile asetshenziswa yibhlokhi A kubhlokhi B (Umthetho kubhlokhi B)

Sebenzisa umthetho wesibili kaNewton wokunyakaza kuzo zombili izithiyo:

∑ F = ma

F – w _A – w _B + N _A – N _A ' = (m _A + m _B ) a

I-N _A kanye ne-N _A ' zingamandla okusabela kwesenzo anobukhulu obufanayo kodwa aphambene ngakho-ke asuswa kulesi sibalo.

F – w _A – w _B = (m _A + m _B ) a

5 – 1 – 3 = (0.1 + 0.3) a

5 – 4 = (0.4) a

1 = (0.4) a

a = 1/0.4

a = 2.5 m/s ²

Sebenzisa umthetho wesibili kaNewton wokunyakaza kubhlokhi A:

∑ F = ma

N _A – w _A = m _A a

I-N _A – 1 = (0.1)(2.5)

I- NA – ₁ = 0.25

I-NA = 1 + _0.25

I-NA = 1.25 _amaNewton

Impendulo efanele ngu-B.

8. Into enesisindo esingu-4 N esisekelwa yintambo kanye ne-pulley. Amandla angu-2 N asebenza ebhulokini kanye nokuphela kwentambo edonswa ngamandla angu-9 N. Thola amandla aphelele entweni X.

A. 3 N phezulu

B. 4 N phansi

C. 9 N phezulu

D. 9 N phansi

Kwaziwa:

Isisindo sika-X (w _X ) = 4 Newton

Amandla okudonsa (F _x ) = 2 Newton

Amandla okucindezela (F _T ) = 9 Newtons

Kufunwa: Amandla e-Net asebenza entweni

Isixazululo:

Amandla aphezulu aqonde phezulu asebenza entweni

Amandla okucindezela anobukhulu obufanayo kuzo zonke izingxenye zentambo. Ngakho amandla okucindezela angama-9 N.

Amandla aqonde phansi asebenza entweni

Kunamandla amabili asebenza entweni X futhi womabili la mandla abheke phansi, ingxenye evundlile yesisindo esingu-w _x kanye nengxenye evundlile yamandla u-F _x.

Isenzo samandla e-net entweni

F _T – w _X – F _x = 9 – 4 – 2 = 9 – 6 = 3

Amandla e-net asebenza entweni u-X angama-Newton amathathu, aqonde phezulu.

Impendulo eyiyo ngu-A.

9. Into eqale iphumule endaweni ebushelelezi evundlile. Amandla angu-16 N asebenza entweni ukuze into isheshise ku-2 m/s ² . Uma into efanayo iphumule endaweni evundlile evundlile ukuze amandla okungqubuzana asebenze entweni engu-2 N, nquma ukusheshisa kwento uma amandla afanayo angu-16 N esebenza entweni.

A. 1.75 m/s ²

B. 1.50 m/s ²

C. 1.00 m/s ²

D. 0.88 m/s ²

Kwaziwa:

Amandla (F) = 16 AmaNewton = 16 kg m/s ²

Ukusheshisa (a) = 2 m/s ²

Amandla okungqubuzana (F _fric ) = 2 AmaNewton = 2 kg m/s ²

Okufunwayo: Ukusheshisa kwento?

Isixazululo:

Ubuso obubushelelezi obuvundlile (akukho mandla okungqubuzana):

∑F = ma

F = ma

16 = (m) 2

m = 16/2

m = 8 kg

Isisindo sale nto singamakhilogremu angu-8.

Ubuso obuqondile obuqinile (kukhona amandla okungqubuzana):

∑F = ma

F – F _fric = ma

16 – 2 = 8 a

14 = 8 a

a = 14/8

a = 1.75 m/s ²

Ukusheshisa kwento kungu-1.75 m/s ².

Impendulo eyiyo ngu-A.

10. UTom no-Andrew bacindezela into phansi ebushelelezi. UTom ucindezela into ngamandla angu-5.70 N. Uma isisindo sento singama-2.00 kg futhi ukusheshisa okubonwa yinto kungu-2.00 ms ^-2 , nquma ubukhulu kanye nesiqondiso sesenzo samandla sikaTom.

