I-physics

1. Ibhola elikhahlelwe lishiya phansi nge-engeli θ = 30^o kuya ngokuvundlile ngesivinini sokuqala esingu-14 m/s. Bala ijubane lokugcina ngaphambi kokuba ibhola lishaye phansi.

Kwaziwa:

I-engela (θ= = 30^o

Ijubane lokuqala (v_o) = 14 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m / s²

Kufunwa: Ijubane lokugcina ngaphambi kokuba ibhola lishaye phansi

Isixazululo:

Ingxenye evundlile yejubane lokuqala:

v_ox =v_o cos θ = (14 m/s)(cos 30^o) = (14 m/s)(0.5√3= = 7√3 m / s

Ingxenye eqondile yejubane lokuqala:

v_oy =v_o isono θ = (14 m/s)(isono 30^o) = (14 m/s)(0.5) = 7 m/s

Ijubane lokugcina esiqondisweni esiqondile

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ijubane lokuqala (v)_o) = 7 m/s (ukuphakama okuhle)

Ukusheshisa kwamandla adonsela phansi (g) = –10 m / s² (ukwehla okungekuhle)

Ukuphakama (h) = 0 (into ibuyele endaweni yokuqala)

Kufunwa: Ijubane lokugcina (v)_t)

Isixazululo:

v_t² =v_o² + 2 gh = 7² + 2(-10)(0) = 49 – 0 = 49

v_t = √49 = 7 m/s

Ijubane lokugcina endaweni evundlile

Ijubane lokuqala endaweni evundlile lingu 7√3 m/s. Ijubane lihlala linjalo ukuze ijubane lokugcina lifane nejubane lokuqala.

Ijubane lokugcina ngaphambi kokuba into ishaye phansi

2. Umzimba uphakanyiswa phezulu nge-engeli engu-30^o nge-horizontal kusuka esakhiweni esingamamitha ama-5 ukuphakama. Isivinini sayo sokuqala singamamitha ayi-10/s. Bala ijubane lokugcina ngaphambi kokuba into ishaye phansi! Ukusheshisa kwamandla adonsela phansi kungu-10 m/s².

Kwaziwa:

I-engela (θ= = 30^o

Ukuphakama kokuqala (h)_o) = amamitha angu-5

Ijubane lokuqala (v)_o) = 10 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Ijubane lokugcina

Isixazululo:

Ingxenye evundlile yejubane lokuqala:

v_ox =v_o cos θ = (10 m/s)(cos 30^o) = (10 m/s)(0.5√3= = 5√3 m / s

Ingxenye eqondile yejubane lokuqala:

v_oy =v_o isono θ = (10 m/s)(isono 30^o) = (10 m/s)(0.5) = 5 m/s

Ijubane lokugcina esiqondisweni esiqondile

Kwaziwa:

Ijubane lokuqala (v)_o) = 5 m/s (ukuphakama okuhle)

ukusheshisa amandla adonsela phansi (g) = –10 m / s² (ukwehla okungekuhle)

Ukuphakama (h) = -5 m (okungekuhle ngoba umhlabathi ungaphansi kokuphakama kokuqala)

Kufunwa: Ijubane lokugcina (v)_t)

Isixazululo:

v_t² =v_o² + 2 gh = 5² + 2(-10)(-5) = 25 + 100 = 125

v_t = √125 m/s

Ijubane lokugcina endaweni evundlile

Ijubane lokugcina ohlangothini oluvundlile lingu 5.3 m/s.

Ijubane lokugcina

3. Ibhola elincane elivela ngokuvundlile ngejubane lokuqala u-v_o = 8 m/s ukusuka esakhiweni esingamamitha ayi-12 ukuphakama. Bala ijubane lokugcina ngaphambi kokuba ibhola lishaye phansiUkusheshisa kwamandla adonsela phansi kungu-10 m/s²

Kwaziwa:

Ukuphakama (h) = amamitha angu-12

Ijubane lokuqala (v)_o) = 8 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Ijubane lokugcina (v)_t)

Isixazululo:

Ingxenye evundlile yejubane lokuqala:

v_ox =v_o = 8m/s

Ingxenye eqondile yejubane lokuqala:

v_oy = 0m/s

Ijubane lokugcina esiqondisweni esiqondile

kubalwe kusetshenziswa i-equation ka ukunyakaza kokuwa kwamahhala.

