ahupūngao

1. Ka tukuna e au ngā hau ki roto i tētahi ipu kua kati , ā, i te tīmatanga he rōrahi V me te pēhanga P. Mena ko te pēhanga whakamutunga he 4P, ā, ka noho pūmau te rōrahi, he aha te ōwehenga o te pūngao nekeneke tīmatanga me te pūngao nekeneke whakamutunga?

Mōhiotia:

Pēhanga tīmatanga (P ₁ ) = P

Pēhanga whakamutunga (P ₂ ) = 4P

Te rōrahi tīmatanga (V ₁ ) = V

Rōrahi whakamutunga (V ₂ ) = V

E hiahiatia ana: Te ōwehenga o te pūngao nekeneke tīmatanga ki te pūngao nekeneke whakamutunga (K E ₁ : K E ₂ )

Rongoā:

Te whanaungatanga i waenga i te pēhanga (P), te rōrahi (V) me te pūngao nekeneke (KE) o ngā hau pai :

Ko te ōwehenga o te pūngao nekeneke tīmatanga ki te pūngao nekeneke whakamutunga:

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2. He aha te pūngao nekeneke whakawhiti toharite o ngā ngota i roto i te hau pai i te 57 ^° C?

Mōhiotia:

Te pāmahana o te hau (T) = 57 ^° C + 273 = 330 Kelvin

Te pūmau o Boltzmann (k) = 1.38 x 10 ^-23 Joule/Kelvin

E hiahiatia ana: Te pūngao nekeneke nekehanga toharite

Rongoā:

Te whanaungatanga i waenga i te pūngao nekeneke (KE) me te pāmahana o te hau (T):

Te pūngao nekeneke whakawhiti toharite:

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3. He hau kei te 27 ^° C i roto i tētahi ipu kua kati . Mēnā ka piki ake te kaha nekeneke o te hau kia 2 ngā wā i te kaha nekeneke tīmatanga, ko te pāmahana whakamutunga o te hau ko…

Mōhiotia:

Te pāmahana tīmatanga (T ₁ ) = 27 ^o C + 273 = 300 K

Pūngao nekeneke tīmatanga = KE

Pūngao nekeneke whakamutunga = 4 K E

E hiahiatia ana: Te pāmahana whakamutunga (T ₂ )

Rongoā:

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4. Kei roto i tētahi ipu kati te hau pai, ā, ka whakamahanahia kia toru ngā wā ka piki ake te tere toharite whakamutunga o ngā matūriki hau i te tere toharite tīmatanga. Mena he 27 ^° C te pāmahana hau tīmatanga, ko te pāmahana whakamutunga o te hau pai ko…

Mōhiotia:

Te pāmahana tīmatanga = 27 ^° C + 273 = 300 Kelvin

Te tere tīmatanga = v

Te tere whakamutunga = 2v

E hiahiatia ana : Te pāmahana whakamutunga o te hau pai

Rongoā:

Ko te tere toharite whakamutunga = 2 x te tere toharite tīmatanga

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5. E toru ngā mole hau kei roto i te wāhi rōrahi 36 rita. Ko te pūngao nekeneke o ia ngota hau he 5 x 10 ^-21 Joules. Ko te pūmau hau whānui = 8.315 J/mole.K me te pūmau Boltzmann = 1.38 x 10 ^-23 J/K. He aha te pēhanga hau i roto i te ipu?

Mōhiotia:

Te maha o ngā mole (n) = 3 mole

Rōrahi = 36 rita = 36 dm ³ = 36 x 10 ^-3 m ³

Te pūmau a Boltzmann (k) = 1.38 x 10 ^-23 J/K

Pūngao nekeneke (KE) = 5 x 10 ^–21 Joules

Pūmau hau whānui (R) = 8.315 J/mole.K

E hiahiatia ana : Pēhanga hau (P)

Rongoā:

Tātaihia te pāmahana mā te whakamahi i te whārite o te pūngao nekeneke o te hau.

Tātaihia te pēhanga hau mā te whakamahi i te whārite o te ture hau pai (i roto i te maha o ngā ira, n):

PV = n RT

P (36 x 10 ^-3 ) = (3)(8.315)(241.5)

P (36 x 10 ^-3 ) = 6024.22

Ko te pēhanga hau he 1.67 x 105 ^Pascal , arā, 1.67 ngā āhumahi.

Pānuitia atu

1. Ka whakatakotoria e au ngā hau ki roto i tētahi ipu kua kati , ā, i te tīmatanga, ko te rōrahi he V, ko te pāmahana he T. Ko te pāmahana whakamutunga he 5/4T, ā, ko te pēhanga whakamutunga he 2P. He aha te rōrahi whakamutunga o te hau?

Mōhiotia:

Te rōrahi tīmatanga (V ₁ ) = V

Te pāmahana tīmatanga (T ₁ ) = T

Te pāmahana whakamutunga (T ₂ ) = 5/4 T

Pēhanga tīmatanga (P ₁ ) = P

Pēhanga whakamutunga (P ₂ ) = 2P

E hiahiatia ana: Te Pukapuka Whakamutunga (V ₂ )

Rongoā:

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2. Tātaihia te rōrahi o te 2.00 mol o ngā hau (hau pai) i te STP. STP = Te Pāmahana me te Pēhanga Paerewa.

Mōhiotia:

Ngā ira hau (n) = 2 ngā ira hukapapa

Pāmahana paerewa (T) = 0 ^° C = 0 + 273 = 273 Kelvin

Pēhanga paerewa (P) = 1 atm = 1.013 x 10 ⁵ Pa

Taarua hau ao (R) = 8.315 Joule/mol e .Kelvin

E hiahiatia ana : Te rōrahi o ngā hau (V)

Rongoā:

Te whārite o te ture hau pai (i roto i te maha o ngā ira, n)

Ko te rōrahi o ngā mole hau e 2 he 44.8 rita.

Ko te rōrahi o te 1 mole o ngā hau he 45.4 rita / 2 = 22.4 rita.

Ko te rōrahi o te 1 mole o tētahi hau he 22.4 rita.

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3. E 27°C te pāmahana o te hau hāora e 4 rita, ā, ko te pēhanga he 2 atm (1 atm = 105 ^Pa ) i roto i tētahi ipu kua kati. Ko te pūmau hau whānui (R) = 8.314 J.mol e ⁻¹ .K ⁻¹ me te tau a Avogadro ( N _​​A ) = 6.02 x ¹⁰²³ ngota/mol e . He aha ngā ngota o ngā hau hāora i roto i te ipu?

Mōhiotia:

^{Te rōrahi o ngā} hau (V) = 4 rita = 4 dm³ ⁼ 4 x 10 ^-3 m³

Te pāmahana o ngā hau (T) = 27 ^° C = 27 + 273 = 300 Kelvin

Te pēhanga o ngā hau (P) = 2 atm = 2 x 10 ⁵ Pa

Pūmau hau whānui (R) = 8.314 J.mol e ⁻¹ .K ⁻¹

Te tau o Avogadro (N _A ) = 6.02 x 10 ²³

E hiahiatia ana : He aha ngā ngota o ngā hau hāora i roto i te ipu (N)

Rongoā:

I roto i te 1 mole o ngā hau hāora, e 1.93 x 1023 ^ngā ngota hāora.

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4. Ko te rōrahi o tētahi ipu kei roto he hau neon (Ne, papatipu ngota = 20 u) i te pāmahana me te pēhanga paerewa (STP ) he 2 m³ ^. Tātaihia te papatipu o te hau neon!

Mōhiotia:

Papatipu ngota o te neon = 20 karamu/mol e = 0,02 kg/mol e

Pāmahana paerewa (T) = 0 ^° C = 273 Kelvin

Pēhanga paerewa (P) = 1 atm = 1.013 x 10 ⁵ Pascal

Rōrahi (V) = 2 ^m3

E hiahiatia ana : te taumaha (m) o te hau neon

Rongoā:

I te pāmahana me te pēhanga paerewa (STP), 1 mole o ngā hau katoa, whakaurua te hau neon, he rōrahi 22.4 ritas = 22.4 dm³ = 0.0448 m³.

I roto i te rōrahi o te 2 m ³ , e 44.6 ngā mole o te hau neon.

