Inkinga eqhubekayo - izinkinga nezixazululo

Inkinga eqhubekayo - izinkinga nezixazululo

1. Isisindo sebhulokhi singama-5 kg, ukusheshisa ngenxa yamandla adonsela phansi = 9.8 m/s ² , tan 37 ^o = 3/4. Kuyini ukusheshisa kwebhulokhi?

Isixazululo

Kwaziwa:

isisindo (m) = 5 kg

ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

isisindo (w) = mg = (5)(10) = 50 N

x = i-3

Ukuphakama kwendiza ethambekele (y) = 4

Ubude bomphezulu wendiza othambekele (l) = 5

Okufunwayo : ukusheshisa kwebhulokhi (a)?

Isixazululo:

Ibhloko lisheshiswa ngamandla ka-w _x . Indiza egobile ibushelelezi ngakho-ke akukho mandla okungqubuzana.

w _x = w sin θ = (w)(y / z)

w _x = (50)(4/5)

w _x = 40 Newton

Ukusheshisa kwebhulokhi (a)?

ΣF = ma

w _x = ma

40 = (5) a

a = 40/5

a = 8 m/s ²

2. Ibhlokhi ekuqaleni lapho liphumule, bese lisheshiswa liye phezulu lihambisana nobuso bendiza obuthambekele. Isisindo sebhlokhi = 8 kg, i-coefficient of static friction µ _s = 0.5 kanye ne-engeli θ = 45 ^o . Iyini ubukhulu bamandla F ukuze ibhlokhi isheshiswe.

Kwaziwa:

I-Coefficient yokungqubuzana okungaguquki (µs ₎ = 0.5

I-engeli (θ) = 45 ^o

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Isisindo sebhulokhi (m) = 8 kg

Isisindo sebhulokhi (w) = mg = (8 kg)(10 m/s ² ) = 80 kg m/s ² = 80 amaNewton

Okufunwayo: Ubukhulu bamandla F

Isixazululo:

I-block qala ukusheshisa uma F ≥ w_x + f_s.

Ingxenye evundlile yesisindo :

w _x = w isono θ = (80)(isono 45) = (80)(0.5√2) = 40√2

Ingxenye eqondile yesisindo:

w _y = w cos θ = (80)(cos 45) = (80)(0.5√2) = 40√2

Amandla ajwayelekile :

N = w _y = 40√2

Amandla okungqubuzana okungaguquki:

f _s = µ _s N = (0.5)(40√2) = 20√2

Ubukhulu bamandla F:

F ≥ w _x + f _s

F ≥ 40√2 + 20√2

F ≥ 60√2 Newton

3. Isisindo sebhulokhi singama-8 kg. Amandla amancane adingekayo ukubamba ibhulokhi ukuze ibhulokhi lingasheleli phansi yi... (sin 37 ^o = 0.6, cos 37 ^o = 0.8, g = 10 ms ^-2 , µ _k = 0.1)

Kwaziwa:

Isisindo sebhulokhi (m) = 8 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

Isisindo sebhulokhi (w) = mg = (8)(10) = 80 amaNewton

Isono 37 ^o = 0.6

I-Cos 37 ^o = 0.8

I-coefficient ye-kinetic friction (µ _k ) = 0.1

Amandla ajwayelekile (N) = w _y = w cos 37 ^o = (80)(0.8) = 64 amaNewton

Okufunwayo: Ubukhulu bamandla F

Isixazululo:

Ibhloko alisheleli phansi uma u-F = w _x

Ingxenye evundlile yesisindo ehambisana nendawo ethambekele:

w _x = w isono θ = (80)(isono 37) = (80)(0.6) = 48

f _k = µ _k N = (0.1)(64) = 6.4

Amandla amancane F ukuze ibhloko lingasheleli phansi:

F + f _k – w _x = 0

F = w _x – f _k = 48 – 6.4 = 41.6 AmaNewton

4. Ibhulokhi elingamakhilogremu angu-5 lidonswa endizeni ethambekele emagebhugebhu ngamandla angu-71 N (g = 10 ms ^-2 , sin 37 ^o = 0.6, cos 37 ^o = 0.8). Uma i-coefficient yamandla okungqubuzana phakathi kwebhulokhi nendiza ethambekele ingu-0.4, iyini ijubane lebhulokhi.

Kwaziwa:

Isisindo sento (m) = 5 kg

Ukusheshisa ngenxa yamandla adonsela phansi (g) = 10 m/s ²

isisindo sebhulokhi (w) = mg = (5)(10) = 50 amaNewton

Amandla F = 71 Newton

Isono 37 ^o = 0.6

I-Cos 37 ^o = 0.8

Isilinganiso sokungqubuzana = 0.4

Okufunwayo : Ukusheshisa kwebhulokhi (a)

Isixazululo:

Ingxenye evundlile yesisindo :

w _x = w isono θ = (50)(isono 37) = (50)(0.6) = 30

Ingxenye eqondile yesisindo :

w _y = w cos θ = (50)(cos 37) = (50)(0.8) = 40

Amandla ajwayelekile:

N = w _y = 40

Amandla okungqubuzana kwe-kinetic:

f _k = µ _k N = (0.4)(40) = 16

Amandla aphelele:

∑F = F – w _x – f _k = 71 – 30 – 16 = 25 Newtons

Ukusheshisa kwento:

a = ∑F / m = 25 / 5 = 5 m/s ²

5. Ibhokisi elingu-500-N eliphakanyiswe elolini ngendiza ethambekele, njengoba kuboniswe esithombeni esingezansi. Uma ukuphakama kweloli kungamamitha angu-1.5, nquma ubukhulu bamandla okuhambisa ibhokisi.

