Izinkinga ezixazululiwe emithethweni kaNewton yokunyakaza – Amandla okungqubuzana okungaguquki kanye nokujikijelana kwe-kinetic
1. Into iphumule phansi evundlile. I-coefficient yokungqubuzana okungaguquki ingu-0.4 kanti ukusheshisa kwamandla adonsela phansi kungu-9.8 m/s 2. Thola (a) Amandla aphezulu okungqubuzana okungaguquki (b) Amandla amancane ka-F
Isixazululo
Kwaziwa:
Isisindo (m) = 1 kg
I-coefficient yokungqubuzana okungaguquki (μ s ) = 0.4
Ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s 2
Isisindo (w) = mg = (1 kg)(10 m/s 2 ) = 10 kg m/s 2 = 10 AmaNewton
Amandla ajwayelekile (N) = w = 10 amaNewton
Kufunwa:
(a) Amandla aphezulu okungqubuzana okungaguquki (b) Amandla amancane ka-F
Isixazululo:
(a) Amandla aphezulu okungqubuzana okungaguquki
fs = μs N
f s = (0.4)(9.8 N) = 3.92 amaNewton
(b) Amandla amancane ka-F
Uma amandla u-F esetshenziswa entweni kodwa into ingashukunyiswa, ngakho-ke kumele kube namandla okungqubuzana okungaguquki asetshenziswa phansi entweni. Uma into izoqala ukuhamba, amandla okungqubuzana okungaguquki edlula, kumele kube namandla okungqubuzana okungaguquki. Into iqala ukuhamba uma u-F emkhulu kunamandla amakhulu okungqubuzana okungaguquki.
Ngakho amandla amancane ka-F = amandla amakhulu okungqubuzana okungaguquki = 3.92 amaNewton.
2. Ibhokisi elingu-1 kg lidonswa endaweni evundlile ngamandla F, ngakho ibhokisi lihamba ngesivinini esingaguquki. Uma i-kinetic friction coefficient ingu-0.1, thola ubukhulu bamandla F! (g = 9.8 m/s 2 )
Kwaziwa:
I- kinetic friction coefficient ( μk ) = 0.1
Isisindo sebhokisi (m) = 1 kg
Ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s 2
Isisindo (w) = mg = (1 kg)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 amaNewton
Amandla ajwayelekile (N) = w = 9.8 amaNewton
Kufunwa : F
Isixazululo:
Umthetho wokuqala kaNewton uthi uma kungekho mandla asebenzayo entweni, yonke into iyaqhubeka isesimweni sayo sokuphumula, noma ijubane elingaguquki emgqeni oqondile.
Ngakho-ke uma into ihamba ngesivinini esingaguquki , akumelwe kube khona amandla aphelele ( Σ F = 0) . Amandla F afakwa entweni ngendlela efanele ukuze amandla okungqubuzana kwe-kinetic afakwe entweni ngendlela eya kwesobunxele.
∑ F = 0
F – f k = 0
F = f k
Amandla okungqubuzana kwe-kinetic:
f k = μ k N = (0.1)(9.8 N) = 0.98 Newtons
into ihamba ngesivinini esingaguquki, F = f k = 0.98 amaNewton
3. Into ishelela phansi endizeni ethambekele ngesivinini esingaguquki. Thola i-kinetic friction coefficient ( μk ) . g = 9.8 m/s 2
Isixazululo
w = isisindo, w x = ingxenye evundlile yesisindo, amaphuzu eceleni kokuthambekela, w y = ingxenye eqondile yesisindo, eqondile endizeni ethambekele, N = amandla avamile, f k = amandla okungqubuzana kwe-kinetic.
Kwaziwa:
Isisindo (m) = 1 kg
Ukusheshisa kwamandla adonsela phansi (g) = 9.8 m/s 2
isisindo (w) = mg = (1 kg)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 amaNewton
w x = w sin 30 o = (9.8 N)(0.5) = 4.9 AmaNewton
w y = w cos 30 o = (9.8 N)(0.5) √ 3 = 4.9 √ 3 AmaNewton
Amandla ajwayelekile (N) = w y = 4.9 √ 3 amaNewton
Okufunwayo : i-kinetic friction coefficient ( μk )
Isixazululo:
Into ishelela phansi endizeni ethambekele ngesivinini esingaguquki ukuze amandla anetha = 0.
∑ F = 0
w x – f k = 0
w x = f k
w x = μ k N
5 = μ k ( 5 √ 3 )
μ k = 5 / 5 √ 3
μ k = 1 / √ 3
μ k = 0.58
[wpdm_package id='472′]
- Isisindo kanye nesisindo
- amandla ajwayelekile
- Umthetho wesibili wokunyakaza kukaNewton
- Amandla okungqubuzana
- Ukunyakaza endaweni evundlile ngaphandle kwamandla okungqubuzana
- Ukunyakaza kwemizimba emibili ngokusheshisa okufanayo endaweni evundlile eqinile ngamandla okungqubuzana
- Ukunyakaza endizeni ethambekele ngaphandle kwamandla okungqubuzana
- Ukunyakaza endizeni ethambekele emangelengele ngamandla okungqubuzana
- Ukunyakaza e-lifti
- Ukunyakaza kwemizimba exhunywe ngezintambo nama-pulley
- Imizimba emibili enesilinganiso esifanayo sokusheshisa
- Ukuzungeza ijika eliyisicaba - amandla okunyakaza okujikelezayo
- Ukuzungeza ijika eligobile - amandla okunyakaza okujikelezayo
- Ukunyakaza okufanayo kumbuthano ovundlile
- Amandla aphakathi ahambisanayo ajikelezayo
