I-physics

Izinkinga Ezixazululiwe Ekuhambeni Okuqondile – Izinto eziwa ngokukhululeka

1. Into ewile isuka phezulu eweni. Kubonakala sengathi ishaya phansi ngemuva kwemizuzwana emi-3. Thola ijubane layo ngaphambi nje kokushayisa phansi. Ukusheshisa kwamandla adonsela phansi ingu-10 m/s². Unganaki ukumelana nomoya.

Kwaziwa:

Ijubane lokuqala (v)_o) = 0 (into ilahliwe)

Isikhawu sesikhathi (t) = 3 imizuzwana

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Ijubane lokugcina (v)_t)

Isixazululo:

Ukusheshisa ngenxa yamandla adonsela phansi ebusweni bomhlaba, ubukhulu bawo buyi-9.8 m/s²Ukuze senze izibalo zibe lula, sisebenzisa i-10 m/s².

10 m / s² noma i-10 m/s / isekhondi eli-1, okusho ukuthi ijubane likhuphuka ngokulandelana ngesikhathi ngama-10 m/s phakathi nomzuzwana ngamunye.

Ngemva komzuzwana owodwa, ijubane lento = 10 m/s

Ngemva kwemizuzwana emi-2, ijubane lento = 20 m/s

Ngemva kwemizuzwana emi-3, ijubane lento = 30 m/s.

Singasebenzisa futhi ama-kinematic equation ukuze ukunyakaza ngokusheshisa okuqhubekayo, njengoba kukhonjisiwe ngezansi.

v_t =v_o + ku-

s = v_o t + ½ ku²

v_t² =v_o² + ama-ekseli ama-2

Ukuwa okukhululekile akunaso isivinini sokuqala (v)_o = 0), ngakho-ke i-equation engenhla ingashintshwa njengoba kuboniswe ngezansi:

Isibalo se Ukunyakaza kwamahhala kokuwa :

v_t = gt ………… 1

h = ½ gt² ………… 2

v_t² = 2 gh ………….. 3

v_t = gt

v_t = (10)(3)

v_t = 30m/s

Ijubane lokugcina lingu-30 m/s

2. Isidumbu siwela ngokukhululeka ekuphumuleni, sisuka ekuphakameni okungamamitha angu-25. Thola (a) Isivinini esishaya ngaso phansi. (b) Isikhathi esithathayo ukufika phansi.

Ukusheshisa ngenxa yamandla adonsela phansi ebusweni boMhlaba kungu-10 m/s².

Kwaziwa:

Ukuphakama (h) = amamitha angu-5

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa:

(a) Ijubane lokugcina (v)_t)

(b) Isikhawu sesikhathi (t)

Isixazululo:

Isibalo sokuwa kwamahhala:

v_t = gt

h = ½ gt²

v_t² = 2 gh

(a) Ijubane lokugcina (v)_t)

v_t² = 2 gh = 2(10)(5) = 100

v_t = 10m/s

(b) Isikhawu sesikhathi (t)

h = ½ gt²

5 = ½ (10) t²

5 = 5 t²

t² = 5/5 = 1

t = 1 umzuzwana

3. Ibhola liwile lisuka ekuphakameni. Thola (a) Ukusheshisa (b) Ibanga ngemva kwemizuzwana emi-3 (c) Isikhathi emoyeni uma ijubane lokugcina lingu-20 m/s. Ukusheshisa ngenxa yamandla adonsela phansi = 10 m/s²

Kuyaziwa :

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa:

(a) Ukusheshisa (a)

(B) ibanga noma ukuphakama (h) uma isikhathi sidlulile (t) = imizuzwana emi-3

(c) Isikhawu sesikhathi (t) uma v_t = 20m/s

Isixazululo:

Isibalo sokuwa kwamahhala:

v_t = gt

h = ½ gt²

v_t² = 2 gh

(a) Ukusheshisa (a)

Ukusheshisa = ukusheshisa ngenxa yamandla adonsela phansi = 10 m/s²Kusho ukwanda kwesivinini ngo-10 m/s ngomzuzwana.

