Miviri yakabatana netambo nepulley - kushandiswa kwematambudziko emutemo waNewton wekufamba uye mhinduro dzawo

1. Mabhokisi maviri akabatana netambo inomhanya pamusoro pepulley. Usafuratira huremu hwetambo nepulley uye chero kukweshana kuri mupulley. Huremu hwebhokisi 1 = 2 kg, huremu hwebhokisi 2 = 3 kg, kukurumidza nekuda kwegiravhiti = 10 m/s 2 . Tsvaga (a) Kukurumidza kwesystem (b) Kumanikidzwa kwetambo!

Miviri yakabatana netambo nepulley - kushandiswa kwematambudziko emutemo waNewton wekufamba uye mhinduro 1

mhinduro

Miviri yakabatana netambo nepulley - kushandiswa kwematambudziko emutemo waNewton wekufamba uye mhinduro 2Zvinozivikanwa:

Huremu hwebhokisi 1 (m1 ) = 2 kg

Huremu hwebhokisi 2 (m2 ) = 3 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2

Kurema kwebhokisi 1 (w 1 ) = m 1 g = (2)(10) = 20 Newtons

Kurema kwebhokisi 2 (w 2 ) = m 2 g = (3)(10) = 30 Newtons

Solution:

(a) hukuru uye gwara rekumhanya

w 2 > w 1 saka bhokisi 2 rinomhanyisa pasi uye bhokisi 1 rinomhanyisa kumusoro.

Masimba ane divi rimwe chete nekukurumidzisa (w 2 na T 1 ), chiratidzo chawo chakanaka. Masimba ane divi rakapesana nekukurumidzisa (T 2 na w 1 ), chiratidzo chavo chakanaka.

∑ F = ma

w2 - T2 +T1 - w1 = (m1 +m2) a ——-> T1 =T2 =T

w 2 – T + T – w 1 = (m 1 + m 2 ) a

w 2 – w 1 = (m 1 + m 2 ) a

30 – 20 = (2 + 3) a

10 = 5 a

a = 10 / 5

a = 2 m/s 2

Hukuru hwekumhanya -mhanya i2 m/s 2.

(b) Simba rekumanikidza

Bhokisi rechipiri:

Pane masimba maviri anoitwa pabhokisi rechipiri: chekutanga, huremu hwebhokisi rechipiri (w 2 ), kunongedzera pasi kuitira kuti rive rakanaka. Chechipiri, simba rekumanikidzwa rinoitwa pabhokisi rechipiri (T 2 ), kunongedzera kumusoro kuitira kuti rive negative. Shandisa mutemo wechipiri waNewton wekufamba.

∑ F = ma

w 2 – T 2 = m 2 a

30 – T 2 = (3)(2)

30 – T 2 = 6

T 2 = 30 – 6

T 2 = 24 Newton

Bhokisi 1:

Pane masimba maviri anoitwa pabhokisi 1. Chekutanga , huremu hwebhokisi 1 (w 1 ), hunonongedza pasi saka huri negative. Chechipiri , simba rekumanikidzwa riri pabhokisi 1 (T 1 ) rinonongedza kumusoro saka riri negative. Shandisa mutemo wechipiri waNewton wekufamba:

∑ F = ma

T 1 – w 1 = m 1 a

T 1 – 20 = (2)(2)

T 1 – 20 = 4

T 1 = 20 + 4

T 1 = 24 Newton

Hukuru hwesimba rekumanikidzwa = T 1 = T 2 = T = 24 Newtons

onawo  Mutemo wekutanga waKirchhoff - matambudziko nemhinduro

2. Chinhu chiri panzvimbo yakatsetseka yakatwasuka. Huremu hwechinhu 1 = 2 kg, huremu hwechinhu 2 = 4 kg, kukurumidza nekuda kwegiravhiti = 10 m/s 2 , kuenzana kwekukweshana kwakasimba = 0.4, kuenzana kwekukweshana kwekinetic = 0.3. Sisitimu yacho yakamira kana kuti yakakurumidza? Kana sisitimu yakakurumidza, tsvaga hukuru negwara rekukwidza kwesisitimu!

Miviri yakabatana netambo nepulley - kushandiswa kwematambudziko emutemo waNewton wekufamba uye mhinduro 3

mhinduro

Miviri yakabatana netambo nepulley - kushandiswa kwematambudziko emutemo waNewton wekufamba uye mhinduro 4Zvinozivikanwa:

Huremu hwechinhu 1 (m1 ) = 2 kg

Huremu hwechinhu 2 (m2 ) = 4 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2

Koefficient yekukweshana kwesimba ( μs ) = 0.4

Chiyero chekukweshana kwekinetic ( μk ) = 0.3

Kurema kwechinhu 1 (w 1 ) = m 1 g = (2)(10) = 20 Newtons

Kurema kwechinhu 2 (w 2 ) = m 2 g = (4)(10) = 40 Newtons

Simba rakajairika rinoshandiswa pachinhu 1 (N) = w 1 = 20 Newtons

Simba rekukweshana kwakasimba kunoitwa pachinhu 1 (fs ) = μ s N = (0.4)(20) = 8 Newtons

Simba rekukweshana kwekinetic rinoitwa pachinhu 1 (f k ) = μ k N = (0.3)(20) = 6 Newtons

Zvinodiwa: kukurumidza (a)

Solution:

w 2 > fs ( 40 Newton > 8 Newton) saka chinhu 2 chinokurumidziswa chakadzika pasi uye chinhu 1 chinokurumidziswa chakatwasuka chakananga kurudyi. Simba rekukweshana rinoita basa pazvinhu 1 isimba rekukweshana kwechinetic (f k ). Shandisa mutemo wechipiri waNewton wekufamba:

∑ F = ma

w 2 – iyo = (m 1 + m 2 ) a

40 – 6 = (2 + 4) a

34 = 6 a

a = 34 / 6 = 17 / 3

a = 5.7 m/s 2

Hukuru hwekukurumidzira = 5.7 m/s 2

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