Mathata a Rarollotsoeng Fisiks ea Motheo

1. 'Mele oa boima ba 1 kg o oa ka bolokolohi ho tloha phomolong, ho tloha bophahamong ba 80 m. Ho potlakisa ka baka la matla a khoheli is 10 limithara / s². Ke eng matla a kinetic ha 'mele o otla fatše.

Tse tsejoang:

Boholo (m) = 1 kg

Height (h) = 80 m

Ho potlakisa ka baka la matla a khoheli (g) = 10 m/s²

Oa Batla: matla a kinetic ha 'mele o otla fatše

Tharollo:

qalong matla a maiketsetso (Nna_o) = matla a khoheli a ka bang teng (LEOTO)

ME_o = P.E = mgh = (1)(10)(80) = 800 Dijoule

Matla a ho qetela a mechini (ME_t) = matla a kinetic (KE)

Molao-motheo oa paballo ea matla a mechini :

ME_o =ME_t

PE = KE

800 = KE

Matla a ho qetela a kinetic ke Li-joule tse 800.

2. 'Mele oa boima ba lik'hilograma tse 4 ho oela mahala ho tloha phomolong, ho tloha bophahamong ba limithara tse 10. Ho potlaka ka lebaka la matla a khoheli ho 10 ms^-2. Matla a kinetic le lebelo la limithara tse 5 ka holimo ho lefatše ke eng?

Tse tsejoang:

Phetoho ea bophahamo (h) = 10 – 5 = limithara tse 5s

Boima (m) = 4 kg

Ho potlakisa ka baka la matla a khoheli (g) = 10 m/s²

Oa Batla: Matla a kinetic a limithara tse 5 ka holim'a lefatše le lebelo la limithara tse 5 ka holim'a lefatše

Tharollo:

(A) Matla a kinetic a limithara tse 5 ka holim'a lefatše

Matla a pele a mechini (ME_o) = matla a khoheli a ka bang teng (PE)

ME_o = P.E = mgh = (4)(10)(5) = 200 Dijoule

Matla a ho qetela a mechini (EM)_t) = matla a kinetic (EK)

ME_t = KE

Molao-motheo oa paballo ea matla a mechini o bolela hore matla a pele a mechini = matla a ho qetela a mechini.

ME_o =ME_t

200 = KE

Matla a kinetic a limithara tse 5 ka holim'a lefatše ke Li-joule tse 200.

(B) lebelo ho Monyetla oa 5holimo ho mobu

Matla a pele a mechini (ME_o) = matla a ho qetela a mechini (ME_t)

PE = KE

200 = ½ mv²

2(200) / 4 = v²

100 = v²

v = √100

v = 10 m / s

Lebelo la 'mele ho limithara tse 5 ka holim'a lefatše ke 10 m/s.

3. Mango e oela ka bolokolohi phomolong, ho tloha bophahamong ba limithara tse 2. Ho potlaka ka lebaka la matla a khoheli ho 10 ms^-2Fumana lebelo la mango ha e fihla fatshe.

Tse tsejoang:

Height (h) = limithara tse 2s

Ho potlakisa ka baka la matla a khoheli (g) = 10 m/s²

Ho batloa: lebelo la mango ha e fihla fatshe.

Tharollo:

Matla a pele a mechini (ME_o) = matla a khoheli a ka bang teng (PE)

ME = P.E = mgh = m (10)(2) = 20 m

Matla a ho qetela a mechini (ME_t) = matla a kinetic (KE)

ME_t = KE = ½ mv²

Molao-motheo oa paballo ea matla a mechini o bolela hore matla a pele a mechini = matla a ho qetela a mechini.

ME_o =ME_t

20 m = ½ mv²

20 = ½ v²

2(20) = v²

40 = v²

v = √40 = √(4)(10) = 2√10 m/s

[ID ea sephutheloana sa wpdm='1166′]

1. Mosebetsi o etsoang ka mathata a matla le litharollo
2. Mathata le litharollo tsa matla a kinetic a mosebetsi
3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
4. Mathata a matla a khoheli le litharollo
5. Matla a ka bang teng a mathata le ditharollo tsa selemo se tenyetsehang
6. Mathata a motlakase le litharollo
7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a bokaholimo bo kobehileng
10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

1. Motho o lahlela lejoe la boima ba 1 kg hodimo ka lebelo la 2 m/s ha a ntse a eme moeding wa lefika e le hore lejwe le ka wela botlaaseng ba lefika le ka tlase ho dimithara tse 40. Ke eng? matla a kinetic ea majoe a bophahamo ba limithara tse 10 ho tloha fatše? Ho potlakisa ka baka la matla a khoheli g = 10 m/s².

Tse tsejoang:

Boholo (m) = 1 kg

Lebelo la pele (v)_o) = 2 m/s

Phetoho ea bophahamo = 40 - 10 = limithara tse 30

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Ho batloa: matla a kinetic a lejoe a limithara tse 10 ka holim'a lefatše

Tharollo:

Matla a pele a mechini

Matla a pele a khoheli (EP) = mgh = (1)(10)(30) = 300 Joule

Matla a kinetic a pele (KE) = ½ mv_o² = ½ (1)(2)² = ½ (4) = 2 Joule

qalong matla a maiketsetso = qalo matla a khoheli a ka bang teng + matla a kinetic a pele = 300 + 2 = 302 Joules.

Matla a ho qetela a mechini

Matla a ho qetela a mechini = matla a ho qetela a kinetic = matla a pele a khoheli + matla a pele a kinetic = 300 + 2 = 302 Joules.

2. Motho o lahlela ntho e boima ba 1-kg hodimo moyeng ka lebelo la pele la 10 m/s. Fumana (a) matla a kgoheli a ka bang teng bophahamong bo phahameng ka ho fetisisa (b) bophahamo bo boholo ka ho fetisisa.

Ho potlaka ka lebaka la matla a khoheli ke 10 m/s²

Tse tsejoang:

Boima (m) = 1 kg

Lebelo la pele (v)_o) = 10 m/s

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

o ne a batla : matla a khoheli a ka bang teng bophahamong bo phahameng ka ho fetisisa le bophahamong bo phahameng ka ho fetisisa

Tharollo:

(a) matla a khoheli a bophahamo bo phahameng ka ho fetisisa

Matla a pele a mechini:

Matla a pele a mechini (ME) = matla a pele a kinetic (KE) = ½ mv_o² = ½ (1)(10)² = ½ (100) = 50 Joule.

Matla a ho qetela a mechini:

Matla a ho qetela a mechini (ME) = matla a khoheli a ka bang teng (PE)

Molao-motheo oa paballo ea matla a mechini:

Matla a pele a mechini = matla a ho qetela a mechini

KE = PE

50 = PE

Matla a khoheli a ka bang teng ke 50 Joules.

(b) Bophahamo bo phahameng ka ho fetisisa

PE = mgh

50 = (1)(10) h

50 = lihora tse 10

h = 50 / 10 = limithara tse 5

Bophahamo bo phahameng ka ho fetisisa ke limithara tse 5 ka holimo ho mobu.

[ID ea sephutheloana sa wpdm='1174′]

1. Mosebetsi o etsoang ka mathata a matla le litharollo
2. Mathata le litharollo tsa matla a kinetic a mosebetsi
3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
4. Mathata a matla a khoheli le litharollo
5. Matla a ka bang teng a mathata le ditharollo tsa selemo se tenyetsehang
6. Mathata a motlakase le litharollo
7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a bokaholimo bo kobehileng
10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

1. Boima ba 2-kg bo hoketswe sedibeng. Haeba bolelele ba sedibeng bo le 4 cm, fumana matla a ka bang teng a selemo se tenyetsehang. Ho potlakisa ka baka la matla a khoheli ke 10 m/s².

Tse tsejoang:

Boholo (m) = 2 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Weight (w) = mg = (2)(10) = 20 N

Teleletso (x) = 4 cm = 0.04 m

Ho batloa: Matla a ka bang teng a selemo se tenyetsehang

Tharollo:

Foromo ea Molao oa Hooke :

F = kx

F = matla, k = selemo se sa fetoheng, x = phetoho boleleleng ba selemo

Nako e tsitsitseng ea selemo:

k = w / x = 20 / 0.04 = 500 N/m

Matla a ka bang teng a selemo se tenyetsehang:

PE = ½ kx² = ½ (500)(0.04)² = (250)(0.0016) = 0.4 Li-joule

Tharollo e 'ngoe:

PE = ½ kx² = ½ (bophara / x) x² = ½ wx = ½ mgx

w = boima, m ​​= boima, x = phetoho boleleleng ba selemo

PE = ½ (2) (10) (0.04) = (10) (0.04) = 0.4 Joules.