A. 1.70 N futhi isiqondiso sayo siphambene nempoqo eyenziwe ngu-Andre.w

B. 1.70 N kanye nesiqondiso sayo kufana namandla asetshenziswa ngu-Andrew

C. 2.30 N futhi isiqondiso sayo siphambene nempoqo eyenziwe ngu-Andrew.

D. 2.30 N kanye nesiqondiso sayo kufana namandla asetshenziswa ngu-Andrew.

Kwaziwa:

Amandla okusunduza asetshenziswa ngu-Andrew (F ₁ ) = 5.70 Newton

Isisindo sento (m) = 2.00 kg

Ukusheshisa (a) = 2.00 m/s ²

Okufunwayo: Ubukhulu kanye nesiqondiso samandla esenziwa nguTom (F ₂ )?

Isixazululo:

Sebenzisa umthetho wesibili kaNewton wokunyakaza:

∑ F = ma

F ₁ + F ₂ = ma

5.70 + F ₂ = (2)(2)

5.70 + F ₂ = 4

F ₂ = 4 – 5.70

F ₂ = – 1.7 Newton

Uphawu lokususa lubonise ukuthi (F ₂ ) luphambene nesenzo sokusunduza sika-Andrew (F ₁ ).

Impendulo eyiyo ngu-A.

11. Uma isisindo sebhulokhi sifana, yisiphi isibalo esibonisa ukusheshisa okuncane kakhulu?

Isixazululo

Amandla aphelele A:

ΣF = 4 N + 2 N – 3 N = 6 N – 3 N = 3 Amathoni amasha, kwesokunxele

Amandla aphelele B:

ΣF = 2 N + 3 N – 4 N = 5 N – 4 N = 1 Amathoni amasha, kwesokudla

Amandla aphelele C:

ΣF = 4 N + 3 N – 2 N = 7 N – 2 N = 5 Amathoni amasha, kwesokudla

Amandla aphelele D:

ΣF = 3 N + 4 N + 2 N = 9 Newtons, kwesokudla

Isilinganiso somthetho wesibili kaNewton:

ΣF = ma

a = ΣF / m

a = ukusheshisa, ΣF = amandla aphelele, m = isisindo

Ngokusekelwe kufomula engenhla, ukusheshisa (a) kuhambelana ngqo namandla aphelele (ΣF) futhi kuhambisana ngokuphambene nobunzima (m). Uma isisindo sento sifana, lapho amandla avelayo emakhulu, lapho ukusheshisa kukhulu noma lapho amandla avelayo emancane, kulapho ukusheshisa kuncane khona.
Ngokusekelwe ekubalweni okungenhla, amandla amancane kakhulu e-net yi-1 Newton ngakho-ke ukusheshisa nakho kuncane kakhulu.

Impendulo efanele ngu-B.

[irp]

12. Amanye amandla asebenza entweni enesisindo esingama-20 kg, njengoba kuboniswe esithombeni esingezansi.

Nquma ukusheshisa kwento.

Kwaziwa:

Isisindo sento (m) = 20 kg

Amandla engqikithi (ΣF) = 25 N + 30 N – 15 N = 40 N

Okufunwayo: Ukusheshisa into

Isixazululo:

Ukusheshisa kwento kubalwe kusetshenziswa i-equation yomthetho wesibili kaNewton:

ΣF = ma

a = ΣF / m = 40 N / 20 kg = 2 N/kg = 2 m/s ²

[irp]

13. Yisiphi isitatimende esingezansi esichaza umthetho wesithathu kaNewton?

(1) Abagibeli baqhubekela phambili lapho ibhasi libhuleka ngokuzumayo

(2) Izincwadi ezisephepheni aziwi uma iphepha lidonswa ngokushesha

(3) Uma udlala i-skateboard uma unyawo lusunduza umhlabathi emuva, i-skateboard izoshelela phambili

(4) O ars esunduzwa emuva, izikebhe ziya phambili

Isixazululo:

(1) Umthetho wokuqala kaNewton

(2) Umthetho wokuqala kaNewton

(3) Umthetho wesithathu kaNewton

(4) Umthetho wesithathu kaNewton

[wpdm_package id='470′]

1. Isisindo kanye nesisindo
2. amandla ajwayelekile
3. Umthetho wesibili wokunyakaza kukaNewton
4. Amandla okungqubuzana
5. Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
6. Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
7. Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
8. Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
9. Ukunyakaza e-lifti
10. Ukunyakaza kwemizimba kuxhunywe ngezintambo nama-pulleys
11. Imizimba emibili enesilinganiso esifanayo sokusheshisa
12. Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
13. Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
14. Ukunyakaza okufanayo kumbuthano ovundlile
15. Amandla aphakathi ahambisanayo ajikelezayo

Funda kabanzi

Izinkinga ezixazululiwe emithethweni kaNewton yokuhamba - Amandla ajwayelekile 

1. Into ehlezi etafuleni, eboniswe esithombeni esingezansi. Isisindo sento siyi-1 kg. Ukusheshisa kwamandla adonsela phansi kungu-9.8 m/s ² . Thola amandla avamile asetshenziswa entweni eduze kwetafula.

