Tšebeliso ea paballo ea matla a mechini bakeng sa motsamao oa liqhomane - mathata le litharollo

1. Bolo ea maoto e rahiloeng e tloha fatše ka sekhutlo θ = 30^o ka lebelo la pele la 10 m/s. boima = 0.1 lik'hilograma. Ho potlakisa ka baka la matla a khoheli ke 10 limithara / s². Etsa qeto (a) The matla a khoheli a ka bang teng ntlheng e phahameng ka ho fetisisa (b) Ntlha e phahameng ka ho fetisisa kapa bophahamo bo phahameng ka ho fetisisa

Tse tsejoang:

Boima (m) = 0.1 kg

Lebelo la pele (v)_o) = 10 m/s

Sekhutlo = 30^o

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Tharollo:

(a) Matla a khoheli a ka bang teng

Bala karolo e rapameng (v)_ox) le karolo e otlolohileng (v_oy) ea lebelo la pele.

v_ox = v_o cos θ = (10)(cos 30^o) = (10)(0.5√3) = 5√3 m/s

v_oy = v_o ntle θ = (10)(sebe sa 30^o) = (10)(0.5) = 5 m/s

Matla a pele a mechini

qalong matla a maiketsetso (Nna_o) = matla a kinetic (HO)

ME_o = KE = ½ mv_o² = ½ (0.1)(10)² = ½ (0.1)(100) = ½ (10) = 5 Joule

Matla a ho qetela a mechini

Matla a kinetic ntlheng e phahameng ka ho fetisisa:

KE = ½ mv_ox² = ½ (0.1)(5√3)² = ½ (0.1)((25)(3)) = ½ (0.1)(75) = 3.75 Dijoule

Molao-motheo oa paballo ea matla a mechini

Matla a pele a mechini (ME)_o) = matla a ho qetela a mechini (ME_t)

KE = PE + KE

5 = EP + 3.75

PE = 5 – 3.75 = 1.25 Joule

Matla a khoheli a ka bang teng ntlheng e phahameng ka ho fetisisa ke 1.25 Joules.

(b) Ntlha e phahameng ka ho fetisisa kapa bophahamo bo phahameng ka ho fetisisa

PE = mgh

1.25 = (0.1)(10) h

1.25 = h

Bophahamo bo phahameng ka ho fetisisa ke limithara tse 1.25.

2. Bolo ea 0.1-kg e phaphametse ka ho otloloha ka lebelo la pele v_o = 10 m/s ho tloha mohahong o bophahamo ba limithara tse 10. Ho potlaka ka lebaka la matla a khoheli ke 10 m/s²Fumana matla a kinetic a bolo ha e otla fatše.

Tse tsejoang:

Boima (m) = 0.1 kg

Lebelo la pele (v)_o) = 10 m/s

Ho potlaka ka lebaka la matla a khoheli (g) = 10 m/s²

Phetoho ea bophahamo (h) = 10 – 2 = 8 m

Oa Batla: matla a kinetic a limithara tse 2 ka holim'a lefatše

Tharollo:

Matla a khoheli a ka bang teng (PE) = mgh = (0.1)(10)(10) = 10 Joules

Matla a kinetic a pele (KE) = ½ mv_o² = ½ (0.1)(10)² = ½ (0.1)(100) = ½ (10) = 5 Joule

Matla a ho qetela a kinetic = matla a pele a khoheli + matla a pele a kinetic = 10 + 5 = 15 Joules

[ID ea sephutheloana sa wpdm='1173′]

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