(b) Ibanga noma ukuphakama (h) ngemva kuka-t = imizuzwana emi-3

h = ½ gt² = ½ (10)(3)² = (5)(9) = amamitha angu-45

(c) Isikhathi esidlulile (t) uma v_t = 20m/s

v_t = gt

20 = (10) t

t = 20 / 10 = 2 imizuzwana

[wpdm_package id='511′]

[wpdm_package id='517′]

1. Ibanga kanye nokufuduka
2. Isivinini esimaphakathi kanye nesivinini esimaphakathi
3. Ijubane eliqhubekayo
4. Ukusheshisa okuqhubekayo
5. Ukunyakaza kwamahhala kokuwa
6. Ukunyakaza phansi ekwindla yamahhala
7. Ukunyakaza okuphezulu nokwehlayo ekuwa okukhululekile

Funda kabanzi

Izinkinga Ezixazululiwe Ekuhambeni Okuqondile - Ukusheshisa Okuqhubekayo

1. Imoto ishesha ukusuka ekuphumuleni iye kuma-20 m/s ngemizuzwana eyi-10. Nquma ukusheshisa kwemoto!

Isixazululo

Kwaziwa:

Ijubane lokuqala (v)_o) = 0 (ukuphumula)

Isikhawu sesikhathi (t) = imizuzwana eyi-10

Ijubane lokugcina (v)_t) = 20 m/s

wayefuna Ukusheshisa (a)

Isixazululo:

v_t =v_o + ku-

20 = 0 + (a)(10)

20 = 10 a

a = 20/10

a = 2 m/s²

2. Imoto yehla isuka ku-30 ​​m/s ukuze iphumule ngemizuzwana eyi-10. Nquma ukusheshisa kwemoto.

Isixazululo

Kwaziwa:

Ijubane lokuqala (v)_o) = 30 m/s

Ijubane lokugcina (v)_t= = 0

Isikhawu sesikhathi (t) = imizuzwana eyi-10

Kufunwa: ukusheshisa (a)

Isixazululo:

v_t =v_o + ku-

0 = 30 + (a)(10)

– 30 = 10 a

a = – 30/10

a = -3 m/s²

Uphawu olubi luvela ngoba okokugcina velocity ingaphansi kwejubane lokuqala.

3. Imoto iqala futhi isheshise ngesivinini esingaguquki esingu-4 m/s² in Isekhondi eli-1. Thola ijubane kanye nebanga ngemva kwemizuzwana eyi-10.

Isixazululo

(a) Isivinini

Ukusheshisa 4 m/s² kusho ukwenyuka kwesivinini ngama-4 m/s njalo ngomzuzwana owodwa. Ngemva kwemizuzwana emibili, isivinini semoto singama-8 m/s. Ngemva kwemizuzwana eyi-10, isivinini semoto singama-40 m/s.

(b) Ibanga

Kwaziwa:

Ijubane lokuqala (v)_o= = 0

Ijubane lokugcina (v)_t) = 40 m/s

Ukusheshisa (a) = 4 m/s²

Kufunwa: ibanga

Isixazululo:

s = v_o t + ½ ku² = 0 + ½ (4)(10²) = (2)(100) = amamitha angu-200

4. Imoto ihamba ngesivinini esingaguquki esingu-10 m/s, bese yehla ngesivinini esingaguquki esingu-2 m/s² kuze kube yilapho uphumule. Thola isikhathi esidlulile kanye nemoto ibanga ngaphambi kokuphumula.

Kwaziwa:

Ijubane lokuqala (v)_o) = 10 m/s

Ukusheshisa (a) = -2 m/s² (Isibonakaliso esingesihle sivela ngoba ijubane lokugcina lingaphansi kwejubane lokuqala)

Ijubane lokugcina (v)_t) = 0 (ukuphumula)

Kufunwa: Isikhawu sesikhathi kanye nebanga

Isixazululo:

(a) Isikhawu sesikhathi (t)

v_t =v_o + ku-

0 = 10 + (-2)(t)

0 = 10 – 2 t

10 = 2 t

t = 10 / 2 = 5 imizuzwana

(b) Ibanga

v_t² =v_o² + ama-ekseli ama-2

= 0 10² + 2(-2) s

0 = 100 – 4 imizuzwana

100 = 4 imizuzwana

s = 100 / 4 = amamitha angu-25

5. Imoto ihamba ngesivinini esingu-40 m/s, yehla ngesivinini esingaguquki esingu-4 m/s² kuze kube yilapho uphumule. Thola isivinini kanye nebanga ngemva kokwehlisa ijubane ngemizuzwana eyi-10!

Isixazululo

Kwaziwa:

Ijubane lokuqala (v)_o) = 40 m/s

Ukusheshisa (a) = -4 m/s²

Isikhawu sesikhathi (t) = imizuzwana eyi-10

Kufunwa: ijubane lokugcina (v_t) kanye nebanga (ama)

Isixazululo:

(a) Ijubane lokugcina

v_t =v_o + ku = 40 + (-4)(10) = 40 – 40 = 0 m/s

I-0 m/s isho ukuphumula kwemoto.