Kwaziwa:

Ukusheshisa kwamandla adonsela phansi (g) = 10 m / s²

Ukuphakama (h) = 12 m

Kufunwa: Ijubane lokugcina (v)_t)

Isixazululo:

v_t² = 2 gh = 2(10)(12) = 240

v_t = √240 m/s

Ijubane lokugcina endaweni evundlile

Ijubane lokuqala ohlangothini oluvundlile lingu-8 m/s. Ijubane aliguquguquki ukuze ijubane lokuqala lilingane nejubane lokugcina. Ngakho ijubane lokugcina ohlangothini oluvundlile lingu-8 m/s.

Ijubane lokugcina

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1. Xazulula ijubane lokuqala libe izingxenye ezivundlile neziqondile
2. Nquma ukufuduka okuvundlile
3. Nquma ukuphakama okuphezulu
4. Nquma isikhathi esinqunyiwe
5. Nquma indawo yento
6. Nquma ijubane lokugcina

Funda kabanzi

Izinkinga ezixazululiwe ekunyakazeni okuqoshwe nge-projectile - nquma indawo yento

1. Umzimba uphakanyiswa phezulu nge-engeli engu-60^o kuya i-horizontal enejubane lokuqala elingu-12 m/s. Thola indawo yento ngemva kokuhamba umzuzwana owodwa! Ukusheshisa kwamandla adonsela phansi ingu-10 m/s².

Kwaziwa:

I-engela (θ) = 60^o

Okokuqala velocity (v_o) = 12 m/s

Isikhawu sesikhathi (t) = umzuzwana o-1

Ukusheshisa kwamandla adonsela phansi (g) = 10 m / s²

Kufunwa: Indawo yento ngemva kokuhamba umzuzwana owodwa

Isixazululo:

Ingxenye evundlile yejubane lokuqala:

v_ox =v_o cos θ = (12 m/s)(cos 60^o) = (12 m/s)(0.5) = 6 m/s

Ingxenye eqondile yejubane lokuqala:

v_oy =v_o isono θ = (12 m/s)(isono 60^o) = (12 m/s)(0.5√3= = 6√3 m / s

Indawo yento endaweni evundlile:

Kwaziwa:

Ingxenye evundlile yejubane (v)_x) = 6 m/s

Isikhawu sesikhathi (t) = umzuzwana o-1

Kufunwa: ububanzi obuvundlile (x)

Isixazululo:

Amamitha ayi-6/umzuzwana kusho ukuthi ibhola lihamba lize lifike kumamitha ayi-6 njalo ngomzuzwana owodwa. Ibanga lebhola ngemva kokuhamba umzuzwana owodwa lingamamitha ayi-6. Ngakho-ke indawo yebhola ohlangothini oluvundlile ingamamitha ayi-6.

Indawo yento esiqondisweni esiqondile:

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ijubane lokuqala (v)_o) = 6√3 m/s (okuphezulu okuhle)

Isikhawu sesikhathi (t) = umzuzwana o-1

Ukusheshisa kwamandla adonsela phansi (g) = -10 m/s² (ukwehla okungekuhle)

Kufunwa: ukuphakama ngemva kokuhamba umzuzwana owodwa

Isixazululo:

h = v_o t + 1/2 gt² = ((6√3(1) + 1/2 (-10)(1²) = 6√3 + (-5)(1) = 6√3 – 5 = 6(1.7) – 5 = 10.2 – 5 = 5.2 amamitha.

Indawo yento ngemva kokuhamba isekhondi eli-1:

Ukuhamba okuvundlile (x) = amamitha ayi-6

Ukuhamba okuqondile (y) = amamitha angu-5.2

2. Umzimba uphakanyiswa phezulu nge-engeli engu-30^o kuya i-horizontal ukusuka esakhiweni esingamamitha angu-20 ukuphakama. Ijubane layo lokuqala lingu-50 m/s. Bala ukufuduka okuqondile ngemva kokuba umzimba unyakaze umzuzwana owodwa! Ukusheshisa kwamandla adonsela phansi kungu-10 m/s².

Kwaziwa:

I-engela (θ) = 30^o

Ukuphakama kokuqala (h)_o) = amamitha angu-20

Ijubane lokuqala (v)_o) = 50 m / s

Isikhawu sesikhathi (t) = umzuzwana o-1

Ukusheshisa kwamandla adonsela phansi (g) = 10 m / s²

Kufunwa: Ubude (h)

Isixazululo:

Ingxenye eqondile yejubane lokuqala:

v_oy =v_o isono θ = (50 m/s)(isono 30^o) = (50 m/s)(0.5) = 25 m / s

Ukuphakama:

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ijubane lokuqala (v)_o) = 25 m/s (okuphezulu okuhle)

Isikhawu sesikhathi (t) = umzuzwana o-1

Ukusheshisa kwamandla adonsela phansi (g) = -10 m / s² (ukwehla okungekuhle)

Kufunwa: Ubude (h)

Isixazululo:

h = v_o t + 1/2 gt² = (25)(1) + 1/2 (-10)(1)²) = 25 + (-5)(1) = 25 – 5 = amamitha angu-20.

Ukuphakama komzimba ngemva kokuhamba umzuzwana owodwa kungamamitha angama-20 ngaphezu kwalapho umzimba ukhona kuhlelwe noma amamitha angu-40 ngaphezu komhlabathi.

3. Ibhola elincane elivela ngokuvundlile ngejubane lokuqala u-v_o = 10 m/s ukusuka esakhiweni esingamamitha ayi-10 ukuphakama. Bala ukufuduka kwebhola ngemva kokuhamba umzuzwana owodwaUkusheshisa kwamandla adonsela phansi kungu-10 m/s²

Kwaziwa:

Ukuphakama kokuqala (h) = amamitha ayi-10

Ijubane lokuqala (v)_o) = 10 m/s

Isikhawu sesikhathi (t) = umzuzwana o-1

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Okufunayo: Indawo yebhola ngemva kokuhamba umzuzwana owodwa!

Isixazululo:

Ukufuduka okuvundlile:

Kwaziwa:

Ingxenye evundlile yejubane (v)_x) = 10 m/s

Isikhawu sesikhathi (t) = umzuzwana o-1

Okufunayo: Indawo yento

Isixazululo:

Amamitha ayi-10/umzuzwana kusho ukuthi into ihamba ibanga elingamamitha ayi-10 njalo ngomzuzwana owodwa. displacement Ngemva kokuhamba umzuzwana owodwa, kuba amamitha ayi-10. Ngakho-ke ukufuduka okuvundlile kungamamitha ayi-10.

Ukufuduka okuqondile:

Kubalwa njenge ukunyakaza kokuwa kwamahhala.

Kwaziwa:

Isikhawu sesikhathi (t) = umzuzwana o-1

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Ukuphakama ngemva kokuhamba umzuzwana owodwa (h)

Isixazululo:

h = 1/2 gt² = 1/2 (10)(1²) = (5)(1) = amamitha ama-5.

Ngemva komzuzwana owodwa, into iwela amamitha angu-5. Ukuphakama ngaphezu komhlabathi = amamitha ayi-10 - amamitha angu-5 = amamitha angu-5.

Indawo yento ngemva kokuhamba umzuzwana owodwa:

Indawo yento ku- isiqondiso esivundlile (x) = amamitha ayi-10

Indawo yento eqonde ngqo (y) = amamitha angu-5

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1. Xazulula ijubane lokuqala libe izingxenye ezivundlile neziqondile
2. Nquma ukufuduka okuvundlile
3. Nquma ukuphakama okuphezulu
4. Nquma isikhathi esinqunyiwe
5. Nquma indawo yento
6. Nquma ijubane lokugcina

Funda kabanzi

Izinkinga ezixazululiwe ekunyakazeni okuqoshwe nge-projectile - nquma isikhathi esinqunyiwe

1. Ibhola elikhahlelwe lishiya phansi nge-engeli θ = 30^o kuya ngokuvundlile ngesivinini sokuqala esingu-10 m/s. Bala isikhathi sokuphumula ukuze ufinyelele ukuphakama okuphezulu! Ukusheshisa kwamandla adonsela phansi ingu-10 m/s².

Kwaziwa:

I-engeli (θ) = 30^o

Ijubane lokuqala (v)_o) = 10 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Isikhathi sokufinyelela ku- ukuphakama okuphezulu

Isixazululo:

Ingxenye eqondile yejubane lokuqala:

v_oy =v_o isono θ = (10 m/s)(isono 30^o) = (10 m/s)(0.5) = 5 m / s

Isikhathi sokufinyelela ukuphakama okuphezulu sinqunywa yi- ukunyakaza okuqondile Khetha isiqondiso esibheke phezulu njengesihle kanye nesiqondiso esibheke phansi njengesibi.

Kwaziwa:

Ijubane lokuqala (v)_o) = 5 m / s (okuqondile phezulu)

Ukusheshisa kwamandla adonsela phansi (g) = –10 m / s² (ukwehla okungekuhle)

Ijubane lokugcina ekuphakameni okuphezulu (v)_t= = 0

Kufunwa: isikhawu sesikhathi (t)

Isixazululo:

v_t =v_o + gt

0 = 5 + (-10)t

0 = 5 – 10 t

5 = 10 t

t = 5/10 = 0.5 imizuzwana

2. Umzimba uphakanyiswa phezulu nge-engeli engu-30^o kuya ijubane lokuqala elingu-30 m/s. Bala isikhathi sokundiza! Ukusheshisa kwamandla adonsela phansi kungu-10 m/s².

Kwaziwa:

I-engeli (θ) = 30^o

Ijubane lokuqala (v)_o) = 8 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m / s²

Kufunwa: Isikhathi esinqunyiwe ngaphambi kokuba umzimba ushaye phansi

Isixazululo:

Ingxenye eqondile yejubane lokuqala:

v_oy =v_o isono θ = (8 m/s)(isono 30^o) = (8 m/s)(0.5) = 4 m / s

Siqala ngokubala isikhathi esiphakathi ukuze sifinyelele ukuphakama okuphezulu sisebenzisa i-equation yokunyakaza okuqondile.

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ijubane lokuqala (v)_o) = 4 m / s (okuqondile phezulu)

Ukusheshisa kwamandla adonsela phansi (g) = –10 m / s² (ukwehla okungekuhle)

Ijubane lokugcina ekuphakameni okuphezulu (v_t= = 0

Kufunwa: Isikhawu sesikhathi (t)

Isixazululo:

v_t =v_o + gt

0 = 4 + (-10)t

0 = 4 – 10 t

4 = 10 t

t = 4/10 = 0,4 imizuzwana

Isikhathi sokufinyelela ukuphakama okuphezulu singamasekhondi angu-0.4.

Isikhathi emoyeni singamasekhondi angu-2 x 0.4 = 0.8.

3. Umzimba uphakanyiswa phezulu nge-engeli engu-30^o ngesakhiwo esivundlile esingamamitha ayi-10 ukuphakama. Ijubane laso lokuqala lingu-40 m/s. Kuthatha isikhathi esingakanani umzimba ukufika phansi? Ukusheshisa amandla adonsela phansi kungu-10 m/s².

Kwaziwa:

I-engeli (θ) = 30^o

Ukuphakama kokuqala (h)_o) = amamitha angu-10

Ijubane lokuqala (v)_o) = 40 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m / s²

Kufunwa: Isikhathi emoyeni (t)

Isixazululo:

Ingxenye eqondile yejubane lokuqala:

v_oy =v_o isono θ = (40 m/s)(isono 30^o) = (40 m/s)(0.5) = 20 m / s

Siqala ngokubala isikhathi esiphakathi ukuze sifinyelele ukuphakama okuphezulu sisebenzisa i-equation yokunyakaza okuqondile.

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ijubane lokuqala (v)_o) = 20 m / s (okuqondile phezulu)

Ukusheshisa kwamandla adonsela phansi (g) = –10 m / s² (ukwehla okungekuhle)

Ijubane lokugcina esicongweni (v)_t= = 0

Kufunwa: Isikhawu sesikhathi (t)

Isixazululo:

v_t =v_o + gt

0 = 20 + (-10)t

0 = 20 – 10 t

20 = 10 t

t = 20/10 = imizuzwana emi-2

Isikhathi emoyeni = 2 x 2 imizuzwana = 4 imizuzwana.

Into ingamamitha ayi-10 ngaphezu komhlabathi. Imizuzwana emi-4 yisikhathi sokufinyelela endaweni ehambisana nendawo yokuqala. Ibhola lisahamba liye phansi.

Isikhathi sokufinyelela phansi sibalwa kusetshenziswa i-equation ka ukunyakaza kokuwa kwamahhala. 

Kwaziwa:

Ukusheshisa kwamandla adonsela phansi (g) = 10 m / s²

Ukuphakama (h) = amamitha ayi-10

Kufunwa: Isikhawu sesikhathi (t)

Isixazululo:

h = 1/2 gt²

10 = 1/2 (10) t²

10 = 5 t²

t² = 10/5 = 2

t = √2 = 1.4 imizuzwana

Isikhawu sesikhathi = imizuzwana eyi-1.4.

Isikhawu sesikhathi esiphelele = imizuzwana emi-4 + imizuzwana eyi-1.4 = imizuzwana emi-5.4.

4. Ibhola elincane elivela ngokuvundlile ngejubane lokuqala u-v_o = 15 m/s ukusuka esakhiweni esingamamitha ama-5 ukuphakama. Bala isikhathi emoyeniUkusheshisa kwamandla adonsela phansi kungu-10 m/s²

Kwaziwa:

Ukuphakama (h) = amamitha ayi-5

Ijubane lokuqala (v)_o) = 15 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Okufunayo: Isikhathi emoyeni (t)

Isixazululo:

Isikhathi emoyeni sibalwa kusetshenziswa isibalo sokunyakaza okuwa ngokukhululeka.

Kwaziwa:

Ukuphakama (h) = amamitha ayi-5

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Isikhawu sesikhathi (t)

Isixazululo:

h = 1/2 gt²

5 = 1/2 (10) t²

5 = 5 t²

t² = 5/5 = 1

t = √1 = 1 umzuzwana

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1. Xazulula ijubane lokuqala libe izingxenye ezivundlile neziqondile
2. Nquma ukufuduka okuvundlile
3. Nquma ukuphakama okuphezulu
4. Nquma isikhathi esinqunyiwe
5. Nquma indawo yezinto
6. Nquma ijubane lokugcina

Funda kabanzi

Izinkinga ezixazululiwe ekunyakazeni okuqoshwe nge-projectile - nquma ukuphakama okuphezulu

1. Ibhola elikhahlelwe lishiya phansi nge-engeli θ = 60^o nge-horizontal inejubane lokuqala elingu-10 m/s. Bala ukuphakama okuphezulu! Ukusheshisa kwamandla adonsela phansi ingu-10 m/s².

Kwaziwa:

I-engeli (θ) = 60^o

Isivinini sokuqala (v)_o) = 10 m/s

Kufunwa: Ukuphakama okuphezulu (h)

Isixazululo:

Ingxenye eqondile yejubane lokuqala:

ngaphandle 60^o =v_oy /v_o

v_oy =v_o ngaphandle 60^o = (10)(isono 60^o) = (10)(0.5√3= = 5√3 m / s

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ukusheshisa kwamandla adonsela phansi (g) = -10 m/s² (ukwehla okungekuhle)

Ingxenye eqondile yejubane lokuqala (v)_oy) = +5√3 m / s (okuqondile phezulu)

Ijubane lokugcina ekuphakameni okuphezulu (v_ty= = 0

Kufunwa: Ukuphakama okuphezulu (h)

Isixazululo:

v_t² =v_o² + 2 gh

0² = (5√3)² + 2 (-10) amahora

0 = 25(3) – amahora ayi-20

0 = 75 – amahora ayi-20

75 = 20 pm

h = 75/20

h = amamitha angu-3.75

Ukuphakama okuphezulu kungamamitha angu-3.75.

2. Umzimba uphakanyiswa phezulu nge-engeli engu-30^o nge-horizontal kusuka esakhiweni esingamamitha angu-20 ukuphakama. Isivinini sayo sokuqala singamamitha angu-4/s. Bala ukuphakama okuphezulu! Ukusheshisa kwamandla adonsela phansi kungu-10 m/s².

Kwaziwa:

I-engeli (θ) = 30^o

Ukuphakama kokuqala (h) = amamitha angu-20

Ijubane lokuqala (v_o) = 4 m/s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Ukuphakama okuphezulu (h)

Isixazululo:

Ingxenye eqondile yejubane lokuqala:

ngaphandle 30^o =v_oy /v_o

v_oy =v_o ngaphandle 30^o = (4)(isono 30^o) = (4)(0.5) = 2 m / s

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ukusheshisa kwamandla adonsela phansi (g) = -10 m/s² (ukwehla okungekuhle)

Ingxenye eqondile yejubane lokuqala (v)_oy) = +2 m / s (okuqondile phezulu)

Ijubane lokugcina ekuphakameni okuphezulu (v)_ty= = 0

Kufunwa: Ukuphakama okuphezulu

Isixazululo:

Ukuphakama okuphezulu:

v_t² =v_o² + 2 gh

0² = 2² + 2 (-10) amahora

0 = 4 – amahora ayi-20

I-4 = 20 pm

h = 4/20

h = amamitha angu-0.2

Ukuphakama okuphezulu kakhulu kungamamitha angu-0.2 + amamitha angu-20 = amamitha angu-20.2.

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1. Xazulula ijubane lokuqala libe izingxenye ezivundlile neziqondile
2. Nquma ukufuduka okuvundlile
3. Nquma ukuphakama okuphezulu
4. Nquma isikhathi esinqunyiwe
5. Nquma indawo yezinto
6. Nquma ijubane lokugcina

Funda kabanzi

Izinkinga ezixazululiwe ekunyakazeni okuqoshwe nge-projectile - nquma ukufuduka okuvundlile

1. Ibhola elikhahlelwe lishiya phansi nge-engeli θ = 60^o Uma ibhola livundlile, ijubane lokuqala lingu-16 m/s. Kuzoba isikhathi esingakanani ngaphambi kokuba ibhola lishaye phansi?

Kwaziwa:

I-engela (θ) = 60^o

Isivinini sokuqala (v)_o) = 16 m / s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: Ukufuduka okuvundlile (x)

Isixazululo:

Ingxenye evundlile yejubane lokuqala:

v_ox =v_o cos θ = (16 m/s)(cos 60^o) = (16 m/s)(0.5) = 8 m / s

Ingxenye eqondile yejubane lokuqala:

v_oy =v_o isono θ = (16 m/s)(isono 60^o) = (16 m/s)(0.5√3= = 8√3 m / s

projectile-motion kungaqondwa ngokuhlaziya izingxenye ezivundlile neziqondile zokunyakaza ngokwehlukana. Ukunyakaza kuka-x kwenzeka ngesivinini esingaguquki kanti ukunyakaza kuka-y kwenzeka ngokusheshisa okungaguquki kwamandla adonsela phansi.

Isikhathi emoyeni

Isikhathi esihlala emoyeni sinqunywa ukunyakaza kuka-y. Siqala ngokuthola isikhathi sisebenzisa ukunyakaza kuka-y bese sisebenzisa leli nani lesikhathi kuzibalo zika-x (ijubane elingaguquki isibalo).

Khetha indlela eya phezulu njengeyakhayo kanye nendlela eya phansi njengeyakhayo.

Kwaziwa:

Ijubane lokuqala (v)_o) = 8√3 m / s (v_o phezulu)

Ukusheshisa kwamandla adonsela phansi (g) = -10 m/s² (g phansi)

Ukuphakama (h) = 0 (ibhola libuyele endaweni efanayo)

Kufunwa: Isikhathi emoyeni

Isixazululo:

h = v_o t + 1/2 gt²

0 = (8√3) t + 1/2 (-10) t²

I-0 = 8√3 t – 5 t²

8√3 t = 5 t²

8 (1.7) = 5 t

14 = 5 t

t = 14 / 5 = imizuzwana engu-2.8

Ukufuduka okuvundlile

Kwaziwa:

Velocity (v) = 8 m/s

Isikhawu sesikhathi (t) = imizuzwana eyi-2.8

Kufunwa: displacement

Isixazululo:

x = vt = (8 m/s)(2.8 s) = 22.4 amamitha

Ukufuduka okuvundlile kungamamitha angu-22.4.

2. Umzimba uphakanyiswa phezulu nge-engeli engu-60^o nge-horizontal kusuka esakhiweni esingamamitha angu-50 ukuphakama. Isivinini sayo sokuqala singama-30 m/s. Bala ukufuduka okuvundlile! Ukusheshisa kwamandla adonsela phansi kungu-10 m/s².

Kwaziwa:

I-engela (θ) = 60^o

Ukuphakama (h) = 15 m

Isivinini sokuqala (v)_o= = 30 m / s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: x

Isixazululo:

Ingxenye evundlile yejubane lokuqala ::

v_ox =v_o cos θ = (30 m/s)(cos 60^o) = (30 m/s)(0.5) = 15 m/s

Ingxenye eqondile yejubane lokuqala:

v_oy =v_o isono θ = (30 m/s)(isono 60^o) = (30 m/s)(0.5√3= = 15√3 m / s

Isikhathi emoyeni

Siqala ngokuthola isikhathi sisebenzisa ukunyakaza kuka-y bese sisebenzisa leli nani lesikhathi kuzibalo zika-x (isilinganiso sejubane eliqhubekayo). Khetha phezulu njengehle kanye nephansi njengehle.

Kwaziwa:

Ijubane lokuqala (v)_o) = 15√3 m / s (okuqondile phezulu)

Ukusheshisa kwamandla adonsela phansi (g) = -10 m/s² (ukwehla okungekuhle)

Ukuphakama (h) = -50 (Umhlaba ngamamitha angu-50 ngaphansi kwendawo yokuqala)

Kufunwa: t

Isixazululo:

h = v_o t + 1/2 gt²

-50 = (15√3) t + 1/2 (-10) t²

-50 = 15√3 t – 5 t²

I-5 t² - 15√3 t – 50 = 0

Bala isikhathi usebenzisa le fomula:

a = 5, b = –15√3, c = –50

Isikhathi emoyeni singamasekhondi angu-6.7.

Ukufuduka okuvundlile:

Kwaziwa:

Ijubane (v) = 15 m/s

Isikhawu sesikhathi (t) = imizuzwana eyi-6.7

Kufunwa: Ukuhambisa

Isixazululo:

s = vt = (15 m/s)(6.7 s) = amamitha ayi-100.5

Ukufuduka okuvundlile kungamamitha angu-100.5.

3. Ibhola elincane elivela ngokuvundlile ngejubane lokuqala u-v_o = 10 m/s ukusuka esakhiweni esingamamitha ayi-10 ukuphakama. Bala ukufuduka okuvundlileUkusheshisa kwamandla adonsela phansi kungu-10 m/s²

Kwaziwa:

Ukuphakama (h) = 10 m

Ijubane lokuqala (v)_o= = 10 m / s

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Kufunwa: x

Isixazululo:

Ingxenye evundlile yejubane lokuqala = ijubane lokuqala = 10 m/s.

Isikhathi emoyeni

Isikhathi emoyeni sibalwa kusetshenziswa ukunyakaza kokuwa kwamahhala i-equation.

Kwaziwa:

Ukusheshisa kwamandla adonsela phansi (g) = 10 m/s²

Ukuphakama (h) = amamitha ayi-10

Kufunwa: t

Isixazululo:

h = 1/2 gt²

10 = 1/2 (10) t²

10 = 5 t²

t² = 10/5 = 2

t = √2 = 1.4 imizuzwana

Ukufuduka okuvundlile

Ukuhanjiswa okuvundlile kubalwe kusetshenziswa i-equation ka ukunyakaza ngesivinini esingaguquki.