Kwaziwa:

Isisindo (m) = 1 kg

Ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s ²

Isisindo (w) = mg = (1 kg)(9.8 m/s ² ) = 9.8 kg m/s ² = 9.8 amaNewton

Okufunwayo: amandla avamile (N)

Isixazululo:

Into iphumule etafuleni, ngakho amandla aphelele entweni ayi-zero (umthetho wokuqala noma wesibili kaNewton). Isisindo sento sisebenza siqonde phansi, sibheke enkabeni yoMhlaba. Kumelwe kube khona elinye amandla entweni ukuze kulinganiswe amandla adonsela phansi . Into ehlezi etafuleni, ukuze itafula lisebenzise la mandla aphezulu. Amandla asetshenziswa yitafula avame ukubizwa ngokuthi amandla ajwayelekile (N). Okujwayelekile kusho ukuthi aqondile.

Khetha isiqondiso esibheke phezulu njengesiqondiso esihle sika-y. Amandla aphelele entweni yilawa:

∑ I-Fy = 0

N – w = 0

N = w

N = mg

N = 9.8 Newton

Amandla avamile entweni, asetshenziswa yithebula angama-9.8 N phezulu.

[irp]

2. Izinto ezimbili ezilele etafuleni. Isisindo sento 1 (m ₁ ) = 1 kg, isisindo sento 2 (m ₂ ) = 2 kg, ukusheshisa ngenxa yamandla adonsela phansi (g) = 9.8 m/s ^2. Nquma ubukhulu kanye nesiqondiso samandla avamile asetshenziswa yi-m ₂ ku-m ₁ kanye namandla avamile asetshenziswa yithebula ku-m ₂.

Isixazululo

Kwaziwa:

Isisindo sento 1 (m ₁ ) = 1 kg

Isisindo sento 2 (m ₂ ) = 2 kg

Ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s ²

Isisindo sento 1 (w ₁ ) = m ₁ g = (1)(9.8 m/s ² ) = 9.8 kg m/s ² = 9.8 amaNewton

Isisindo sento 2 (w ₂ ) = m ₂ g = (2)(9.8 m/s ² ) = 19.6 kg m/s ² = 19.6 amaNewton

Kufunwa: N ₁ kanye N ₂

Isixazululo:

(a) Amandla ajwayelekile asetshenziswa yi-m ₂ kuya ku-m ₁ (N ₁ )

N ₁ = w ₁ = 9.8 Newton

Isiqondiso se-N1 _siphezulu.

(b) Amandla ajwayelekile asetshenziswa yithebula ku-m ₂ (N ₂ )

N ₂ = w ₁ + w ₂ = 9.8 AmaNewton + 19.6 AmaNewton = 29.4 AmaNewton

Isiqondiso se-N2 _siphezulu.

[irp]

3. Into elele etafuleni. Isisindo sento singama-2 kg, ukusheshisa ngenxa yamandla adonsela phansi kungu-9.8 m/s ² . Ubukhulu bamandla u-F bungama-Newton ayi-10. Thola ubukhulu kanye nesiqondiso samandla avamile asetshenziswa yithebula entweni.

Isixazululo

Kwaziwa:

Isisindo sento (m) = 2 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 9.8 m/s ²

Isisindo (w) = mg = (2 kg)(9.8 m/s ² ) = 19.6 kg m/s ² = 19.6 amaNewton

Amandla F (F) = 10 Newton

Okufunwayo : ubukhulu kanye nesiqondiso samandla avamile (N)

Isixazululo:

isiqondiso samandla avamile siphezulu.

Ubukhulu bamandla avamile:

∑ F = 0

N – F – w = 0

N = F + w

N = 10 Newtons + 20 Newtons

N = 30 Newton

[irp]

4. Into elele etafuleni. Isisindo sento singu-1 kg, ukusheshisa ngenxa yamandla adonsela phansi kungu-9,8 m/s ² , amandla F ₁ angu-10 N kanye namandla F ₂ angu-20 N. Thola ubukhulu kanye nesiqondiso samandla avamile asetshenziswa yithebula entweni. g = 9.8 m/s ²

Isixazululo

Kwaziwa:

Isisindo (m) = 1 kg

Ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s ²

Isisindo (w) = mg = (1 kg)(9.8 m/s ² ) = 9.8 kg m/s ² = 9.8 amaNewton

F ₁ = 10 Newton

F ₂ = 20 Newton

Okufunwayo: ubukhulu kanye nesiqondiso samandla avamile (N)

Isixazululo:

Isiqondiso samandla avamile siphezulu.

Ubukhulu bamandla avamile:

∑ F = 0

N – F ₂ – w + F ₁ = 0

N = F ₂ + w – F ₁

N = 20 Newtons + 9.8 Newtons – 10 Newtons

N = 19.8 Newton

[irp]

5. Isisindo sento (m) = 2 kg, ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s ² , i-engeli = 30 ^o . Thola ubukhulu kanye nesiqondiso samandla avamile asetshenziswa entweni.

Isixazululo:

u-w uyisisindo, u-w _x uyisici esivundlile sesisindo, u -w _y uyisici esiqondile sesisindo, u-N ungamandla avamile.

Kwaziwa:

isisindo (m) = 2 kg

ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s ²

isisindo (w) = mg = (2 kg)(9.8 m/s ² ) = 19.6 kg m/s ² = 19.6 amaNewton

w _x = w sin 60 ^o = (19.6 N)(0.5) √ 3 = 9.8 √ 3 AmaNewton

w _y = w cos 60 = (19.6 N)(0.5) = 9.8 amaNewton

Okufunwayo: amandla avamile (N)

Isixazululo:

∑ F = 0

N – w _y = 0

N = w _y

N = 9.8 Newton

[irp]

[wpdm_package id='467′]

1. Isisindo kanye nesisindo
2. amandla ajwayelekile
3. Umthetho wesibili wokunyakaza kukaNewton
4. Amandla okungqubuzana
5. Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
6. Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
7. Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
8. Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
9. Ukunyakaza e-lifti
10. Ukunyakaza kwemizimba kuxhunywe ngezintambo nama-pulleys
11. Imizimba emibili enesilinganiso esifanayo sokusheshisa
12. Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
13. Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
14. Ukunyakaza okufanayo kumbuthano ovundlile
15. Amandla aphakathi ahambisanayo ajikelezayo

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Izinkinga ezixazululiwe emithethweni kaNewton yokunyakaza - Isisindo, kanye nesisindo

1. Isisindo sesisindo esingu-1 kg ebusweni boMhlaba singu… g = 9.8 m/s ²

Kwaziwa:

Isisindo (m) = 1 kg

Ukusheshisa okubangelwa amandla adonsela phansi ebusweni boMhlaba (g) = 9.8 m/s ²

Okufunwayo: isisindo (w)

Isixazululo:

w = mg

m = isisindo (Iyunithi ye-SI yesisindo yi-kilogram, kg)

g = ukusheshisa ngenxa yamandla adonsela phansi (Iyunithi ye-SI ka-g ingu-m/s ² )

w = isisindo (Iyunithi ye-SI ka-w ingu-kg m/s ² noma i-Newton)

Isisindo:

w = (1 kg)(9.8 m/s ² ) = 9.8 kg m/s ² = 9.8 amaNewton

[irp]

2.

(a) Dweba amandla adonsela phansi (isisindo) asebenza entweni lapho into ihlezi etafuleni, njengoba kuboniswe esithombeni (a).

(b) Dweba amandla adonsela phansi (isisindo) kanye nezingxenye zawo ezisebenza entweni eshelela phansi endizeni ethambekele , njengoba kuboniswe esithombeni (b)

Isixazululo

Indlela isisindo esiqondiswa ngayo ibheke phansi enkabeni yoMhlaba.

w _x = ingxenye evundlile yesisindo kanye w _y = ingxenye eqondile yesisindo

[irp]

3. Isisindo sebhokisi singu-1 kg kanti ukusheshisa ngenxa yamandla adonsela phansi kungu-9.8 m/s ^2. Thola (a) isisindo (b) ingxenye evundlile kanye nengxenye eqondile yesisindo.

Isixazululo

Isisindo: w = mg = (1 kg)(9.8 m/s ² ) = 9.8 kg m/s ² = 9.8 amaNewton

Ingxenye evundlile yesisindo:

w _x = w sin 30 ^o = (9,8 N)(0,5) = 4.9 AmaNewton

Ingxenye eqondile yesisindo:

w _y = w cos 30 ^o = (9.8 N)(0.5√3) = 4.9√3 AmaNewton

[irp]

[wpdm_package id='458′]

1. Isisindo kanye nesisindo
2. amandla ajwayelekile
3. Umthetho wesibili wokunyakaza kukaNewton
4. Amandla okungqubuzana
5. Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
6. Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
7. Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
8. Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
9. Ukunyakaza e-lifti
10. Ukunyakaza kwemizimba kuxhunywe ngezintambo nama-pulleys
11. Imizimba emibili enesilinganiso esifanayo sokusheshisa
12. Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
13. Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
14. Ukunyakaza okufanayo kumbuthano ovundlile
15. Amandla aphakathi ahambisanayo ajikelezayo

Funda kabanzi

Izinkinga Ezixazululiwe Ekunyakazeni Okuqondile – Ukunyakaza Okuphezulu Nokwehla Ekuweni Okukhululekile

1. Umuntu uphonsa ibhola phezulu emoyeni ngesivinini sokuqala esingu-20 m/s. Bala ukuthi liya phezulu kangakanani. Unganaki ukumelana kwamanzi. Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ².

Isixazululo

Sisebenzisa enye yalezi zibalo ze-kinematic ukunyakaza ngokusheshisa okuqhubekayo , njengoba kuboniswe ngezansi.

v _t = vo _o + at

s = vot ₊ ½ ku- ²

v _t ² = v _o ² + 2 njengoba

Kwaziwa:

Sikhetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Ijubane lokuqala (v _o ) = 20 m/s (elihle phezulu)

Ukusheshisa kwamandla adonsela phansi (g) = – 10 m/s ² (ukwehla okungekuhle).

Ijubane lokugcina (v _t ) = 0 (ijubane layo liyi-zero ngesikhashana endaweni ephezulu kakhulu)

Okufunwayo: Ukuphakama okuphezulu (h)

Isixazululo:

v _t ² = v _o ² + 2 gh

0 = (20 ² ) + 2(-10) amahora

0 = 400 – 20 amahora

400 = amahora angu-20

h = 400 / 20 = 40 / 2 = amamitha angu-20

[irp]

2. Umuntu uphonsa itshe phezulu ngesivinini esingamamitha angu-20 ngomzuzwana ngenkathi emi onqenqemeni lwedwala, ukuze itshe liwele phansi kwedwala elingamamitha ayi-100 ngaphansi.

(a) Kuthatha isikhathi esingakanani ibhola ukufinyelela phansi kwedwala (b) Ijubane lokugcina ngaphambi nje kokuba itshe lishaye phansi. Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ² . Unganaki ukumelana kwamanzi.

Kwaziwa:

Sikhetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Ukuphakama (h) = -100 amamitha (okubi ngoba indawo yokugcina ingaphansi kwesikhundla sokuqala)

Ijubane lokuqala (v _o ) = 20 m/s (elihle phezulu)

Ukusheshisa kwamandla adonsela phansi (g) = -10 m/s ² (ukwehla okungekuhle)

Kufunwa:

(a) Isikhathi emoyeni noma isikhathi esiphakathi (t)

(b) Ijubane lokugcina (v _t )

Isixazululo:

(a) Isikhawu sesikhathi (t)

Kwaziwa:

Ukuphakama (h) = -100 amamitha (okubi ngoba indawo yokugcina ingaphansi kwesikhundla sokuqala)

Ijubane lokuqala (v _o ) = 20 m/s (elihle phezulu), Ukusheshisa kwamandla adonsela phansi (g) = -10 m/s ² (elibi phansi).

h = vot ₊ ½ gt ²

-100 = (20) t + ½ (-10) t ²

-100 = 20 t – 5 t ²

-5 t ² + 20 t + 100 = 0

Sisebenzisa ifomula ye-quadratic:

(b) Ijubane lokugcina

v _t ² = v _o ² + 2 gh

v _t ² = (20 ² ) + 2 (-10)(-100)

v _t ² = 400 + 2000

v _t ² = 2400

v _t = 49 m/s

[irp]

[wpdm_package id='515′]

[wpdm_package id='517′]

1. Ibanga kanye nokufuduka
2. Isivinini esimaphakathi kanye nesivinini esimaphakathi
3. Ijubane eliqhubekayo
4. Ukusheshisa okuqhubekayo
5. Ukunyakaza kwamahhala kokuwa
6. Ukunyakaza phansi ekwindla yamahhala
7. Ukunyakaza okuphezulu nokwehlayo ekuwa okukhululekile

Funda kabanzi

Izinkinga Ezixazululiwe Ekuhambeni Okuqondile – Ukunyakaza Okuphansi Ekuweni Okukhululekile

1. Ibhola liphonswa phansi liqonde phezulu ngesivinini sokuqala esingu-10 m/s bese lifika phansi ngemizuzwana emi-2. Thola isivinini sokugcina ngaphambi nje kokuba ibhola lishaye phansi. Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s ² . Unganaki ukumelana kwamanzi.

Kwaziwa:

Ijubane lokuqala (v _o ) = 10 m/s

Isikhathi esidlulile (t) = imizuzwana emi-2

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: Ijubane lokugcina (v _t )

Isixazululo:

Ukusheshisa okungu-10 m/s ² kusho ukwanda kwesivinini ngo- 10 m/s ngomzuzwana. Ngemva kwemizuzwana emi-3, isivinini = 30 m/s.

Ijubane lokugcina = 10 m/s + 20 m/s = 30 m/s.

Izibalo ze-Kinematic zokunyakaza ngokusheshisa okuqhubekayo , njengoba kuboniswe ngezansi:

v _t = vo _o + at ……. 1

h = vot ₊ ½ ku- ² ………. 2

v _t ² = v _o ² + 2 ah ………. 3

v _t = vo _o + g t

v _t = 10 + (10)(2)

v _t = 10 + 20 = 30 m/s

Ijubane lokugcina = v _t = 30 m/s

[irp]

2. Itshe liphonswa phansi liqonde phezulu lisuka ebhulohweni ngesivinini sokuqala esingu-5 m/s bese lifika emanzini ngemizuzwana emi-2. Bala ukuphakama kwebhuloho.

Kwaziwa:

Ijubane lokuqala (v _o ) = 5 m/s

Isikhathi esidlulile (t) = imizuzwana emi-2

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Okufunwayo: ukuphakama kwebhuloho (h)

Isixazululo:

h = vot ₊ ½ gt ²

h = (5)(2) + ½ (10)(2) ²

h = 10 + (5)(4)

h = 10 + 20

h = amamitha angu-30

[irp]

3. Ibhola liphonswa phansi liqonde phezulu ngesivinini sokuqala esingu-10 m/s ukusuka ekuphakameni kwamamitha angu-80. Thola (a) Isikhathi emoyeni (b) Ijubane lokugcina ngaphambi nje kokuba ibhola lishaye phansi.

Kwaziwa:

ukuphakama (h) = amamitha angu-80

Ijubane lokuqala (v _o ) = 10 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s ²

Kufunwa:

(a) Isikhawu sesikhathi (t)

(b) Ijubane lokugcina (v _t )

Isixazululo:

(a) Isikhawu sesikhathi (t)

Ijubane lokugcina:

v _t ² = v _o ² + 2 gh

v _t ² = (10) ² + 2(10)(80) = 100 + 1600 = 1700

v _t = 41 m/s

Isikhawu sesikhathi (t):

v _t = vo _o + g t

41 = 10 + (10)(t)

41 – 10 = 10 t

31 = 10 t

t = 31 / 10 = 3,1 imizuzwana

(b) Ijubane lokugcina (v _{t )}?

v _t = 41 m/s

[irp]

[wpdm_package id='513′]

[wpdm_package id='517′]

1. Ibanga kanye nokufuduka
2. Isivinini esimaphakathi kanye nesivinini esimaphakathi
3. Ijubane eliqhubekayo
4. Ukusheshisa okuqhubekayo
5. Ukunyakaza kwamahhala kokuwa
6. Ukunyakaza phansi ekwindla yamahhala
7. Ukunyakaza okuphezulu nokwehlayo ekuwa okukhululekile

Funda kabanzi