(b) Ibanga

s = v_o t + ½ ku² = (40)(10) + ½ (-4)(10²) = 400 + (-2)(100) = 400 – 200 = amamitha angu-200

6. Thola ibanga ngemva kwemizuzwana eyi-10!

Isixazululo

Ibanga: s = vt = (10-0)(5-0) = (10)(5) = amamitha angu-50

7. Thola ibanga ngemva kwemizuzwana eyi-4!

Isixazululo

Ibanga = indawo yesikwele + indawo engunxantathu

Ibanga = (8-0)(8-0) + ½ (16-8)(8-0) = (8)(8) + ½ (8)(8) = 64 + 32 = amamitha angu-96

8. Nquma ibanga lemoto ngemva kwemizuzwana emi-4!

Isixazululo

Ibanga = indawo engunxantathu = ½ (4-0)(8-0) = ½ (4)(8) = amamitha ayi-16

9. Imoto ihamba ngesivinini esingamakhilomitha angama-90 ngehora idlula imoto yamaphoyisa ema eceleni komgwaqo. Ngemva komzuzu owodwa, imoto yamaphoyisa iyajaha at 0.8 m / s². Ukuthi imoto yamaphoyisa ifinyelela kude kangakananies imoto?

Kwaziwa:

Isivinini semoto (v) = 90 km/hora = 90,000 amamitha / 3600 imizuzwana = 25 amamitha/umzuzwana

Isikhawu sesikhathi (t) = umzuzu ongu-1 = imizuzwana engama-60

Ukusheshisa imoto yamaphoyisa (a) = 0.8 m/s²

Isivinini sokuqala semoto yamaphoyisa (v)_o) = 0 m/s

Kufunwa: Ibanga elihanjwe ngemoto yamaphoyisa

Isixazululo:

Imoto ihamba ngesivinini esingaguquki. Ibanga elihanjwa ngemoto:

Ibanga lokuqala:

s = vt = (25)(60) = amamitha angu-1500

Ibanga lokugcina:

s = vt = (25)(t)

Ibanga eliphelele = 1500 + 25 t

Imoto yamaphoyisa ihamba ngesivinini esingaguquki. Ibanga elihanjwa yimoto yamaphoyisa:

s = v_o t + ½ ku² = (0)(t) + ½ (0.8)(t²) = 0 + 0.4 t² = 0.4 t²

Uma imoto yamaphoyisa ifika emotweni, ibanga elihanjwa yimoto yamaphoyisa lifana nebanga elihanjwa yimoto.

Ibanga elihanjiwe ngemoto = ibanga elihanjwe ngemoto yamaphoyisa

1500 + 25 t = 0.4 t²

I-0.4 t² – 25 t – 1500 = 0

Sebenzisa ifomula ye-quadratic:

Ibanga elihanjwe ngemoto yamaphoyisa:

s = 0.4 t² = (0.4)(100²) = (0.4)(10,000) = amamitha angu-4000s = 4 km

10. A car uhamba ngesivinini esingaguquki esingu-24 m/s amabhuleki ukuze abe ukwehla kwejubane okuqhubekayo ka-0.952 m/s². Nquma isivinini semotongemuva kwebanga elingama-250 mama-eter.

Kwaziwa:

Ijubane lokuqala (v)_o) = 24 m/s

ukusheshisa (a) = – 0.952 m/s² (kusayinwe okungekuhle ngoba ukwehla kwejubane)

ibanga (d) = 250 amamithas

Kufunwa: Isivinini semoto ngemuva Imitha ye-250s

Isixazululo:

Okuyaziwayo: isivinini sokuqala (v_o), ukusheshisa (a), ibanga (d), okufunwayo: isivinini sokugcina (v_t) ngakho sebenzisa i-equation ye v_t² =v_o² + 2 kube d

v_t = ijubane lokugcinae_o = ijubane lokuqala, a = ukusheshisa, d = ibanga

v_t² = (24)² + (2)(-0.952)(250)

v_t² = 576 - 476

v_t² = 100

v_t = √100

v_t = 10m/s

[wpdm_package id='507′]

[wpdm_package id='517′]

1. Ibanga kanye nokufuduka
2. Isivinini esimaphakathi kanye nesivinini esimaphakathi
3. Ijubane eliqhubekayo
4. Ukusheshisa okuqhubekayo
5. Ukunyakaza kwamahhala kokuwa
6. Ukunyakaza phansi ekwindla yamahhala
7. Ukunyakaza okuphezulu nokwehlayo ekuwa okukhululekile

Funda kabanzi

Izinkinga Ezixazululiwe Ekuhambeni Okuqondile - Ijubane eliqhubekayo

1. Imoto ihamba ngesivinini esingaguquki esingu-10 m/s. Thola ibanga ngemva kwemizuzwana eyi-10 nemizuzwana engama-60.

Isixazululo

Ijubane elingaguquki elingamamitha ayi-10 ngomzuzwana lisho ukuthi imoto ihamba amamitha ayi-10 njalo ngomzuzwana owodwa.

