Kufamba mundege yakakotama pasina simba rekukweshana - kushandiswa kwemutemo waNewton wematambudziko ekufamba uye mhinduro

1. Huremu hwebhokisi = 2 kg, kumhanyisa nekuda kwegiravhiti = 9.8 m/s ² . Tsvaga (a) simba rinomhanyisa bhokisi richidzika (b) hukuru hwekumhanya kwebhokisi.

mhinduro

Zvinozivikanwa:

Huremu (m) = 2 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 9.8 m/s ²

Huremu (w) = mg = (2)(9.8) = 19.6 Newtons

w _x = w chivi 30 = (19.6)(0.5) = 9.8 Newtons

w _y = w cos 30 = (19.6)(0.5√3) = 9.8√3 MaNewton

Solution:

(a) Mambure ekusimbisa anokurumidzisa bhokisi

Nzvimbo yakakotama yakatsetseka, saka hapana simba rekukweshana. Simba rega rinoshanda pachinhu chacho ndi w _x.

∑ F = w _x

∑ F = 9.8 Newton

(b) hukuru hwekukurumidzira

∑ F = ma

9.8 = (2) a

a = 9.8 / 2

a = 4.9 m/s ²

Hukuru hwekumhanya kwemotokari ndeye 4.9 m/s ² , divi rekumhanya kwemotokari riri pasi.

[irp]

2. Nzvimbo yakakotama yakatsetseka saka hapana simba rekukweshana . Huremu hwechinhu i3 kg, kukurumidza nekuda kwegiravhiti i9.8 m/s ² . Sarudza hukuru hwesimba F kana (a) chinhu chiri pachigaro (b) chinhu chiri kufamba pasi nekumhanya kunogara kwe2 m/s ² (c) chinhu chiri kufamba kumusoro nekumhanya kunogara kwe2 m/s ².

mhinduro

Zvinozivikanwa:

Huremu (m) = 3 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 9.8 m/s ²

Huremu (w) = mg = (3)(9.8) = 29.4 Newtons

w _x = w chivi 30 = (29.4)(0.5) = 14.7 Newtons

w _y = w cos 30 = (29.4)(0.5√3) = 14.7√3 MaNewton

Solution:

(a) Hukuru hwesimba F kana chinhu chiri pachigaro

Mutemo wekutanga waNewton wekufamba unoti kana chinhu chiri pachigaro, simba remagetsi rinoita basa pachinhu chacho izero.

∑ F = 0

F – w _x = 0

F = w _x

F = 14.7 Newton

(b) Hukuru hwesimba F kana chinhu chiri kufamba chichidzika pasi pa 2 m/s ²

∑ F = ma

w _x – F = ma

14.7 – F = (3)(2)

14.7 – F = 6

F = 14.7–6

F = 8.7 Newton

(c) Hukuru hwesimba F kana chinhu chiri kufamba mudenga pa 2 m/s ²

∑ F = ma

F – w _x = ma

F – 14.7 = (3)(2)

F – 14.7 = 6

F = 14.7 + 6

F = 20.7 Newton

[irp]

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