Ko te papatipu ngota whanaunga o te hau neon he 20 karamu/mole.

Ko te tikanga o tēnei, i roto i te 1 ira he 20 karamu, arā, 0.02 kg o te hau neon. Nā te mea he 0.02 kg o te hau neon i roto i te 1 ira, nō reira, i roto i te 44.6 ira he 44.6 ira x 0.02 kg/ira = 0.892 kg = 892 karamu o ngā hau neon.

Pānuitia atu

1. Ko ngā hau e tukuna ana e au i te tīmatanga he pēhanga P me te pāmahana T. Ka pāngia te hau e te tukanga isochoric kia 4 ngā wā o te pēhanga whakamutunga i te pēhanga tīmatanga. He aha te pāmahana whakamutunga o te hau?

Mōhiotia:

Pēhanga tīmatanga (P ₁ ) = P

Pēhanga whakamutunga (P ₂ ) = 4P

Te pāmahana tīmatanga (T ₁ ) = T

E hiahiatia ana: Te pāmahana whakamutunga (T ₂ )

Rongoā:

Ko te tauira o te ture a Gay-Lussac :

E whā ngā whakarea o te pāmahana whakamutunga i te pāmahana tīmatanga.

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2. I roto i tētahi ipu kua kati, ko te pāmahana o ngā hau pai i te tīmatanga he 27 ^° C. Mēnā ka 2 te whakarea o te pēhanga whakamutunga i te pēhanga tīmatanga, he aha te pāmahana whakamutunga?

Mōhiotia:

Pēhanga tīmatanga (P ₁ ) = P

Pēhanga whakamutunga (P ₂ ) = 2P

Te pāmahana tīmatanga (T ₁ ) = 27 ^o C + 273 = 300 K

E hiahiatia ana: Te pāmahana whakamutunga (T ₂ )

Rongoā:

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3. Ka whakakīia te potae ki te pēhanga ine o te 2 atm i te 27°C. I muri i te taraiwa, ka piki te pāmahana i roto i te potae ki te 47°C. He aha te pēhanga i roto i te potae ināianei?

Mōhiotia:

Te pēhanga hau = 1 atm = 1 x 10 ⁵ Pa

Ko te pēhanga ine tuatahi = 2 atm = 2 x 10 ⁵ Pa

Ko te pēhanga tino tīmatanga (P ₁ ) = 1 atm + 2 atm = 3 atm = 3 x 10 ⁵ Pa

Ko te pāmahana tīmatanga (T ₁ ) = 27 ^° C + 273 = 300 K

Ko te pāmahana whakamutunga (T ₁ ) = 47 ^° C + 273 = 320 K

E hiahiatia ana: Te pāmahana ine whakamutunga

Rongoā:

Te pēhanga ine whakamutunga = te pēhanga tino whakamutunga – te pēhanga hauātea

Ko te pēhanga ine whakamutunga = 3.2 atm – 1 atm

Ko te pēhanga ine whakamutunga = 2.2 atm

Pānuitia atu

1. I roto i tētahi ipu kua kati, ka whakawhanui te hau kia toru ngā whakarea o te rōrahi whakamutunga i te rōrahi tīmatanga (V = rōrahi tīmatanga, T = pāmahana tīmatanga ). He aha te pāmahana whakamutunga?

Mōhiotia:

Te rōrahi tīmatanga (V ₁ ) = V

Te rōrahi whakamutunga (V ₂ ) = 3V

Te pāmahana tīmatanga (T ₁ ) = T

E hiahiatia ana: Te pāmahana whakamutunga (T ₂ )

Rongoā:

Ko te tauira o te ture a Charles :

E toru ngā whakarea o te pāmahana whakamutunga o ngā hau i tōna pāmahana tīmatanga.

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2. Ko te rōrahi o ngā hau e tukuna ana e au i te tīmatanga ko V, ā, ko te pāmahana ko T. Mēnā ka pāngia te hau e te tukanga isobaric kia rua ngā wā o te pāmahana i te pāmahana tīmatanga, ko te rōrahi whakamutunga o ngā hau ko…

Mōhiotia:

Te rōrahi tīmatanga (V ₁ ) = V

Te pāmahana tīmatanga (T ₁ ) = T

Te pāmahana whakamutunga (T ₂ ) = 2T

E hiahiatia ana: te pukapuka whakamutunga (V ₂ )

Rongoā:

E rua ngā whakarea o te rōrahi whakamutunga o ngā hau i te rōrahi tīmatanga.

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3. I roto i tētahi ipu kua kati, ko te rōrahi o ngā hau pai i te tīmatanga he 2 rita, ā, ko te pāmahana he 27 ^° C. Mēnā ka 3 rita te rōrahi whakamutunga o ngā hau, ko te pāmahana whakamutunga ko…

Mōhiotia:

Te rōrahi tīmatanga (V ₁ ) = 2 rita = 2 dm ³ = 2 x 10 ^-3 m ³

Te rōrahi whakamutunga (V ₂ ) = 3 rita = 3 dm ³ = 3 x 10 ^-3 m ³

Te pāmahana tīmatanga (T ₁ ) = 27 ^o C + 273 = 300 K

E hiahiatia ana: Te pāmahana whakamutunga (T ₂ )

Rongoā:

Ko te pāmahana whakamutunga ko 177 ^° C, arā, 177 + 273 = 450 Kelvin.

Pānuitia atu

1. I te tīmatanga, ko te pēhanga o ētahi hau pai ko P, ā, ko te rōrahi ko V. Mēnā ka pāngia te hau e te tukanga isothermal kia 4 ngā wā o te pēhanga whakamutunga i te pēhanga tuatahi, ko te rōrahi whakamutunga o te hau ko…

Mōhiotia:

Pēhanga tīmatanga (P ₁ ) = P

Pēhanga whakamutunga (P ₂ ) = 4P

Te rōrahi tīmatanga (V ₁ ) = V

E hiahiatia ana: Te Pukapuka Whakamutunga (V ₂ )

Rongoā:

Ko te tauira o te ture a Boyle :

PV = pūmau

P ₁ V ₁ = P ₂ V ₂

(P)(V) = (4P)(V ₂ )

V = 4 V ₂

V ₂ = V / 4 = ¼ V

Ko te rōrahi whakamutunga o ngā hau he ¼ te wā o te rōrahi tīmatanga.

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2. I roto i tētahi ipu kua kati, ka whakawhanui te hau kia rua ngā whakarea o te rōrahi whakamutunga i te rōrahi tīmatanga (V = rōrahi tīmatanga, P = pēhanga tīmatanga). Ko te pēhanga whakamutunga o ngā hau ko…

Mōhiotia:

Pēhanga tīmatanga (P ₁ ) = P

Te rōrahi tīmatanga (V ₁ ) = V

Te rōrahi whakamutunga (V ₂ ) = 2V

E hiahiatia ana : Pēhanga whakamutunga (P ₂ )

Rongoā:

P ₁ V ₁ = P ₂ V ₂

PV = P ₂ (2V)

P = P ₂ (2)

P ₂ = P / 2 = ½ P

Ka piki te pēhanga hau ki te ½ whakarea o te pēhanga tīmatanga.

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3. I roto i tētahi ipu kua kati, ko ngā hau he 2 atm te pēhanga me te 1 rita te rōrahi. Mēnā ka huri te pēhanga hau ki te 4 atm, ka huri te rōrahi hau ki...

Mōhiotia:

Pēhanga tīmatanga (P ₁ ) = 2 atm = 2 x 10 ⁵ Pa

Pēhanga whakamutunga (P ₂ ) = 4 atm = 4 x 10 ⁵ Pa

Te rōrahi tīmatanga (V ₁ ) = 1 rita = 1 dm ³ = 1 x 10 ^-3 m ³

E hiahiatia ana : Te pukapuka whakamutunga (V ₂ )

Rongoā:

P ₁ V ₁ = P ₂ V ₂

( 2 x 10 ⁵ )(1 x 10 ^{- 3} ) = (4 x 10 ⁵ ) V ₂

( 1)(1 x 10 ^-3 ) = (2) V ₂

1 x 10 ^-3 = (2) V ₂

V ₂ = ½ x 10 ^-3

V ₂ = 0.5 x 10 ^-3 m ³ = 0.5 dm ³ = 0.5 rita s

Pānuitia atu

1. E toru ngā pūnga hiko, C ₁ = 2 μF, C ₂ = 4 μF, C ₃ = 4 μF, e honoa ana i roto i te raupapa me te whakarara . Tātaihia te kaha o tētahi pūnga hiko kotahi ka rite te pānga ki te whakakotahitanga.