Ngemva kwemizuzwana emibili, imoto ihambe amamitha angu-20,

Ngemva kwemizuzwana emibili, imoto ihambe amamitha angu-50,

Ngemva kwemizuzwana eyi-10, imoto ihambe amamitha ayi-100,

Ngemva kwemizuzwana eyi-60, imoto ihambe amamitha ayi-600.

2. Imoto ihamba emgwaqweni oqondile ngesivinini esingaguquki esingu-72 km/h. Nquma ibanga lemoto ngemva kwemizuzu emi-2 nemizuzu emi-5.

Isixazululo

72 km/h = (72)(amamitha ayi-1000) / imizuzwana engu-3600 = 72,000 / imizuzwana engu-3600 = amamitha angu-20/umzuzwana.

Ijubane elingaguquki kumamitha angu-20 ngomzuzwana lisho ukuthi imoto ihamba amamitha angu-20 njalo ngomzuzwana owodwa.

Ngemva kwemizuzwana eyi-120 noma imizuzu emi-2, imoto ihamba amamitha angama-20 x 120 = amamitha angama-2400,

Ngemva kwemizuzwana eyi-300 noma imizuzu emi-5, imoto ihamba amamitha angama-20 x 300 = amamitha angama-6000.

3. Umzimba uhamba emgwaqweni oqondile amamitha ayi-100 ngemizuzwana engama-50. Thola isivinini somzimba.

Isixazululo

Amamitha ayi-100 / imizuzwana engama-50 = amamitha ayi-10 / imizuzwana emi-5 = amamitha ama-2/umzuzwana.

4. Thola isivinini ngokwendlela echazwe kumdwebo ongezansi….

Isixazululo

Isivinini = Ibanga / isikhathi esidlulile

Isivinini = amamitha ama-2 / umzuzwana o-1 = amamitha ama-4 / imizuzwana emi-2 = amamitha ayi-6 / imizuzwana emi-3 = amamitha ayi-8 / imizuzwana emi-4 = amamitha ama-2 ngomzuzwana.

5. Izimoto u-A no-B ziyasondelana emigwaqweni ehambisanayo. Uma ibanga eliphakathi kwezimoto ezimbili lingamamitha ayi-100, imoto u-A ihamba ngesivinini esingaguquki esingu-10 m/s, imoto u-B ihamba ngesivinini esingaguquki esingu-40 m/s. Nquma (a) ibanga lemoto u-A ngaphambi kokudlula imoto u-B (b) isikhathi esiphakathi ngaphambi kokudlula imoto u-B.

Isixazululo

Imoto A ihamba ngesivinini esingaguquki kumamitha ayi-10 ngomzuzwana, okusho ukuthi imoto A ihamba amamitha ayi-10 njalo ngomzuzwana. Ngemva kwemizuzwana emi-2, imoto ihamba amamitha angama-20.

Imoto B ihamba ngesivinini esingaguquki kumamitha angu-40 ngomzuzwana, okusho ukuthi imoto B ihamba amamitha angu-40 njalo ngomzuzwana. Ngemva kwemizuzwana emibili, imoto B ihamba amamitha angu-80.

Amamitha angu-20 + amamitha angu-80 = amamitha ayi-100.

(a) Ibanga lemoto A ngaphambi kokudlula imoto B lingamamitha angama-20. Ibanga lemoto B ngaphambi kokudlula imoto A lingamamitha angama-80.

(b) Isikhathi semoto u-B ngaphambi kokudlula imoto u-A singamasekhondi ama-2. Isikhathi semoto u-A ngaphambi kokudlula imoto u-B singamasekhondi ama-2

5. Uma i-speedometer yemoto ikhombisa isivinini esingu-108 km/h, thola ibanga elihanjwa ngemoto ngomzuzu owodwa.

Isixazululo:

I-speedometer iyithuluzi lokukala isivinini. Ijubane lemoto lingu-108 km/ihora.
108 km / h = (108) (amamitha ayi-1000) / imizuzwana engu-3600 = amamitha angu-30 ngomzuzwana.

