Marangrang a Gurumuda
Lipotso tse 3 mabapi le equation ea matla a khoheli
1. Dikaroloana tse tharo ka nngwe tse nang le boima ba 1 kg di hodima dikhutlotharo tse lekanang tseo mahlakore a tsona a bolelele ba 1 m. Matla a kgoheli a fumanwang ke karoloana ka nngwe ya ntlha (ho G) a maholo hakae?
tharollo
Boholo ba matla a khoheli a bonoang ke e 'ngoe ea likaroloana.
F12 = G (m1)(m2) / r2 = G (1)(1) / 12 = G/1 = G
F13 = G (m1)(m3) / r2 = G (1)(1) / 12 = G/1 = G
Matla a khoheli a hlahang ntlheng ea 1:
Lipotso tse 3 mabapi le li-equation tsa tšimo ea motlakase
1. Bolo e tsamaisang motlakase e nang le radius ea 10 cm e na le tjhaja ea motlakase ea 500 μC. Lintlha tsa A, B, le C li lutse moleng le bohareng ba bolo bo hole ba 12 cm, 10 cm le 8 cm ka ho latellana ho tloha bohareng ba bolo. Bala matla a tšimo ea motlakase lintlheng tsa A, B, le C!
Tsejoa:
Radius ea bolo e tsamaisang (R) = 10 cm = 0.1 m
Tefiso ea motlakase (q) = 500 μC = 500 x 10-6 C
rA = 12 cm = 0,12 m
rB = 10 cm = 0,1 m
rC = 8 cm = 0,08 m
Coulomb e sa fetoheng (k) = 9 x 109
Oa Batla: Matla a tšimo ea motlakase ntlheng ea A (E)A), ntlheng ea B (EB) le ntlheng ea C (EC)
tharollo:
Lipotso tse 3 mabapi le equation e sa fetoheng ea selemo
1. Seliba se ka hara sethiba se lokolohileng se na le bolelele ba 10 cm. Qetellong e lokolohileng, boima ba digrama tse 200 bo a leketliswa e le hore bolelele ba seliba e be 11 cm. Haeba g = 10 m/s2, matla a selemo a sa fetoheng ke afe?
Tse tsejoang:
Bolelele ba pele ba selemo (y1) = 10 cm = 0.10 m
Bolelele ba ho qetela ba selemo (y2) = 11 cm = 0.11 m
Phetoho ea bolelele ba selemo (Δy) = 0.11 – 0.10 = 0.01 limithara
Boima ba mojaro (m) = 200 grams = 0.2 kg
Boima ba mojaro (w) = mg = (0,2)(10) = 2 Newtons
Oa Batla: Sephetho sa selemo (k)
tharollo:
Lipotso tse 3 mabapi le equation ea phapang e ka bang teng
1. Tefiso ea motlakase e tsamaisoa tšimong ea motlakase e ts'oanang ka matla a 2√3 N sebaka sa 20 cm. Haeba tataiso ea matla e le ka lehlakoreng la 30o ho ea ho ho falla ha tjhaja ea motlakase, phapang ke efe matla a motlakase a ka bang teng maemong a pele le a ho qetela a tjhaja ea motlakase.
Tse tsejoang:
Matla (F) = 2√3 N
Sebaka (libaka) = 20 cm = 0.2 m
Sekhutlo (θ) = 30o
Oa Batla: Phapang ea bokhoni ba motlakase
tharollo:
Lipotso tse 3 mabapi le equation ea lebelo la Angular
1. Ntho e tsamayang tseleng e chitja e na le radius ya 0.5 m. Karoloana e kgona ho kwahela sekhutlo sa 60π rad ka metsotswana e 15. Fumana lebelo la angular la ntho eo.
Tse tsejoang:
Radius (r) = limithara tse 0.5
Sekhutlo (θ) = 60π rad
Nako ea ho arohana (t) = metsotsoana e 15
Oa Batla: Lebelo la Angular (ω)
tharollo:
Lipotso tse 3 mabapi le Tekanyo ea matla e hlahang
1. Koloi e boima ba lithane tse 5 e tloha phomolong ka metsotsoana e 50, e fihla lebelong la 72 km/hora. Matla koloing ke…
Tse tsejoang:
Boima (m) = lithane tse 5 = 5000 kg
Lebelo la pele (vo) = 0
Lebelo la ho qetela (vt) = 72 km/h = 20 m/s
Nako ea ho arohana (t) = metsotsoana e 50
Oa Batla: Matla (F)
tharollo:
Lipotso tse 3 mabapi le equation ea Impulse
1. Koloi e boima ba 250 kg e tsamaya ka lebelo la 72 km/hora, ebe e potlakiswa ka matla a sa fetoheng hoo ka metsotsoana e 5 lebelo la yona le fetohang 80 km/hora. Fumana hore na pululelo e tsamaya ka metsotsoana e 5.
Tse tsejoang:
Boima ba koloi (m) = 250 kg
Lebelo la pele (v)o) = 72 km/h = 20 m/s
Lebelo la ho qetela (v)t) = 80 km/h = 22 m/s
Nako ea ho arohana (t) = metsotsoana e 5
Oa Batla: Fumana tšusumetso (I)
tharollo:
Lipotso tse 3 mabapi le equation ea matla a khohlano
1. Boloko A 3 kg e beoa tafoleng ebe e tlangwa ka thapo e hoketsweng lejwe B = 2 kg ka pulley jwalo ka ha ho bontshitswe. Boima le kgohlano ya pulley di hlokomolohuwa. Ho potlaka ka lebaka la matla a kgoheli g = 10 m/s2Fumana hore na sistimi e potlakile hakae le hore na e tsitsitse hakae thapong haeba:
a) tafole e boreleli
b) tafole e sa tebang e nang le coefficient ea kinetic friction ea 0.4
Tse tsejoang:
Boima ba boloko A (mA) = 3 kg
Boima ba lefika B (mB) = 2 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2
Boima ba boloko A (w)A) = mg = (3)(10) = 30 Newton
Boima ba lefika B (w)B) = mg = (2)(10) = 20 Newton
Oa Batla: Ho potlaka ha sistimi (a) le kgatello thapong (T)
tharollo:
Lipotso tse 3 mabapi le equation ea matla a tloaelehileng
1. Boloko bo na le boima ba 5 kg. Haeba g = 10 m/s2, etsa qeto:
a) boima ba boloko
b) matla a tloaelehileng haeba boloko bo behiloe sefofaneng se bataletseng
c) matla a tloaelehileng haeba boloko bo lutse sefofaneng se sekametseng se etsang sekhutlo sa 30o ho ea ho rapameng
Tse tsejoang:
Boima ba boloko (m) = 5 kg
Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s2
Oa Batla: w, N sefofaneng le N moeding
tharollo:
Lipotso tse 3 mabapi le equation ea khatello ea thapo
1. Setšoantšo se ka tlase se bontša liboloko tse tharo, e leng A, B le C tse fumanehang sebakeng se bataletseng se bataletseng. Haeba boima ba A = 1 kg, boima ba B = 2 kg le boima ba C = 2 kg le F = 10 N, joale fumana karolelano ea khatello thapong pakeng tsa A le B le khatello thapong pakeng tsa B le C.
Tse tsejoang:
Boima ba A (mA) = 1 kg
Boima ba B (mB) = 2 kg
Boima ba C (mC) = 2 kg
Matla a ho tsikinyeha (F) = 10 N
Oa Batla: TAB :TBC
tharollo: