Te taurite o ngā tinana e honoa ana e ngā taura me ngā pūrei – te whakamahinga o ngā raruraru me ngā otinga o te ture tuatahi a Newton

1. Kei runga i te papa piko tētahi pouaka he 5 kg te taumaha i te koki 30 ° . E tautokona ana te pouaka e tētahi taura. Tātaihia te kaha kume (T) me te kaha noa (N)!

Te taurite o ngā tinana e honoa ana e ngā taura me ngā pūwero – te whakamahinga o ngā raruraru me ngā otinga o te ture tuatahi a Newton 1

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Te taurite o ngā tinana e honoa ana e ngā taura me ngā pūwero – te whakamahinga o ngā raruraru me ngā otinga o te ture tuatahi a Newton 2∑Fx = 0

T – w sin 30 o = 0

T = w sin 30 o

T = (5 kg)(9.8 m/s 2 ) sin 30 o

T = (49)(0.5)

T = 24.5 Ngā Niutona

∑ F y = 0

N – w cos 30 o = 0

N = w cos 30 o

N = (49)(0.87)

N = 43 Niutona

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2. E rua ngā mea he taumaha m 1 = m 2 = 2 kg, e honoa ana e te aho kore taumaha i runga i te pūrei kore waku. Kimihia ngā kaha kume T 1 me T 2.

Te taurite o ngā tinana e honoa ana e ngā taura me ngā pūwero – te whakamahinga o ngā raruraru me ngā otinga o te ture tuatahi a Newton 3

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Te taurite o ngā tinana e honoa ana e ngā taura me ngā pūwero – te whakamahinga o ngā raruraru me ngā otinga o te ture tuatahi a Newton 4

(a) Kauwhata tinana-kore mō te mea 1 (b) Kauwhata tinana-kore mō te mea 2

Whakamahia te ture tuatahi a Newton ki te mea 1:

∑ F y = 0

T 1 – w 1 = 0

T 1 = w 1 = m 1 karamu = (2 kg)(9.8 m/s 2 ) = 19.6 N

Whakamahia te ture tuatahi a Newton ki te mea 2:

∑ F y = 0

T 2 – w 2 = 0

T 2 = w 2 = m 2 karamu = (2 kg)(9.8 m/s 2 ) = 19.6 N

T 1 = T 2 = 19.6 N.

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3. He mea taumaha w A = 30 N me te mea taumaha w B = 40 N, e herea ana e te taura māmā e whiti ana i runga i te pūrei kore-waku he iti noa te papatipu. Whakatauhia te tauwehenga o te waku pūmau mōrahi i waenga i te w B me te mata piko, mena kei te okioki te pūnaha.

Te taurite o ngā tinana e honoa ana e ngā taura me ngā pūwero – te whakamahinga o ngā raruraru me ngā otinga o te ture tuatahi a Newton 5

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Te taurite o ngā tinana e honoa ana e ngā taura me ngā pūwero – te whakamahinga o ngā raruraru me ngā otinga o te ture tuatahi a Newton 6

(a) Kauwhata tinana-kore mō te mea w A (b) Kauwhata tinana-kore mō te mea w B

Whakamahia te ture tuatahi a Newton ki te mea w A i te ahunga poutū (y):

∑ F y = 0 (kāore he whakaterenga i te ahunga poutū)

T – w A = 0

T = w A = 30 Newton

Whakamahia te ture tuatahi a Newton ki te mea w B i te ahunga poutū (y) :

∑ F y = 0

N – w B cos 45 o = 0

N = w B cos 45 o = (40)(0.7) = 28 Ngā Newton

Whakamahia te ture tuatahi a Newton ki te mea w B i te ahunga whakapae (x):

∑ F x = 0

F k + w B sin 45 o – T = 0

μ s N + w B hara 45 o – T = 0

μ s (28) + (40)(0.7) – 30 = 0

μs (28) + 28 – 30 = 0

μs (28) = 30 – 28

μs (28) = 2

μs = 2 / 28

μs = 0.07

Ko te tauwehenga o te waku pūmau mōrahi i waenga i te w B me te mata piko = 0.07.

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  1. Ngā matūriki i roto i te taurite kotahi-ahu
  2. Ngā matūriki i roto i te taurite rua-ahu
  3. Te taurite o ngā tinana e honoa ana e ngā taura me ngā pūwero
  4. Te taurite o ngā tinana i runga i te papa whakarara

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