Izinkinga ezixazululiwe emithethweni kaNewton yokunyakaza – umthetho wesibili kaNewton wokunyakaza
1. Into engu-1 kg isheshiswe ngokulingana okungu-5 m/s 2 . Linganisa amandla aphelele adingekayo ukuze kusheshiswe into.
Kwaziwa:
Isisindo (m) = 1 kg
Ukusheshisa (a) = 5 m/s 2
Kufunwa : amandla aphelele (∑F)
Isixazululo:
Sisebenzisa umthetho wesibili kaNewton ukuthola amandla e-net.
∑ F = ma
∑ F = (1 kg)(5 m/s 2 ) = 5 kg m/s 2 = 5 Newtons
[irp]
2. Isisindo sento = 1 kg, amandla aphelele ∑F = 2 amaNewton. Nquma ubukhulu kanye nesiqondiso sokusheshisa kwento….
Kwaziwa:
Isisindo (m) = 1 kg
Amandla aphelele (∑F) = 2 Newton
Okufunwayo : Ubukhulu kanye nesiqondiso sokusheshisa (a)
Isixazululo:
a = ∑F / m
a = 2/1
a = 2 m/s 2
Isiqondiso sokusheshisa = isiqondiso samandla aphelele (∑F)
[irp]
3. Isisindo sento = 2 kg, F 1 = 5 Newtons, F 2 = 3 Newton. Ubukhulu kanye nesiqondiso sokusheshisa…
Kwaziwa:
Isisindo (m) = 2 kg
F 1 = 5 Newton
F 2 = 3 Newton
Okufunwayo: Ubukhulu kanye nesiqondiso sokusheshisa (a)
Isixazululo:
amandla aphelele:
∑ F = F 1 – F 2 = 5 – 3 = 2 AmaNewton
Ubukhulu bokusheshisa:
a = ∑F / m
a = 2/2
a = 1 m/s 2
Isiqondiso sokusheshisa = isiqondiso samandla aphelele = isiqondiso sika-F 1
[irp]
4. Isisindo sento = 2 kg, F 1 = 10 Newtons, F 2 = 1 Newton. Ubukhulu kanye nesiqondiso sokusheshisa…
Kwaziwa:
Isisindo (m) = 2 kg
F 2 = 1 Newton
F 1 = 10 Newton
F 1x = F 1 cos 60 o = (10)(0.5) = 5 Newtons
Okufunwayo : Ubukhulu kanye nesiqondiso sokusheshisa (a)
Isixazululo:
Amandla aphelele:
∑ F = F 1x – F 2 = 5 – 1 = 4 amaNewton
Ubukhulu bokusheshisa:
a = ∑F / m
a = 4/2
a = 2 m/s 2
Isiqondiso sokusheshisa = isiqondiso samandla aphelele = isiqondiso se-F 1x
[irp]
5. F 1 = 10 Newtons, F 2 = 1 Newton, m 1 = 1 kg, m 2 = 2 kg. Ubukhulu kanye nesiqondiso sokusheshisa…
Kwaziwa:
Isisindo 1 (m1 ) = 1 kg
Isisindo 2 (m2 ) = 2 kg
F 1 = 10 Newton
F 2 = 1 Newton
Okufunwayo : Ubukhulu kanye nesiqondiso sokusheshisa (a)
Isixazululo:
Amandla aphelele:
∑ F = F 1 – F 2 = 10 – 1 = 9 AmaNewton
Ubukhulu bokusheshisa:
a = ∑F / (m 1 + m 2 )
a = 9 / (1 + 2)
a = 9/3
a = 3 m/s 2
Isiqondiso sokusheshisa = isiqondiso samandla aphelele = isiqondiso sika-F 1
[irp]
6.
Ibhulokhi engama-40 kg esheshiswa ngamandla angu-200 N. Ukusheshisa kwebhulokhi kungu-3 m/ s 2. Thola ubukhulu bamandla okungqubuzana abhekene nebhulokhi.
A. 15 N
B. 40 N
C. 43 N
D. 80 N
Kwaziwa:
Isisindo (m) = 40 kg
Amandla (F) = 200 N
Ukusheshisa (a) = 3 m/s 2
Okufunwayo: Amandla okungqubuzana (F g )
Isixazululo:
Isilinganiso somthetho wesibili wokunyakaza kaNewton
∑ F = ma
∑ F = amandla aphelele, m = isisindo, a = ukusheshisa
Isiqondiso samandla F ngakwesokudla, isiqondiso samandla okungqubuzana ngakwesobunxele (isiqondiso samandla okungqubuzana siphambene nesiqondiso sokunyakaza kwento).
Khetha okuya kwesokudla okuhle nokuya kwesobunxele njengokubi.
∑ F = ma
F – F g = ma
200 – F g = (40)(3)
200 – F g = 120
F g = 200 – 120
F g = 80 Newton
Impendulo efanele ngu-D.
7. Ibhulokhi A enesisindo esingamagremu ayi-100 beka ngaphezu kwebhulokhi B enesisindo esingamagremu angu-300, bese ibhulokhi B icindezelwa ngamandla angu-5 N phezulu. Thola amandla avamile asetshenziswa yibhulokhi B kubhulokhi A.
A. 1 N
B. 1.25 N
C. 2 N
D. 3 N
Kwaziwa:
Amandla (F) = 5 Newton
Isisindo sebhulokhi A (m A ) = amagremu ayi-100 = 0.1 kg
Isisindo sebhulokhi B (m B ) = amagremu angu-300 = 0.3 kg
Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s 2
Isisindo sebhulokhi A (w A ) = (0.1 kg)(10 m/s 2 ) = 1 kg m/s 2 = 1 Newton
Isisindo sebhulokhi B (w B ) = (0.3 kg)(10 m/s 2 ) = 3 kg m/s 2 = 3 amaNewton
Okufunwayo: Amandla ajwayelekile asetshenziswa yibhlokhi B ukuze kuvinjwe ibhlokhi A
Isixazululo:
Kunamandla amaningana asebenza kuzo zombili izithiyo, njengoba kuboniswe esithombeni.
F = amandla okusunduza (isenzo kubhlokhi B)
w A = isisindo sebhulokhi A (isenzo kubhulokhi A)
w B = isisindo sebhulokhi B (isenzo kubhulokhi B)
N A = amandla avamile asetshenziswa yibhlokhi B kubhlokhi A (Umthetho kubhlokhi A)
N A ' = amandla avamile asetshenziswa yibhlokhi A kubhlokhi B (Umthetho kubhlokhi B)
Sebenzisa umthetho wesibili kaNewton wokunyakaza kuzo zombili izithiyo:
∑ F = ma
F – w A – w B + N A – N A ' = (m A + m B ) a
I-N A kanye ne-N A ' zingamandla okusabela kwesenzo anobukhulu obufanayo kodwa aphambene ngakho-ke asuswa kulesi sibalo.
F – w A – w B = (m A + m B ) a
5 – 1 – 3 = (0.1 + 0.3) a
5 – 4 = (0.4) a
1 = (0.4) a
a = 1/0.4
a = 2.5 m/s 2
Sebenzisa umthetho wesibili kaNewton wokunyakaza kubhlokhi A:
∑ F = ma
N A – w A = m A a
I-N A – 1 = (0.1)(2.5)
I- NA – 1 = 0.25
I-NA = 1 + 0.25
I-NA = 1.25 amaNewton
Impendulo efanele ngu-B.
8. Into enesisindo esingu-4 N esisekelwa yintambo kanye ne-pulley. Amandla angu-2 N asebenza ebhulokini kanye nokuphela kwentambo edonswa ngamandla angu-9 N. Thola amandla aphelele entweni X.
A. 3 N phezulu
B. 4 N phansi
C. 9 N phezulu
D. 9 N phansi
Kwaziwa:
Isisindo sika-X (w X ) = 4 Newton
Amandla okudonsa (F x ) = 2 Newton
Amandla okucindezela (F T ) = 9 Newtons
Kufunwa: Amandla e-Net asebenza entweni
Isixazululo:
Amandla aphezulu aqonde phezulu asebenza entweni
Amandla okucindezela anobukhulu obufanayo kuzo zonke izingxenye zentambo. Ngakho amandla okucindezela angama-9 N.
Amandla aqonde phansi asebenza entweni
Kunamandla amabili asebenza entweni X futhi womabili la mandla abheke phansi, ingxenye evundlile yesisindo esingu-w x kanye nengxenye evundlile yamandla u-F x.
Isenzo samandla e-net entweni
F T – w X – F x = 9 – 4 – 2 = 9 – 6 = 3
Amandla e-net asebenza entweni u-X angama-Newton amathathu, aqonde phezulu.
Impendulo eyiyo ngu-A.
9. Into eqale iphumule endaweni ebushelelezi evundlile. Amandla angu-16 N asebenza entweni ukuze into isheshise ku-2 m/s 2 . Uma into efanayo iphumule endaweni evundlile evundlile ukuze amandla okungqubuzana asebenze entweni engu-2 N, nquma ukusheshisa kwento uma amandla afanayo angu-16 N esebenza entweni.
A. 1.75 m/s 2
B. 1.50 m/s 2
C. 1.00 m/s 2
D. 0.88 m/s 2
Kwaziwa:
Amandla (F) = 16 AmaNewton = 16 kg m/s 2
Ukusheshisa (a) = 2 m/s 2
Amandla okungqubuzana (F fric ) = 2 AmaNewton = 2 kg m/s 2
Okufunwayo: Ukusheshisa kwento?
Isixazululo:
Ubuso obubushelelezi obuvundlile (akukho mandla okungqubuzana):
∑F = ma
F = ma
16 = (m) 2
m = 16/2
m = 8 kg
Isisindo sale nto singamakhilogremu angu-8.
Ubuso obuqondile obuqinile (kukhona amandla okungqubuzana):
∑F = ma
F – F fric = ma
16 – 2 = 8 a
14 = 8 a
a = 14/8
a = 1.75 m/s 2
Ukusheshisa kwento kungu-1.75 m/s 2.
Impendulo eyiyo ngu-A.
10. UTom no-Andrew bacindezela into phansi ebushelelezi. UTom ucindezela into ngamandla angu-5.70 N. Uma isisindo sento singama-2.00 kg futhi ukusheshisa okubonwa yinto kungu-2.00 ms -2 , nquma ubukhulu kanye nesiqondiso sesenzo samandla sikaTom.
A. 1.70 N futhi isiqondiso sayo siphambene nempoqo eyenziwe ngu-Andre.w
B. 1.70 N kanye nesiqondiso sayo kufana namandla asetshenziswa ngu-Andrew
C. 2.30 N futhi isiqondiso sayo siphambene nempoqo eyenziwe ngu-Andrew.
D. 2.30 N kanye nesiqondiso sayo kufana namandla asetshenziswa ngu-Andrew.
Kwaziwa:
Amandla okusunduza asetshenziswa ngu-Andrew (F 1 ) = 5.70 Newton
Isisindo sento (m) = 2.00 kg
Ukusheshisa (a) = 2.00 m/s 2
Okufunwayo: Ubukhulu kanye nesiqondiso samandla esenziwa nguTom (F 2 )?
Isixazululo:
Sebenzisa umthetho wesibili kaNewton wokunyakaza:
∑ F = ma
F 1 + F 2 = ma
5.70 + F 2 = (2)(2)
5.70 + F 2 = 4
F 2 = 4 – 5.70
F 2 = – 1.7 Newton
Uphawu lokususa lubonise ukuthi (F 2 ) luphambene nesenzo sokusunduza sika-Andrew (F 1 ).
Impendulo eyiyo ngu-A.
11. Uma isisindo sebhulokhi sifana, yisiphi isibalo esibonisa ukusheshisa okuncane kakhulu?
Isixazululo
Amandla aphelele A:
ΣF = 4 N + 2 N – 3 N = 6 N – 3 N = 3 Amathoni amasha, kwesokunxele
Amandla aphelele B:
ΣF = 2 N + 3 N – 4 N = 5 N – 4 N = 1 Amathoni amasha, kwesokudla
Amandla aphelele C:
ΣF = 4 N + 3 N – 2 N = 7 N – 2 N = 5 Amathoni amasha, kwesokudla
Amandla aphelele D:
ΣF = 3 N + 4 N + 2 N = 9 Newtons, kwesokudla
Isilinganiso somthetho wesibili kaNewton:
ΣF = ma
a = ΣF / m
a = ukusheshisa, ΣF = amandla aphelele, m = isisindo
Ngokusekelwe kufomula engenhla, ukusheshisa (a) kuhambelana ngqo namandla aphelele (ΣF) futhi kuhambisana ngokuphambene nobunzima (m). Uma isisindo sento sifana, lapho amandla avelayo emakhulu, lapho ukusheshisa kukhulu noma lapho amandla avelayo emancane, kulapho ukusheshisa kuncane khona.
Ngokusekelwe ekubalweni okungenhla, amandla amancane kakhulu e-net yi-1 Newton ngakho-ke ukusheshisa nakho kuncane kakhulu.
Impendulo efanele ngu-B.
[irp]
12. Amanye amandla asebenza entweni enesisindo esingama-20 kg, njengoba kuboniswe esithombeni esingezansi.
Nquma ukusheshisa kwento.
Kwaziwa:
Isisindo sento (m) = 20 kg
Amandla engqikithi (ΣF) = 25 N + 30 N – 15 N = 40 N
Okufunwayo: Ukusheshisa into
Isixazululo:
Ukusheshisa kwento kubalwe kusetshenziswa i-equation yomthetho wesibili kaNewton:
ΣF = ma
a = ΣF / m = 40 N / 20 kg = 2 N/kg = 2 m/s 2
[irp]
13. Yisiphi isitatimende esingezansi esichaza umthetho wesithathu kaNewton?
(1) Abagibeli baqhubekela phambili lapho ibhasi libhuleka ngokuzumayo
(2) Izincwadi ezisephepheni aziwi uma iphepha lidonswa ngokushesha
(3) Uma udlala i-skateboard uma unyawo lusunduza umhlabathi emuva, i-skateboard izoshelela phambili
(4) O ars esunduzwa emuva, izikebhe ziya phambili
Isixazululo:
(1) Umthetho wokuqala kaNewton
(2) Umthetho wokuqala kaNewton
(3) Umthetho wesithathu kaNewton
(4) Umthetho wesithathu kaNewton
[wpdm_package id='470′]
- Isisindo kanye nesisindo
- amandla ajwayelekile
- Umthetho wesibili wokunyakaza kukaNewton
- Amandla okungqubuzana
- Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
- Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
- Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
- Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
- Ukunyakaza e-lifti
- Ukunyakaza kwemizimba kuxhunywe ngezintambo nama-pulleys
- Imizimba emibili enesilinganiso esifanayo sokusheshisa
- Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
- Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
- Ukunyakaza okufanayo kumbuthano ovundlile
- Amandla aphakathi ahambisanayo ajikelezayo
