1. Bophahamo ba sathelaete e tsamaisanang le geosynchronous ka hodima bokahodimo ba Lefatshe ke bofe?
G = boleng bo sa fetoheng ba bokahohle = 6.67 x 10 -11 N m 2 /kg 2
M = Boima ba Lefatše = 5.97 x 10 24 kg
T = lihora tse 24 = 24 (metsotsoana e 3600) = metsotsoana e 86,400 = 8.64 x 10 metsotsoana e 4
tharollo

Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = 4.22 x 10 7 m = 4.22 x 10 4 km = 42,200 km
Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = 6.38 x 10 6 m = 6.38 x 10 3 km = 6380 km
Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = sebaka sa sathelaete ho tloha bohareng ba Lefatše - radius ea Lefatše
Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = 42,200 km - 6380 km
Bophahamo ba sathelaete ka holim'a bokaholimo ba Lefatše = 35,820 km
[irp]
2. Lebelo la sathelaete e tsamaisanang le jeosynchronous ke lefe?
Sephetho sa bokahohleng (G) = 6.67 x 10 -11 N m 2 /kg 2
Boima ba Lefatše (m E ) = 5.97 x 10 24 kg
Sebaka se pakeng tsa sathelaete le setsi sa Lefatše (r) = 4.22 x 10 7 m
tharollo

kapa sebelisa equation ena

[ID ea sephutheloana sa wpdm='949′]
- Molao oa Newton oa mathata a khoheli a bokahohleng le litharollo
- Matla a khoheli, mathata a boima ba 'mele le litharollo
- Ho potlaka ka lebaka la mathata a matla a khoheli le litharollo
- Mathata le litharollo tsa sathelaete tsa geosynchronous
- Mathata le litharollo tsa molao oa Kepler