Kurerekera - matambudziko nemhinduro
1. Huremu hwebhuroko i5 kg, kumhanyisa nekuda kwegiravhiti = 9.8 m/s 2 , tan 37 o = 3/4. Chii chinonzi kumhanyisa kwebhuroko?

mhinduro
Zvinozivikanwa:
huremu (m) = 5 kg
kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
huremu (w) = mg = (5)(10) = 50 N
x = 3
Kureba kwenzvimbo yakatsamira (y) = 4
Kureba kwenzvimbo yakakombama (l) = 5
Zvinodiwa : kukurumidza kweblock (a)?
Solution:
Chivharo chinokurumidziswa nesimba re w x . Nzvimbo yakakotama yakatsetseka saka hapana simba rekukweshana.
w x = w sin θ = (w)(y / z)
w x = (50)(4/5)
w x = 40 Newton
Kukurumidza kwebhuroko (a)?
ΣF = ma
w x = ma
40 = (5) a
a = 40 / 5
a = 8 m/s 2
2. Bhurukwa rinotanga rakamira, rozokurumidziswa richikwira richienderana nepamusoro penzvimbo yakatsveyama. Huremu hweBhurukwa = 8 kg, coefficient of static friction µ s = 0.5 uye angle θ = 45 o . Chii chinonzi hukuru hwesimba F kuitira kuti bhurukwa rikurumidziswe.
Zvinozivikanwa:
Koefficient yekukweshana kwesimba (µs ) = 0.5
Angle (θ) = 45 o
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
Huremu hwebhuroko (m) = 8 kg
Huremu hwemabhuroko (w) = mg = (8 kg)(10 m/s 2 ) = 80 kg m/s 2 = 80 Newtons
Zvinodiwa: Hukuru hwesimba F
Solution:
Block tanga kukurumidza kana F ≥ wx + fs. 
Chikamu chakatarwa chehuremu :
w x = w chivi θ = (80)(chivi 45) = (80)(0.5√2) = 40√2
Chikamu chehuremu chakamira:
w y = w cos θ = (80)(cos 45) = (80)(0.5√2) = 40√2
N = w y = 40√2
Simba rekukakavadzana kwakasimba:
f s = µ s N = (0.5)(40√2) = 20√2
Hukuru hwesimba F:
F ≥ w x + f s
F ≥ 40√2 + 20√2
F ≥ 60√2 Newton
3. Huremu hwebhuroko i8 kg. Simba shoma rinodiwa kuti bhuroko ribate bhuroko kuitira kuti bhuroko risatsvedzerere pasi ndi … (sin 37 o = 0.6, cos 37 o = 0.8, g = 10 ms -2 , µ k = 0.1)
Zvinozivikanwa:
Huremu hwebhuroko (m) = 8 kg
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
Kurema kwebhuroko (w) = mg = (8)(10) = 80 Newtons
Chivi 37 o = 0.6
Cos 37 o = 0.8
Kukweshana kwekinetic (µk ) = 0.1
Simba rakajairika (N) = w y = w cos 37 o = (80)(0.8) = 64 Newtons
Zvinodiwa: Hukuru hwesimba F
Solution:
Bhokisi haritsvedzeri pasi kana F = w x
Chikamu chakatarwa chehuremu chakaenzana nepamusoro penzvimbo yakatsveyama:
w x = w chivi θ = (80)(chivi 37) = (80)(0.6) = 48
f k = µ k N = (0.1)(64) = 6.4
Simba shoma F kuitira kuti bhokisi risatsvedzerere pasi:
F + f k – w x = 0
F = w x – f k = 48 – 6.4 = 41.6 Newtons
4. Bhokisi re5-kg rinodhonzwa pamwe chete nedenderedzwa rakakombama nesimba re71 N (g = 10 ms -2 , sin 37 o = 0.6, cos 37 o = 0.8). Kana coefficient yesimba rekukweshana pakati pebhokisi nedenderedzwa iri 0.4, chii chinonzi kukurumidza kwebhokisi.
Zvinozivikanwa:
Huremu hwechinhu (m) = 5 kg
Kukurumidza kunokonzerwa negiravhiti (g) = 10 m/s 2
huremu hwebhuroko (w) = mg = (5)(10) = 50 Newtons
Simba F = 71 Newton
Chivi 37 o = 0.6
Cos 37 o = 0.8
Kukweshana kwemusanganiswa wekoefficient = 0.4
Zvinodiwa : Kukurumidza kwebhuroko (a)
Solution:
Chikamu chakatarwa chehuremu :
w x = w chivi θ = (50)(chivi 37) = (50)(0.6) = 30
Chikamu chehuremu chakamira :
w y = w cos θ = (50)(cos 37) = (50)(0.8) = 40
Simba rakajairika:
N = w y = 40
Simba rekukweshana kwekinetic:
f k = µ k N = (0.4)(40) = 16
Simba reNet:
∑F = F – w x – f k = 71 – 30 – 16 = 25 Newtons
Kukurumidzisa kwechinhu:
a = ∑F / m = 25 / 5 = 5 m/s 2
5. Bhokisi re500-N rakasimudzwa kurori richipfuura nepakati penzira yakatsamira, sezvakaratidzwa mumufananidzo uri pazasi. Kana kureba kwerori kuri 1.5 metres, tarisa kukura kwesimba rekufambisa bhokisi.
Zvinozivikanwa:
huremu hwebhokisi (w) = 500 Newtons
kureba kwerori (h) = 1.5 metres
kureba kwendege yakatsamira (l) = mamita matatu
Zvinodiwa: Hukuru hwesimba rekufambisa bhokisi (F)
Solution:
Chivi θ = opp / hyp = 1.5 mamita / 3 mamita = 1.5 / 3 = 0.5
Simba (F) rinodiwa kuti bhokisi rifambiswe, zvakafanana nechikamu chakatarwa chehuremu chakaenzana nedenderedzwa rakanamira (w x ).
w x = w chivi θ = (500 N)(0.5) = 250 N
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