2. Ho lelefala ha selemo ho otlollotsweng ke matla F = 50 N ke 10 cm. Matla a ka bang teng a selemo se tenyetsehang ke afe haeba ho lelefala ha selemo e le 12 cm.

Tse tsejoang:

Teleletso (x) = 10 cm = 0.1 m

Matla (F) = 50 N

o ne a batla : Matla a ka bang teng a selemo se tenyetsehang

Tharollo:

Nako e tsitsitseng ea selemo:

k = F / x = 50 / 0.1 = 500 N/m

Matla a ka bang teng a selemo se tenyetsehang haeba bolelele ba selemo e le 12 cm. :

PE = ½ kx² = ½ (500)(0.12)² = (250)(0.0144) = 3.6 Dijoule.

3. Kerafo ea F khahlanong le x e bontšitsoeng setšoantšong se ka tlase. Matla a ka bang teng a selemo se tenyetsehang ke afe, haeba bolelele ba selemo e le 10 cm.

Tse tsejoang:

Matla (F) = 5 N

Ho lelefala ha selemo (x) = 2 cm = 0.02 m

Oa Batla: Matla a ka bang teng a selemo se tenyetsehang haeba bolelele ba selemo e le 0.1 m.

Tharollo:

Nako e tsitsitseng ea selemo:

k = F / x = 5 / 0.02 = 250 N/m

Matla a ka bang teng a selemo se tenyetsehang haeba bolelele ba selemo e le 0.1 m:

PE = ½ kx² = ½ (250)(0.1)² = (125)(0.01) = 1.25 Dijoule.

4. Moatlelete o tlolela hodima seletsa sa selemo se nang le boima ba 500 N, selemo se kgutsufala ka 4 cm. Fumana hore na matla a ka bang teng a ka qobella moatlelete hakae.

A. 20 Joule

B. 10 Joule

C. 5 Joule

D. 2 Joule

Tse tsejoang:

Matla (F) = 500 N

Phetoho ea bolelele ba selemo (Δx) = 4 cm = 0.04 m

Oa Batla: Matla a ka bang teng a selemo

Tharollo:

Bala botsitso ba elastic ba selemo o sebedisa equation ya molao wa Hooke:

k = F / Δx = 500 N / 0.04 m = 12500 N/m

Matla a kgonego a ho tenyetseha a selemo:

PE = ½ k Δx² = ½ (12500)(0.04)² = (6250)(0.0016)

PE = 10 Joule

Karabo e nepahetseng ke B.

5. Selemo ha e leketlileng ka bongata ba Ligrama tse 500, bolelele ba eona e eketseha ka 5 cm. Fumana qeto ea eona kamehla le eona matla a ka bang teng.

Tse tsejoang:

Boima ba ntho (m) = 500 dikgerama = (500/1000) kg = 5/10 kg = 0.5 kg

Ho potlaka (g) = 10 m/s²

Boima ba ntho (w) = mg = (0.5 kg)(10 m/s²) = 5 kg m/s² = 5 Newton

Phetoho ea bolelele ba selemo (Δx) = 5 cm = 0.05 m

Ho batloa: matla a sa fetoheng a selemo (k) le a ka bang teng (PE)

Tharollo:

Taba ea pele, bala palo e sa fetoheng ea selemo u sebelisa equation ea molao oa Hooke:

k = w / Δx = 5 N / 0.05 m = 100 N/m

Ho tenyetseha ho ka bang teng ha selemo:

PE = ½ k Δx² = ½ (100)(0.05)² = (50)(0.0025)

PE = 0.125 Joule

[ID ea sephutheloana sa wpdm='1179′]

1. Mosebetsi o etsoang ka mathata a matla le litharollo
2. Mathata le litharollo tsa matla a kinetic a mosebetsi
3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
4. Mathata a matla a khoheli le litharollo
5. Matla a ka bang teng a mathata le litharollo tsa selemo se tenyetsehang
6. Mathata a motlakase le litharollo
7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a libaka tse kobehileng
10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

1. 'Mele oa boima ba lik'hilograma tse 1 ho oela mahala ho tloha phomolong, ho tloha bophahamong ba 10 m.

Etsa qeto:

(A) Mosebetsi o etsoang ka matla of matla a khoheli

(b) Phetoho ho matla a khoheli a ka bang teng

Ho potlakisa ka baka la matla a khoheli (g) = 10 m/s²

Tse tsejoang:

Boholo (m) = 1 kg

Bolelele (h) = 10 m

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Weight (w) = mg = (1 kg)(10 m/s²) = 10 N

Tharollo:

(A) Mosebetsi o entsoeng ka matla a khoheli

W = wh = mgh

W = (1)(10)(10) = 100 Joule

(B) Phetoho ea matla a khoheli

Phetoho ea matla a khoheli e lekana le mosebetsi o etsoang ke matla a khoheli.

ΔEP = 100 Joule

2. Ntho ea 10 N e thella fatše holim'a sefofane se sekametseng ka boreledi ho ea ka limithara tse 2. Fumana mosebetsi o entsoeng ka matla a boima!

Tse tsejoang:

boima (w) = 10 N

w_x = sebe θ = (10)(sebe sa 30^o) = (10)(0.5) = 5 N

d = 2 m

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Ho batloa: mosebetsi o etsoang ka matla a boima

Tharollo:

W = F d = w_x d = (5)(2) = 10 Joule

Tharollo e 'ngoe:

Sebe sa 30^o = h / d

0.5 = lihora / 2

h = (0.5)(2)

h = 1 m

Mosebetsi o etsoang ka matla a boima;

W = F d = wh = (10 N)(1 m) = 10 N m = 10 Joule

3. Ntho ea boima ba ligrama tse 1,500 limithara tse 20 ka holimo ho lefatše, ho wela fatshe ka bolokolohi. Matla a khoheli a ntho ke afe. ​​Ho potlaka ka lebaka la matla a khoheli ke 10 m/s².

Tse tsejoang:

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Boima (m) = digrama tse 1500 = 1500/1000 dikhilograma = 1.5 dikhilograma

Bophahamo (h) = limithara tse 20

Ho batloa: Matla a khoheli a ka bang teng

Tharollo:

PE = mgh = (1.5 kg)(10 m/s²)(20 m) = 300 kg m²/s² = 300 Joule

4. Ho latela setshwantsho se ka tlase, haeba boima ba ntho ya 1 e le 2 kg mme boima ba ntho ya 2 e le 4 kg, Papiso ea matla a ka bang teng a ntho ea 1 le ntho ea 2 ke…..

Tse tsejoang:

Boima ba ntho 1 (m₁) = 2 lik'hilograma

Boima ba ntho 2 (m₂) = 4 lik'hilograma

Bophahamo 1 (h₁) = limithara tse 12

Bophahamo 2 (h₂) = limithara tse 9

Oa Batla: Cpapiso ea matla a ka bang teng a ntho ea 1 le ntho ea 2

Tharollo:

PE = mgh

m = boima (tekanyo ea eona ea machaba ke kilogram, e khutsufalitsoeng kg)

g = ho potlaka ka lebaka la matla a khoheli (yuniti ea eona ea machaba ke limithara ka motsotsoana e sekoere, e khutsufalitsoeng m/s²)

h = bophahamo (yuniti ea eona ea machaba ke mithara, e khutsufalitsoeng ka m)

PE = matla a khoheli (yuniti ea eona ea machaba ke kg m²/s² kapa Joule)

Matla a khoheli a ntho ea 1:

EP₁ = m₁ gh₁= (2)(g)(12) = 24 g

Matla a khoheli a ntho ea 2:

EP₂ = m₂ gh₂ = (4)(g)(9) = 36 g

Cpapiso ea matla a ka bang teng a ntho ea 1 le ntho ea 2:

PE₁ : PE₂

24 g : 36 g

24: 36

12/24: 12/36

2: 3

[ID ea sephutheloana sa wpdm='1175′]

1. Mosebetsi o etsoang ka mathata a matla le litharollo
2. Mathata le litharollo tsa matla a kinetic a mosebetsi
3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
4. Mathata a matla a khoheli le litharollo
5. Matla a ka bang teng a mathata le ditharollo tsa selemo se tenyetsehang
6. Mathata a motlakase le litharollo
7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a bokaholimo bo kobehileng
10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

1. Lebokose la 2-kg le theoha ka lebelo ho tloha ho 10 m/s ho ea phomolong. khohlano ea kinetic ke 0.2. Ho potlakisa ka baka la matla a khoheli ke 10 m/s²Boholo ba ho baleha?

Tsejoang;

Boholo (m) = 2 kg

Lebelo la pele (v)_o) = 10 m/s

Lebelo la ho qetela (v)_t) = 0 m/s

Palo ea khohlano ea kinetic (μ_k= 0.2

Weight (w) = mg = (1 kg)(10 m/s²) = 10 kg m/s² = 10N

Ho batloa: Boholo ba ho falla (d)

Tharollo:

Molao-motheo oa matla a mosebetsi le mechine :

W_nc = ΔEM

W_nc = ΔEK + ΔEP

W_nc = ½ m (v_t² - v_o²) + mgh

W_nc = mosebetsi etsoa ke matla a sa bolokeheng ho sebetsa hodima ntho eo

ΔEK = phetoho ho matla a kinetic

ΔEP = phetoho ho matla a ka bang teng

m = boima

v = lebelo

g = ho potlaka ka lebaka la matla a khoheli

h = phetoho bophahamong

Phetoho bophahamong h = 0 kahoo ΔEP = 0

W_nc = ΔEK

Mosebetsi o etsoang ke matla a sa batleng mekhoa ea khale:

W_nc = -F_c d = – μ_k N d = – μ_k wd = – μ_k mgd

W_nc = -(0.2)(2)(10)(s)

W_nc = – (4)(2)

Letšoao la ho tlosa le bontša hore tataiso ea matla a khohlano ea kinetic e fapane le tataiso ea ho falla.

Phetoho ea matla a kinetic:

ΔEK = ½ m (v_t² - v_o²) = ½ (2)(0 – 10²) = 0 – 100 = -100

Boholo ba ho falla:

W_nc = ΔEK

– 4 s = – 100

s = -100/-4

s = 25 m

2. Boloko bo thella fatshe sefofaneng se sekametseng. Koefficient ya kinetic friction ke 0.4. Ho potlaka ka lebaka la matla a khoheli ke g = 10 ms^-2Fumana lebelo la ho qetela ha boloko e otla fatshe.

Tse tsejoang:

Bolelele ba qalong (h)_o) = 6 m

Bolelele ba ho qetela (h_t) = 0 m

Lebelo la pele (v)_o= 0

Palo ea khohlano ea kinetic (μ_k= 0.4

Ho potlaka ka lebaka la matla a khoheli (g) = 10 ms^-2

cos θ = 8 / 10

Karolo e otlolohileng ea boima = w_y = w cos θ = mg cos θ = m (10)(8/10) = m (10)(4/5) = m (40/5) = 8 m

Matla a tloaelehileng = N = w_y = 8 limithara

Matla a moferefere oa kinetic = f_k = μ_k N= μ_k w_y = (0.4)(8 m) = 3.2 m

Ho batloa: Lebelo la ho qetela (v)_t)

Tharollo:

Molao-motheo oa matla a mosebetsi le mechine:

W_nc = ΔEM

W_nc = ΔEK + ΔEP

Phetoho ea matla a kinetic:

ΔEK = 1/2 m (v_t² - v_o²) = 1/2 m (v_t² - 0) = 1/2 mv_t²

Phetoho ea matla a ka bang teng:

ΔEP = mg (h)_t -h_o) = m (10)(0-6) = m (10)(-6) = – 60 m

Mosebetsi o etsoang ka matla a moferefere oa kinetic:

W_nc = – f_k s = – (3.2 m(10) = – 32 m

Letšoao la ho tlosa le bontša hore tataiso ea matla a khohlano ea kinetic e fapane le tataiso ea ho falla.

Lebelo la ho qetela (v_t):

W_nc = ΔEK + ΔEP

- 32 limithara = 1/2 mv_t² - 60 limithara

- 32 limithara = m (1/2 v_t² - 60)

- 32 = 1/2 v_t² - 60

– 32 + 60 = 1/2 v_t²

28 = halofo ea v_t²

2 (28) = v_t²

56 = v_t²

v_t = 4.14

v_t = 2√14 ms^-1

3. Boloko bo thella fatshe sefofaneng se sekametseng ka thata. Lebelo la pele ke 0 m/s mme lebelo la ho qetela ke 10 ms^-1Haeba matla a khohlano ea kinetic e le 2 N le ho potlaka ka lebaka la matla a khoheli g = 10 ms^-2, bolelele (h) ke eng?

Tse tsejoang:

Boima (m) = 1 kg

Lebelo la pele (v)_o= 0 (phomolo ea boloko)

Lebelo la ho qetela (v)_t) = 10 ms^-1

Bolelele ba qalong (h)_o) = h

Bolelele ba ho qetela (h_t= 0

Matla a khohlano ea kinetic (f)_k) = 2 N

Ho potlaka ka lebaka la matla a khoheli (g) = 10 ms^-2

Ho batloa: Bophahamo (h)

Tharollo:

Mosebetsi o etsoang ka matla a moferefere oa kinetic:

W_nc = – f_k s = – (2)(15) = – 30

Letšoao la ho tlosa le bontša hore tataiso ea matla a khohlano ea kinetic e fapane le tataiso ea ho falla.

Phetoho ea matla a kinetic:

ΔEK = 1/2 m (v_t² - v_o²) = 1/2 (1)(10² - 0) = 1/2 (10²) = 1/2 (100= 50

Phetoho ea matla a ka bang teng:

ΔEP = mg (h)_t -h_o) = (1)(10)(0-h) = (10)(-h) = -10 h

Molao-motheo oa matla a mosebetsi le mechine:

W_nc = ΔEK + ΔEP

– 30 = 50 – 10 dihora

Lihora tse 10 = 50 + 30

Lihora tse 10 = 80

h = 80/10

h = 8 m

4Haeba boloko bo theoha ka tsela e sekametseng hanyane, joale….
A. Mosebetsi o etsoang ke matla a khoheli holim'a boloko o moholo ho feta phetoho ea matla a ka bang teng a boloko.
B. Matla a mechini aa eketseha
C. Bongata ba matla a kinetic le matla a ka bang teng a fokotsehile
D. Mosebetsi o etsoa ke matla a khohlano a lekanang le phetoho ea matla a kinetic a block
tharollo

A e fositse

Mosebetsi o etsoang ke matla a khoheli holim'a boloko o lekana le phetoho ea matla a khoheli a boloko.

B o fositse

Haeba ho kenacSefofane se nang le mela se boreleli joale matla a mechini a boloko aa tsitsitse. Ha e le holimo ho sefofane se sekametseng 'me e sa sisinyehe, matla a mechini a boloko a lekana le matla a khoheli a khoheli. Seboloko se ntse se phomotse kahoo matla a sona a kinetic ke lefela. Ha se theoha sefofaneng se sekametseng, bophahamo ba boloko boa fokotseha kahoo matla a khoheli a khoheli le 'ona aa fokotseha. Matla a khoheli a fokotseha hobane a fetoha matla a kinetic. Leha matla a khoheli a fetoha matla a kinetic, matla a mechini aa tsitsitse.

Haeba sefofane se sekametseng se le thata, matla a mechini a boloko aa fokotseha ka lebaka la mosebetsi o mobe o etsoang ke matla a khohlano. Matla a khohlano ke matla a sa bolokeng. Mosebetsi o etsoang ke matla a sa bolokeng nthong o etsa hore matla a mechini a ntho a fokotsehe.

C e nepahetse

Sefofane se sekametseng se makukuno kahoo ho na le matla a khohlano a phephetsang motsamao oa block. Matla a khohlano ke matla a sa bolokeng. Matla a mosebetsi-mechanical a theorem a bolela hore mosebetsi o etsoang ke matla a sa bolokeng (mohlala, matla a khohlano) o lekana le phetoho ea matla a mechini. Leetong lena, matla a mechini aa fokotseha.

Matla a mechine a boloko = matla a khoheli a ka bang teng + matla a kinetic.

D o fositse.

Mosebetsi o etsoang ke matla a khohlano bolokong o lekana le phetoho ea matla a mechini a boloko, eseng phetoho ea matla a kinetic a boloko. Ke 'nete hore matla a khohlano a phephetsa motsamao oa boloko kahoo a fokotsa lebelo la boloko 'me a fokotsa matla a kinetic a boloko. Empa hlokomela hore matla a kinetic a boloko a tsoa matla a khoheli a ka bang teng. Kahoo ke 'nete hore mosebetsi o etsoa ke matla a khohlano a lekanang le phetoho ea matla a mechini (matla a mechini aa fokotseha).

Karabo e nepahetseng ke C.

5Ntho e mokatong o bataletseng e otloa kahoo e tsamaea metsotsoana e 3 ebe ea ema. Haeba boima bo tsejoang ba ntho eo e le ligrama tse 10, matla a khohlano pakeng tsa ntho le mokatong ke lik'hilojule tse 2. Fumana mosebetsi o etsoang ke matla a khohlano.