Umzuzu owodwa = imizuzwana engama-60

Ijubane lemoto elingamamitha angu-30 ngomzuzwana lisho ukuthi imoto ifinyelela kumamitha angu-30 ngomzuzwana owodwa.

Ngemva komzuzwana owodwa, imoto iqhubekela phambili kuze kufike kumamitha angu-1 x 30 = amamitha angu-30.

Ngemva kwemizuzwana emibili, imoto iqhubekela phambili kuze kufike kumamitha angu-2 x 30 = amamitha angu-60.

Ngemva kwemizuzwana emibili, imoto iqhubekela phambili kuze kufike kumamitha angu-60 x 30 = amamitha angu-1800.

6. Tom uphonsa a ibhola liqondile ku-Andrew. UTom no-Andrew bakhona ihlukaniswe kuze kufike ku-10.08 mama-eterIbhola liyaphonswa ovundlile kanye nezinyathelo at 20 m/s (ungawanaki amandla adonsela phansi). Andrew hits ibhola 4.00 x 10^-3 imizuzwana embalwa ngemuva kokuphonswa kwebhola. Uma ibhola umshayi uhamba ngokungaguquki ijubane ngesivinini esingu-5.00 m/s, ibhola lishaywa yi- umshayi emva kwe umshayi udlulela kude…

Kwaziwa:

Ibanga phakathi kukaTom no-Andrew = amamitha ayi-10.08

Isivinini sebhola (v) = 20 m/s

Isikhathi sesikhawu (t) = 4 x 10^-3 imizuzwana = 0.004 imizuzwana

Isivinini somshayi (v) = 5 m / s

Okufunayo: Ibhola lishaywa ngumuntu oshaya ibhola ngemva kokuba ibhola selihambe ibanga elide...

Isixazululo:

Ibanga lebhola:

s₁ = vt = (20)(0.004) = 0.08 amamitha

Ibanga lomshayi:

s₂ = vt = 5 t

Ibanga lebhola + ibanga lomshayi = ibanga phakathi kukaTom no-Andrew.

0.08 + 5 t = 10.08

5 t = 10.08 – 0.08

5 t = 10

t = 10 / 5

t = imizuzwana emi-2

Ibanga lomshayi:

s₂ = vt = 5 t = (5) (2) = amamitha ayi-10

7. Umzingeli onemoto yakhe uxosha inyamazane. Imoto ihamba ngesivinini esingu-72 km/h kanti inyamazane igijima ngesivinini esingu-64.8 km/h. Lapho ibanga phakathi kwemoto nenyamazane lingama-2012 metres, umzingeli udubula isibhamu sakhe. Izinhlamvu ziphuma esibhamuni ngama-200 m/s. Thola isikhathi lapho inyamazane idutshulwa khona.

A. 0.5 imizuzwana

B. 1 imizuzwana

C. 1.25 imizuzwana

D. 1.5 imizuzwana

Kwaziwa:

Isivinini semoto (v)_b) = 72 km/h = (72)(1000 m) / 3600 s = 20 m/s

Isivinini senyamazane (v)_r) = 64.8 km/h = (64.8)(1000 m) / 3600 s = 64800 m / 3600 s = 18 m/s

Uma inhlamvu idutshuliwe, ibanga eliphakathi kwemoto nenyamazane liyancishiswa (s) = amamitha angu-202

Isivinini somlilo (v)_p) = 20 m/s + 200 m/s = 220 m/s

Izikhali ziphethwe ngabazingeli abasemotweni ehamba ngesivinini esingama-20 m/s ukuze isivinini semoto siphinde sengezwe esivinini senhlamvu.

Okufunayo: Nquma isikhathi lapho inyamazane idutshulwa khona

Isixazululo:

Cabanga ngezimoto nezinyamazane ezihamba ngesivinini esingaguquki.

Isibalo: v = s / t noma s = vt

v = isivinini, s = ibanga, t = isikhawu sesikhathi

Ibanga = 202 + X_r = 202 + v_r t = 202 + 18 t

Ibanga = Y_p =v_p t = 220 t

Ibanga elihanjwa yinyamazane = ibanga elihanjwa yinhlamvu

202 + 18 t = 220 t

202 = 220 t – 18 t

202 = 202 t

t = 202 / 202

t = 1 umzuzwana

Impendulo efanele ngu-B.

[wpdm_package id='507′]

[wpdm_package id='517′]

1. Ibanga kanye nokufuduka
2. Isivinini esimaphakathi kanye nesivinini esimaphakathi
3. Ijubane eliqhubekayo
4. Ukusheshisa okuqhubekayo
5. Ukunyakaza kwamahhala kokuwa
6. Ukunyakaza phansi ekwindla yamahhala
7. Ukunyakaza okuphezulu nokwehlayo ekuwa okukhululekile

Funda kabanzi

Izinkinga Ezixazululiwe Ekuhambeni Okuqondile - Isivinini esimaphakathi kanye nesivinini esimaphakathi

1. Imoto ihamba ngomgwaqo oqondile oya empumalanga amamitha ayi-100 ngemizuzwana emi-4, bese iya entshonalanga amamitha angama-50 ngomzuzwana owodwa. Thola isivinini esimaphakathi kanye nesivinini esimaphakathi.

Isixazululo

Ibanga = amamitha ayi-100 + amamitha angama-50 = amamitha ayi-150

displacement = amamitha ayi-100 – amamitha angu-50 = amamitha angu-50, ngasempumalanga.

Isikhathi esidlulile = imizuzwana emi-4 + umzuzwana o-1 = imizuzwana emi-5.

Isivinini esimaphakathi = Ibanga / isikhathi esidlulile = amamitha ayi-150 / imizuzwana emi-5 = amamitha angama-30 ngomzuzwana.

Ijubane elimaphakathi = Ukufuduka / isikhathi esidlulile = amamitha angu-50 / imizuzwana emi-5 = amamitha ayi-10/umzuzwana.

2. Umuntu uhamba amamitha angu-4 empumalanga ngomzuzwana owodwa, bese ehamba amamitha amathathu enyakatho ngomzuzwana owodwa. Thola isivinini esimaphakathi kanye nesivinini esimaphakathi.

Isixazululo

Ibanga = amamitha ayi-4 + amamitha angama-3 = amamitha ayi-7

Ukufuduka = = amamitha, enyakatho-mpumalanga.

Isikhathi esidlulile = umzuzwana o-1 + umzuzwana o-1 = imizuzwana emi-2.

Isivinini esimaphakathi = ibanga / isikhathi esidlulile = amamitha ayi-7 / imizuzwana emi-2 = amamitha ayi-3.5/umzuzwana

Ijubane elimaphakathi = ukufuduka / isikhathi esidlulile = amamitha ama-5 / imizuzwana emi-2 = amamitha angu-2.5/umzuzwana

3. Umgijimi uhambahamba ithrekhi engunxande enobude = amamitha angu-50 nobubanzi = amamitha angu-20. Ngemva kokuhambahamba ithrekhi engunxande kabili, umgijimi ubuyela lapho eqala khona. Uma isikhathi sidlula = imizuzwana eyi-100, nquma isivinini esimaphakathi kanye nesivinini esimaphakathi.

Isixazululo

Ukujikeleza konxande = 2 (amamitha angu-50) + 2 (amamitha angu-20) = amamitha ayi-100 + amamitha angu-40 = amamitha angu-140.

Uhamba nxazonke kwesikwele izikhathi ezimbili = 2 (amamitha ayi-140) = amamitha angama-280.

Ibanga = amamitha angu-280.

Ukufuduka = ​​0 amamitha. (umgijimi obuyela endaweni yokuqala)

Isivinini esimaphakathi = ibanga / isikhathi esidlulile = amamitha angu-280 / imizuzwana eyi-100 = amamitha angu-2.8 ngomzuzwana.

Ijubane elimaphakathi = ukufuduka / isikhathi esidlulile = 0 / imizuzwana eyi-100 = 0.

[wpdm_package id='505′]

[wpdm_package id='517′]

1. Ibanga kanye nokufuduka
2. Isivinini esimaphakathi kanye nesivinini esimaphakathi
3. Ijubane eliqhubekayo
4. Ukusheshisa okuqhubekayo
5. Ukunyakaza kwamahhala kokuwa
6. Ukunyakaza phansi ekwindla yamahhala
7. Ukunyakaza okuphezulu nokwehlayo ekuwa okukhululekile

Funda kabanzi

Izinkinga ezixazululiwe kuma-vector - umphumela wamavekhtha amabili kusetshenziswa izingxenye zevekhtha

I-1. F₁ = 6 N, F₂ = 10 N. Thola i-vector ephumela.

Isixazululo

F_1x =F₁ ibe 60^o = (6)(0.5) = 3 N (okuhle ngoba kunesiqondiso esifanayo ne-x axis)

F_2x =F₂ ibe 30^o = (10)(0.5√3) = 5√3 = (5)(1.372) = -8.66 N (engemihle ngoba inesiqondiso esifanayo ne-axis -x)

F_1y =F₁ ngaphandle 60^o = (6)(0.5√3) = 3√3 = (3)(1.372) = 4.116 N (okuhle ngoba kunesiqondiso esifanayo ne-y axis)

F_2y =F₂ ngaphandle 30^o = (10)(0.5) = -5 N (negative ngoba inesiqondiso esifanayo ne-axis -y)

F_x =F_1x - F_2x = 3 – 8.66 = -5.66 N

F_y =F_1y - F_2y = 4.116 – 5 = -0.884 N

 

Umphumela wala mandla amabili u-5.7 N.

I-2. F₁ = 4 N, F₂ = 4 N, F₃ = 8 N. Thola i-vector ephumela.

Isixazululo

F_1x =F₁ ibe 60^o = (4)(0.5) = 2 N (okuhle ngoba kunesiqondiso esifanayo ne-x axis)

F_2x = -4 N (negative ngoba inesiqondiso esifanayo ne-axis -x)

F_3x =F₃ ibe 60^o = (8)(0.5) = 4 N (okuhle ngoba kunesiqondiso esifanayo ne-x axis)

F_1y =F₁ ngaphandle 60^o = (4)(0.5√3) = 2√3 N (okuhle ngoba kunesiqondiso esifanayo ne-y axis)

F_2y = 0

F_3y =F₃ ngaphandle 60^o = (8)(0.5√3) = -4√3 N (okubi) ngoba inesiqondiso esifanayo ne-axis -y)

F_x =F_1x - F_2x +F_3x = 2 – 4 + 4 = 2 N

F_y =F_1y +F_2y - F_3y = 2√3 + 0 - 4√3 = -2√I-3 N

Umphumela wala mandla amathathu ngu-5.7 N.

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Nquma umphumela we-vector yomugqa
2. Nquma izingxenye zevektha
3. Thola umphumela wamavektha amabili usebenzisa i-Pythagorean theorem
4. Nquma umphumela wamavektha amabili usebenzisa i-cosine equation
5. Nquma umphumela wamavektha amabili usebenzisa izingxenye zamavektha

Funda kabanzi

Izinkinga ezixazululiwe kuma-vector - nquma umphumela wamavektha amabili usebenzisa i-cosine equation

I-1. F₁ = 10 N kanye no-F₂ = 20 N. Thola i-vector ephumela.

I-2. A₁ = 15 kanye no-A₂ = 9. I-engeli phakathi kwamavektha amabili ingu-60^o. Nquma i-vector ephumela.

Isixazululo

3. ku₁ = 5 kanye no-v₂ = 12. I-engeli phakathi kwamavektha amabili ingu-90^o. Nquma i-vector ephumela.

Isixazululo

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Nquma umphumela we-vector yomugqa
2. Nquma izingxenye zevektha
3. Thola umphumela wamavektha amabili usebenzisa i-Pythagorean theorem
4. Nquma umphumela wamavektha amabili usebenzisa i-cosine equation
5. Nquma umphumela wamavektha amabili usebenzisa izingxenye zamavektha

Funda kabanzi

Izinkinga ezixazululiwe kuma-vector - thola umphumela wamavektha amabili usebenzisa i-Pythagorean theorem

1. Thola umphumela walokhu okubili Ukuhambisa ama-vector njengoba kuboniswe esithombeni esingezansi.

I-2. Thola umphumela wamandla amabili, 12 N kanye no-5 N.

3. Umfundi uhamba amamitha angu-4 entshonalanga, bese kuba amamitha angu-6 enyakatho kanye namamitha angu-4 entshonalanga. Thola indawo umfundi afudukele kuyo.

Isixazululo

Ukufuduka kungama-10 minater, enyakatho-ntshonalanga.

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Nquma umphumela we-vector yomugqa
2. Nquma izingxenye zevektha
3. Thola umphumela wamavektha amabili usebenzisa i-Pythagorean theorem
4. Nquma umphumela wamavektha amabili usebenzisa i-cosine equation
5. Nquma umphumela wamavektha amabili usebenzisa izingxenye zamavektha

Funda kabanzi

Izinkinga ezixazululiwe kuma-vector - nquma izingxenye zevektha

1. Amandla angama-20 amaNewton enza i-engeli engama-30^o nge-x-axis. Thola zombili izingxenye zika-x no-y zamandla.

Isixazululo

F_x = F cos 30^o = (20)(cos 30^o) = (20)(0.5√3= = 10√3 Newton

F_y = Isono sika-F 30^o = (20)(isono 30^o) = (20)(0.5) = 10 Newton

I-2. F₁ = 20 AmaNewton enza i-engeli engu-30^o nge-axis ka-y kanye no-F₂ = 30 AmaNewton enza i-engeli engu-60^o nge-axis ka--x. Thola zombili izingxenye zika-x no-y zika-F₁ noF₂.

Isixazululo

F_1x =F₁ cos 60^o = (20)(cos 60^o) = (20)(0.5) = -10 AmaNewton (angu-negative ngoba anesiqondiso esifanayo ne-axis -x)

F_2x =F₂ cos 60^o = (30)(cos 60^o) = (30)(0.5) = -15 AmaNewton (angu-negative ngoba anesiqondiso esifanayo ne-axis -x)

F_1y =F₁ Isono 60^o = (20)(isono 60^o) = (20)(0.5√3= = 10√3 I-Newton (enhle ngoba inesiqondiso esifanayo ne-axis y)

F_2y =F₂ Isono 60^o = (30)(isono 60^o) = (30)(0.5√3) = -15√3 I-Newton (engemihle ngoba inesiqondiso esifanayo ne-axis -y)

I-3. F₁ = 2 N, F₂ = 4 N, F₃ = 6 N. Thola zombili izingxenye zika-x no-y zika-F₁, F₂ noF₃!

Isixazululo

F_1x =F₁ cos 60^o = (2)(cos 60^o) = (2)(0.5) = 1 Newton (enhle ngoba inesiqondiso esifanayo ne-x axis)

F_2x =F₂ cos 30^o = (4)(cos 30^o) = (4)(0.5√3) = -2√3 I-Newton (engemihle ngoba inesiqondiso esifanayo ne-axis -x)

F_3x =F₃ cos 60^o = (6)(cos 60^o) = (6)(0.5) = 3 Newton (enhle ngoba inesiqondiso esifanayo ne-x axis)

F_1y =F₁ Isono 60^o = (2)(isono 60^o) = (2)(0.5√3) = √3 I-Newton (enhle ngoba inesiqondiso esifanayo ne-axis y)

F_2y =F₂ ngaphandle 30^o = (4)(isono 30^o) = (4)(0.5) = 2 amaNewton (aqondile ngoba anesiqondiso esifanayo ne-y axis)

F_3y =F₃ Isono 60^o = (6)(isono 60^o) = (6)(0.5√3) = -3√3 I-Newton (engemihle ngoba inesiqondiso esifanayo ne-axis -y)

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Nquma umphumela we-vector yomugqa
2. Nquma izingxenye zevektha
3. Thola umphumela wamavektha amabili usebenzisa i-Pythagorean theorem
4. Nquma umphumela wamavektha amabili usebenzisa i-cosine equation
5. Nquma umphumela wamavektha amabili usebenzisa izingxenye zamavektha

Funda kabanzi

Izinkinga ezixazululiwe kuma-vector - umphumela we-vector yomugqa

1. Umfundi uhamba enyakatho aze afike kumamitha ayi-10 bese eya eningizimu aze afike kumamitha amane. Ukufuduka komfundi…

Isixazululo

R = 10 m – 4 m = 6 amamitha

Ubukhulu be Ukuhambisa ingamamitha ayi-6, indlela yokufuduka isenyakatho.

I-2. F₁ = 10 N, F₂ = 15 N. Thola i-vector ephumela…

Isixazululo

R = 10 N + 15 N = 25 Newton

Ubukhulu bevektha ephumelayo bungama-Newton angu-25, isiqondiso sevektha ephumelayo sibheke empumalanga noma kwesokudla.

I-3. F₁ = 4 N, F₂ = 8 N. Thola i-vector ephumela…

Isixazululo

R = 8 N – 4 N = 4 Newton

Ubukhulu bevektha ephumelayo bungama-Newton angu-4, isiqondiso sevektha ephumelayo sibheke empumalanga noma kwesokudla.

I-4. F₁ = 10, F₂ = 15 N, F₃ = 5 N. Thola i-vector ephumela…

Isixazululo

R = 10 N + 5 N – 15 N = 0

Ubukhulu bevektha ephumelayo ngu-0.

[wpdm_package id='542′]

[wpdm_package id='554′]

1. Nquma umphumela we-vector yomugqa
2. Nquma izingxenye zevektha
3. Thola umphumela wamavektha amabili usebenzisa i-Pythagorean theorem
4. Nquma umphumela wamavektha amabili usebenzisa i-cosine equation
5. Nquma umphumela wamavektha amabili usebenzisa izingxenye zamavektha

Funda kabanzi