Kwaziwa:

isisindo sebhokisi (w) = amaNewton angu-500

ukuphakama kweloli (h) = 1.5 amamitha

ubude bendiza ethambekele (l) = amamitha angu-3

Kufunwa: Ubukhulu bamandla okuhambisa ibhokisi (F)

Isixazululo:

Isono θ = opp / hyp = 1.5 amamitha / 3 amamitha = 1.5 / 3 = 0.5

Amandla (F) adingekayo ukuhambisa ibhokisi, okufanayo nengxenye evundlile yesisindo ehambisana nendiza ethambekele (w _x ).

w _x = w isono θ = (500 N)(0.5) = 250 N

1. Iyini indiza ethambekele, futhi yenza kanjani ukuthi ukusebenza kube lula?
   • Impendulo: Indiza ethambekele iwubuso obuyisicaba obubekwe ekhoneni (ngaphandle kwe-engeli yesokudla) bubheke endaweni evundlile. Kwenza umsebenzi ube lula ngokuvumela amandla ukuthi asetshenziswe ibanga elide ukuze kunqotshwe amandla aphikisayo, ngokuvamile kunciphisa ubukhulu bamandla adingekayo ukuphakamisa noma ukwehlisa into.
2. I-engeli yokuthambekela iwathinta kanjani amandla adingekayo ukuze kushukunyiswe into endizeni?
   • Impendulo: Uma i-engeli yokuthambekela iphakeme, kulapho amandla adingekayo ukuhambisa into phezulu endizeni. Njengoba i-engeli incipha, amandla adingekayo ayancipha kodwa asetshenziswa ibanga elide.
3. Kungani kulula ukusunduza ibhokisi elisindayo endaweni yokuma kunokuliphakamisa liqonde phezulu?
   • Impendulo: Ukusunduza ibhokisi phezulu endaweni yokuma (indawo ethambekele) kuhlukanisa isisindo sebhokisi ibanga elide, kunciphisa amandla adingekayo nganoma yisiphi isikhathi. Ukuliphakamisa liqonde phezulu kudinga umuntu ukuba alwe nesisindo esiphelele sebhokisi ngqo, okudinga amandla amakhulu kakhulu.
4. Ubude bendiza ethambekele buhlobana kanjani namandla adingekayo ukuhambisa into phezulu endizeni?
   • Impendulo: Uma indilinga ethambekele inde (ukuphakama okuzinzile), kudingeka amandla amancane ukuhambisa into phezulu endizeni. Kodwa-ke, amandla kumele asetshenziswe ibanga elide.
5. Uma ukungqubuzana kungeniswa endizeni ethambekele, kukuthinta kanjani ukunyakaza kwento ekuyo?
   • Impendulo: Ukungqubuzana kuphikisana nokunyakaza kwento. Uma into isunduzelwa phezulu endizeni ethambekele, ukungqubuzana kuya phansi, kwandisa amandla adingekayo ukuhambisa into. Uma into ihamba phansi endizeni, ukungqubuzana kuyayibambezela ukwehla kwayo.
6. Kungani izisebenzi zisebenzisa izindiza ezithambekele ukulayisha izinto ezisindayo emalolini?
   • ImpenduloUkusebenzisa indiza ethambekele (i-ramp) kuvumela abasebenzi ukuthi basebenzise amandla amancane ebangeni elide ukulayisha izinto ezisindayo, okwenza umsebenzi ube lula futhi ungabi nzima kunokuphakamisa izinto ziqonde phezulu.
7. Isisindo sento sihlobene kanjani nokuthambekela kwayo kokushelela phansi endizeni ethambekele?
   • Impendulo: Ingxenye yesisindo sento esebenza ngokuhambisana nobuso bendawo ethambekele kuyo ibangela ukuthi ishelele. Uma into isinda, le ngxenye yesisindo iba nkulu, futhi ngaleyo ndlela, kulapho ukuthambekela kwento ukuthi ishelele phansi kuba kukhulu khona.
8. Iyiphi indima edlalwa amandla avamile endizeni ethambekele?
   • Impendulo: Amandla avamile asebenza ngokuqondile ebusweni bendiza ethambekele. Anesibopho senani lamandla okungqubuzana phakathi kwento nendiza ngoba ukungqubuzana kuvame ukulingana namandla avamile.
9. Kungani isihlabathi noma utshani bungabekwa endaweni ethambekele phakathi nezimo zeqhwa?
   • Impendulo: Isihlabathi noma ulwelwesi kwandisa amandla okungqubuzana phakathi kwendiza ethambekele nezinto (njengezicathulo noma amathayi) ezithintana nayo. Lokhu kungqubuzana okwengeziwe kusiza ukuvimbela ukushelela ngesikhathi sezimo ezibandayo noma ezimanzi.
10. Uma ibhola ligoqwa libheke phezulu bese libuyela phansi, ingabe lizofika esivinini salo sokuqala ngesikhathi libuyela endaweni yalo yokuqala, lingakunaki ukumelana nomoya nokungqubuzana?

• Impendulo: Yebo, uma kungekho ukumelana nomoya nokungqubuzana, amandla ebhola angase abe khona endaweni yawo ephezulu azoguqulwa ngokuphelele abe amandla e-kinetic njengoba ehla, okuzovumela ukuthi lifinyelele ijubane lalo lokuqala ngesikhathi libuyela endaweni yalo yokuqala ngenxa yokongiwa kwamandla.