Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao o otlolohileng nakong ea ho oa ka bolokolohi - mathata le litharollo

1. Motho o lahlela lejoe la boima ba 1-kg hodimo ka lebelo la 2 m/s ha a ntse a eme moeding wa lefika e le hore lejwe le ka wela botlaaseng ba lefika le dimithara tse 40 ka tlase. Matla a kinetic a lejwe a dimithara tse 10 ka hodima lefatshe ke afe? Ho potlaka ka lebaka la matla a kgoheli g = 10 m/s ².

Tse tsejoang:

Boima (m) = 1 kg

Lebelo la pele (vo _o ) = 2 m/s

Phetoho ea bophahamo = 40 - 10 = limithara tse 30

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Ho batloa: matla a kinetic a lejoe a limithara tse 10 ka holim'a lefatše

Tharollo:

Matla a pele a mechini

Matla a pele a khoheli (EP) = mgh = (1)(10)(30) = 300 Joules

Matla a kinetic a pele (KE) = ½ mv _o ² = ½ (1)(2) ² = ½ (4) = 2 Joules

Matla a pele a mechini = matla a pele a khoheli + matla a pele a kinetic = 300 + 2 = 302 Joules.

Matla a ho qetela a mechini

Matla a ho qetela a mechini = matla a ho qetela a kinetic = matla a pele a khoheli + matla a pele a kinetic = 300 + 2 = 302 Joules.

2. Motho o lahlela ntho e boima ba 1-kg hodimo moyeng ka lebelo la pele la 10 m/s. Fumana (a) matla a kgoheli a ka bang teng bophahamong bo phahameng ka ho fetisisa (b) bophahamo bo boholo ka ho fetisisa.

Ho potlaka ka lebaka la matla a khoheli ke 10 m/s ²

Tse tsejoang:

Boima (m) = 1 kg

Lebelo la pele (vo _o ) = 10 m/s

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s ²

Ho batloa : matla a khoheli a ka bang teng bophahamong bo phahameng ka ho fetisisa le bophahamong bo phahameng ka ho fetisisa

Tharollo:

(a) matla a khoheli a bophahamo bo phahameng ka ho fetisisa

Matla a pele a mechini:

Matla a pele a mechini (ME) = matla a pele a kinetic (KE) = ½ mv _o ² = ½ (1)(10) ² = ½ (100) = 50 Joules.

Matla a ho qetela a mechini:

Matla a ho qetela a mechini (ME) = matla a khoheli a ka bang teng (PE)

Molao-motheo oa paballo ea matla a mechini:

Matla a pele a mechini = matla a ho qetela a mechini

KE = PE

50 = PE

Matla a khoheli a ka bang teng ke 50 Joules.

(b) Bophahamo bo phahameng ka ho fetisisa

PE = mgh

50 = (1)(10) h

50 = lihora tse 10

h = 50 / 10 = limithara tse 5

Bophahamo bo phahameng ka ho fetisisa ke limithara tse 5 ka holimo ho mobu.

[ID ea sephutheloana sa wpdm='1174′]

1. Mosebetsi o etsoang ka mathata a matla le litharollo
2. Mathata le litharollo tsa matla a kinetic a mosebetsi
3. Mathata le litharollo tsa motheo oa matla a sebetsang le a mechini
4. Mathata a matla a khoheli le litharollo
5. Matla a ka bang teng a mathata le ditharollo tsa selemo se tenyetsehang
6. Mathata a motlakase le litharollo
7. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa ho oa ka bolokolohi
8. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa holimo le tlase motsamaong oa ho oa ka bolokolohi
9. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao holim'a bokaholimo bo kobehileng
10. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao sefofaneng se sekametseng
11. Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane