Ukunyakaza okusheshisa njalo - izinkinga nezixazululo

Izinkinga Ezixazululiwe Ekuhambeni Okuqondile - Ukusheshisa Okuqhubekayo

1. Imoto ishesha ukusuka ekuphumuleni iye kuma-20 m/s ngemizuzwana eyi-10. Nquma ukusheshisa kwemoto!

Isixazululo

Kwaziwa:

Ijubane lokuqala (v o ) = 0 (ukuphumula)

Isikhawu sesikhathi (t) = imizuzwana eyi-10

Ijubane lokugcina (v t ) = 20 m/s

Okufunwayo : Ukusheshisa (a)

Isixazululo:

v t = vo o + at

20 = 0 + (a)(10)

20 = 10 a

a = 20/10

a = 2 m/s 2

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2. Imoto yehla isuka ku-30 ​​m/s ukuze iphumule ngemizuzwana eyi-10. Nquma ukusheshisa kwemoto.

Isixazululo

Kwaziwa:

Ijubane lokuqala (v o ) = 30 m/s

Ijubane lokugcina (v t ) = 0

Isikhawu sesikhathi (t) = imizuzwana eyi-10

Okufunwayo: ukusheshisa (a)

Isixazululo:

v t = vo o + at

0 = 30 + (a)(10)

– 30 = 10 a

a = – 30/10

a = -3 m/s 2

Uphawu olubi luvela ngoba ijubane lokugcina lingaphansi kwejubane lokuqala.

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3. Imoto iqala futhi isheshise ngesivinini esingaguquki esingu-4 m/s 2 ngomzuzwana o-1. Thola isivinini kanye nebanga ngemva kwemizuzwana eyi-10.

Isixazululo

(a) Isivinini

Ukusheshisa okungu-4 m/s 2 kusho ukwanda kwesivinini okungu-4 m/s njalo ngomzuzwana owodwa. Ngemva kwemizuzwana emibili, isivinini semoto singama-8 m/s. Ngemva kwemizuzwana eyi-10, isivinini semoto singama-40 m/s.

(b) Ibanga

Kwaziwa:

Ijubane lokuqala (v o ) = 0

Ijubane lokugcina (v t ) = 40 m/s

Ukusheshisa (a) = 4 m/s 2

Okufunwayo: Ibanga

Isixazululo:

s = vot + ½ ku- 2 = 0 + ½ (4)(10 2 ) = (2)(100) = amamitha angu-200

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4. Imoto ihamba ngesivinini esingaguquki esingu-10 m/s, bese yehla ngesivinini esingaguquki esingu-2 m/s kuze kube yilapho iphumula. Thola isikhathi esidlulile kanye nebanga lemoto ngaphambi kokuphumula.

Kwaziwa:

Ijubane lokuqala (v o ) = 10 m/s

Ukusheshisa (a) = -2 m/s 2 (Isibonakaliso esingesihle sivela ngoba ijubane lokugcina lingaphansi kwejubane lokuqala)

Ijubane lokugcina (v t ) = 0 (ukuphumula)

Okufunwayo: Isikhathi esiphakathi kanye nebanga

Isixazululo:

(a) Isikhawu sesikhathi (t)

v t = vo o + at

0 = 10 + (-2)(t)

0 = 10 – 2 t

10 = 2 t

t = 10 / 2 = 5 imizuzwana

(b) Ibanga

v t 2 = v o 2 + 2 njengoba

0 = 10 2 + 2(-2) s

0 = 100 – 4 imizuzwana

100 = 4 imizuzwana

s = 100 / 4 = amamitha angu-25

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5. Imoto ihamba ngesivinini esingu-40 m/s, yehla ngesivinini esingaguquki esingu-4 m/s 2 kuze kube yilapho iphumula. Thola isivinini kanye nebanga ngemva kokwehla ngemizuzwana eyi-10!

Isixazululo

Kwaziwa:

Ijubane lokuqala (v o ) = 40 m/s

Ukusheshisa (a) = -4 m/s 2

Isikhawu sesikhathi (t) = imizuzwana eyi-10

Okufunwayo: ijubane lokugcina (v t ) kanye nebanga (s)

Isixazululo:

(a) Ijubane lokugcina

v t = vo o + at = 40 + (-4)(10) = 40 – 40 = 0 m/s

I-0 m/s isho ukuphumula kwemoto.

(b) Ibanga

s = vot + ½ ku- 2 = (40)(10) + ½ (-4)(10 2 ) = 400 + (-2)(100) = 400 – 200 = amamitha angu-200

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6. Thola ibanga ngemva kwemizuzwana eyi-10!

Ukusheshisa okuqhubekayo - izinkinga nezixazululo 1

Isixazululo

Ibanga: s = vt = (10-0)(5-0) = (10)(5) = amamitha angu-50

7. Thola ibanga ngemva kwemizuzwana eyi-4!

Ukusheshisa okuqhubekayo - izinkinga nezixazululo 2

Isixazululo

Ibanga = indawo yesikwele + indawo engunxantathu

Ibanga = (8-0)(8-0) + ½ (16-8)(8-0) = (8)(8) + ½ (8)(8) = 64 + 32 = amamitha angu-96

8. Nquma ibanga lemoto ngemva kwemizuzwana emi-4!

Isixazululo

Ukusheshisa okuqhubekayo - izinkinga nezixazululo 3

Ibanga = indawo engunxantathu = ½ (4-0)(8-0) = ½ (4)(8) = amamitha ayi-16

9. Imoto ihamba ngesivinini esingamakhilomitha angama - 90 ngehora idlula imoto yamaphoyisa ema eceleni komgwaqo. Ngemva komzuzu owodwa, imoto yamaphoyisa iyajaha ngesivinini esingama-0.8 m/s . 2. Imoto yamaphoyisa ifinyelela kude kangakanani emotweni?

Kwaziwa:

Isivinini semoto (v) = 90 km/hora = 90,000 amamitha / 3600 imizuzwana = 25 amamitha/umzuzwana

Isikhawu sesikhathi (t) = umzuzu ongu-1 = imizuzwana engama-60

Ukusheshisa imoto yamaphoyisa (a) = 0.8 m/s 2

Isivinini sokuqala semoto yamaphoyisa (v o ) = 0 m/s

Kufunwa: Ibanga elihanjwa ngemoto yamaphoyisa

Isixazululo:

Imoto ihamba ngesivinini esingaguquki. Ibanga elihanjwa ngemoto:

Ibanga lokuqala:

s = vt = (25)(60) = amamitha angu-1500

Ibanga lokugcina:

s = vt = (25)(t)

Ibanga eliphelele = 1500 + 25 t

Imoto yamaphoyisa ihamba ngesivinini esingaguquki. Ibanga elihanjwa yimoto yamaphoyisa:

s = vot + ½ ku- 2 = (0)(t) + ½ (0.8)(t 2 ) = 0 + 0.4 t 2 = 0.4 t 2

Uma imoto yamaphoyisa ifika emotweni, ibanga elihanjwa yimoto yamaphoyisa lifana nebanga elihanjwa yimoto.

Ibanga elihanjwa ngemoto = ibanga elihanjwa ngemoto yamaphoyisa

1500 + 25 t = 0.4 t 2

0.4 t 2 – 25 t – 1500 = 0

Sebenzisa ifomula ye-quadratic:

Ukusheshisa okuqhubekayo - izinkinga nezixazululo 1

Ibanga elihanjwe ngemoto yamaphoyisa:

s = 0.4 t 2 = (0.4)(100 2 ) = (0.4)(10,000) = 4000 amamitha s = 4 km

10. Imoto ihamba ngamabhuleki angu-24 m/s angaguquki ukuze ibe nokwehla okuqhubekayo okungu - 0.952 m/s 2. Nquma ijubane lemoto ngemva kwebanga elingamamitha angu- 250.

Kwaziwa:

Ijubane lokuqala (v o ) = 24 m/s

Ukusheshisa (a) = – 0.952 m/s 2 ( kusayinwe okungekuhle ngoba ukwehla kwejubane )

Ibanga ( d ) = amamitha angu-250 s

Okufunwayo: Isivinini semoto ngemuva kwamamitha angu-250 s

Isixazululo:

Okuyaziwayo: isivinini sokuqala (vo), ukusheshisa (a), ibanga (d), okufunwayo: isivinini sokugcina (vt) ngakho sebenzisa i-equation ye vt2 =vo2 + 2 kube d

v t = ijubane lokugcina , v o = ijubane lokuqala , a = ukusheshisa , d = ibanga

v t 2 = (24) 2 + (2)(-0.952)(250)

v t 2 = 576 – 476

v t 2 = 100

v t = √100

v t = 10 m/s

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  1. Ibanga kanye nokufuduka
  2. Isivinini esimaphakathi kanye nesivinini esimaphakathi
  3. Ijubane eliqhubekayo
  4. Ukusheshisa okuqhubekayo
  5. Ukunyakaza kwamahhala kokuwa
  6. Ukunyakaza phansi ekwindla yamahhala
  7. Ukunyakaza okuphezulu nokwehlayo ekuwa okukhululekile

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