Mōhiotia:

Pūnga C ₁ = 2 μ F

Pūnga C ₂ = 4 μ F

Pūnga C ₃ = 4 μ F

E hiahiatia ana: Te kaha ōrite (C)

Rongoā:

Ka honoa ngā pūnga C ₂ me C _{3 ki te taha whakarara. Ko te pūnga ōrite:}

C _P = C ₂ + C ₃ = 4 + 4 = 8 μ F

Ka honoa ngā pūnga C ₁ me C _{p i roto i te raupapa. Ko te pūnga ōrite:}

1/C = 1/C ₁ + 1/ C _P = 1/2 + 1/8 = 4 / 8 + 1/8 = 5/8

C = 8/5 μF

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2. E rima ngā pūnga hiko, C ₁ = 2 μF, C ₂ = 4 μF, C ₃ = 6 μF, C ₄ = 5 μF, C ₅ = 10 μF, kua honoa raupapa, kua honoa whakarara hoki. Tātaihia te kaha o tētahi pūnga hiko kotahi ka rite te pānga ki te whakakotahitanga.

Mōhiotia:

Pūnga C₁ = 2 μF

Pūnga C ₂ = 4 μ F

Pūnga C ₃ = 6 μ F

Pūnga C ₄ = 5 μ F

Pūnga C ₅ = 10 μ F

E hiahiatia ana: Te kaha ōrite (C)

Rongoā:

Ka honoa ngā pūnga C ₂ me C _{3 ki te taha whakarara. Ko te pūnga ōrite:}

CP = _{C2 +} C3_​

CP = 4 + ₆

CP ₌ 10 μF​

Ka honoa ngā pūnga hiko C1 , _CP , C4 _me C5 _{i roto i te raupapa. Ko te pūnga hiko ōrite:}

1/C = 1/C ₁ + 1/ C _P + 1/ C ₄ + 1/ C ₅

1 / C = 1/2 + 1/10 + 1/5 + 1/10

1/C = 5/10 + 1/10 + 2/10 + 1/10

1/C = 9/10

C = 10/9 μF

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3 C₁ = 3 μF, C₂ = 4 μF me C₃ = 3 μKo ngā F, he mea hono raupapa, he mea hono whakarara hoki. Whakatauhia te pūngao hiko i runga i te awheawhe.

Mōhiotia:

Pūnga C₁ = 3 μF

Pūnga C ₂ = 4 μ F

Pūnga C ₃ = 3 μ F

E hiahiatia ana: Te kaha ōrite (C)

Rongoā:

Ka honoa ngā pūnga C ₂ me C _{3 ki te taha whakarara. Ko te pūnga ōrite:}

CP = _{C2 +} C3_​

CP = 4 ₊ 3

CP ₌ 7 μF​

Ka honoa ngā pūnga C ₁ me C _{P i roto i te raupapa. Ko te pūnga ōrite:}

1/C = 1/C ₁ + 1/ C _P

1/C = 1/3 + 1/7

1/C = 7/21 + 3/21

1/C = 10/21

C = 21/10

C = 2.1 µF

C = 2.1 x 10 ^-6 F

Te pūngao hiko i runga i ngā ara iahiko:

E = ½ CV ²

E = ½ ( 2.1 x 10 ^-6 )(12 ² )

E = ½ (2.1 x 10 ^-6 )(144)

E = (2.1 x 10 ^-6 )(72)

E = 151.2 x 10 ^-6 Joule

E = 1.5 x 10 ^-4 Joule

Pānuitia atu

1. E whā ngā pūnga hiko, C ₁ = 2 μF, C ₂ = 1 μF, C ₃ = 3 μF, C ₄ = 4 μF, e honoa raupapa ana . Tātaihia te kaha o tētahi pūnga hiko kotahi ka rite te pānga ki te huinga.