Kwaziwa:

Ijubane (v) = 10 m/s

Isikhawu sesikhathi (t) = imizuzwana eyi-1.4

Kufunwa: x

Isixazululo:

s = vt = (10 m/s)(1.4 s) = amamitha ayi-14

Ukufuduka okuvundlile kungamamitha angu-14.

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1. Xazulula ijubane lokuqala libe izingxenye ezivundlile neziqondile
2. Nquma ukufuduka okuvundlile
3. Nquma ukuphakama okuphezulu
4. Nquma isikhathi esinqunyiwe
5. Nquma indawo yezinto
6. Nquma ijubane lokugcina

Funda kabanzi

Izinkinga ezixazululiwe ekunyakazeni okuqoshwe nge-projectile - lungisa ijubane lokuqala libe izingxenye ezivundlile neziqondile

1. Ibhola elikhahlelwe lishiya phansi nge-engeli θ = 60^o ngejubane elingu-10 m/s. Bala izingxenye zejubane lokuqala!
Kwaziwa:
I-engeli (θ) = 60^o
Ijubane lokuqala (v)_o) = 10 m/s
Kufunwa: v_ox kanye no-v_oy
Isixazululo:
Xazulula ijubane lokuqala libe yi-x component (evundlile) kanye ne-y component (evundlile).
isono θ = v_oy /v_o —–> v_oy =v_o isono θ
cos θ = v_ox /v_o —–> v_ox =v_o cosθ

ingxenye engu-x (evundlile):
v_ox =v_o cos θ = (10 m/s)(cos 60^o) = (10 m/s)(0.5) = 5 m/s

ingxenye ka-y (eqondile):
v_oy =v_o isono θ = (10 m/s)(isono 60^o) = (10 m/s)(0.5√3) = 5√3 m/s

2. Into ishiya umhlabathi nge-engeli θ = 30^o ngengxenye engu-y yejubane engu-10 m/s. Bala ijubane lokuqala!
Kwaziwa:
I-engeli (θ) = 30^o
ingxenye ka-y (v_oy) = 10 m/s
Kufunwa: Ijubane lokuqala (v)_o)
Isixazululo:
v_oy =v_o isono θ
10 = (v_o)(isono 30^o)
10 = (v_o)(0.5)
v_o = 10/0.5
v_o = 20m/s

3. Ingxenye evundlile yejubane lokuqala ingu-30 m/s kanti ingxenye evundlile yejubane lokuqala ingu-40 m/s. Bala ijubane lokuqala.
Kwaziwa:
Ingxenye evundlile yejubane lokuqala (v)_ox) = 30 m/s
Ingxenye eqondile yejubane lokuqala (v)_oy) = 40 m/s
Kufunwa: Ijubane lokuqala (v)_o)
Isixazululo:
v_o² =v_ox² +v_oy² = 30² 40 +² = 900 + 1600 = 2500
v_o = √2500
v_o = 50m/s

4. Ibhola elincane liphakanyiswa ngokuvundlile ngejubane lokuqala v_o = 6m/s. Bala ingxenye ka-x kanye nengxenye ka-y yejubane lokuqala.
Kwaziwa:
Ijubane lokuqala (v)_o) = 6 m/s
Kufunwa: i-vox kanye ne-v_oy
Isixazululo:
Ibhola lihamba ngokuvundlile ukuze ingxenye yejubane evundlile (v)_ox) = ijubane lokuqala (v_o) = 6 m/s. Ingxenye eqondile yejubane (v)_oy= 0.

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[wpdm_package id='536′]

1. Xazulula ijubane lokuqala libe izingxenye ezivundlile neziqondile
2. Nquma ukufuduka okuvundlile
3. Nquma ukuphakama okuphezulu
4. Nquma isikhathi esinqunyiwe
5. Nquma indawo yezinto
6. Nquma ijubane lokugcina

Funda kabanzi