E rua ngā kaiārahi hiko whakarara e kawe ana i ngā iahiko – ngā raruraru me ngā otinga

1. Ko te waea P e kawe ana i te iahiko 6-A ki runga e whakaaturia ana i te pikitia i raro nei. Mena ko µ o = 4π.10 -7 wb A -1 m -1 , ā, he kaha pana kei waenganui i te waea P me Q 1.2.10 -5 Nm – 1. Tātaihia te rahi me te ahunga o te iahiko hiko i runga i te waea Q.

Mōhiotia:E rua ngā kaiārahi whakarara e kawe ana i ngā iahiko – ngā raruraru me ngā otinga 1

IP = 6 Āmpere

µ o = 4π x 10 -7 wb A -1 m -1

F/l = 1,2 x 10 -5 N m -1

L = 1 mita

E hiahiatia ana: Te rahi me te ahunga o te iahiko hiko i runga i te waea Q

Rongoā:

Ko te ahunga o te iahiko i runga i te waea Q:

He kaha pana kei waenganui i te waea P me Q, ā, he rerekē te ahunga o te iahiko i runga i te waea P ki te ahunga o te iahiko i runga i te waea Q.

I runga i te waea P, kei runga te iahiko hiko, ā, kei raro te iahiko i runga i te waea Q.

Te au hiko i runga i te waea Q:

E rua ngā kaiārahi whakarara e kawe ana i ngā iahiko – ngā raruraru me ngā otinga 2

2. E rua ngā waea e whakarara ana, a L, me M, he 2-cm te tawhiti (tirohia te pikitia). He 4-A te iahiko o te waea M. He kaha panapana kei waenganui i ngā waea e rua, 6 x 10 -5 Nm -1 . Tātaihia te rahi me te ahunga o te iahiko hiko ki runga i te waea L. (µ o = 4π.10 -7 Wb.A -1 m -1 )

Mōhiotia:E rua ngā kaiārahi whakarara e kawe ana i ngā iahiko – ngā raruraru me ngā otinga 3

IM = 4 Āmpere

µ o = 4π x 10 -7 wb A -1 m -1

F/l = 6 x 10 -5 N m -1

R = 2 henimita = 0.02 mita

E hiahiatia ana: Te rahi me te ahunga o te iahiko hiko i runga i te waea L

Rongoā:

Te ahunga o te iahiko i runga i te waea L:

He kaha pana kei waenganui i te waea L me te waea M, ā, kei te taha kē te ahunga o te iahiko i runga i te waea L ki te ahunga o te iahiko i runga i te waea M.

I runga i te waea M ka anga whakarunga te iahiko, kia anga whakararo ai te iahiko i runga i te waea L.

Te au hiko i runga i te waea L:

E rua ngā kaiārahi whakarara e kawe ana i ngā iahiko – ngā raruraru me ngā otinga 4

3. He 1-m te tawhiti o te waea P me te Q. Ko te iahiko e mau ana i te waea P he 1-A. Mena ko te µ o = 4 π.10 -7 Wb.A -1 .m -1 , ā, he kaha kukume kei waenganui i a rātou anō he 10 -7 Nm -1 , whakatauhia te rahi me te ahunga o te iahiko i runga i te waea Q.

Mōhiotia:

IP = 1 ĀmpereE rua ngā kaiārahi whakarara e kawe ana i ngā iahiko – ngā raruraru me ngā otinga 5

µ o = 4π x 10 -7 wb A -1 m -1

F/l = 10 -7 N m -1

L = 1 mita

E hiahiatia ana: Te rahi me te ahunga o te iahiko i runga i te waea Q

Rongoā:

Ko te ahunga o te iahiko i runga i te waea Q:

He kaha kukume kei waenganui i te waea P me te waea Q, ā , ka rite te ahunga o te iahiko i runga i te waea P ki te ahunga o te iahiko i runga i te waea Q.

I runga i te waea P, ko te ahunga o te iahiko kei raro, pērā anō i runga i te waea Q, ko te ahunga o te iahiko kei raro.

Te au hiko i runga i te waea Q:

E rua ngā kaiārahi whakarara e kawe ana i ngā iahiko – ngā raruraru me ngā otinga 6

Waiho i te Comment