1. Kerafo ea matla (F) khahlanong le ho lelefala (x ) e bontšitsoe setšoantšong se ka tlase. Fumana botsitso ba selemo!
tharollo
k = F / x
F = matla (Newton)
k = nako e sa fetoheng ea selemo (Newton/mithara)
x = phetoho ea bolelele (limithara)
Nako e tsitsitseng ea selemo:
k = 10 / 0.02 = 20 / 0.04
k = 500 N/m
[irp]
2. Fumana hore na selemo se tiile hakae.
tharollo
Nako e tsitsitseng ea selemo:
k = F / x
k = 5 / 0.01 = 10 / 0.02 = 15 / 0.03 = 20 / 0.04
k = 500 N/m
[irp]
3. Selemo A se na le bolelele ba pele ba 60 cm mme selemo B se na le bolelele ba pele ba 90 cm. Selemo A se na le botsitso ba 100 N/m, selemo B se na le botsitso ba 200 N/m. Karolelano ea phetoho boleleleng ba selemo A ho ea phetohong ea bolelele ba selemo B ke…
Tse tsejoang:
Sephetho sa selemo A (k A ) = 100 N/m
Sephetho sa selemo B (k B ) = 200 N/m
Matla a selemo A (F A ) = F
Matla a selemo B (F B ) = F
Ho batloa: Δl A : Δl B
Tharollo:
Foromo ea molao oa Hooke:
Δl = F / k
Δl = phetoho ea bolelele, F = matla, k = e sa fetoheng
Phetoho boleleleng ba selemo A:
Δl A = F A / k A = F / 100
Phetoho boleleleng ba selemo sa B:
Δl B = F B / k B = F / 200
Karolelano ea phetoho boleleleng ba selemo A ho ea phetohong boleleleng ba selemo B:
Δl A : Δl B
F/100 : F/200
1/100: 1/200
1/1: 1/2
2: 1
[irp]
4. Thapo ea naelone e bolelele ba pele ba 20 cm, e huloa ke matla a 10 N. Phetoho ea bolelele ba khoele ke 2 cm. Fumana boholo ba matla haeba phetoho ea bolelele e le 6 cm.
Tse tsejoang:
Matla (F) = 10 N
Phetoho ea bolelele ( Δl ) = 2 cm = 0.02 m
Ho batlwa : boholo ba matla (F) haeba Δl = 0.06 m.
Tharollo:
Kamehla:
k = F / Δl
k = 10 / 0.02 = 500 N/m
Boholo ba matla (F) haeba Δl = 0.06 m :
F = kx
F = (500)(0.06)
F = 30N
[irp]
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