Kufamba mundege yakakombama zvine simba rekukweshana - kushandiswa kwemutemo waNewton wematambudziko ekufamba uye mhinduro

1. Huremu hwechinhu = 2 kg, kukurumidza nekuda kwegiravhiti = 9.8 m/s ² , kuenzana kwekukakavadzana kwakagadzika = 0.2, kuenzana kwekukakavadzana kwekinetic = 0.1. Chinhu chiri kuzorora here kana kuti chiri kukurumidza? Kana chinhu chacho chichikurumidza, tsvaga (a) simba remagetsi (b) hukuru uye gwara rekumhanya kwebhokisi!

mhinduro

Zvinozivikanwa:

Huremu (m) = 2 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 9.8 m/s ²

Koefficient ye static friction ( μs ₎ = 0.2

Kukweshana kwekinetic ( μk ₎ = 0.1

Huremu (w) = mg = (2)(9.8) = 19.6 Newtons

Chikamu chakatarwa chehuremu ( w _x ) = w sin 30 ^o = (19.6)(0.5) = 9.8 Newtons

Chikamu chakamira chehuremu hwe th (w _y ) = w cos 30 ^o = (19.6)(0.5√3) = 9.8√3 Newtons

Simba rakajairika (N) = w _y = 9.8√3 Newtons

Simba rekukweshana kusingachinji (fs ₎ = (0.2)(9.8√3) = 1.96√3 Newton = 3.39 Newton

Simba rekukweshana kwekinetic (f _k ) = (0.1)(9.8√3) = 0.98√3 Newton = 1.69 Newton

Solution:

Chinhu chiri pazororo kana w _x < fs _, chinhu chiri kufamba pasi kana w _x > _fs.

w _x = 9.8 Newtons uye fs ₌ 3.39 Newtons.

(a) simba remagetsi

∑ F = w _x – f _k = 9.8 – 1.69 = 8.11 Newtons

(b) hukuru uye gwara rekumhanya

∑ F = ma

8.11 = (2) a

kuti = 4.05

Hukuru hwekukurumidzira = 4.05 m/s ² uye divi rekukurumidzira = pasi.

2. Huremu hwechinhu = 4 kg, kukurumidza nekuda kwegiravhiti = 9,8 m/s ² . Coefficient yekinetic friction = 0.2 uye coefficient yestatic friction = 0.4. Hukuru hwesimba F = 40 Newtons. Chinhu chacho chiri pazororo kana kuti chinotsvedza pasi? Kana chinhu chacho chikatsvedza pasi, tsvaga (a) simba remambure (b) hukuru uye gwara rekumhanya!

mhinduro

Zvinozivikanwa:

Huremu (m) = 4 kg

Kukurumidza kunokonzerwa negiravhiti (g) = 9.8 m/s ²

Chiyero chekukweshana kwesimba ( μs ₎ = 0.4

Chiyero chekukweshana kwekinetic ( μk ₎ = 0.2

Huremu (w) = mg = (4)(9.8) = 39.2 Newtons

Chikamu chakatarwa chehuremu (w _x ) = w sin 30 ^o = (39.2)(0.5) = 19.6 Newtons

Chikamu chakamira chehuremu (w _y ) = w cos 30 ^o = (392)(0..5√3) = 19.6√3 Newtons

Simba rakajairika (N) = w _y = 19.6√3 Newtons = 33.95 Newtons

simba rekukweshana kwesimba (fs ₎ = μ _s N = (0,4)(33.95) = 13.58 Newtons

Simba rekukweshana kwekinetic (f _k ) = μ _k N = (0.2)(33.95) = 6.79 Newtons

F = 40 Newton

Solution:

Chinhu chinotsvedza pasi kana F < w _x + fs _. Chinhu chinotsvedza kumusoro kana F > w _x + _fs.

F = 40 Newtons, w _x = 19.6 Newtons uye fs ₌ 13.58 Newtons.

F yakakura kupfuura w _x + f _s saka chinhu chacho chinotsvedza.

(a) Simba remagetsi

∑ F = F – w _{x – fk =} 40 – 19.6 – 6.79 = 13.61 Newtons

(b) Hukuru uye gwara rekumhanya

∑ F = ma

6.4 = (4) a

kuti = 1.6

Hukuru hwekumhanya kwemhepo ndeye 1.6 m/s ² uye divi rekumhanya kwemhepo riri mudenga.

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