1. Lebokose la boima ba 2 kg le theoha ka lebelo ho tloha ho 10 m/s ho ea phomolong. Coefficient ea kinetic friction ke 0.2. Potlako e bakoang ke matla a khoheli ke 10 m/s 2. Boholo ba ho falla ke bofe?

Tsejoang;
Boima (m) = 2 kg
Lebelo la pele (vo o ) = 10 m/s
Lebelo la ho qetela (v t ) = 0 m/s
Koefficient ea ho ferekana ha kinetic ( μk ) = 0.2
Boima (w) = mg = (1 kg)(10 m/s 2 ) = 10 kg m/s 2 = 10 N
Ho batloa: Boholo ba ho falla (d)
Tharollo:
Molao-motheo oa matla a mosebetsi le mechine :
W nc = ΔEM
W nc = ΔEK + ΔEP
W nc = ½ m (v t 2 – vo 2 ) + mgh
W nc = mosebetsi o etsoang ke matla a sa laoleheng a sebetsang nthong eo
ΔEK = phetoho ea matla a kinetic
ΔEP = phetoho ea matla a ka bang teng
m = boima
v = lebelo
g = ho potlaka ka lebaka la matla a khoheli
h = phetoho bophahamong
Phetoho bophahamong h = 0 kahoo ΔEP = 0
W nc = ΔEK
Mosebetsi o etsoang ke matla a sa batleng mekhoa ea khale:
W nc = -F c d = – μ k N d = – μ k wd = – μ k mgd
W nc = -(0.2)(2)(10)(s)
W nc = – (4)(2)
Letšoao la ho tlosa le bontša hore tataiso ea matla a khohlano ea kinetic e fapane le tataiso ea ho falla.
Phetoho ea matla a kinetic:
ΔEK = ½ m (v t 2 – v o 2 ) = ½ (2) (0 – 10 2 ) = 0 – 100 = -100
Boholo ba ho falla:
W nc = ΔEK
– 4 s = – 100
s = -100/-4
s = 25 m
2. Boloko bo thella fatshe hodima sefofane se sekametseng. Coefficient ya kinetic friction ke 0.4. Ho potlaka ka lebaka la matla a khoheli ke g = 10 ms -2 . Fumana lebelo la ho qetela ha boloko bo otla fatshe.
Tse tsejoang:
Bolelele ba pele (h o ) = 6 m
Bolelele ba ho qetela (h t ) = 0 m
Lebelo la pele (v o ) = 0
Koefficient ea ho ferekana ha kinetic ( μk ) = 0.4
Ho potlaka ka lebaka la matla a khoheli (g) = 10 ms -2
cos θ = 8/10
Karolo e otlolohileng ea boima = w y = w cos θ = mg cos θ = m (10) (8/10) = m (10)(4/5) = m (40/5) = 8 m
Matla a tloaelehileng = N = w y = 8 m
Matla a kgohlano ya kinetic = f k = μ k N = μ k w y = (0.4)(8 m) = 3.2 m
Ho batloa: Lebelo la ho qetela (v t )
Tharollo:
Molao-motheo oa matla a mosebetsi le mechine:
W nc = Δ EM
W nc = Δ EK + Δ EP
Phetoho ea matla a kinetic:
ΔEK = 1/2 m (vt2 - vo2) = 1/2 m (vt2 - 0) = 1/2 mvt2
Phetoho ea matla a ka bang teng:
Δ EP = mg (h t – ho ) = m (10)(0-6) = m (10)(-6) = – 60 m
Mosebetsi o etsoang ka matla a moferefere oa kinetic:
W nc = – f ks = – ( 3.2 m)(10) = – 32 m
Letšoao la ho tlosa le bontša hore tataiso ea matla a khohlano ea kinetic e fapane le tataiso ea ho falla.
Lebelo la ho qetela (v t ):
W nc = Δ EK + Δ EP
– 32 m = 1/2 mv t 2 – 60 m
– 32 m = m (1/2 v t 2 – 60)
– 32 = 1/2 v t 2 – 60
– 32 + 60 = 1/2 v t 2
28 = 1/2 v t 2
2 (28) = v t 2
56 = v t 2
v t = √4.14
v t = 2 √14 ms -1
3. Boloko bo thella fatshe sefofaneng se sekametseng ka tsela e sa tsitsang. Lebelo la pele ke 0 m/s mme lebelo la ho qetela ke 10 ms -1 . Haeba matla a kgohlano ya kinetic e le 2 N mme ho potlaka ka lebaka la matla a kgoheli g = 10 ms -2 , bolelele (h) ke eng?