Mōhiotia:

Pūnga C ₁ = 2 μ F

Pūnga C ₂ = 1 μ F

Pūnga C ₃ = 3 μ F

Pūnga C ₃ = 4 μ F

E hiahiatia ana: Te kaha ōrite

Rongoā:

Te kaha ōrite:

1/C = 1/C ₁ + 1/C ₂ + 1/C ₃ + 1/C ₄

1/C = 1/2 + 1/1 + 1/3 + 1/4

1/C = 6/12 + 12/12 + 4/12 + 3/12

1/C = 25/12

C = 12/25

C = 0.48

Ko te kaha ōrite o te huinga katoa ko 0.48 μF.

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2. Tāutuhia te utu i runga i te pūnga C ₁ mēnā ko te rerekētanga pūmanawa i waenga i a P me Q he 12 Volts…

Mōhiotia:

Pūnga C ₁ = 1 0 μ F = 1 0 x 10 ^-6 F

Pūnga C ₂ = 2 0 μ F = 2 0 x 10 ^-6 F

Rerekētanga pūmanawa (V) = 12 Volts

E hiahiatia ana: te utu i runga i te pūnga C ₁ (Q ₁ )

Rongoā:

Te kaha ōrite:

1/C = 1/C ₁ + 1/ C ₂

1/C = 1/10 + 1/20 = 2/20 + 1/20 = 3/20

C = 20/3 μ F = (20/3) x 10 ^-6 F

Te utu hiko i runga i te pūnga rite:

Q = (C)(V) = (20/3)(12)(10 ^-6 ) = 80 x 10 ^-6 C

Q = 80 µC

Ka honoa ngā pūnga hiko i roto i te raupapa kia puta ai te utu hiko i runga i ngā pūnga hiko ōrite = te utu hiko i runga i te pūnga hiko C ₁ = te utu hiko i runga i te pūnga hiko C ₂.

Ko te utu hiko i runga i te pūnga C ₁ he 80 μC.

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3. E rua ngā pūnga hiko, C ₁ = 2 μF me C ₂ = 4 μF, e honoa ana i roto i te raupapa. Ka utua ngā pūnga hiko. Ko te rerekētanga pūmanawa i runga i te pūnga hiko C ₁ he 2 Volts. Ko te utu hiko i runga i te pūnga hiko C ₂ he…

Mōhiotia:

C apa c itor C ₁ = 2 μ F = 2 x 10 ^-6 F

C apa c itor C ₂ = 4 μ F = 4 x 10 ^-6 F

Ko te rerekētanga pūmanawa i runga i te pūnga C ₁ (V ₁ ) = 2 Volts

E hiahiatia ana : Te utu hiko i runga i te pūnga C2_.

Rongoā:

Te utu hiko i runga i te pūnga C ₁ :

Q ₁ = C ₁ V ₁ = (2 x 10 ^-6 )(2) = 4 x 10 ^-6 C

Q ₁ = 4 μC

Ka honoa ngā pūnga hiko i roto i te raupapa kia rite ai te utu hiko i runga i te pūnga hiko C ₁ ki te utu hiko i runga i te pūnga hiko C ₂.

Ko te utu i runga i te pūnga C ₂ he 4 μC.

Pānuitia atu

1. E whā ngā pūnga hiko , C ₁ = 2 μF, C ₂ = 1 μF, C ₃ = 3 μF, C ₄ = 4 μF, e honoa ana i te taha whakarara. Tātaihia te kaha o tētahi pūnga hiko kotahi ka rite te pānga ki te huinga.

Mōhiotia:

Pūnga C ₁ = 2 μ F

Pūnga C ₂ = 1 μ F

Pūnga C ₃ = 3 μ F

Pūnga C ₃ = 4 μ F

E hiahiatia ana: Te kaha ōrite

Rongoā:

Te kaha ōrite:

C = _C1 + _C2 + _C3

C = 4 μF + 2 μF + 3 μF = 9 μF

Ko te kaha ōrite o te huinga katoa ko 9 μF.

