Mathata a rarollotsoeng melaong ea Newton ea motsamao – Matla a khohlano e sa fetoheng le ea kinetic
1. Ntho e lutse mokatong o bataletseng. Koefficient ea khohlano e sa fetoheng ke 0.4 'me ho potlaka ha matla a khoheli ke 9.8 m/s 2. Fumana (a) Matla a maholo a khohlano e sa fetoheng (b) Matla a bonyane a F
tharollo
Tse tsejoang:
Boima (m) = 1 kg
Koefficient ea khohlano e sa fetoheng (μ s ) = 0.4
Ho potlaka ha matla a khoheli (g) = 9.8 m/s 2
Boima (w) = mg = (1 kg)(10 m/s 2 ) = 10 kg m/s 2 = 10 Li-Newton
Matla a tloaelehileng (N) = w = 10 Newtons
Ho batloa:
(a) Matla a maholo a khohlano e sa fetoheng (b) Matla a bonyane a F
Tharollo:
(a) Matla a maholohali a khohlano e sa fetoheng
fs = μs N
f s = (0.4)(9.8 N) = 3.92 Newton
(b) Matla a bonyane a F
Haeba matla a F a sebediswa nthong empa ntho e sa sisinyehe, kahoo ho tlameha ho be le matla a kgohlano e sa fetoheng a sebediswang ke fatshe nthong eo. Haeba ntho e tla qala ho tsamaya, matla a kgohlano e sa fetoheng a feta, ho tlameha ho be le matla a kgohlano ya kinetic. Ntho e qala ho tsamaya haeba F e le kgolo ho feta matla a hodimo a kgohlano e sa fetoheng.
Kahoo matla a bonyane a F = matla a maholo a khohlano e sa fetoheng = 3.92 Newtons.
2. Lebokose la 1 kg le hulwa hodima bokahodimo bo bataletseng ke matla a F, kahoo lebokose le tsamaya ka lebelo le sa fetoheng. Haeba coefficient ya kinetic friction e le 0.1, fumana boholo ba matla a F! (g = 9.8 m/s 2 )
Tse tsejoang:
Koefficient ea kinetic friction ( μk ) = 0.1
Boima ba lebokose (m) = 1 kg
Ho potlaka ha matla a khoheli (g) = 9.8 m/s 2
Boima (w) = mg = (1 kg)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 Newtons
Matla a tloaelehileng (N) = w = 9.8 Newtons
Ho batloa : F
Tharollo:
Molao oa pele oa Newton o re haeba ho se na matla a letlooa a sebetsang nthong, ntho e 'ngoe le e 'ngoe e tsoela pele boemong ba eona ba ho phomola, kapa lebelo le sa fetoheng moleng o otlolohileng.
Kahoo haeba ntho e tsamaya ka lebelo le sa fetoheng , ha hoa lokela hore ho be le matla a letlooa ( Σ F = 0) . Matla F a sebelisoa nthong ka tsela e nepahetseng e le hore matla a kinetic friction a sebelisoe nthong ka lehlakoreng le letšehali.
∑ F = 0
F – f k = 0
F = f k
Matla a moferefere oa kinetic:
f k = μ k N = (0.1) (9.8 N) = 0.98 Newtons
ntho e tsamaya ka lebelo le sa fetoheng, F = f k = 0.98 Newtons
3. Ntho e thella fatshe sefofaneng se sekametseng ka lebelo le sa fetoheng. Fumana coefficient ya kinetic friction ( μk ) . g = 9.8 m/s 2
tharollo
w = boima, w x = karolo e rapameng ea boima, lintlha tse pela moepa, w y = karolo e otlolohileng ea boima, e otlolohileng ho sefofane se sekametseng, N = matla a tloaelehileng, f k = matla a khohlano ea kinetic.
Tse tsejoang:
Boima (m) = 1 kg
Ho potlaka ha matla a khoheli (g) = 9.8 m/s 2
boima (w) = mg = (1 kg)(9.8 m/s 2 ) = 9.8 kg m/s 2 = 9.8 Li-Newton
w x = w sin 30 o = (9.8 N)(0.5) = 4.9 Newton
w y = w cos 30 o = (9.8 N)(0.5) √ 3 = 4.9 √ 3 Li-Newton
Matla a tloaelehileng (N) = w y = 4.9 √ 3 Newtons
Ho batloa : coefficient ea kinetic friction ( μk )
Tharollo:
Ntho e thellisa fatshe sefofaneng se sekametseng ka lebelo le sa fetoheng e le hore matla a letlowa = 0.
∑ F = 0
w x – f k = 0
w x = f k
w x = μ k N
5 = μ k ( 5 √ 3 )
μ k = 5 / 5 √ 3
μ k = 1 / √ 3
μ k = 0.58
[ID ea sephutheloana sa wpdm='472′]
- Boima le boima
- Matla a tloaelehileng
- Molao oa bobeli oa Newton oa ho sisinyeha
- Matla a khohlano
- Motsamao holim'a bokaholimo bo otlolohileng ntle le matla a khohlano
- Motsamao oa 'mele e 'meli ka lebelo le tšoanang holim'a sebaka se bataletseng se bataletseng ka matla a khohlano
- Motsamao sefofaneng se sekametseng ntle le matla a khohlano
- Motsamao sefofaneng se sekametseng ka thata ka matla a khohlano
- Motsamao ka lifting
- Motsamao oa 'mele o hokahaneng ka lithapo le li-pulley
- 'Mele e 'meli e nang le boholo bo tšoanang ba ho potlaka
- Ho potoloha mothapo o bataletseng - matla a motsamao o chitja
- Ho potoloha mothapo o kobehileng - matla a motsamao o chitja
- Motsamao o tšoanang ka selikalikoe se otlolohileng
- Matla a bohareng a motsamao o chitja o tšoanang
