1. Motho o hula boloko bo bolelele ba limithara tse 2 holim'a bokaholimo bo bataletseng ka matla a sa fetoheng F = 20 N. Fumana mosebetsi o entsoeng ka matla F o sebetsang holim'a boloko.

Tse tsejoang:
Matla (F) = 20 N
Sebaka (s) sa ho falla = 2 m
Sekhutlo (θ ) = 0
Ho Batloa : Mosebetsi (W)
Tharollo:
W = F d cos θ = (20)(2)(cos 0) = (20)(2)(1) = 40 Joules
[irp]
2. Matla F = 10 N a sebetsang lebokoseng la 1 m hodima bokaholimo bo otlolohileng. Matla a sebetsa ka sekhutlo sa 30 o jwalo ka ha ho bontshitswe setshwantshong se ka tlase. Fumana mosebetsi o etswang ka matla F!

Tse tsejoang :
Matla (F) = 10 N
Matla a rapameng (F x ) = F cos 30 o = (10)(0.5√3) = 5√3 N
Ho falla (d) = mithara e le 1
Ho Batloa : Mosebetsi (W)?
Tharollo :
W = F x d = (5√3)(1) = 5√3 Li-joule
3. 'Mele o oa ka bolokolohi phomolong, ho tloha bophahamong ba limithara tse 2. Haeba lebelo le bakoang ke matla a khoheli e le 10 m/s , fumana mosebetsi o etsoang ke matla a khoheli!
Tse tsejoang:
Boima ba ntho (m) = 1 kg
Bolelele (h) = 2 m
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2
Ho batloa: Mosebetsi o entsoeng ka matla a khoheli (W)
Tharollo:
W = F d = wh = mgh
W = (1)(10)(2) = 20 Joule
W = mosebetsi, F = matla, d = sebaka, w = boima , h = bophahamo, m = boima, g = ho potlaka ka lebaka la matla a khoheli.
[irp]
4. Ntho e boima ba 1-kg e hoketswe sedibeng kahoo e lelefatswa ka 2 cm. Haeba lebelo le bakwang ke matla a kgoheli e le 10 m/s 2 , fumana (a) botsitso ba selemo (b) mosebetsi o etswang ke matla a selemo nthong eo
Tse tsejoang:
Boima (m) = 1 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s 2
Teleletso (x) = 2 cm = 0.02 m
Boima (w) = mg = (1 kg)(10 m/s 2 ) = 10 kg m/s 2 = 10 N
Ho batloa: Nako e tsitsitseng ea selemo le mosebetsi o etsoang ke matla a selemo
Tharollo:
(a) Sephetho sa selemo
Foromo ea molao oa Hooke :
F = k x.
k = F / x = w / x = mg / x
k = (1)(10) / 0.02 = 10 / 0.02
k = 500 N/m
(b) mosebetsi o etsoang ke matla a selemo
W = – ½ kx 2
W = – ½ (500)(0.02) 2
W = – (250)(0.0004)
W = -0.1 Joule
Letšoao la ho tlosa le bontša hore tataiso ea matla a selemo e fapane le tataiso ea ho falla ha ntho.
[irp]
5. Matla F = 10 N a potlakisa lebokose holim'a ho falla ha 2 m. Fatše le khopame 'me le na le matla a khohlano F k = 2 N. Fumana mosebetsi oa letlooa o entsoeng lebokoseng.

Tse tsejoang:
Matla (F) = 10 N
Matla a khohlano ea kinetic (F k ) = 2 N
Ho falla (d) = 2 m
Ho batloa: Marang-rang (W net )
Tharollo:
Mosebetsi o etsoang ka matla F:
W 1 = F d cos 0 = (10)(2)(1) = 20 Joule
Mosebetsi o etsoang ka matla a moferefere oa kinetic (F k ):
W 2 = F k d = (2)(2)(cos 180) = (2)(2)(-1) = -4 Dijoule
Marang-rang:
W letlooa = W 1 – W 2
W letlooa = 20 – 4
W net = 16 Joule
6. Mosebetsi o etsoang ka matla F bolokong ke ofe?
Tse tsejoang:
Matla (F) = 12 Newton
Ho falla (d) = limithara tse 4
Ho Batloa: Mosebetsi (W)
Tharollo:
W = F d = (12 Newton)(limithara tse 4) = 48 N m = 48 Joule
[irp]
7. Boloko bo sutumelletsoa ke matla a 200 N. Ho falla ha boloko ke limithara tse 2. Mosebetsi o etsoang bolokong ke ofe?
Tse tsejoang:
Matla (F) = 200 Newton
Ho falla (d) = limithara tse 2
Ho Batloa: Mosebetsi (W)
Tharollo:
Mosebetsi:
W = F s
W = (200 Newton)(limithara tse 2)
Bophahamo = 400 N m
W = 400 Joule
8. Mokhanni oa sedan o batla ho paka koloi ea hae hantle 0.5 m ka pel'a teraka e leng 10 m ho tloha moo sedan e leng teng. Mosebetsi o hlokoa ke ofe ke oa sedan?
Tse tsejoang:
Ho falla (d) = limithara tse 10 – limithara tse 0.5 = limithara tse 9.5
Matla (F) = 50 Newton
Ho Batloa: Mosebetsi (W)
Tharollo:
W = F s
W = (50 Newton)(limithara tse 9.5)
Bophahamo = 475 N m
W = 475 Joule
[irp]
9.

Mosebetsi o entsoeng ke Tom le Jerry e le hore koloi e ka tsamaea ho fihlela ho limithara tse 4. Matla a sebelisoang ke Tom le Jerry ke 50 N le 70 N.
Tse tsejoang:
Ho falla (ma) = limithara tse 4
Matla a letlooa (F) = 50 Newtons + 70 Newtons = 120 Newtons
Ho Batloa: Mosebetsi (W)
Tharollo:
W = F s = (120 Newton)(limithara tse 4) = 480 N m = 480 Joule
10. Mokhanni o hula koloi hore koloi e tsamaee ho fihlela ho 1000 cm. Mosebetsi o etsoa koloing ke ofe?
Tse tsejoang:
Matla (F) = 250 Newton
Sebaka (ma) sa ho falla = 1000 cm = 1000/100 metres = 10 metres
Ho Batloa: Mosebetsi (W)
Tharollo:
W = F s = (250 Newton)(limithara tse 10) = 2500 N m = 2500 Joule
11. Ho latela setšoantšo se ka tlase, haeba mosebetsi o etsoang ka matla a letlooa e le 375 Joules, fumana ho falla ha ntho.

Tse tsejoang:
Mosebetsi (W) = 375 Joule
Matla a marang-rang ( ΣF) = 40 N + 10 N – 25 N = 25 Newtons ( ka ho le letona )
Ho Batloa: Ho falla ( d )
Tharollo:
Tekanyo ea mosebetsi:
W = F s
Ho falla ha ntho:
d = W / F = 375 Joule / 25 Newtons
d = limithara tse 15 s
12. Mesebetsi e ka tlase e sa sebetseng ke …
A. Sututsa ntho ho fihlela ho dimithara tse 10
B. Sututsa koloi ho fihlela e tsamaea
C. Sututsa lebota
D. Ke hutse lebokose
Tharollo:
Tekanyo ea mosebetsi:
W = ΣF s
W = mosebetsi , F = matla , d = ho falla
Ho latela foromo e ka holimo, mosebetsi o etsoa ka matla 'me ho na le ho falla.
Karabo e nepahetseng ke C.
1 3. Andrew o sututsa ntho ka matla a 20 N kahoo ntho e tsamaya ka motsamao o chitja ka radius ya dimithara tse 7. Fumana mosebetsi o entsweng ke Andrew bakeng sa motsamao o chitja o makgetlo a mabedi.
A. 0 Joule
B. 1400 Joule
C. 1540 Joule
D. 1760 Joule
Tharollo:
Haeba motho a sututsa setulo sa likooa ka motsamao o chitja habeli, motho eo le setulo sa likooa ba khutlela boemong ba bona ba pele, kahoo ho falla ha motho eo ke lefela.
Ho falla = 0 kahoo mosebetsi = 0.
Karabo e nepahetseng ke A.
14. Motho e mong o sutumelletsa ntho fatše ka matla a 350 N. Fatše le na le matla a khohlano a 70 N. Fumana mosebetsi o etsoang ka matla ho tsamaisa ntho ho fihlela limithara tse 6.
A. 45 J
B. 72 J
C. 1680 J
D. 2580 J
Tse tsejoang:
Matla a ho sututsa (F) = 350 Newtons
Matla a khohlano (F fric ) = 70 Newtons
Ho falla ha ntho (lintho) = limithara tse 6
Ho Batloa: Mosebetsi (W)
Tharollo:
Ho na le matla a mabeli a sebetsang nthong, matla a sutumetsang (F) le matla a khohlano (F fric ). Matla a sutumetsang a na le tataiso e tšoanang le ho falla ha ntho hobane matla a sutumetsang a etsa mosebetsi o motle. Ka lehlakoreng le leng, matla a khohlano a na le tataiso e fapaneng le ho falla ha ntho hoo matla a khohlano a etsang mosebetsi o mobe.
Mosebetsi o etsoang ka matla a ho sutumelletsa:
W = F d = (350 Newton)(limithara tse 6) = 2100 Limithara tsa Newton = 2100 Joule
Mosebetsi o etsoang ka matla a khohlano:
W = – (F fric )(s) = – (70 Newton)(limithara tse 6) = – 420 Newton-meters = – 420 Joule
Marangrang:
W net = 2100 Joule – 420 Joule
W net = 1680 Joule
Karabo e nepahetseng ke C.
15. Ntho e sutumelletsoa ke matla a bataletseng a li-Newton tse 14 mokatong o bataletseng ka matla a khohlano a li-Newton tse 10. Fumana mosebetsi oa letlooa oa ho tsamaisa ntho ho fihlela limithara tse 8.
A. 0.5 Joule
B. 3 Joule
C. 32 Joule
D. 192 Joule
Tse tsejoang:
Matla a sutumetsang (F) = 14 Newton
Matla a khohlano (F fric ) = 10 Newtons
Ho falla ha ntho (d) = limithara tse 8
Ho Batloa: Mosebetsi (W)
Tharollo:
Ho na le matla a mabeli a sebetsang nthong, matla a sutumetsang (F) le matla a khohlano (F fric ).
Matla a sututsang a na le tataiso e tšoanang le ho falla ha ntho e le hore matla a sututsang a etse mosebetsi o motle. Ka lehlakoreng le leng, matla a khohlano a na le tataiso e fapaneng le ho falla ha ntho e le hore matla a khohlano a etse mosebetsi o mobe.
Mosebetsi o etsoang ka matla a ho sutumelletsa:
W = F s = (14 Newton)(limithara tse 8) = 112 Limithara tsa Newton = 112 Lijoule
Mosebetsi o etsoang ka matla a khohlano:
W = – (F fric )(s) = – (10 Newton)(limithara tse 8) = – 80 Limithara tsa Newton = – 80 Lijoule
Marangrang:
W net = 112 Joule – 80 Joule
W net = 32 Joule
Karabo e nepahetseng ke C.
16. Fumana mosebetsi oa netweke ho latela setšoantšo se ka tlase.
A. 360 Joule
B. 450 Joule
C. 600 Joule
D. 750 Joule
Tharollo:
Mosebetsi = Matla (F) x ho falla (d)
Mosebetsi = Sebaka sa khutlotharo 1 + sebaka sa khutlotharo + sebaka sa khutlotharo 2
Work = 1/2(40-0)(3-0) + (40-0)(9-3) + 1/2(40-0)(12-9)
Mosebetsi = 1/2(40)(3) + (40)(6) + 1/2(40)(3)
Mosebetsi = (20)(3) + 240 + (20)(3)
Mosebetsi = 60 + 240 + 60
Mosebetsi = 360 Joule
Karabo e nepahetseng ke A.
17. Sekotwana sa patsi se bolelele ba 60 cm se kentswe mobung ka ho otloloha. Patsi e otlwa ka hamore ya 10-kg ho tloha bophahamong ba 40 cm hodimo ho patsi. Haeba matla a mahareng a khanyetso ya lefatshe e le 2 x 10 3 N mme lebelo le bakwang ke matla a kgoheli e le 10 m/s 2 , patsi e tla kena mobung ka botlalo kamora ho… otla.
A. 4
B. 16
C. 28
D. 30
Tse tsejoang:
Boima ba hamore (m) = 10 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/ s 2
Boima ba hamore (w) = mg = (10)(10) = 100 kg m/s 2
Ho tlosa hamore pele e otla patsi (d) = 40 cm = 0.4 metres
Khanyetso ea lehong (F) = 2 x 10 3 N = 2000 N
Bolelele ba patsi = 60 cm = 0.6 metres
Ho batloa: Patsi e tla kena ka botlalo mobung kamora ho… otla.
Tharollo:
Mosebetsi o entsoeng holim'a hamore ha hamore e tsamaea ho fihlela ho limithara tse 0.4 ke:
W = F d = ws = (100 N)(0.4 m) = 40 Nm = 40 Joule
Mosebetsi o etsoang ke matla a khanyetso a lefats'e:
W = F d = (2000 N)(0.6 m) = 1200 Nm = 1200 Joule
Patsi e tla kena ka botlalo mobung kamora… ho otloa.
Lijoule tse 1200 / Lijoule tse 40 = 30
Karabo e nepahetseng ke D.
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