Tse tsejoang:
Boima (m) = 1 kg
Lebelo la pele (v o ) = 0 (phomolo ea boloko)
Lebelo la ho qetela (v t ) = 10 ms -1
Bolelele ba pele (h o ) = h
Bolelele ba ho qetela (h t ) = 0
Matla a khohlano ea kinetic (f k ) = 2 N
Ho potlaka ka lebaka la matla a khoheli (g) = 10 ms -2
Ho batloa: Bolelele (h)
Tharollo:
Mosebetsi o etsoang ka matla a moferefere oa kinetic:
W nc = – f ks = – (2 )(15) = – 30
Letšoao la ho tlosa le bontša hore tataiso ea matla a khohlano ea kinetic e fapane le tataiso ea ho falla.
Phetoho ea matla a kinetic:
ΔEK = 1/2 m (vt2 - vo2) = 1/2 (1)(102 - 0) = 1/2 (102) = 1/2 (100= 50
Phetoho ea matla a ka bang teng:
Δ EP = mg (h t – ho ) = (1)(10)(0-h) = (10)(-h) = -10 h
Molao-motheo oa matla a mosebetsi le mechine:
W nc = Δ EK + Δ EP
– 30 = 50 – 10 dihora
Lihora tse 10 = 50 + 30
Lihora tse 10 = 80
h = 80/10
h = 8 m
4Haeba boloko bo theoha ka tsela e sekametseng hanyane, joale….
A. Mosebetsi o etsoang ke matla a khoheli holim'a boloko o moholo ho feta phetoho ea matla a ka bang teng a boloko.
B. Matla a mechini aa eketseha
C. Bongata ba matla a kinetic le matla a ka bang teng a fokotsehile
D. Mosebetsi o etsoa ke matla a khohlano a lekanang le phetoho ea matla a kinetic a block
tharollo
A e fositse
Mosebetsi o etsoang ke matla a khoheli holim'a boloko o lekana le phetoho ea matla a khoheli a boloko.
B o fositse
Haeba sefofane se nang le mola o ka hare se boreleli, matla a mechini a boloko ha a fetohe. Ha se le ka holimo ho sefofane se sekametseng mme se sa sisinyehe, matla a mechini a boloko a lekana le matla a khoheli a khoheli. Boloko bo ntse bo phomotse kahoo matla a sona a kinetic ke lefela. Ha se theohela tlase sefofaneng se sekametseng, bophahamo ba boloko boa fokotseha kahoo matla a khoheli a khoheli le ona aa fokotseha. Matla a khoheli a fokotseha hobane a fetoha matla a kinetic. Le hoja matla a khoheli a fetoha matla a kinetic empa matla a mechini a lula a le teng.
Haeba sefofane se sekametseng se le thata, matla a mechini a boloko aa fokotseha ka lebaka la mosebetsi o mobe o etsoang ke matla a khohlano. Matla a khohlano ke matla a sa bolokeng. Mosebetsi o etsoang ke matla a sa bolokeng nthong o etsa hore matla a mechini a ntho a fokotsehe.
C e nepahetse
Sefofane se sekametseng se makukuno kahoo ho na le matla a khohlano a phephetsang motsamao oa block. Matla a khohlano ke matla a sa bolokeng. Matla a mosebetsi-mechanical a theorem a bolela hore mosebetsi o etsoang ke matla a sa bolokeng (mohlala, matla a khohlano) o lekana le phetoho ea matla a mechini. Leetong lena, matla a mechini aa fokotseha.
Matla a mechine a boloko = matla a khoheli a ka bang teng + matla a kinetic.
D o fositse.
Mosebetsi o etsoang ke matla a khohlano bolokong o lekana le phetoho ea matla a mechini a boloko, eseng phetoho ea matla a kinetic a boloko. Ke 'nete hore matla a khohlano a phephetsa motsamao oa boloko kahoo a fokotsa lebelo la boloko 'me a fokotsa matla a kinetic a boloko. Empa hlokomela hore matla a kinetic a boloko a tsoa matla a khoheli a ka bang teng. Kahoo ke 'nete hore mosebetsi o etsoa ke matla a khohlano a lekanang le phetoho ea matla a mechini (matla a mechini aa fokotseha).
Karabo e nepahetseng ke C.
5. Ntho e mokatong o bataletseng e otloa kahoo e tsamaea metsotsoana e 3 ebe ea ema. Haeba boima bo tsejoang ba ntho eo e le ligrama tse 10, matla a khohlano pakeng tsa ntho le mokatong ke lik'hilojule tse 2. Fumana mosebetsi o etsoang ke matla a khohlano.