A. 0.18 J

B. -0.18 J

C. 0.36 J

D. -0.36 J

Tse tsejoang:

Nako ea ho arohana (t) = metsotsoana e 3

Lebelo la ho qetela (v)_t) = 0 m/s (ntho e phomotse)

Boima ba ntho (m) = 10 grams = 10/1000 kg = 1/100 kg = 0.01 kg

Matla a khohlano (F) = 2 kilodyne = 2 x 10³ matla

Ho batloa: Mosebetsi (W) o etsoa ka matla a khohlano

Tharollo:

Phetoho ea li-unit tsa matla:

1 Newton = 1 x 10⁵ matla

Dyne e le 'ngoe = 1/10⁵ Newton = 1 x 10^-5 Newton = 10^-5 Newton

Matla a khohlano (F) = 2 x 10³ dyne = 2 x 10³ x 10^-5 Newton = 2 x 10^-2 Newton = 2/100 Newton = 0.02 Newton

Khopolo-taba ea matla a mosebetsi le mechine e bolela hore mosebetsi o etsoa ke matla a sa bolokeheng nthong e lekanang le phetoho ea matla a mechini a ntho eo.

Haeba ntho e tsamaya sefofaneng se sekametseng, matla a mechini (ME) = matla a khoheli (PE) + matla a kinetic (KE). Empa haeba ntho e tsamaya feela sefofaneng se otlolohileng kahoo ho se na phetoho bophahamong, matla a mechini = matla a kinetic. Sebakeng se otlolohileng, matla a khoheli ke lefela hobane ha ho na phetoho bophahamong.

Matla a khohlano ke matla a sa bolokeheng. Matla a khohlano hangata a fokotsa lebelo la ntho le matla a kinetic a ntho. A ka etsa qeto ea hore mosebetsi o etsoang ke matla a khohlano nthong o lekana le ho fokotseha ha matla a mechini.

Ka lipalo:

Mosebetsi (W) = Phetoho ea matla a mechini (ΔEM)

F s = ΔEP + ΔEK

F s = mg Δh + ½ m (v_t² - v_o²)

F s = mg (0) + ½ m (0² - v_o²)

Fs = 0 + ½ m (– (v_o²))

F s = – ½ mv_o² ——— Tekanyo ea 1

Tlhaloso: F = matla a khohlano, d = ho falla, m = boima, v_o = lebelo la pele

Ho falla (d) le lebelo la pele (v)_o) ha e so tsejoe hobane pele bala v_o kapa d. Mosebetsi o etsoang ke matla a khohlano o baloang ho sebelisoa e 'ngoe ea li-equation kamora v e tsejoang_o kapa d.

Tekanyo ea ho falla (d) motsamaong o sa lekanang oa mola o otlolohileng:

v_t² = v_o² + 2 (-a) s

Lebelo la ho qetela (v_t) = 0 mme ho potlaka (a) ho saennwe ka hore ke negative hobane ntho e fokotsehile (lebelo la ntho le fokotsehile).

0 = v_o² – lipapatso tse 2

v_o² = Papatso e 2

d = v_o² / 2 a ——— Tekanyo ea 2

Phetoho ea d ho equation ea 2 le d ho equation ea 1:

F d = – ½ mv_o²

F (v_o²/2a) = – ½ mv_o²

(F/2a) v_o² = – ½ mv_o²

F/2a = – ½ m

F = (2)(a)(-1/2)(m)

F = – (a)(m)

a = – (F / m)

a = – 0.02 Newtons / 0.01 lik'hilograma

a = – 2 Newton/kilogerama

a = – 2 m/s²

Tekanyo ea ho bala lebelo la pele (v_o) ka motsamao o sa lekanang wa mola o otlolohileng :

v_t = v_o + ho —–> Lebelo la ho qetela (v_t) = 0, Ho potlaka (a) = 2 m/s², nako e sa fellang (t) = metsotsoana e 3

0 = v_o + (-2)(3)

0 = v_o - 6

v_o = limithara tse 6/motsotsoana

Mosebetsi (W) o etsoang ke matla a khohlano:

W = – ½ mv_o² = -1/2 (0.01)(6²) = -1/2 (0.01)(36)

W = -1/2 (0.36)

W = – 0.18 Joule

Mosebetsi o etsoang ke matla a khohlano o saennoe ka hore o na le moelelo o fosahetseng, ho bolelang hore mosebetsi o fokotsa matla a mechini a ntho.

Haeba ho tsejoa d, mosebetsi o ka bala o sebelisa equation ea W = F d.

Karabo e nepahetseng ke B.

[ID ea sephutheloana sa wpdm='1178′]

1. Mosebetsi o etsoang ka mathata a matla le litharollo
2. Mathata le litharollo tsa matla a kinetic a mosebetsi
3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
4. Mathata a matla a khoheli le litharollo
5. Matla a ka bang teng a mathata le ditharollo tsa selemo se tenyetsehang
6. Mathata a motlakase le litharollo
7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a bokaholimo bo kobehileng
10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

Matla a Kinetic a Mosebetsi :

1. Koloi ea boima ba lik'hilograma tse 5000 e potlakile ho tloha phomolong ho ea ho 20 m/s. Fumana letlooa mosebetsi e entsoe koloing.

Tse tsejoang:

Boholo (m) = 5000 kg

Lebelo la pele (v_o) = 0 m/s (phomolo ea koloi)

Lebelo la ho qetela (v_t) = 20 m/s

o ne a batla : mosebetsi oa marang-rang

Tharollo:

Molao-motheo oa matla a kinetic a mosebetsi :

W_letlooa = ΔEK

W_letlooa = ½ m (v_t² - v_o²)

W_letlooa = mosebetsi oa marang-rang

ΔEK = phetoho ea matla a kinetic

m = boima (kg),

v_t = lebelo la ho qetela (Mof),

v_o = lebelo la pele (Mof).

Marang-rang:

W_letlooa = ½ m (v_t² - v_o²)

W_letlooa = ½ (5000)(20² - 0²)

W_letlooa = (2500)(400 – 0)

W_letlooa = (2500)(400)

W_letlooa = 1000,000 Joule

2. Ntho e boima ba 10 kg e potlakisitswe ho tloha ho 5 m/s ho isa ho 10 m/s. Fumana mosebetsi wa letlowa o entsweng nthong eo!

Tse tsejoang:

Boholo (m) = 10 kg

Lebelo la pele (v_o) = 5 m/s

Lebelo la ho qetela (v_t) = 10 m/s

o ne a batla : mosebetsi oa marang-rang

Tharollo:

Marang-rang:

W_letlooa = ΔEK

W_letlooa = ½ m (v_t² - v_o²)

W_letlooa = ½ (10)(10² - 5²)

W_letlooa = (5)(100 – 25)

W_letlooa = (5)(75)

W_letlooa = 375 Joule

3. Koloi e boima ba lik'hilograma tse 2000 e theoha ka lebelo ho tloha ho 10 m/s ho ea ho 5 m/s. Mosebetsi o etsoang koloing ke ofe?

Tse tsejoang:

Koloi ea mesele (m) = 2000 kg

Lebelo la pele (v_o) = 10 m/s

Lebelo la ho qetela (v_t) = 5 m/s

Oa Batla: mosebetsi oa marang-rang

Tharollo:

Marang-rang:

W_letlooa = ΔEK

W_letlooa = ½ m (v_t² - v_o²)

W_letlooa = ½ (2000)(5² - 10²)

W_letlooa = (1000)(25 – 100)

W_letlooa = (1000)(-75)

W_letlooa = -75,000 Joule

Letšoao la ho tlosa le bontša hore tataiso ea ho falla e fapane le tataiso ea matla a letlooa.

4. Matla a sa fetoheng a 60-N a sebediswang nthong ya boima ba 10-kg ka metsotswana e 12. Lebelo la pele la ntho ke 6 m/s mme tataiso ya ntho e tshwana le tataiso ya matla.

(1) Mosebetsi o entsoeng nthong eo ke 30,240 Joules

(2) Matla a ho qetela a kinetic ke li-joule tse 30,240

(3) matla ke 2,520 Watt

(4) Keketseho ea matla a kinetic a ntho ke 180 Joules

Lipolelo tse nepahetseng ke…

Tse tsejoang:

Matla (F) = 60 N

Nako ea ho arohana (t) = metsotsoana e 12

Boima ba ntho (m) = 10 kg

Lebelo la pele (v)_o) = 6 m/s

Ho batloa: Lipolelo tse nepahetseng

Tharollo:

Ho potlakisa ntho:

∑F = ma

60 = 10 a

a = 60 / 10 = 6 m/s²

Lebelo la ho qetela:

v_t = v_o + ho

v_t = 6 + (6)(12)

v_t = 6 + 72

v_t = 78 m/s

The distanta o tsamaile ka metsotsoana e 12:

s = v_o t + 1/2 ho²

s = (6)(12) + 1/2 (6)(12)²

s = 72 + (3)(144)

s = 72 + 432

s = limithara tse 504

(1) Mosebetsi o etsoang ka likhoka

W = F s = (60)(504) = 30,240 Joule

(2) Matla a ho qetela a kinetic

KE = 1/2 mv_t² = 1/2 (10)(78)² = (5)(6084) = 30,420 Li-joule

(3) Matla

P = W / t = 30,240 / 12 = 2,520 Joules/motsotsoana

(4) Keketseho ea matla a kinetic

ΔKE = 1/2 mv_t² – 1/2 mv_o² = 1/2 m (v_t² - v_o²) = 1/2 (10)(78² - 6²) = 5 (6084 –36) = 5 (6048)

ΔKE = 30,240 Joule

5. Mosebetsi o moholo o etsoa ka nomoro ea ntho…

Tharollo:

Mosebetsi oa netweke = phetoho ea matla a kinetic

W_letlooa = ½ m (v_t² - v_o²)

Mosebetsi o moholo:

W₁ = ½ (8)(4² - 2²) = (4)(16 – 4) = (4)(12) = 48 Joule

W₂ = ½ (8)(5² -3²) = (4)(25 – 9) = (4)(16) = 64 Joule

W₃ = ½ (10)(6² - 5²) = (5)(36 – 25) = (5)(11) = 55 Joule

W₄ = ½ (10)(4² - 0²) = (5)(16 – 0) = (5)(16) = 80 Joule

W₅ = ½ (20)(3² - 3²) = (10)(9 – 9) = (10)(0) = 0 Joule

6. Koloi ea boima ba 4000 kg e tsamaea moleng o otlolohileng ka lebelo la 25 m/s. Koloi e fokotsoa hore lebelo la ho qetela la koloi e be 15 m/s. Mosebetsi o etsoang koloing ke ofe?

Tse tsejoang:

Boima (m) = 4000 kg

Lebelo la pele (v)_o) = 25 m/s

Lebelo la ho qetela (v_t) = 15 m/s

o ne a batla : Mosebetsi o entsoeng koloing

Tharollo:

W_letlooa = ½ m (v_t² - v_o²) = ½(4000)(15²-25²) = (2000)(225-625) = (2000)(-400) = -800,000 Lijoule = -800 kJ

7. 0.1-kg e lahleloang ka ho rapama ka lebelo la 6 m/s ho tloha bophahamong ba limithara tse 5. Haeba ho potlaka ha matla a khoheli ke 10 m/s², joale matla a kinetic a bolo bophahamong ba limithara tse 2 ke afe.

Tse tsejoang:

Boima (m) = 0.1 kg

Phetoho ea bophahamo (h) = 5 m - 2 m = 3 metres

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Ho batloa: Matla a kinetic a bophahamo ba limithara tse 2.

Tharollo:

Motsamao o otlolohileng o ka utloisisoa ka ho sekaseka likarolo tse otlolohileng le tse otlolohileng tsa motsamao ka thoko. Motsamao o shebileng ka lehlakoreng le otlolohileng o hlahlobiloe e le motsamao o sa fetoheng oa lebelo le motsamao o shebileng ka lehlakoreng le otlolohileng o sekasekiloe joalo ka motsamao wa ho wa ka bolokolohi kapa motsamao o otlolohileng.

qalong matla a maiketsetso = matla a khoheli a ka bang teng.

PE = mgh = (0.1)(10)(3) = 3 Joule.

The ho qetela matla a maiketsetso = matla a kinetic.

KE = 3 Joule.

8. Koloi ea boima ba lik'hilograma tse 1000 e potlakisa ho tloha phomolong 'me e tsamaea ka lebelo la 5 m/s. Mosebetsi o etsoang ke koloi ke ofe?

Tse tsejoang:

Boima (m) = 1000 kg

Lebelo la pele (v)_o= 0

Lebelo la ho qetela (v)_t) = 5 m/s

Ho batloa: Mosebetsi (W) o etsoang ka koloi

Tharollo:

W_letlooa = ½ m (v_t² - v_o²)

Mosebetsi o etsoang ka koloi:

W_letlooa = ½ (1000)(5² - 0²) = (500)(25 – 0) = (500)(25) = 12,500 Joule

9. Bolo ea ligrama tse 500 e lahleloa holimo ka holimo ho tloha holim'a lefatše ka lebelo la pele la 10 m/s². Ho potlaka ka lebaka la matla a khoheli ke 10 ms^-2Mosebetsi o etsoang ke matla a boima ke ofe ha bolo e fihla bophahamong bo phahameng ka ho fetisisa?

Tsejoa :

Boima ba bolo (m) = 500 grams = 0.5 kg

Lebelo la pele (v)_o) = 10 m/s²

Lebelo la ho qetela (v)_t) = 0 (lebelo le phahameng ka ho fetisisa)

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Ho batloa: Mosebetsi (W) o etsoang ka boima

Tharollo:

Mosebetsi oa letlooa o etsoang ke matla a letlooa nthong = phetoho ea matla a kinetic.

W_letlooa = ΔEK = EK_t – EK_o

Wnet = ½ mv_t² – ½ mv_o² = ½ m (v_t² - v_o²)

KE_t = matla a ho qetela a kinetic, KE_o = matla a kinetic a pele, m = boima ba ntho, v_t = lebelo la ho qetela la ntho, v_o = lebelo la pele la ntho.

Marang-rang:

W_letlooa = ½ m (v_t² - v_o²) = ½ (0.5)(0² - 10²)

W_letlooa = (0.25)(-100) = -25 Lijoule

Letšoao la ho tlosa le bontša hore tsela eo bolo e tsamaeang ka eona e fapane le boima ba eona. Tsela eo bolo e tsamaeang ka eona e otlolohile 'me tsela eo boima bo tsamaeang ka eona e otlolohile.

10. Ntho e boima ba 1-kg e oa ntle le ho oa ka phapang ea bolelele = limithara tse 2.5. Ho potlaka ka lebaka la matla a khoheli ke 10 ms^-2Mosebetsi o etswang nthong eo ke ofe?

Tse tsejoang:

Boima ba bolo (m) = 1 kg

Lebelo la pele (v)_o) = 0 m/s

Bophahamo (h) = limithara tse 2.5

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Ho batloa: Marang-rang nakong ea ho falla

Tharollo:

Lebelo la ho qetela la bolo (v_t)

E baloa ho sebelisoa equation ea motsamao oa ho oa ka bolokolohi. Tse tsejoang: Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s², Phetoho bophahamong ba bolo (h) = limithara tse 2.5. Ho batloa: Lebelo la ho qetela.

v_t² = 2 gh = 2(10)(2.5) = 2(25)

v_t = √2(25)

v_t = 5√2

Mosebetsi oa netweke = phetoho ea matla a kinetic

W_letlooa = ΔEK = ½ m (v_t² - v_o²) = ½ (1){(5√2)² - 0²}

W_letlooa = ½ (25)(2) = 25 Joule

11. Ntho e boima ba 2 kg e tsamaya ka lebelo la 72 km/hora. Kamora ho tsamaya ka dimithara tse 400, lebelo la ho qetela la ntho ke 144 km/hora. Ho potlaka ka lebaka la matla a khoheli ke 10 ms^-2Fumana netweke.

Tse tsejoang:

Boima ba ntho (m) = 2 kg

Lebelo la pele (v)_o) = 72 km/h = 20 m/s

Lebelo la ho qetela (v)_t) = 144 km/h = 40 m/s

distanta (s) = limithara tse 400

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Ho batloa: Marangrang

Tharollo:

Mosebetsi oa netweke = liphetoho tsa matla a kinetic

W_letlooa = ΔEK = ½ m (v_t² - v_o²) = ½ (2)(40² - 20²}

W_letlooa = ½ (2)(1600 - 400) = 1200 Joule

12. Ntho ea boima ba 2 kg e tsamaea ka 2 ms^-1Mosebetsi o entsoeng nthong ke 21 Joules. Lebelo la ho qetela la ntho ke lefe.

Tse tsejoang:

Boima (m) = 2 kg

Lebelo la pele (v)_o) = 2 m/s

Mosebetsi (W) = 21 Joule

Ho batloa: lebelo la ho qetela (v_t)

Tharollo:

W_letlooa= ΔEK

W_letlooa= 1/2 mv_t² -1/2 mv_o²

W_letlooa = 1/2 m (v_t² - v_o²)

21 = 1/2 (2) (v_t² - 2²)

21 = (v_t² - 2²)

21 = v_t² - 4

v_t² 21 + 4 = 25

v_t = √25

v_t = 5 m/s

13Matla a sa fetoheng a 8 N a sebetsa nthong e boima ba 16 kg. Haeba ntho eo e phomotse qalong, joale fumana lebelo la ntho eo ka mor'a hore matla a sebetse nthong eo metsotsoana e 4.

Tse tsejoang:

Matla a sa fetoheng (F) = 8 Newton

Boima ba ntho (m) = 16 kg

Lebelo la pele la ntho (v)_o) = 0 m/s

Nako ea nako ea matla e sebetsa nthong (t) = metsotsoana e 4

Ho batloa: Lebelo la ho qetela (v_t)

Tharollo:

Mosebetsi = Phetoho ea matla a kinetic

W = KE ea ho qetela – KE ea pele

W = ½ mv_t² – ½ mv_o²

W = ½ mv_t² - 0

W = ½ mv_t² —— Tekanyo ea 1

Mosebetsi = Matla x Ho falla

W = F d

W = 8 d

Sebelisa equation ea motsamao o sa lekanang oa mola o ka tlase ho bala ho falla (d):

d = v_o t + ½ ho²

d = ho falla, v_o = lebelo la pele, t = nako e sa fellang, a = ho potlaka

d = 0 + ½ ho² = ½ ho² —-> a = (v_t - v_o) / t = v_t / t

d = ½ (v_t / t) t²

^d = ½ (v_t) t

Phetoho ea ho falla (d) ho equation ea Sebetsa le ho falla (d) ho equation ena:

W = 8 d

W = 8(1/2)(v_t(t)

W = (4)(v_t)(t) —— equation 2

Tekanyo ea 1 = Tekanyo ea 2

W = W

½ mv_t² = (4)(v_t(t)

½ mv_t = (4)(t)

½ (16)(v)_t) = 4(4)

8 v_t = 16

v_t = 16/8

v_t = limithara tse 2/motsotsoana

14Ho eketsa lebelo la ntho e fetohang ka makhetlo a mabeli ho feta lebelo la pele, fumana mosebetsi o hlokahalang ts'ebetsong…

Tse tsejoang:

Boima ba ntho (m) = 1 kg

Lebelo la pele (v)_o) = 1 m/s

Lebelo la ho qetela (v)_t) = 2 x lebelo la pele = 2 x 1 = 2 m/s

Ho batloa: Sebetsa

Tharollo:

Matla a pele a kinetic:

Leihlo la pele la KE = ½ mv_o² = ½ (1)(1)² = ½ (1)(1) = ½ (1) = 0.5

Matla a ho qetela a kinetic ha lebelo la ntho le fetoha makhetlo a 2 a lebelo la eona la pele:

KE ea ho qetela = ½ mv_t² = ½ (1)(2)² = ½ (4) = 2

Khopolo-taba ea matla a sebetsang le a kinetic:

Mosebetsi = Phetoho ea matla a kinetic

Mosebetsi = Matla a ho qetela a kinetic – matla a pele a kinetic

Mosebetsi = 2 – 0.5

Mosebetsi = 1.5

Matla a kinetic a pele = 0.5

Mosebetsi = 3 x 0.5 = 1.5

Mosebetsi o hlokahalang ka makhetlo a 3 a matla a eona a kinetic a pele.

15Koloi e boima ba 1500 kg e tsamaya ka lebelo la 36 km/hora tseleng e otlolohileng le e boreleli e otlolohileng. Koloi e potlakile ho fihla ho 72 km/hora. Fumana mosebetsi o hlokahalang ho potlakisa koloi.

Tse tsejoang:

Boima ba koloi (m) = 1500 kg

Lebelo la pele la koloi (v)_o) = 36 km/hora = 36,000 metres / 3600 metsotsoana = 10 metres/motsotsoana

Lebelo la ho qetela la koloi (v)_t) = 72 km/hora = 72,000 metres / 3600 metsotsoana = 20 metres/motsotsoana

Ho batloa: Mosebetsi o hlokahalang ho potlakisa koloi

Tharollo:

Khopolo-taba ea matla a sebetsang le a kinetic:

W = EK final – EK initial

W = ½ mv_t² – ½ mv_o² = ½ m (v_t² –v_o²)

W = ½ (1500)(20² - 10²)

W = ½ (1500)(400 - 100)

W = ½ (1500)(300)

W = (1500)(150)

W = 225,000 Joule

16Ntho e boima ba 2 kg qalong e tsamaya ka lebelo la 72 km hora^-1Kamora ho tsamaya tseleng e otlolohileng e otlolohileng ho fihlela ho 400 m, lebelo la ntho ke 144 km. hora^-1Fumana kakaretso ea mosebetsi holim'a ntho eo.

Tse tsejoang:

Boima ba ntho (m) = 2 kg

Lebelo la pele (v)_o) = 72 km/hora = limithara tse 72,000 / metsotsoana e 3600 = 20 m/s

Lebelo la ho qetela (v)_t) = 144 km/hora = limithara tse 144,000 / metsotsoana e 3600 = 40 m/s

Sebaka sa ntho = limithara tse 400

Ho batloa: Marang-rang hodima ntho

Tharollo:

Khopolo-taba ea matla a kinetic a mosebetsi e bolela hore mosebetsi oa netweke o sebetsa nthong ka tsela e tšoanang le phetoho ea matla a kinetic a ntho.

W net = HO ea ho qetela – HO ea qalong

W nete = ½ mv_t² – ½ mv_o²

W letlooa = ½ m (v_t² - v_o²)

W letlooa = ½ (2)(40² - 20²)

W letlooa = 1600 – 400

W net = 1200 Joule

Tlhaloso:

W = Mosebetsi, KE = matla a kinetic

Matla a kinetic

17. Kulo ea ligrama tse 10 e tsamaeang ka lebelo le sa fetoheng la 100 m/s. Matla a kinetic a kulo ke afe?

Tse tsejoang:

Boima ba kulo (m) = 10 grams = 10/1000 lik'hilograma = 1/100 lik'hilograma = 0.01 lik'hilograma

Lebelo la kulo (v) = limithara tse 100/motsotsoana

Oa Batla: Matla a kinetic

Tharollo:

KE = 1/2 mv²

KE = Karolo e le 'ngoe (0,01 kg)(100 m/s)²

KE = 1/2 (0,01 kg)(10.000 m²/s²)

KE = (0,01 kg)(5000 m²/s²)

KE = 50 kg m²/s²

KE = 50 Joule

[ID ea sephutheloana sa wpdm='1191′]

1. Mosebetsi o etsoang ka mathata a matla le litharollo
2. Mathata le litharollo tsa matla a kinetic a mosebetsi
3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
4. Mathata a matla a khoheli le litharollo
5. Matla a ka bang teng a mathata le litharollo tsa selemo se tenyetsehang
6. Mathata a motlakase le litharollo
7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a sekhutlo
10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

1. Motho o hula boloko bo bolelele ba limithara tse 2 holim'a bokaholimo bo bataletseng ka matla a sa fetoheng F = 20 N. Fumana mosebetsi o etsoang ka likhoka F e sebetsa hodima boloko.

Tse tsejoang:

Matla (F) = 20 N

Ho tlosoa (s) = 2 m

Angle (θ)) = 0

o ne a batla Mosebetsi (W)

Tharollo:

W = F d cos θ = (20)(2)(cos 0) = (20)(2)(1) = 40 Joule

2. Matla F = 10 N a sebetsang lebokoseng la 1 m hodima bokaholimo bo bataletseng. Matla a sebetsa ho 30^o sekhutlo joalo ka ha ho bontšitsoe setšoantšong se ka tlase. Fumana mosebetsi o etsoang ka matla F!

Tsejoa :

Matla (F) = 10 N

Matla a rapameng (F)_x) = F cos 30^o = (10)(0.5√3) = 5√3 N

Ho falla (d) = mithara e le 1

o ne a batla : Mosebetsi (W) ?

tharollo :

W = F_x d = (5√3)(1) = 5√3 Joule

3. 'Mele o oa ka bolokolohi ho tloha phomolong, ho tloha bophahamong ba limithara tse 2. Haeba ho potlaka ka lebaka la matla a khoheli ke 10 m/s², fumana mosebetsi o entsoeng ke matla a khoheli!

Tse tsejoang:

Ntho ea boima (m) = 1 kg

Bolelele (h) = 2 m

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Ho batloa: Mosebetsi o etsoang ka matla a khoheli (W)

Tharollo:

W = F d = wh = mgh

W = (1)(10)(2) = 20 Joule

W = mosebetsi, F = matla, d = sebaka, w = boima ba 'mele, h = bophahamo, m ​​= boima, g = ho potlaka ka lebaka la matla a khoheli.

4. Ntho e boima ba 1-kg e hoketswe sedibeng kahoo e lelefatswa ka 2 cm. Haeba lebelo le bakwang ke matla a khoheli e le 10 m/s², fumana (a) sekgahla sa selemo (b) mosebetsi o etswang ke matla a selemo nthong

Tse tsejoang:

Boima (m) = 1 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Teleletso (x) = 2 cm = 0.02 m

Boima (w) = mg = (1 kg)(10 m/s²) = 10 kg m/s² = 10N

Ho batloa: Nako e sa fetoheng ea selemo le mosebetsi o etsoang ke matla a selemo

Tharollo:

(a) Sephetho sa selemo

Foromo ea Molao oa Hooke :

F = k x.

k = F / x = w / x = mg / x

k = (1)(10) / 0.02 = 10 / 0.02

k = 500 N/m

(b) mosebetsi o etsoang ke matla a selemo

W = – ½ kx²

W = – ½ (500)(0.02)²

W = – (250)(0.0004)

W = -0.1 Joule

Letšoao la ho tlosa le bontša hore tataiso ea matla a selemo e fapane le tataiso ea ho falla ha ntho.

5. Matla F = 10 N a potlakisa lebokose hodima ho falla ha 2 m. Fatse e makukuno mme e na le matla a khohlano F_k = 2 N. Fumana mosebetsi oa letlooa o entsoeng lebokoseng.

Tse tsejoang:

Matla (F) = 10 N

Matla a khohlano ea kinetic (F)_k) = 2 N

Ho falla (d) = 2 m

Ho batloa: Marangrang (W)_letlooa)

Tharollo:

Mosebetsi o etsoang ka matla F:

W₁ = F d cos 0 = (10)(2)(1) = 20 Joule

Mosebetsi o etsoang ka matla a moferefere oa kinetic (F)_k):

W₂ =F_k d = (2)(2)(cos 180) = (2)(2)(-1) = -4 Joules

Marang-rang:

W_letlooa = W.₁ - W₂

W_letlooa = 20 - 4

W_letlooa = 16 Joule

6Mosebetsi o etsoang ka matla F bolokong ke ofe?

Tse tsejoang:

Matla (F) = 12 Newton

Ho falla (d) = limithara tse 4

Oa Batla: Mosebetsi (W)

Tharollo:

W = F d = (12 Newton)(limithara tse 4) = 48 N m = 48 Joule

7. Boloko bo sutumelletsoa ke matla a 200 N. Ho falla ha boloko ke limithara tse 2. Mosebetsi o etsoang bolokong ke ofe?

Tse tsejoang:

Matla (F) = 200 Newton

Ho falla (d) = limithara tse 2

Oa Batla: Mosebetsi (W)

Tharollo:

Mosebetsi:

W = F s

W = (200 Newton)(limithara tse 2)

Bophahamo = 400 N m

W = 400 Joule

8. Mokhanni oa sedan o batla ho paka koloi ea hae hantle ka 0.5 m ka pel'a teraka e leng 10 m ho tloha moo sedan e leng teng. Mosebetsi o hlokoa ke ofe ke oa sedan?

Tse tsejoang:

Ho falla (d) = limithara tse 10 – limithara tse 0.5 = limithara tse 9.5

Matla (F) = 50 Newton

Ho batloa: Mosebetsi (W)

Tharollo:

W = F s

W = (50 Newton)(limithara tse 9.5)

Bophahamo = 475 N m

W = 475 Joule

9.

Mosebetsi o entsoeng ke Tom le Jerry e le hore koloi e ka tsamaea ho fihlela ho limithara tse 4. Matla a sebelisoang ke Tom le Jerry ke 50 N le 70 N.

Tse tsejoang:

Ho falla (ma) = limithara tse 4

Matla a letlooa (F) = 50 Newtons + 70 Newtons = 120 Newtons

Oa Batla: Mosebetsi (W)

Tharollo:

W = F s = (120 Newton)(limithara tse 4) = 480 N m = 480 Joule

10Mokhanni o hula koloi hore koloi e tsamaee ho fihlela ho 1000 cm. Mosebetsi o etsoang koloing ke ofe?

Tse tsejoang:

Matla (F) = 250 Newton

Sebaka (ma) sa ho falla = 1000 cm = 1000/100 metres = 10 metres

Ho batloa: Mosebetsi (W)

Tharollo:

W = F s = (250 Newton)(limithara tse 10) = 2500 N m = 2500 Joule

11. Ho latela setšoantšo se ka tlase, haeba mosebetsi o etsoang ke matla a marang-rang o Li-joule tse 375, fumana hore na ntho e falla hokae.

Tse tsejoang:

Sebetsa (W) = 375 Joule

Matla a marang-rang (ΣF) = 40 N + 10 N – 25 N = 25 Newtons (ka ho le letona)

Ho batloa: Ho tlosoa (d)

Tharollo:

Tekanyo ea mosebetsi:

W = F s

Ho falla ha ntho:

d = W / F = 375 Joule / 25 Newtons

d = 15 limitharas

12. Mesebetsi e ka tlase ho who joalo seke oa etsa mosebetsi is ...

A. Sututsa ntho ho fihlela ho dimithara tse 10

B. Sututsa koloi ho fihlela e tsamaea

C. Sututsa lebota

D. Ke hutse lebokose

Tharollo:

Tekanyo ea mosebetsi:

W = ΣF s

W= mosebetsi, F = lebotho la, d = ho baleha

Bho latela foromo e ka holimo, mosebetsi o etsoang ka likhoka 'me ho na le ho falla.

Karabo e nepahetseng ke C.

13Andrew o sututsa ntho ka matla a 20 N kahoo ntho e tsamaya ka motsamao o chitja ka radius ya dimithara tse 7. Fumana mosebetsi o entsweng ke Andrew ka makgetlo a mabedi. motsamao o chitja.

A. 0 Joule

B. 1400 Joule

C. 1540 Joule

D. 1760 Joule

Tharollo:

Haeba motho a sututsa setulo sa likooa bakeng sa motsamao o chitja habeli, motho le setulo sa likooa ba kgutlela boemong ba bona ba pele, kahoo ho falla ha motho ke lefela.

Ho falla = 0 kahoo mosebetsi = 0.

Karabo e nepahetseng ke A.

14Motho e mong o sutumelletsa ntho fatše ka matla a 350 N. Fatše le na le matla a khohlano a 70 N. Fumana mosebetsi o etsoang ka matla ho tsamaisa ntho ho fihlela limithara tse 6.

A. 45 J

B. 72 J

C. 1680 J

D. 2580 J

Tse tsejoang:

Matla a ho sututsa (F) = 350 Newtons

Matla a khohlano (F)_chelete) = 70 Newton

Ho falla ha ntho (lintho) = limithara tse 6

Oa Batla: Mosebetsi (W)

Tharollo:

Ho na le matla a mabeli a sebetsang nthong, matla a sutumetsang (F) le matla a khohlano (F)._chelete). Matla a sututsang a na le tataiso e tšoanang le ho falla ha ntho hobane matla a sututsang a etsa mosebetsi o motle. Ka lehlakoreng le leng, matla a khohlano a na le tataiso e fapaneng le ho falla ha ntho hoo matla a khohlano a etsang mosebetsi o mobe.

Mosebetsi o etsoang ka matla a ho sutumelletsa:

W = F d = (350 Newton)(limithara tse 6) = 2100 Limithara tsa Newton = 2100 Joule

Mosebetsi o etsoang ka matla a khohlano:

W = – (F_chelete)(s) = – (70 Newton)(limithara tse 6) = – 420 Newton-limithara = – 420 Joule

Marangrang:

W net = 2100 Joule – 420 Joule

W net = 1680 Joule

Karabo e nepahetseng ke C.

15Ntho e sutumelletsoa ke matla a bataletseng a li-Newton tse 14 mokatong o bataletseng ka matla a khohlano a li-Newton tse 10. Fumana mosebetsi oa letlooa oa ho tsamaisa ntho ho fihlela limithara tse 8.

A. 0.5 Joule

B. 3 Joule

C. 32 Joule

D. 192 Joule

Tse tsejoang:

Matla a sutumetsang (F) = 14 Newton

Matla a khohlano (F)_chelete) = 10 Newton

Ho falla ha ntho (d) = limithara tse 8

Oa Batla: Mosebetsi (W)

Tharollo:

Ho na le matla a mabeli a sebetsang nthong, matla a sutumetsang (F) le matla a khohlano (F)._chelete).

Matla a sututsang a na le tataiso e tšoanang le ho falla ha ntho e le hore matla a sututsang a etse mosebetsi o motle. Ka lehlakoreng le leng, matla a khohlano a na le tataiso e fapaneng le ho falla ha ntho e le hore matla a khohlano a etse mosebetsi o mobe.

Mosebetsi o etsoang ka matla a ho sutumelletsa:

W = F s = (14 Newton)(limithara tse 8) = 112 Limithara tsa Newton = 112 Lijoule

Mosebetsi o etsoang ka matla a khohlano:

W = – (F_chelete)(s) = – (10 Newton)(limithara tse 8) = – 80 Limithara tsa Newton = – 80 Lijoule

Marangrang:

W net = 112 Joule – 80 Joule

W net = 32 Joule

Karabo e nepahetseng ke C.

16Fumana mosebetsi oa netweke ho latela setšoantšo se ka tlase.

A. 360 Joule

B. 450 Joule

C. 600 Joule

D. 750 Joule

Tharollo:

Mosebetsi = Matla (F) x ho falla (d)

Mosebetsi = Sebaka sa khutlotharo 1 + sebaka sa khutlotharo + sebaka sa khutlotharo 2

Work = 1/2(40-0)(3-0) + (40-0)(9-3) + 1/2(40-0)(12-9)

Mosebetsi = 1/2(40)(3) + (40)(6) + 1/2(40)(3)

Mosebetsi = (20)(3) + 240 + (20)(3)

Mosebetsi = 60 + 240 + 60

Mosebetsi = 360 Joule

Karabo e nepahetseng ke A.

17. Sekotwana sa patsi se bolelele ba 60 cm se kenngwa fatshe ka ho otloloha. Se otlwa ka hamore ya 10-kg ho tloha bophahamong ba 40 cm hodimo ho patsi. Haeba matla a mahareng a ho hanyetsa a lefatshe e le 2 x 10³ N mme lebelo le bakwang ke matla a khoheli ke 10 m/s², ebe patsi e tla kena ka botlalo mobung ka mora… ho otloa.

A. 4

B. 16

C. 28

D. 30

Tse tsejoang:

Boima ba hamore (m) = 10 kg

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Boima ba hamore (w) = mg = (10)(10) = 100 kg m/s²

Ho tlosa hamore pele e otla patsi (d) = 40 cm = 0.4 metres

Khanyetso ea lehong (F) = 2 x 10³ N = 2000 N

Bolelele ba patsi = 60 cm = 0.6 metres

Ho batloa: TPatsi e tla kena ka ho feletseng mobung ka mora… ho otloa.

Tharollo:

Mosebetsi o entsoeng holim'a hamore ha hamore e tsamaea ho fihlela ho limithara tse 0.4 ke:

W = F d = ws = (100 N)(0.4 m) = 40 Nm = 40 Joule

Mosebetsi o etsoang ke matla a khanyetso a lefats'e:

W = F d = (2000 N)(0.6 m) = 1200 Nm = 1200 Joule

TPatsi e tla kena ka ho feletseng mobung ka mora… ho otloa.

Lijoule tse 1200 / Lijoule tse 40 = 30

Karabo e nepahetseng ke D.

[ID ea sephutheloana sa wpdm='1192′]

1. Mosebetsi o etsoang ka mathata a matla le litharollo
2. Mathata le litharollo tsa matla a kinetic a mosebetsi
3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
4. Mathata a matla a khoheli le litharollo
5. Matla a ka bang teng a mathata le ditharollo tsa selemo se tenyetsehang
6. Mathata a motlakase le litharollo
7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a sekhutlo
10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane

Bala haholoanyane

1. Lefatše la distanta ho tloha Letsatsing ke 149.6 x 10⁶ km 'me nako ea phetohelo ea Lefatše ke selemo se le seng. Bala T² /r³

Tse tsejoang:

T = selemo se le seng, r = 149.6 x 10⁶ km

o ne a batla :T² /r³ = … ?

tharollo :

k = T² /r³ = 1² / (149.6 x 10⁶)³ = 1 / (3348071.9 x 10¹⁸) = 2.98 x 10^-25 selemo²/ km³

2. Kakaretso ea bokahohle (G) = 6.67 x 10^-11 Nm²/ lik'hilograma² le Letsatsi la 1.99 x 10³⁰ kg.

3. Sebaka se mahareng sa Lefatše ho tloha Letsatsing ke 149.6 x 10⁶ km 'me sebaka se tloaelehileng sa Mercury ho tloha Letsatsing ke 57.9 x 10⁶ km. Nako ea phetohelo ea Lefatše ke selemo se le seng, nako ea phetohelo ea Mercury ke efe?

Tse tsejoang:

r ea Lefatše = 149.6 x 10⁶ km

r ea mercury = 57.9 x 10⁶ km

T ea Lefatše = selemo se le seng

Oa Batla: T ea mercury?

Tharollo:

[ID ea sephutheloana sa wpdm='953′]

1. Molao oa Newton oa mathata a khoheli a bokahohleng le litharollo
2. Matla a khoheli, mathata a boima ba 'mele le litharollo
3. Ho potlaka ka lebaka la mathata a matla a khoheli le litharollo
4. Mathata le litharollo tsa sathelaete tsa geosynchronous
5. Mathata le litharollo tsa molao oa Kepler

Bala haholoanyane

1. Bophahamo ba sathelaete e tsamaisanang le geosynchronous ka hodima bokahodimo ba Lefatshe ke bofe?

G = kamehla ea bokahohle = 6.67 x 10^-11 N m²/ lik'hilograma²

M = Lefatše boima = 5.97x10²⁴ kg

T = lihora tse 24 = 24 (metsotsoana e 3600) = metsotsoana e 86,400 = 8.64 x 10⁴ metsotsoana

tharollo

Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = 4.22 x 10⁷ m = 4.22 x 10⁴ km = 42,200 km

Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = 6.38 x 10⁶ m = 6.38 x 10³ km = 6380 km

Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = sathelaete distanta ho tloha bohareng ba Lefatše – radius ea Lefatše

Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = 42,200 km – 6380 km

Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = 35,820km

2. Lebelo la sathelaete e tsamaisanang le jeosynchronous ke lefe?

Kakaretso ea bokahohle (G) = 6.67 x 10^-11 N m²/ lik'hilograma²

Boima ba Lefatše (m_E) = 5.97 x 10²⁴ kg

Sebaka se pakeng tsa sathelaete le setsi sa Lefatše (r) = 4.22 x 10⁷ m

tharollo

kapa sebelisa equation ena

[ID ea sephutheloana sa wpdm='949′]

1. Molao oa Newton oa mathata a khoheli a bokahohleng le litharollo
2. Matla a khoheli, mathata a boima ba 'mele le litharollo
3. Ho potlaka ka lebaka la mathata a matla a khoheli le litharollo
4. Mathata le litharollo tsa sathelaete tsa geosynchronous
5. Mathata le litharollo tsa molao oa Kepler

Bala haholoanyane

1. The distanta Pakeng tsa Motho ea boima ba 40 kg le motho ea boima ba 30 kg ke limithara tse 2. Boholo ba matla a khoheli e 'ngoe le e 'ngoe e sebetsa holim'a e 'ngoe. Bokahohle bo sa fetoheng = 6.67: x 10^-11 N m² /kg²

Tse tsejoang:

m₁ = 40 kg, m₂ = 30 kg, r = 2 m, G = 6.67 x 10^-11 N m² /kg²

Ho batloa: boholo ba matla a khoheli (F) ?

Tharollo:

2. Sebaka se pakeng tsa Lefatše le Khoeli (r) ke 3.84 x 10⁸ m. Matla a khoheli a maholo ao e 'ngoe le e 'ngoe e a sebelisang ho e 'ngoe ke afe?

Tse tsejoang:

Tsa Lefatshe boima (m_E) = 5.97 x 10²⁴ kg

Boima ba Khoeli (m_M) = 7.35 x 10²² kg

Sebaka se pakeng tsa setsi sa Lefatše le setsi sa Khoeli (r) = 3.84 x 10⁸ m

Sephetho sa bokahohleng (G) = 6.67 x 10^-11 N m² /kg²

Oa Batla: Boholo ba matla a khoheli (F)

Tharollo:

3. Sebaka se hokae ho tloha Lefatšeng, boholo ba matla a khoheli a lefats'e le khoeli ke lefela?

Tse tsejoang:

Boima ba lefats'e = 5.97x10²⁴ kg

Boima ba Khoeli = 7.35x10²² kg

Sebaka se pakeng tsa setsi sa Lefatše le setsi sa Khoeli (r) = 3.84 x 10⁸ m.

Sephetho sa bokahohleng (G) = 6.67 x 10^-11 N m² /kg²

Oa Batla: hole le Lefatshe

Tharollo:

Matla a khoheli a net ke lefela.

Sebelisa foromo ea quadratic:

A = – 6.35

B = – 7.68: x 10⁸

C = 87.76 x 10^-14

 

[ID ea sephutheloana sa wpdm='955′]

1. Molao oa Newton oa mathata a khoheli a bokahohleng le litharollo
2. Matla a khoheli, mathata a boima ba 'mele le litharollo
3. Ho potlaka ka lebaka la mathata a matla a khoheli le litharollo
4. Mathata le litharollo tsa sathelaete tsa geosynchronous
5. Mathata le litharollo tsa molao oa Kepler

 

Bala haholoanyane