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2. Tāutuhia te utu i runga i te pūnga C ₂ mēnā ko te rerekētanga pūmanawa i waenga i ngā pūwāhi A me B he 9 Volts…

Mōhiotia:

C apa c itor C ₁ = 20 μ F = 20 x 10 ^-6 F

C apa c itor C ₂ = 30 μ F = 30 x 10 ^-6 F

Te rerekētanga pūmanawa i waenga i ngā pūwāhi A me B (V _AB ) = 9 Volts

E hiahiatia ana : te utu i runga i te pūnga C ₂ (Q ₂ )

Rongoā:

Rerekētanga pūmanawa:

Ka honoa ngā pūnga hiko i te taha whakarara kia rite ai te rerekētanga pūmanawa i waenga i a A me B (V _AB ) = te rerekētanga pūmanawa i runga i te pūnga hiko C ₁ (V ₁ ) = te rerekētanga pūmanawa i runga i te pūnga hiko C ₂ (V ₂ ) = 9 Volts.

Te utu hiko i runga i te pūnga C ₂ :

Q ₂ = C ₂ V ₂ = (30 x 10 ^-6 )(9) = 270 x 10 ^-6 C

Q ₂ = 270 μC

Ko te utu hiko i runga i te pūnga C ₂ he 27 0 μC.

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3. E toru ngā pūnga hiko, C ₁ = 4 μF, C ₂ = 2 μF, C ₃ = 3 μF, e honoa ana i te taha whakarara. Ka utaina ngā pūnga hiko. Ko te rerekētanga pūmanawa i runga i te pūnga hiko C ₂ he 4 Volts. Whakatauhia

(a) Te utu hiko i runga i ngā pūnga hiko C ₁ , C ₂ me C ₃

(b) Te utu hiko i runga i te pūnga rite o te huinga katoa

Mōhiotia:

C apa c itor C ₁ = 4 μ F = 4 x 10 ^-6 F

Pūhiko C 2 ₌ 2 μ F = 2 x 10 ^-6 F

Pūhiko C 3 ₌ 3 μ F = 3 x 10 ^-6 F

Te rerekētanga pūmanawa i runga i te pūnga C ₂ (V ₂ ) = 4 Volts

E hiahiatia ana : Te utu hiko i runga i te pūnga C ₃ (Q ₃ )

Rongoā:

(a) Te utu hiko i runga i te pūnga C ₃

Te rerekētanga pūmanawa i runga i te pūnga C ₃ :

Ka honoa ngā pūnga iahiko i te taha whakarara kia puta ai te rerekētanga pūmanawa i runga i te pūnga iahiko C₃ (V₃) = te rerekētanga pūmanawa i runga i ngā pūnga C₂ (V₂) = te rerekētanga pūmanawa i runga i ngā pūnga C₁ (V₁) = te rerekētanga pūmanawa i runga i ngā pūnga taurite (V) = 4 Ngāohiko

Te utu hiko i runga i te pūnga C ₁ :

Q ₁ = C ₁ V ₁ = (4 x 10 ^-6 )(4) = 16 x 10 ^-6 C

Q ₁ = 16 μC

Te utu hiko i runga i te pūnga C ₂ :

Q ₂ = C ₂ V ₂ = (2 x 10 ^-6 )(4) = 8 x 10 ^-6 C

Q ₂ = 8 μC

Te utu hiko i runga i te pūnga C ₃ :

Q ₃ = C ₃ V ₃ = (3 x 10 ^-6 )(4) = 12 x 10 ^-6 C

Q ₃ = 12 μC

(b) Utu hiko i runga i te pūnga rite

Q = _Q1 + _Q2 + _Q3

Q = 16 μ C + 8 μ C + 12 μ C = 36 μ C

Otinga kē atu:

Te kaha ōrite:

C = _C1 + _C2 + _C3

C = 4 μF + 2 μF + 3 μF = 9 μF

C = 9 x 10 ^-6 F

Te rerekētanga pūmanawa i runga i te pūnga taurite:

V ₁ = V ₂ = V ₃ = V = 4 Ngāohiko

Ko te utu hiko i runga i te pūnga rite:

Q = CV = (9 x 10 ^-6 )(4) = 36 x 10 ^-6 C

Q = 36 µC

Pānuitia atu