A. 0.18 J
B. -0.18 J
C. 0.36 J
D. -0.36 J
Tse tsejoang:
Nako ea ho arohana (t) = metsotsoana e 3
Lebelo la ho qetela (v t ) = 0 m/s (phomolo ea ntho)
Boima ba ntho (m) = 10 grams = 10/1000 kg = 1/100 kg = 0.01 kg
Matla a khohlano (F) = 2 kilodynes = 2 x 10 3 dynes
Ho batloa: Mosebetsi (W) o etsoang ke matla a khohlano
Tharollo:
Phetoho ea li-unit tsa matla:
1 Newton = 1 x 10 5 dyne
Dyne e le 1 = 1 / 10 5 Li-Newton = 1 x 10 -5 Li-Newton = 10 -5 Li-Newton
Matla a khohlano (F) = 2 x 10 3 dyne = 2 x 10 3 x 10 -5 Newton = 2 x 10 -2 Newton = 2/100 Newton = 0.02 Newton
Mosebetsi oa theorem-matla a mechini a bolela hore mosebetsi o etsoa ke matla a sa bolokeheng nthong e lekanang le phetoho ea matla a mechini a ntho.
Haeba ntho e tsamaya sefofaneng se sekametseng, matla a mechini (ME) = matla a khoheli (PE) + matla a kinetic (KE). Empa haeba ntho e tsamaya feela sefofaneng se otlolohileng kahoo ho se na phetoho bophahamong, matla a mechini = matla a kinetic. Sebakeng se otlolohileng, matla a khoheli ke lefela hobane ha ho na phetoho bophahamong.
Matla a khohlano ke matla a sa bolokeheng. Matla a khohlano hangata a fokotsa lebelo la ntho le matla a kinetic a ntho. A ka etsa qeto ea hore mosebetsi o etsoang ke matla a khohlano nthong o lekana le ho fokotseha ha matla a mechini.
Ka lipalo:
Mosebetsi (W) = Phetoho ea matla a mechini (ΔEM)
F s = ΔEP + ΔEK
F s = mg Δh + ½ m (v t 2 – vo 2 )
F s = mg (0) + ½ m (0 2 – v o 2 )
Fs = 0 + ½ m (– (v o 2 ))
F s = – ½ mv o 2 ———— Tekanyo 1
Tlhaloso: F = matla a khohlano, d = ho falla, m = boima, v o = lebelo la pele
Ho falla (d) le lebelo la pele (vo o ) ha li so tsejoe hobane pele bala v o kapa d. Mosebetsi o etsoang ke matla a khohlano o baloang ho sebelisoa e 'ngoe ea li-equation kamora v o kapa d e tsejoang.
Tekanyo ea ho falla (d) motsamaong o sa lekanang oa mola o otlolohileng:
v t 2 = v o 2 + 2 (-a) s
Lebelo la ho qetela (v t ) = 0 mme ho potlakisa (a) ho saennwe ka negative hobane ntho e fokotsehile (lebelo la ntho le fokotsehile).
0 = vo2 – lipapatso tse 2
vo2 = Papatso e 2
d = v o 2 / 2 a ———— Tekanyo ea 2
Phetoho ea d ho equation ea 2 le d ho equation ea 1:
F d = – ½ mv o 2
F (v o 2 /2a) = – ½ mv o 2
(F/2a) v o 2 = – ½ mv o 2
F/2a = – ½ m
F = (2)(a)(-1/2)(m)
F = – (a)(m)
a = – (F / m)
a = – 0.02 Newtons / 0.01 lik'hilograma
a = – 2 Newton/kilogerama
a = – 2 m/s 2
Tekanyo ea ho bala lebelo la pele (v o ) motsamaong o sa lekanang oa mola o otlolohileng:
v t = vo o + ho —–> Lebelo la ho qetela (v t ) = 0, Ho potlaka (a) = 2 m/s 2 , nako e sa fellang (t) = metsotsoana e 3
0 = v o + (-2)(3)
0 = v o – 6
v o = limithara tse 6/motsotsoana
Mosebetsi (W) o etsoang ke matla a khohlano:
W = – ½ mv o 2 = -1/2 (0.01) (6 2 ) = -1/2 (0.01) (36)
W = -1/2 (0.36)
W = – 0.18 Joule
Mosebetsi o etsoang ke matla a khohlano o saennoe ka hore o na le moelelo o fosahetseng, ho bolelang hore mosebetsi o fokotsa matla a mechini a ntho.
Haeba ho tsejoa d, mosebetsi o ka baloa ho sebelisoa equation ea W = F d.
Karabo e nepahetseng ke B.
[ID ea sephutheloana sa wpdm='1178′]
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