Izinkinga Ezixazululiwe Ekuhambeni Okuqondile - Ukusheshisa Okuqhubekayo
1. Imoto ishesha ukusuka ekuphumuleni iye kuma-20 m/s ngemizuzwana eyi-10. Nquma ukusheshisa kwemoto!
Isixazululo
Kwaziwa:
Ijubane lokuqala (v o ) = 0 (ukuphumula)
Isikhawu sesikhathi (t) = imizuzwana eyi-10
Ijubane lokugcina (v t ) = 20 m/s
Okufunwayo : Ukusheshisa (a)
Isixazululo:
v t = vo o + at
20 = 0 + (a)(10)
20 = 10 a
a = 20/10
a = 2 m/s 2
2. Imoto yehla isuka ku-30 m/s ukuze iphumule ngemizuzwana eyi-10. Nquma ukusheshisa kwemoto.
Isixazululo
Kwaziwa:
Ijubane lokuqala (v o ) = 30 m/s
Ijubane lokugcina (v t ) = 0
Isikhawu sesikhathi (t) = imizuzwana eyi-10
Okufunwayo: ukusheshisa (a)
Isixazululo:
v t = vo o + at
0 = 30 + (a)(10)
– 30 = 10 a
a = – 30/10
a = -3 m/s 2
Uphawu olubi luvela ngoba ijubane lokugcina lingaphansi kwejubane lokuqala.
3. Imoto iqala futhi isheshise ngesivinini esingaguquki esingu-4 m/s 2 ngomzuzwana o-1. Thola isivinini kanye nebanga ngemva kwemizuzwana eyi-10.
Isixazululo
(a) Isivinini
Ukusheshisa okungu-4 m/s 2 kusho ukwanda kwesivinini okungu-4 m/s njalo ngomzuzwana owodwa. Ngemva kwemizuzwana emibili, isivinini semoto singama-8 m/s. Ngemva kwemizuzwana eyi-10, isivinini semoto singama-40 m/s.
(b) Ibanga
Kwaziwa:
Ijubane lokuqala (v o ) = 0
Ijubane lokugcina (v t ) = 40 m/s
Ukusheshisa (a) = 4 m/s 2
Okufunwayo: Ibanga
Isixazululo:
s = vot + ½ ku- 2 = 0 + ½ (4)(10 2 ) = (2)(100) = amamitha angu-200
4. Imoto ihamba ngesivinini esingaguquki esingu-10 m/s, bese yehla ngesivinini esingaguquki esingu-2 m/s kuze kube yilapho iphumula. Thola isikhathi esidlulile kanye nebanga lemoto ngaphambi kokuphumula.
Kwaziwa:
Ijubane lokuqala (v o ) = 10 m/s
Ukusheshisa (a) = -2 m/s 2 (Isibonakaliso esingesihle sivela ngoba ijubane lokugcina lingaphansi kwejubane lokuqala)
Ijubane lokugcina (v t ) = 0 (ukuphumula)
Okufunwayo: Isikhathi esiphakathi kanye nebanga
Isixazululo:
(a) Isikhawu sesikhathi (t)
v t = vo o + at
0 = 10 + (-2)(t)
0 = 10 – 2 t
10 = 2 t
t = 10 / 2 = 5 imizuzwana
(b) Ibanga
v t 2 = v o 2 + 2 njengoba
0 = 10 2 + 2(-2) s
0 = 100 – 4 imizuzwana
100 = 4 imizuzwana
s = 100 / 4 = amamitha angu-25
5. Imoto ihamba ngesivinini esingu-40 m/s, yehla ngesivinini esingaguquki esingu-4 m/s 2 kuze kube yilapho iphumula. Thola isivinini kanye nebanga ngemva kokwehla ngemizuzwana eyi-10!
Isixazululo
Kwaziwa:
Ijubane lokuqala (v o ) = 40 m/s
Ukusheshisa (a) = -4 m/s 2
Isikhawu sesikhathi (t) = imizuzwana eyi-10
Okufunwayo: ijubane lokugcina (v t ) kanye nebanga (s)
Isixazululo:
(a) Ijubane lokugcina
v t = vo o + at = 40 + (-4)(10) = 40 – 40 = 0 m/s
I-0 m/s isho ukuphumula kwemoto.
(b) Ibanga
s = vot + ½ ku- 2 = (40)(10) + ½ (-4)(10 2 ) = 400 + (-2)(100) = 400 – 200 = amamitha angu-200
6. Thola ibanga ngemva kwemizuzwana eyi-10!

Isixazululo
Ibanga: s = vt = (10-0)(5-0) = (10)(5) = amamitha angu-50
7. Thola ibanga ngemva kwemizuzwana eyi-4!

Isixazululo
Ibanga = indawo yesikwele + indawo engunxantathu
Ibanga = (8-0)(8-0) + ½ (16-8)(8-0) = (8)(8) + ½ (8)(8) = 64 + 32 = amamitha angu-96
8. Nquma ibanga lemoto ngemva kwemizuzwana emi-4!
Isixazululo

Ibanga = indawo engunxantathu = ½ (4-0)(8-0) = ½ (4)(8) = amamitha ayi-16
9. Imoto ihamba ngesivinini esingamakhilomitha angama - 90 ngehora idlula imoto yamaphoyisa ema eceleni komgwaqo. Ngemva komzuzu owodwa, imoto yamaphoyisa iyajaha ngesivinini esingama-0.8 m/s . 2. Imoto yamaphoyisa ifinyelela kude kangakanani emotweni?
Kwaziwa:
Isivinini semoto (v) = 90 km/hora = 90,000 amamitha / 3600 imizuzwana = 25 amamitha/umzuzwana
Isikhawu sesikhathi (t) = umzuzu ongu-1 = imizuzwana engama-60
Ukusheshisa imoto yamaphoyisa (a) = 0.8 m/s 2
Isivinini sokuqala semoto yamaphoyisa (v o ) = 0 m/s
Kufunwa: Ibanga elihanjwa ngemoto yamaphoyisa
Isixazululo:
Imoto ihamba ngesivinini esingaguquki. Ibanga elihanjwa ngemoto:
Ibanga lokuqala:
s = vt = (25)(60) = amamitha angu-1500
Ibanga lokugcina:
s = vt = (25)(t)
Ibanga eliphelele = 1500 + 25 t
Imoto yamaphoyisa ihamba ngesivinini esingaguquki. Ibanga elihanjwa yimoto yamaphoyisa:
s = vot + ½ ku- 2 = (0)(t) + ½ (0.8)(t 2 ) = 0 + 0.4 t 2 = 0.4 t 2
Uma imoto yamaphoyisa ifika emotweni, ibanga elihanjwa yimoto yamaphoyisa lifana nebanga elihanjwa yimoto.
Ibanga elihanjwa ngemoto = ibanga elihanjwa ngemoto yamaphoyisa
1500 + 25 t = 0.4 t 2
0.4 t 2 – 25 t – 1500 = 0
Sebenzisa ifomula ye-quadratic:

Ibanga elihanjwe ngemoto yamaphoyisa:
s = 0.4 t 2 = (0.4)(100 2 ) = (0.4)(10,000) = 4000 amamitha s = 4 km
10. Imoto ihamba ngamabhuleki angu-24 m/s angaguquki ukuze ibe nokwehla okuqhubekayo okungu - 0.952 m/s 2. Nquma ijubane lemoto ngemva kwebanga elingamamitha angu- 250.
Kwaziwa:
Ijubane lokuqala (v o ) = 24 m/s
Ukusheshisa (a) = – 0.952 m/s 2 ( kusayinwe okungekuhle ngoba ukwehla kwejubane )
Ibanga ( d ) = amamitha angu-250 s
Okufunwayo: Isivinini semoto ngemuva kwamamitha angu-250 s
Isixazululo:
Okuyaziwayo: isivinini sokuqala (vo), ukusheshisa (a), ibanga (d), okufunwayo: isivinini sokugcina (vt) ngakho sebenzisa i-equation ye vt2 =vo2 + 2 kube d
v t = ijubane lokugcina , v o = ijubane lokuqala , a = ukusheshisa , d = ibanga
v t 2 = (24) 2 + (2)(-0.952)(250)
v t 2 = 576 – 476
v t 2 = 100
v t = √100
v t = 10 m/s
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- Ibanga kanye nokufuduka
- Isivinini esimaphakathi kanye nesivinini esimaphakathi
- Ijubane eliqhubekayo
- Ukusheshisa okuqhubekayo
- Ukunyakaza kwamahhala kokuwa
- Ukunyakaza phansi ekwindla yamahhala
- Ukunyakaza okuphezulu nokwehlayo ekuwa okukhululekile